Statistic of PPISMP Tesl students

1. BASIC
MATHEMATIC
HISTOGRAM

2. Introduction
We as a group conduct a survey regarding to the
height of student PPISMP TESL JUNE 2011. From
the survey, we analyzed and calculate based on mode,
median and mean of the students height.
DEFINITION
What is a Histogram?
• A Histogram is a vertical bar chart that depicts the
distribution of a set of data.

3. Information
 Mode
The average value, calculated by adding all the observations and
dividing by the number of observations
 Median
Middle value of a list
If the list has an even number of entries, the median is equal to the
sum of the two middle (after sorting) numbers divided by two
 Mean
the mode is the most common (frequent) value.

4. Survey Form
A survey on the height of PPISMP TESL
A survey on the height of PPISMP TESL
Semester 3 June 2011 intake students
Semester 3 June 2011 intake students
Age
Age :________________________
:________________________
19
Class
Class :________________________
:________________________
TESL SK2
Gender
Gender :________________________
:________________________
male
Height(cm) :________________________
Height(cm) :________________________
180 cm
Thank you for your cooperation
Thank you for your cooperation
We conducted a survey of height with the total of 77 people in
PPISMP TESL Semester 3 June 2011 intake

5. Table
HEIGHT OF PPISMP TESL 2011 JUN
INTAKE
HEIGHT FREQUENCY CUMULATIVE LOWER UPPER MIDPOINT
FREQUENCY BOUNDARY BOUNDARY
140 – 144 1 1 139.5 144.5 142
145 – 149 5 6 144.5 149.5 147
150 – 154 10 16 149.5 154.5 152
155 – 159 29 45 154.5 159.5 157
160 – 164 12 57 159.5 164.5 162
165 – 169 6 63 164.5 169.5 167
170 – 174 5 68 169.5 174.5 172
175 – 179 6 74 174.5 179.5 177
180 – 184 2 76 179.5 184.5 182
185 – 189 1 77 184.5 189.5 187
Total 77

6. Graph (Histogram)

7. Ogive

8. Analysis
• Mode = 155 – 159 HEIGHT FREQUENCY
150 – 154 10
155 – 159 29
• Median =
Using formula L + h/f (n/2 - c)
• L= is the lower class boundary of median class
h =is the size of median class i.e. difference between upper and
lower class boundaries of median class
f= is the frequency of median class
c =is previous cumulative frequency of the median class
n/2= is total no. of observations divided by 2
Calculation:
• 154.5+ (38-16)= 157.53

9. • Mean =
(1x142)+(5x147)+(10x152)+(29x157)+(12x162)+
(6x167)+(5x172)+(6x177)+(2x182)+(1x187)____
77
=142+735+1520+4553+1944+1002+860+1062+
364+187
77
=12369
77
=160.63

10. THE END