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Vertex form (standard form) for the equation of a parabola




 y = a(x – h)2 + k                     x = a(y – k)2 + h
 Vertex: (h, k)                          Vertex: (h, k)
Line of symmetry: x = h            Line of symmetry: y = k
Graph x = 2y2 + 8y + 9
x = (2y2 + 8y     )+9
x = 2(y2 + 4y + 4) + 9 - 8
x = 2(y + 2)2 + 1
Vertex: (1, -2)
Axis of symmetry: y = -2
Opens to the right
focus




        directrix
latus rectum




          directrix
y = a(x – h)2 + k




                    focus
                                                    1
                                    same distance
                                                    4a
                            directrix




                                          latus rectum
y = a(x – h)2 + k




                    focus
     latus rectum
      length
       1
                            directrix
       a
Pg 422
4(y – 2) = (x + 3)2   y = a(x – h)2 + k
4y – 8 = (x + 3)2
4y = (x + 3)2 + 8
4         4
y = ¼ (x + 3)2 + 2
a=¼
h = -3
k=2
y = ¼ (x + 3)2 + 2
vertex: (-3, 2)
axis of symmetry:
     x = -3
a=¼
distance from vertex
             1_
to focus = 4(¼) = 1
                       Length of latus
distance from vertex   rectum:
to directrix = 1
                       1 = 4 units
                       ¼
4x – 13 = y2 – 2y            x = a(y – k)2 + h
4x – 13 = (y2 – 2y +1) – 1
   +13                +13
4x = (y – 1)2 + 12
4         4
x = ¼ (y – 1)2 + 3
x = ¼ (y – 1)2 + 3
vertex: (3, 1)
axis of symmetry:
     y=1
a=¼
distance from vertex
             1_
to focus = 4(¼) = 1
                       Length of latus
distance from vertex   rectum:
to directrix = 1
                       1 = 4 units
                       ¼

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Alg2 lesson 8-2

  • 1. Vertex form (standard form) for the equation of a parabola y = a(x – h)2 + k x = a(y – k)2 + h Vertex: (h, k) Vertex: (h, k) Line of symmetry: x = h Line of symmetry: y = k
  • 2. Graph x = 2y2 + 8y + 9 x = (2y2 + 8y )+9 x = 2(y2 + 4y + 4) + 9 - 8 x = 2(y + 2)2 + 1 Vertex: (1, -2) Axis of symmetry: y = -2 Opens to the right
  • 3. focus directrix
  • 4. latus rectum directrix
  • 5. y = a(x – h)2 + k focus 1 same distance 4a directrix latus rectum
  • 6. y = a(x – h)2 + k focus latus rectum length 1 directrix a
  • 8. 4(y – 2) = (x + 3)2 y = a(x – h)2 + k 4y – 8 = (x + 3)2 4y = (x + 3)2 + 8 4 4 y = ¼ (x + 3)2 + 2 a=¼ h = -3 k=2
  • 9.
  • 10. y = ¼ (x + 3)2 + 2 vertex: (-3, 2) axis of symmetry: x = -3 a=¼ distance from vertex 1_ to focus = 4(¼) = 1 Length of latus distance from vertex rectum: to directrix = 1 1 = 4 units ¼
  • 11. 4x – 13 = y2 – 2y x = a(y – k)2 + h 4x – 13 = (y2 – 2y +1) – 1 +13 +13 4x = (y – 1)2 + 12 4 4 x = ¼ (y – 1)2 + 3
  • 12. x = ¼ (y – 1)2 + 3 vertex: (3, 1) axis of symmetry: y=1 a=¼ distance from vertex 1_ to focus = 4(¼) = 1 Length of latus distance from vertex rectum: to directrix = 1 1 = 4 units ¼