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SPECIAL MATH PROJECT
1. Translating Word Problems
2. Integer Problem
3. Age Problem
4. Digit Problem
5. Money Problem
6. Motion Problem
Martinez, Irish Benette M.
Tongo, Faith Bes
Sabino, Hans Ferdinand
Jimenez, Mel Jericho
Translating Word
Problems
Mr. Fredrickson
asked Russle to buy
him
Red, Blue, and
Green Balloons.
He asked him to buy blue
balloons that is 6 more
than the number of red
balloons.
X + 6
and green balloons
that is 4 times 3 less
than the number of
blue balloons.
4(x+6-3))
If the total number
of the balloons is
60, how many red,
blue, and green
balloons are needed
to make Mr.
Frederick’s house
float?
X + X+6 + 4(x+6-3))
=
60
X+x+6+4(x+6-3)=60
X+x+6+4x+24-12=60
6x+30-12=60
6x-18=60
6x=60-18
6x=42
6x
6
=
42
6
X=7
Therefor there are:
Red Balloon :
x =7
Blue Balloon
X+6- 7+6=13
Green Balloon
4(x+6-3) – 4(7+6-3)=40
Thankyou for
helping
Mr.Frederick buy
his balloons now
he can travel to
their wife’s drem
place !
Age Problems
Gru was
planning to have
a surprise
birthday party
for dave
While Gru was making dave’s
birthday cake he noticed that the
birthdaycandles was missing
?
Gru decided to go back to his
home to ask his daughter ,
Agnes about Dave’s Age
Agnes
Hey dad!
Do you know how
old dave is?Dave is 7 years younger
than me.
2 years ago, Agnes is 5 years less than the half ofGru’s age and
dave is 7 years younger than agnes, What is dave’s present age
if their ages is equal to 33?
Name Age 2 years ago
Gru X X-2
Agnes 1
2
𝑥 - 5
1
2
𝑥 − 5-2
Dave 1
2
𝑥-5-7
1
2
𝑥-5-7-2
X-2+
1
2
𝑥 − 5-2+
1
2
𝑥 − 5-7-2 = 33
2[X-2+
1
2
𝑥 − 5-2+
1
2
𝑥 − 5-7-2 =
33]2
2x-4+x-10-4+x-10-14-4=66
2x+x+x=
4+10+4+10+14+4+66
4x=112
4𝑥
4
=
112
4
X=28
Name Age 2 years ago Present age
Gru X-2 26+2 = 28
Agnes
1
2
𝑥 – 5-2 7+2 = 9
Dave
1
2
𝑥 – 5-7-2 0 +2 = 2
Digit Word Problems
It’s Sunday and so Rico was bored.
He went to the living room and
decided
to watch something in the TV.
Today we’re going to learn how to
solve
Digit Word Problems!
Let’s try to solve this Digit Word
Problem and analyze it.
The digit at the ten’s place of a two digit number is twice
the
digit at the unit’s place. If the sum of this number and the
number formed by reversing the digits is 66. Find the
number.
x2x
(2x) (x)
Solution :
Let the unit place digit = x
Ten’s place digit = 2x
TENS UNIT
10 1
Number formed = 10(2x ) + x = 20 x + x = 21x
+
(2x) (x)
Solution :
Let the unit place digit = x
Ten’s place digit = 2x
TENS UNIT
10 1
Number formed = 10(2x ) + x = 20 x + x = 21x
+
The digit at the ten’s place of a two digit number is twice
the
digit at the unit’s place.
If the sum of this number and the number formed
by reversing the digits is 66. Find the number.
Reversing the digit :
Unit digit = 2x
Ten’s digit = x
1
0
(X) + (2x)1
Reversed number formed = 10 (x) + 2x = 10x + 2x = 12x
As the sum of the number is 66.
The equation will be:
21x + 12x = 66
33x = 66
X = 2
Original number formed = 10(2x ) + x = 20 x + x = 21x
So unit digit = 2
x = 22x = 10[2(2)]
4 2
The number and the answer is:
That’s it! You already know how to solve and analyze Digit
Word Problems. Remember to make your solution neat and
clear so you will not be confused.
THANK YOU FOR WATCHING!
“Oh, that’s how!” Rico exclaimed. He was happy because
he learned to solve Digit Word Problems.
MONEY
PROBLEM
Sandy wants to have a
lunch with her two friends,
Patrick and Squidward.
Sandy is buying 5 krabby patty that cost $ 1.50 each. She
wants to share her burger with her two friends. She asks her
friends to pay for her for their share. Including Patrick, How
much does each person spend on burger?
5 x $1.50 = $7.50
(5 x $1) = $5.00
($0.50 x 5) = $2.50
($5.00 + $2.50) = $7.50
convert $7.50 into cents
750 cents ÷ 3 = 250 cents
250 cents= $2.50
A car and another car, who live 14 miles
apart, started at noon to drive towards each
other at the rate of 3 mph and 4 mph
respectively. In how many hours will they
meet?
3X + 4X = 14
7X = 14
7X/7 = 14/7
FIRST DO A TABLE CONSISTING.
THE RATE OR SPEED OF THE
CARS.
THEN MAKE YOUR OWN
WORKING EQUATION.
AFTER THAT COMPUTE FOR THE
FINAL ANSWER, THEN START
CONCLUDING ABOUT YOUR
ANSWER.
RATE TIME DISTANCE
CAR 1 3 X 3X
CAR 2 4 X 4X

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Spec Math

  • 1. SPECIAL MATH PROJECT 1. Translating Word Problems 2. Integer Problem 3. Age Problem 4. Digit Problem 5. Money Problem 6. Motion Problem Martinez, Irish Benette M. Tongo, Faith Bes Sabino, Hans Ferdinand Jimenez, Mel Jericho
  • 3. Mr. Fredrickson asked Russle to buy him Red, Blue, and Green Balloons. He asked him to buy blue balloons that is 6 more than the number of red balloons. X + 6
  • 4. and green balloons that is 4 times 3 less than the number of blue balloons. 4(x+6-3))
  • 5. If the total number of the balloons is 60, how many red, blue, and green balloons are needed to make Mr. Frederick’s house float?
  • 6. X + X+6 + 4(x+6-3)) = 60
  • 8. Therefor there are: Red Balloon : x =7 Blue Balloon X+6- 7+6=13 Green Balloon 4(x+6-3) – 4(7+6-3)=40
  • 9. Thankyou for helping Mr.Frederick buy his balloons now he can travel to their wife’s drem place !
  • 11. Gru was planning to have a surprise birthday party for dave
  • 12. While Gru was making dave’s birthday cake he noticed that the birthdaycandles was missing ?
  • 13. Gru decided to go back to his home to ask his daughter , Agnes about Dave’s Age
  • 14. Agnes Hey dad! Do you know how old dave is?Dave is 7 years younger than me.
  • 15. 2 years ago, Agnes is 5 years less than the half ofGru’s age and dave is 7 years younger than agnes, What is dave’s present age if their ages is equal to 33?
  • 16. Name Age 2 years ago Gru X X-2 Agnes 1 2 𝑥 - 5 1 2 𝑥 − 5-2 Dave 1 2 𝑥-5-7 1 2 𝑥-5-7-2
  • 17. X-2+ 1 2 𝑥 − 5-2+ 1 2 𝑥 − 5-7-2 = 33 2[X-2+ 1 2 𝑥 − 5-2+ 1 2 𝑥 − 5-7-2 = 33]2 2x-4+x-10-4+x-10-14-4=66 2x+x+x= 4+10+4+10+14+4+66 4x=112 4𝑥 4 = 112 4 X=28
  • 18. Name Age 2 years ago Present age Gru X-2 26+2 = 28 Agnes 1 2 𝑥 – 5-2 7+2 = 9 Dave 1 2 𝑥 – 5-7-2 0 +2 = 2
  • 19.
  • 20.
  • 21.
  • 23. It’s Sunday and so Rico was bored.
  • 24. He went to the living room and decided to watch something in the TV.
  • 25. Today we’re going to learn how to solve Digit Word Problems!
  • 26. Let’s try to solve this Digit Word Problem and analyze it.
  • 27. The digit at the ten’s place of a two digit number is twice the digit at the unit’s place. If the sum of this number and the number formed by reversing the digits is 66. Find the number. x2x
  • 28. (2x) (x) Solution : Let the unit place digit = x Ten’s place digit = 2x TENS UNIT 10 1 Number formed = 10(2x ) + x = 20 x + x = 21x +
  • 29. (2x) (x) Solution : Let the unit place digit = x Ten’s place digit = 2x TENS UNIT 10 1 Number formed = 10(2x ) + x = 20 x + x = 21x +
  • 30. The digit at the ten’s place of a two digit number is twice the digit at the unit’s place. If the sum of this number and the number formed by reversing the digits is 66. Find the number. Reversing the digit : Unit digit = 2x Ten’s digit = x 1 0 (X) + (2x)1
  • 31. Reversed number formed = 10 (x) + 2x = 10x + 2x = 12x As the sum of the number is 66. The equation will be: 21x + 12x = 66 33x = 66 X = 2 Original number formed = 10(2x ) + x = 20 x + x = 21x
  • 32. So unit digit = 2 x = 22x = 10[2(2)] 4 2 The number and the answer is:
  • 33. That’s it! You already know how to solve and analyze Digit Word Problems. Remember to make your solution neat and clear so you will not be confused.
  • 34. THANK YOU FOR WATCHING! “Oh, that’s how!” Rico exclaimed. He was happy because he learned to solve Digit Word Problems.
  • 36. Sandy wants to have a lunch with her two friends, Patrick and Squidward.
  • 37. Sandy is buying 5 krabby patty that cost $ 1.50 each. She wants to share her burger with her two friends. She asks her friends to pay for her for their share. Including Patrick, How much does each person spend on burger?
  • 38. 5 x $1.50 = $7.50 (5 x $1) = $5.00 ($0.50 x 5) = $2.50 ($5.00 + $2.50) = $7.50 convert $7.50 into cents 750 cents ÷ 3 = 250 cents 250 cents= $2.50
  • 39.
  • 40. A car and another car, who live 14 miles apart, started at noon to drive towards each other at the rate of 3 mph and 4 mph respectively. In how many hours will they meet?
  • 41. 3X + 4X = 14 7X = 14 7X/7 = 14/7 FIRST DO A TABLE CONSISTING. THE RATE OR SPEED OF THE CARS. THEN MAKE YOUR OWN WORKING EQUATION. AFTER THAT COMPUTE FOR THE FINAL ANSWER, THEN START CONCLUDING ABOUT YOUR ANSWER. RATE TIME DISTANCE CAR 1 3 X 3X CAR 2 4 X 4X