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~How	
  to	
  Decide	
  more	
  Ra0onally~
Cheng-­‐Shu	
  Liu
We	
  are	
  Made	
  of	
  What	
  We	
  Have	
  Decided
2
3
A	
  Decision	
  
	
  to	
  Make	
  
Make	
  the	
  Decision	
  
	
  Sequen0ally	
  
Own	
  a	
  Private	
  	
  
Informa0on	
  
Observe	
  What	
  	
  
Others	
  Do	
  	
  
4
5
6
1
 2
 3
 4
 5
 6
MB/
MR
Ball
7
8
9
10
11
12
A∩B
A
B
Pr A B! #$=
Pr A∩B[ ]
Pr B[ ]
Pr B A! #$=
Pr B∩ A[ ]
Pr A[ ]
=
Pr A∩B[ ]
Pr A[ ]
Pr A B! #$=
Pr A[ ]⋅Pr B A! #$
Pr B[ ]
Pr A B! #$⋅Pr B[ ]= Pr A∩B[ ]= Pr B A! #$⋅Pr A[ ]
Pr A[ ]
Pr B[ ] 13
Pr true =Y report =Y! #$=
Pr true =Y[ ]⋅Pr report =Y true =Y! #$
Pr report =Y[ ]
Pr true =Y[ ]= 0.2;Pr report =Y true =Y! #$= 0.8
Pr report =Y[ ]= Pr true =Y[ ]⋅Pr report =Y true =Y! #$+ Pr true = B[ ]⋅Pr report =Y true = B! #$= 0.2⋅0.8+ 0.8⋅0.2 = 0.32
Pr true =Y report =Y! #$=
Pr true =Y[ ]⋅Pr report =Y true =Y! #$
Pr report =Y[ ]
=
0.2⋅0.8
0.32
= 0.5
14
15
Pr majority − blue blue# $%=
Pr majority − blue[ ]⋅Pr blue majority − blue#$ %
Pr blue[ ]
numerator =
1
2
⋅
2
3
=
1
3
Pr blue[ ]= Pr majority − blue[ ]⋅Pr blue majority − blue#$ %+
Pr majority −red[ ]⋅Pr blue majority −red#$ %=
1
2
⋅
2
3
+
1
2
⋅
1
3
=
1
2
Pr majority − blue blue#$ %=
1
3
1
2
=
2
3
16
Pr majority−blue blue,blue,red# $%=
Pr majority−blue[ ]⋅Pr blue,blue,red majority−blue#$ %
Pr blue,blue,red[ ]
Pr blue,blue,red majority−blue# $%=
2
3
⋅
2
3
⋅
1
3
=
4
27
Pr blue,blue,red[ ]= Pr majority−blue[ ]⋅Pr blue,blue,red majority−blue#$ %+
Pr majority−red[ ]⋅Pr blue,blue,red majority−red#$ %=
1
2
⋅
2
3
⋅
2
3
⋅
1
3
+
1
2
⋅
1
3
⋅
1
3
⋅
2
3
=
6
54
=
1
9
Pr majority−blue blue,blue,red#$ %=
4
27
⋅
1
2
1
9
=
2
3
17
18
19
~Thanks	
  for	
  Listening~
22

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CS Liu-final presentaion-information cascades

  • 1. ~How  to  Decide  more  Ra0onally~ Cheng-­‐Shu  Liu
  • 2. We  are  Made  of  What  We  Have  Decided 2
  • 3. 3
  • 4. A  Decision    to  Make   Make  the  Decision    Sequen0ally   Own  a  Private     Informa0on   Observe  What     Others  Do     4
  • 5. 5
  • 6. 6
  • 7. 1 2 3 4 5 6 MB/ MR Ball 7
  • 8. 8
  • 9. 9
  • 10. 10
  • 11. 11
  • 12. 12
  • 13. A∩B A B Pr A B! #$= Pr A∩B[ ] Pr B[ ] Pr B A! #$= Pr B∩ A[ ] Pr A[ ] = Pr A∩B[ ] Pr A[ ] Pr A B! #$= Pr A[ ]⋅Pr B A! #$ Pr B[ ] Pr A B! #$⋅Pr B[ ]= Pr A∩B[ ]= Pr B A! #$⋅Pr A[ ] Pr A[ ] Pr B[ ] 13
  • 14. Pr true =Y report =Y! #$= Pr true =Y[ ]⋅Pr report =Y true =Y! #$ Pr report =Y[ ] Pr true =Y[ ]= 0.2;Pr report =Y true =Y! #$= 0.8 Pr report =Y[ ]= Pr true =Y[ ]⋅Pr report =Y true =Y! #$+ Pr true = B[ ]⋅Pr report =Y true = B! #$= 0.2⋅0.8+ 0.8⋅0.2 = 0.32 Pr true =Y report =Y! #$= Pr true =Y[ ]⋅Pr report =Y true =Y! #$ Pr report =Y[ ] = 0.2⋅0.8 0.32 = 0.5 14
  • 15. 15
  • 16. Pr majority − blue blue# $%= Pr majority − blue[ ]⋅Pr blue majority − blue#$ % Pr blue[ ] numerator = 1 2 ⋅ 2 3 = 1 3 Pr blue[ ]= Pr majority − blue[ ]⋅Pr blue majority − blue#$ %+ Pr majority −red[ ]⋅Pr blue majority −red#$ %= 1 2 ⋅ 2 3 + 1 2 ⋅ 1 3 = 1 2 Pr majority − blue blue#$ %= 1 3 1 2 = 2 3 16
  • 17. Pr majority−blue blue,blue,red# $%= Pr majority−blue[ ]⋅Pr blue,blue,red majority−blue#$ % Pr blue,blue,red[ ] Pr blue,blue,red majority−blue# $%= 2 3 ⋅ 2 3 ⋅ 1 3 = 4 27 Pr blue,blue,red[ ]= Pr majority−blue[ ]⋅Pr blue,blue,red majority−blue#$ %+ Pr majority−red[ ]⋅Pr blue,blue,red majority−red#$ %= 1 2 ⋅ 2 3 ⋅ 2 3 ⋅ 1 3 + 1 2 ⋅ 1 3 ⋅ 1 3 ⋅ 2 3 = 6 54 = 1 9 Pr majority−blue blue,blue,red#$ %= 4 27 ⋅ 1 2 1 9 = 2 3 17
  • 18. 18
  • 19. 19
  • 21.
  • 22. 22