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Quadratic Equations



          By: Sushmita Kumari
          Roll: 03
          Class: X ‘B’
Definition

• In mathematics, a quadratic equation is a
  polynomial equation of the second degree. The
  general form is
               2
            ax      bx c       0
• where x represents a variable or an unknown,
  and a, b, and c are constants with a ≠ 0. (If
  a = 0, the equation is a linear equation.)
• The constants a, b, and c are called
  respectively, the quadratic coefficient, the linear
  coefficient and the constant term or free term.
Quadratic & Roots
Quadratic: A polynomial of degree=2

                   y= ax2+bx+c
                                 is a quadratic equation. (a   0)


Here is an example of one:




•   The name Quadratic comes from "quad" meaning square,
    because the variable gets squared (like x2).
•   It is also called an "Equation of Degree 2" (because of the "2"
    on the x)
Roots

 A real number α is called a root of the
  quadratic equation                          ,a≠0
  if aα2 + bα2 + c = 0.
 If α is a root of                      ,then we
  say that:
(i) x= α satisfies the equation ax2+bx+c =0
Or (ii) x= α is a solution of the equation
  ax2+bx+c =0
 The Root of a quadratic equation ax2+bx+c
  =0 are called zeros of the polynomial
  ax2+bx+c .
More Examples of Quadratic
Equations
                    In this one a=2, b=5 and c=3.
                 This one is a little more tricky:
    Where is a? In fact a=1, as we don't usually
    write "1x2“ b = -3 and where is c? Well, c=0, so
    is not shown.
                 Oops! This one is not a
    quadratic equation, because it is missing x2 (in
    other words a=0, and that means it can't be
    quadratic)
Hidden Quadratic Equations!

So far we have seen the "Standard Form" of a Quadratic
  Equation:


But sometimes a quadratic equation doesn't look like that..!
Here are some examples of different form:
 In disguise                              In Standard Form   a, b and c




 x2 = 3x -1           Move all terms to   x2 - 3x + 1 = 0    a=1, b=-3, c=1
                      left hand side
 2(w2 - 2w) = 5       Expand (undo the    2w2 - 4w - 5 = 0   a=2, b=-4, c=-5
                      brackets), and
                      move 5 to left
 z(z-1) = 3           Expand, and move                       a=1, b=-1, c=-3
                      3 to left
                                          z2 - z - 3 = 0


 5 + 1/x - 1/x2 = 0   Multiply by x2      5x2 + x - 1 = 0    a=5, b=1, c=-1
How To Solve It?

There are 3 ways to find the solutions:
 We can Factor the Quadratic (find what to multiply to make the
  Quadratic Equation)
 We can Complete the Square, or
 We can use the special Quadratic Formula:




Thus ax2+bx+c =0 has two roots α and β, given by

     b    b 2 4ac                  b    b 2 4 ac
α=                          β=
          2a                            2a
Discriminant
 The expression b2 - 4ac in the formula


 It is called the Discriminant, because it can "discriminate"
  between the possible types of answer.It can be denoted by “D”
 when b2 - 4ac, D is positive, you get two real solutions
 when it is zero you get just ONE real solution (both answers are
  the same)
 when it is negative you get two Complex solutions

    Value of D           Nature of Roots     Roots
    D>0                 Real and Unequal    [(-b±√D)/2a]
    D=0                 Real and Equal      Each root = (-b/2a)
    D<0                 No real roots       None
Using the Quadratic Formula
Just put the values of a, b and c into the Quadratic Formula, and do
   the calculation
Example: Solve 5x² + 6x + 1 = 0
Coefficients are: a = 5, b = 6, c = 1
Quadratic Formula: x = [ -b ± √(b2-4ac) ] / 2a
Put in a, b and c:
                             6    62 4 5 1
                       x=         2 5

                 6      36   20
Solve: x =
                       10

           6          16
x=
                 10

         6  4
x=
         10
x = -0.2 or -1
Continue..

 Answer: x = -0.2 or x = -1
 Check -0.2: 5×(-0.2)² + 6×(-0.2) + 1
  = 5×(0.04) + 6×(-0.2) + 1
  = 0.2 -1.2 + 1
  =0


 Check -1: 5×(-1)² + 6×(-1) + 1
  = 5×(1) + 6×(-1) + 1
  =5-6+1
  =0
Factoring Quadratics
 To "Factor" (or "Factorize") a Quadratic is to find what to multiply
  to get the Quadratic
   It is called "Factoring" because you find the factors (a factor is
  something you multiply by)
 Example
The factors of x2 + 3x - 4 are:
(x+4) and (x-1)
Why? Well, let us multiply them to see:
(x+4)(x-1)
= x(x-1) + 4(x-1)
= x2 - x + 4x - 4
= x2 + 3x – 4
• Multiplying (x+4)(x-1) together is called Expanding.
• In fact, Expanding and Factoring are opposites:
Examples of Factor
To solve by factoring:
1. Set the equation equal to zero.
2. Factor. The factors will be linear expressions.
3. Set each linear factor equal to zero.
4. Solve both linear equations.
Example: Solve by factoring x2 + 3x = 0
x2 + 3x = 0            set equation to zero
x( x + 3) = 0            factor

x=0        ,     x+3=0
                 x = -3 set the linear factors equal to zero and
                        solve the linear equation
Completing the Square
Solving General Quadratic Equations by Completing
  the Square:

"Completing the Square" is where we take a Quadratic Equation :
ax2 + bx + c = 0 and turn into a(x+d)2 + e = 0

We can use that idea to solve a Quadratic Equation (find where it
   is equal to zero).
But a general Quadratic Equation can have a coefficient of a in
   front of x2:

But that is easy to deal with ... just divide the whole equation by "a"
   first, then carry on.
Steps
Now we can solve Quadratic Equations in 5 steps:
 Step 1 Divide all terms by a (the coefficient of x2).


 Step 2 Move the number term (c/a) to the right side of the
  equation.


 Step 3 Complete the square on the left side of the equation and
  balance this by adding the same value to the right side of the
  equation.


 Step 4 Take the square root on both sides of the equation.


 Step 5 Add or subtract the number that remains on the left side
  of the equation to find x.
Example
Example 1: Solve x2 + 4x + 1 = 0
Step 1 can be skipped in this example since the coefficient of x2 is
   1
Step 2 Move the number term to the right side of the equation:
                x2 + 4x = -1
Step 3 Complete the square on the left side of the equation and
   balance this by adding the same number to the right side of the
   equation:
               x2 + 4x + 4 = -1 + 4
               (x + 2)2 = 3
Step 4 Take the square root on both sides of the equation:
                x + 2 = ±√3 = ±1.73 (to 2 decimals)
Step 5 Subtract 2 from both sides:
                x = ±1.73 – 2 = -3.73 or -0.27
BIBLIOGRAPHY

 Internet (Wikipedia,www.mathsisfun.com)


 Secondary School Mathematics (R.S. Aggarwal)

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Quadratic equations

  • 1. Quadratic Equations By: Sushmita Kumari Roll: 03 Class: X ‘B’
  • 2. Definition • In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is 2 ax bx c 0 • where x represents a variable or an unknown, and a, b, and c are constants with a ≠ 0. (If a = 0, the equation is a linear equation.) • The constants a, b, and c are called respectively, the quadratic coefficient, the linear coefficient and the constant term or free term.
  • 3. Quadratic & Roots Quadratic: A polynomial of degree=2 y= ax2+bx+c is a quadratic equation. (a 0) Here is an example of one: • The name Quadratic comes from "quad" meaning square, because the variable gets squared (like x2). • It is also called an "Equation of Degree 2" (because of the "2" on the x)
  • 4. Roots  A real number α is called a root of the quadratic equation ,a≠0 if aα2 + bα2 + c = 0.  If α is a root of ,then we say that: (i) x= α satisfies the equation ax2+bx+c =0 Or (ii) x= α is a solution of the equation ax2+bx+c =0  The Root of a quadratic equation ax2+bx+c =0 are called zeros of the polynomial ax2+bx+c .
  • 5. More Examples of Quadratic Equations  In this one a=2, b=5 and c=3.  This one is a little more tricky: Where is a? In fact a=1, as we don't usually write "1x2“ b = -3 and where is c? Well, c=0, so is not shown.  Oops! This one is not a quadratic equation, because it is missing x2 (in other words a=0, and that means it can't be quadratic)
  • 6. Hidden Quadratic Equations! So far we have seen the "Standard Form" of a Quadratic Equation: But sometimes a quadratic equation doesn't look like that..! Here are some examples of different form: In disguise In Standard Form a, b and c x2 = 3x -1 Move all terms to x2 - 3x + 1 = 0 a=1, b=-3, c=1 left hand side 2(w2 - 2w) = 5 Expand (undo the 2w2 - 4w - 5 = 0 a=2, b=-4, c=-5 brackets), and move 5 to left z(z-1) = 3 Expand, and move a=1, b=-1, c=-3 3 to left z2 - z - 3 = 0 5 + 1/x - 1/x2 = 0 Multiply by x2 5x2 + x - 1 = 0 a=5, b=1, c=-1
  • 7. How To Solve It? There are 3 ways to find the solutions:  We can Factor the Quadratic (find what to multiply to make the Quadratic Equation)  We can Complete the Square, or  We can use the special Quadratic Formula: Thus ax2+bx+c =0 has two roots α and β, given by b b 2 4ac b b 2 4 ac α= β= 2a 2a
  • 8. Discriminant  The expression b2 - 4ac in the formula  It is called the Discriminant, because it can "discriminate" between the possible types of answer.It can be denoted by “D”  when b2 - 4ac, D is positive, you get two real solutions  when it is zero you get just ONE real solution (both answers are the same)  when it is negative you get two Complex solutions Value of D Nature of Roots Roots D>0 Real and Unequal [(-b±√D)/2a] D=0 Real and Equal Each root = (-b/2a) D<0 No real roots None
  • 9. Using the Quadratic Formula Just put the values of a, b and c into the Quadratic Formula, and do the calculation Example: Solve 5x² + 6x + 1 = 0 Coefficients are: a = 5, b = 6, c = 1 Quadratic Formula: x = [ -b ± √(b2-4ac) ] / 2a Put in a, b and c: 6 62 4 5 1 x= 2 5 6 36 20 Solve: x = 10 6 16 x= 10 6 4 x= 10 x = -0.2 or -1
  • 10. Continue..  Answer: x = -0.2 or x = -1  Check -0.2: 5×(-0.2)² + 6×(-0.2) + 1 = 5×(0.04) + 6×(-0.2) + 1 = 0.2 -1.2 + 1 =0  Check -1: 5×(-1)² + 6×(-1) + 1 = 5×(1) + 6×(-1) + 1 =5-6+1 =0
  • 11. Factoring Quadratics  To "Factor" (or "Factorize") a Quadratic is to find what to multiply to get the Quadratic It is called "Factoring" because you find the factors (a factor is something you multiply by)  Example The factors of x2 + 3x - 4 are: (x+4) and (x-1) Why? Well, let us multiply them to see: (x+4)(x-1) = x(x-1) + 4(x-1) = x2 - x + 4x - 4 = x2 + 3x – 4 • Multiplying (x+4)(x-1) together is called Expanding. • In fact, Expanding and Factoring are opposites:
  • 12. Examples of Factor To solve by factoring: 1. Set the equation equal to zero. 2. Factor. The factors will be linear expressions. 3. Set each linear factor equal to zero. 4. Solve both linear equations. Example: Solve by factoring x2 + 3x = 0 x2 + 3x = 0 set equation to zero x( x + 3) = 0 factor x=0 , x+3=0 x = -3 set the linear factors equal to zero and solve the linear equation
  • 13. Completing the Square Solving General Quadratic Equations by Completing the Square: "Completing the Square" is where we take a Quadratic Equation : ax2 + bx + c = 0 and turn into a(x+d)2 + e = 0 We can use that idea to solve a Quadratic Equation (find where it is equal to zero). But a general Quadratic Equation can have a coefficient of a in front of x2: But that is easy to deal with ... just divide the whole equation by "a" first, then carry on.
  • 14. Steps Now we can solve Quadratic Equations in 5 steps:  Step 1 Divide all terms by a (the coefficient of x2).  Step 2 Move the number term (c/a) to the right side of the equation.  Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.  Step 4 Take the square root on both sides of the equation.  Step 5 Add or subtract the number that remains on the left side of the equation to find x.
  • 15. Example Example 1: Solve x2 + 4x + 1 = 0 Step 1 can be skipped in this example since the coefficient of x2 is 1 Step 2 Move the number term to the right side of the equation: x2 + 4x = -1 Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation: x2 + 4x + 4 = -1 + 4 (x + 2)2 = 3 Step 4 Take the square root on both sides of the equation: x + 2 = ±√3 = ±1.73 (to 2 decimals) Step 5 Subtract 2 from both sides: x = ±1.73 – 2 = -3.73 or -0.27
  • 16. BIBLIOGRAPHY  Internet (Wikipedia,www.mathsisfun.com)  Secondary School Mathematics (R.S. Aggarwal)