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Polyhedral Computation




                        Jayant Apte
                         ASPITRG




October 3, 2012          Jayant Apte. ASPITRG   1
Part I




October 3, 2012   Jayant Apte. ASPITRG   2
The Three Problems of
                  Polyhedral Computation
 ●   Representation Conversion
     ●   H-representation of polyhedron



     ●   V-Representation of polyhedron


 ●   Projection
     ●




 ●   Redundancy Removal
     ●   Compute the minimal representation of a polyhedron


October 3, 2012                   Jayant Apte. ASPITRG        3
Outline
           ●   Preliminaries
               ● Representations of convex polyhedra, polyhedral cones

               ●   Homogenization - Converting a general polyhedron in   to
                     a cone in
               ●   Polar of a convex cone
           ●   The three problems
               ●   Representation Conversion
                   –   Review of LRS
                   –   Double Description Method
               ●   Projection of polyhedral sets
                   –   Fourier-Motzkin Elimination
                   –   Block Elimination
                   –   Convex Hull Method (CHM)
               ●   Redundancy removal
                   –   Redundancy removal using linear programming


October 3, 2012                                 Jayant Apte. ASPITRG          4
Outline for Part 1
●     Preliminaries
      ●    Representations of convex polyhedra, polyhedral cones
      ●    Homogenization – Converting a general polyhedron in
          to a cone in
      ●
           Polar of a convex cone
●     The first problem
      ●    Representation Conversion
            –     Review of LRS
            –     Double Description Method

October 3, 2012                   Jayant Apte. ASPITRG             5
Preliminaries




October 3, 2012      Jayant Apte. ASPITRG   6
Convex Polyhedron




October 3, 2012        Jayant Apte. ASPITRG   7
Examples of polyhedra
                  Bounded- Polytope                          Unbounded - polyhedron




October 3, 2012                       Jayant Apte. ASPITRG                            8
H-Representation of a Polyhedron




October 3, 2012   Jayant Apte. ASPITRG   9
V-Representation of a Polyhedron




October 3, 2012   Jayant Apte. ASPITRG   10
Example
                                           (0.5,0.5,1.5)
                                                                (1,1,1)


                  (0,1,1)




                                           (0,0,1)             (1,1,0)




                    (0,1,0)
                                                                          (1,0,0)

                                                     (0,0,0)

October 3, 2012     Jayant Apte. ASPITRG                                     11
Switching between the two representations :
    Representation Conversion Problem
●   H-representation         V-representation: The
    Vertex Enumeration problem
●   Methods:
      ●   Reverse Search, Lexicographic Reverse Search
      ●   Double-description method
●   V-representation               H-representation
    The Facet Enumeration Problem
●   Facet enumeration can be accomplished by using
    polarity and doing Vertex Enumeration

October 3, 2012           Jayant Apte. ASPITRG           12
Polyhedral Cone




October 3, 2012       Jayant Apte. ASPITRG   13
A cone in




October 3, 2012    Jayant Apte. ASPITRG   14
Homogenization




October 3, 2012       Jayant Apte. ASPITRG   15
H-polyhedra




October 3, 2012     Jayant Apte. ASPITRG   16
Example(d=2,d+1=3)




October 3, 2012         Jayant Apte. ASPITRG   17
Example




October 3, 2012   Jayant Apte. ASPITRG   18
V-polyhedra




October 3, 2012     Jayant Apte. ASPITRG   19
Polar of a convex cone




October 3, 2012          Jayant Apte. ASPITRG   20
Polar of a convex cone



                                                Looks like an H-representation!!!



                                                Our ticket back to the original cone!!!




October 3, 2012          Jayant Apte. ASPITRG                                       21
Polar: Intuition




October 3, 2012       Jayant Apte. ASPITRG   22
Polar: Intuition




October 3, 2012       Jayant Apte. ASPITRG   23
Polar: Intuition




October 3, 2012       Jayant Apte. ASPITRG   24
Polar: Intuition




October 3, 2012       Jayant Apte. ASPITRG   25
Use of Polar
 ●   Representation Conversion
      ●    No need to have two different algorithms i.e. for
                       and             .
 ●   Redundancy removal
      ●    No need to have two different algorithms for
           removing redundancies from H-representation
           and V-representation
 ●   Safely assume that input is always an H-
     representation for both these problems
October 3, 2012              Jayant Apte. ASPITRG              26
Polarity: Intuition




October 3, 2012        Jayant Apte. ASPITRG   27
Polar: Intuition




                                                Then take polar again to get
                                                facets of this cone

                                             Perform Vertex Enumeration
                                             on this cone.

October 3, 2012       Jayant Apte. ASPITRG                           28
Problem #1
                  Representation Conversion




October 3, 2012           Jayant Apte. ASPITRG   29
Review of Lexicographic Reverse
                Search




October 3, 2012   Jayant Apte. ASPITRG   30
Reverse Search:
                   High Level Idea
 ●   Start with dictionary corresponding to the optimal
     vertex
 ●   Ask yourself 'What pivot would have landed me at this
     dictionary if i was running simplex?'
 ●   Go to that dictionary by applying reverse pivot to
     current dictionary
 ●   Ask the same question again
 ●   Generate the so-called 'reverse search tree'



October 3, 2012           Jayant Apte. ASPITRG            31
Reverse Search on a Cube




   Ref.David Avis, lrs: A Revised Implementation of the Reverse Search Vertex Enumeration
   Algorithm
October 3, 2012                        Jayant Apte. ASPITRG                                 32
Double Description Method
 ●   First introduced in:
      “ Motzkin, T. S.; Raiffa, H.; Thompson, G. L.; Thrall, R. M.
     (1953). "The double description method". Contributions to the
     theory of games. Annals of Mathematics Studies. Princeton, N.
     J.: Princeton University Press. pp. 51–73”
 ●   The primitive algorithm in this paper is very inefficient.
     (How? We will see later)
 ●   Several authors came up with their own efficient
     implementation(viz. Fukuda, Padberg)
 ●   Fukuda's implementation is called cdd


October 3, 2012                 Jayant Apte. ASPITRG              33
Some Terminology




October 3, 2012       Jayant Apte. ASPITRG   34
Double Description Method:
                     The High Level Idea
●   An Incremental Algorithm
●   Starts with certain subset of rows of H-representation
    of a cone            to form initial H-representation

●   Adds rest of the inequalities one by one constructing
    the corresponding V-representation every iteration
●   Thus, constructing the V-representation incrementally.




October 3, 2012           Jayant Apte. ASPITRG               35
How it works?




October 3, 2012      Jayant Apte. ASPITRG   36
How it works?




October 3, 2012      Jayant Apte. ASPITRG   37
Initialization




October 3, 2012      Jayant Apte. ASPITRG   38
Initialization
                                            Very trivial and inefficient




October 3, 2012      Jayant Apte. ASPITRG                                  39
Example: Initialization




October 3, 2012          Jayant Apte. ASPITRG   40
Example: Initialization




October 3, 2012          Jayant Apte. ASPITRG   41
Example : Initialization

                                      -1   -1    18
                                       1   -1     0
                                       0    1    -4

                                   A    B              C
                                4.0000 14.0000        9.0000
                                 4.0000 4.0000        9.0000
                                 1.0000 1.0000        1.0000




October 3, 2012           Jayant Apte. ASPITRG                 42
How it works?




October 3, 2012      Jayant Apte. ASPITRG   43
Iteration: Insert a new constraint




October 3, 2012     Jayant Apte. ASPITRG    44
Iteration 1 A                   B         C
                                          4.0000 14.0000   9.0000
                                           4.0000 4.0000   9.0000
                                           1.0000 1.0000   1.0000




October 3, 2012    Jayant Apte. ASPITRG                             45
Iteration 1: Insert a new constraint
                  Constraint 2




October 3, 2012   Jayant Apte. ASPITRG     46
Iteration 1: Insert a new constraint




October 3, 2012   Jayant Apte. ASPITRG     47
Iteration 1: Insert a new constraint




October 3, 2012   Jayant Apte. ASPITRG     48
Main Lemma for DD Method




October 3, 2012       Jayant Apte. ASPITRG   49
Iteration 1: Insert a new constraint




October 3, 2012   Jayant Apte. ASPITRG     50
Iteration 1: Get the new DD pair
                            -1 -1 18
                             1 -1 0
                             0 1 -4
                             -1 1 6



                  10.0000 12.0000        4.0000   9.0000
                    4.0000 6.0000        4.0000   9.0000
                    1.0000 1.0000        1.0000   1.0000




October 3, 2012       Jayant Apte. ASPITRG                 51
Iteration 2




October 3, 2012    Jayant Apte. ASPITRG   52
Iteration 2: Insert new constraint




October 3, 2012    Jayant Apte. ASPITRG    53
Iteration 2: Insert new constraint




October 3, 2012    Jayant Apte. ASPITRG    54
Iteration 2: Insert new constraint




October 3, 2012    Jayant Apte. ASPITRG    55
Get the new DD pair

                                 -1 -1 18
                                   1 -1 0
                                   0 1 -4
                                  -1 1 6
                                   0 -1 8



                    9.2000 10.0000 8.0000 10.0000 12.0000 4.0000
                     8.0000 8.0000 8.0000 4.0000 6.0000 4.0000
                     1.0000 1.0000 1.0000 1.0000 1.0000 1.0000




October 3, 2012            Jayant Apte. ASPITRG                    56
Iteration 3




October 3, 2012    Jayant Apte. ASPITRG   57
Get the new DD pair
                                          -1 -1 18
                                            1 -1 0
                                            0 1 -4
                                           -1 1 6
                                            0 -1 8
                                            1 1 -12




 A           B       C       D        E         F               G       H      I       J

6.2609     6.4000   6.0000   8.0000   7.2000    9.2000       10.0000 8.0000 10.0000 12.0000
5.7391     5.6000   6.0000   4.0000   4.8000    8.0000       8.0000 8.0000 4.0000 6.0000
1.0000     1.0000   1.0000   1.0000   1.0000    1.0000       1.0000 1.0000 1.0000 1.0000


 October 3, 2012                      Jayant Apte. ASPITRG                                 58
Termination




October 3, 2012     Jayant Apte. ASPITRG   59
Efficiency Issues
 ●   Is the implementation I just described good
     enough?




October 3, 2012        Jayant Apte. ASPITRG        60
Efficiency Issues
 ●   Is the implementation I just described good
     enough?
      ●    Hell no!
             –    The implementation just described suffers from
                  profusion of redundancy




October 3, 2012                   Jayant Apte. ASPITRG             61
Efficiency Issues           We can
                                              totally
                                              do
                                              without
                                              this one!!




October 3, 2012        Jayant Apte. ASPITRG            62
Efficiency Issues           And without
                                              all these!!!




October 3, 2012        Jayant Apte. ASPITRG           63
Efficiency Issues




October 3, 2012        Jayant Apte. ASPITRG   64
The Primitive DD method




October 3, 2012           Jayant Apte. ASPITRG   65
What to do?
 ●   Add some more structure
 ●   Strengthen the Main Lemma




October 3, 2012      Jayant Apte. ASPITRG   66
Add some more structure




October 3, 2012           Jayant Apte. ASPITRG   67
Some definitions




October 3, 2012       Jayant Apte. ASPITRG   68
October 3, 2012   Jayant Apte. ASPITRG   69
October 3, 2012   Jayant Apte. ASPITRG   70
Algebraic Characterization of adjacency




October 3, 2012              Jayant Apte. ASPITRG           71
Combinatorial Characterization of adjacency
                  (Combinatorial Oracle)



October 3, 2012             Jayant Apte. ASPITRG                72
Example: Combinatorial Adjacency
              Oracle




October 3, 2012   Jayant Apte. ASPITRG   73
Example: Combinatorial Adjacency
              Oracle
            Only the pairs            and              will be used to
            generate new rays




October 3, 2012                 Jayant Apte. ASPITRG                     74
Strengthened Main Lemma
                    for DD Method




October 3, 2012       Jayant Apte. ASPITRG   75
Procedural Description




October 3, 2012          Jayant Apte. ASPITRG   76
Part 2




October 3, 2012   Jayant Apte. ASPITRG   77
●    Projection of polyhedral sets
                  –   Fourier-Motzkin Elimination
                  –   Block Elimination
                  –   Convex Hull Method (CHM)
         ●        Redundancy removal
                  –   Redundancy removal using linear programming




October 3, 2012                    Jayant Apte. ASPITRG         78
Projection of a Polyhedra




October 3, 2012            Jayant Apte. ASPITRG   79
Fourier-Motzkin Elimination
 ●   Named after Joseph Fourier and Theodore
     Motzkin




October 3, 2012         Jayant Apte. ASPITRG   80
How it works?




October 3, 2012      Jayant Apte. ASPITRG   81
How it works? Contd...




October 3, 2012          Jayant Apte. ASPITRG   82
Efficiency of FM algorithm




October 3, 2012            Jayant Apte. ASPITRG   83
Convex Hull Method(CHM)
 ●   First appears in “C. Lassez and J.-L. Lassez, Quantifier
     elimination for conjunctions of linear constraints via
     aconvex hull algorithm, IBM Research Report, T.J. Watson
     Research Center (1991)”
 ●   Found to be better than most other existing algorithms
     when dimension of projection is small
 ●   Cited by Weidong Xu, Jia Wang, Jun Sun in their ISIT
     2008 paper “A Projection Method for Derivation of Non-
     Shannon-Type Information Inequalities”




October 3, 2012            Jayant Apte. ASPITRG               84
CHM intuition




October 3, 2012      Jayant Apte. ASPITRG   85
CHM intuition




October 3, 2012      Jayant Apte. ASPITRG   86
CHM intuition             (12,6,6)

                                                       (12,6)




October 3, 2012      Jayant Apte. ASPITRG               87
CHM intuition




October 3, 2012      Jayant Apte. ASPITRG   88
Moral of the story
 ●   We can make decisions about                         without
     actually having its H-representation.
 ●   It suffices to have         ,      the original polyhedron
 ●   We run linear programs on                    to make these
     decisions




October 3, 2012            Jayant Apte. ASPITRG                    89
Input:
                          Faces A of P


                       Construct an initial
                      Approximation      of
                       extreme points of




                        Perform Facet              Update     by adding r to it
                      Enumeration on
                         to get
Convex Hull Method:
    Flowchart
                                                   Take an inequality from
                                                     that is not a face of
                                                       and move it outward
                                                  To find a new extreme point r

                      Are all inequalities
                        In        faces
                                                  No
                           Of
                                ?



                              Yes
                             Stop

October 3, 2012            Jayant Apte. ASPITRG                                   90
Example




October 3, 2012   Jayant Apte. ASPITRG   91
Example




October 3, 2012   Jayant Apte. ASPITRG   92
Example




October 3, 2012   Jayant Apte. ASPITRG   93
Input:
                         Faces A of P


                      Construct an initial
                      Approximation     of
                      extreme points of




                        Perform Facet              Update     by adding r to it
                      Enumeration on
Convex Hull Method:      to get
    Flowchart
                                                   Take an inequality from
                                                     that is not a face of
                                                       and move it outward
                                                  To find a new extreme point r

                      Are all inequalities
                        In       facets
                           Of
                                ?




                             Stop

October 3, 2012            Jayant Apte. ASPITRG                                   94
How to get the extreme points of
           initial approximation?




October 3, 2012   Jayant Apte. ASPITRG   95
Example: Get the first two points




October 3, 2012   Jayant Apte. ASPITRG    96
Example: Get the first two points




October 3, 2012    Jayant Apte. ASPITRG   97
Example: Get the first two points




October 3, 2012    Jayant Apte. ASPITRG   98
Get rest of the points so you have a
          total of d+1 points




October 3, 2012   Jayant Apte. ASPITRG   99
Get the rest of the points so you
           have a total of d+1 points




October 3, 2012     Jayant Apte. ASPITRG    100
Get the rest of the points so you
            have a total d+1 points




October 3, 2012     Jayant Apte. ASPITRG   101
How to get the initial facets of the
                projection?




October 3, 2012    Jayant Apte. ASPITRG     102
How to get the initial facets of the
                projection?




October 3, 2012    Jayant Apte. ASPITRG     103
Input:
                          Faces A of P


                       Construct an initial
                      Approximation      of
                       extreme points of




                      Incrementally update           Update     by adding r to it
                        The Convex Hull
Convex Hull Method:      (Perform Facet
                       Enumeration on
    Flowchart           to get     )
                                                    Take an inequality from
                                                      that is not a face of
                                                        and move it outward
                                                   To find a new extreme point r

                       Are all inequalities
                         In        faces           No
                            Of
                                 ?



                              Yes
                              Stop

October 3, 2012             Jayant Apte. ASPITRG                                    104
Input:
                          Faces A of P


                       Construct an initial
                      Approximation      of
                       extreme points of




                      Incrementally update           Update     by adding r to it
                        The Convex Hull
Convex Hull Method:      (Perform Facet
                       Enumeration on
    Flowchart           to get     )
                                                    Take an inequality from
                                                      that is not a face of
                                                        and move it outward
                                                   To find a new extreme point r

                       Are all inequalities
                         In        faces            No
                            Of
                                 ?



                              Yes
                              Stop

October 3, 2012             Jayant Apte. ASPITRG                                    105
Input:
                          Faces A of P


                       Construct an initial
                      Approximation      of
                       extreme points of




                      Incrementally update           Update     by adding r to it
                        The Convex Hull
Convex Hull Method:      (Perform Facet
                       Enumeration on
    Flowchart           to get     )
                                                    Take an inequality from
                                                      that is not a facet of
                                                        and move it outward
                                                   To find a new extreme point r

                       Are all inequalities
                         In        faces            No
                            Of
                                 ?



                              Yes
                              Stop

October 3, 2012             Jayant Apte. ASPITRG                                    106
Incremental refinement
 ●   Find a facet in current approximation of
     that is not actually the facet of
 ●   How to do that?




October 3, 2012          Jayant Apte. ASPITRG   107
Incremental refinement

                                                This inequality is
                                                Not a facet of




October 3, 2012          Jayant Apte. ASPITRG                    108
Incremental refinement




October 3, 2012          Jayant Apte. ASPITRG   109
Input:
                          Faces A of P


                        Construct an initial
                       Approximation      of
                        extreme points of




                      Incrementally update           Update     by adding r to it
                        The Convex Hull
Convex Hull Method:      (Perform Facet
                       Enumeration on
    Flowchart           to get     )
                                                    Take an inequality from
                                                      that is not a facet of
                                                        and move it outward
                                                   To find a new extreme point r

                       Are all inequalities
                                                     No
                         In        faces
                            Of
                                 ?



                              Yes
                              Stop

October 3, 2012             Jayant Apte. ASPITRG                                    110
How to update the H-representation
      to accommodate new point ?




October 3, 2012   Jayant Apte. ASPITRG   111
Example




October 3, 2012   Jayant Apte. ASPITRG   112
Example




October 3, 2012   Jayant Apte. ASPITRG   113
Example: New candidate facets




October 3, 2012    Jayant Apte. ASPITRG   114
How to update the H-representation
      to accommodate new point ?




                                         Determine validity of
                                         The candidate facet
                                         And also its sign




October 3, 2012   Jayant Apte. ASPITRG                           115
Example




October 3, 2012   Jayant Apte. ASPITRG   116
Example




October 3, 2012   Jayant Apte. ASPITRG   117
How to update the H-representation
      to accommodate new point ?




October 3, 2012   Jayant Apte. ASPITRG   118
Example




October 3, 2012   Jayant Apte. ASPITRG   119
Example




October 3, 2012   Jayant Apte. ASPITRG   120
Example




October 3, 2012   Jayant Apte. ASPITRG   121
nd
                  2 iteration



                    Not a facet of




October 3, 2012     Jayant Apte. ASPITRG   122
rd
                  3 iteration



                        Not a facet of




October 3, 2012     Jayant Apte. ASPITRG   123
th
                  4 iteration: Done!!!




October 3, 2012         Jayant Apte. ASPITRG   124
Comparison of Projection
                       Algorithms
 ●   Fourier Motzkin Elimination and Block
     Elimination doesn't work well when used on big
     problems
 ●   CHM works very well when the dimension of
     projection is relatively small as compared to the
     dimention of original polyhedron.
 ●   Weidong Xu, Jia Wang, Jun Sun have already
     used CHM to get non-Shannon inequalities.


October 3, 2012           Jayant Apte. ASPITRG       125
Computation of minimal
              representation/Redundancy
                       Removal




October 3, 2012        Jayant Apte. ASPITRG   126
Definitions




October 3, 2012    Jayant Apte. ASPITRG   127
References
●
  K. Fukuda and A. Prodon. Double description method revisited. Technical report, Department of Mathematics,
  Swiss Federal Institute of Technology, Lausanne, Switzerland, 1995
●
  G. Ziegler, Lectures on Polytopes, Springer, 1994, revised 1998. Graduate Texts in Mathematics.
●
  Tien Huynh, Catherine Lassez, and Jean-Louis Lassez. Practical issues on the projection of polyhedral sets.
  Annals of mathematics and artificial intelligence, November 1992
●
  Catherine Lassez and Jean-Louis Lassez. Quantifier elimination for conjunctions of linear constraints via a
  convex hull algorithm. In Bruce Donald, Deepak Kapur, and Joseph Mundy, editors, Symbolic and Numerical
  Computation for Artificial Intelligence. Academic Press, 1992.
●
  R. T. Rockafellar. Convex Analysis (Princeton Mathematical Series). Princeton Univ Pr.
●
  W. Xu, J. Wang, J. Sun. A projection method for derivation of non-Shannon-type information inequalities. In
  IEEE International Symposiumon Information Theory (ISIT), pp. 2116 – 2120, 2008.




October 3, 2012                             Jayant Apte. ASPITRG                                          128
Minkowski's Theorem for
                     Polyhedral Cones




                    Weyl's Theorem for
                     Polyhedral Cones




October 3, 2012         Jayant Apte. ASPITRG   129

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Jayant chm

  • 1. Polyhedral Computation Jayant Apte ASPITRG October 3, 2012 Jayant Apte. ASPITRG 1
  • 2. Part I October 3, 2012 Jayant Apte. ASPITRG 2
  • 3. The Three Problems of Polyhedral Computation ● Representation Conversion ● H-representation of polyhedron ● V-Representation of polyhedron ● Projection ● ● Redundancy Removal ● Compute the minimal representation of a polyhedron October 3, 2012 Jayant Apte. ASPITRG 3
  • 4. Outline ● Preliminaries ● Representations of convex polyhedra, polyhedral cones ● Homogenization - Converting a general polyhedron in to a cone in ● Polar of a convex cone ● The three problems ● Representation Conversion – Review of LRS – Double Description Method ● Projection of polyhedral sets – Fourier-Motzkin Elimination – Block Elimination – Convex Hull Method (CHM) ● Redundancy removal – Redundancy removal using linear programming October 3, 2012 Jayant Apte. ASPITRG 4
  • 5. Outline for Part 1 ● Preliminaries ● Representations of convex polyhedra, polyhedral cones ● Homogenization – Converting a general polyhedron in to a cone in ● Polar of a convex cone ● The first problem ● Representation Conversion – Review of LRS – Double Description Method October 3, 2012 Jayant Apte. ASPITRG 5
  • 6. Preliminaries October 3, 2012 Jayant Apte. ASPITRG 6
  • 7. Convex Polyhedron October 3, 2012 Jayant Apte. ASPITRG 7
  • 8. Examples of polyhedra Bounded- Polytope Unbounded - polyhedron October 3, 2012 Jayant Apte. ASPITRG 8
  • 9. H-Representation of a Polyhedron October 3, 2012 Jayant Apte. ASPITRG 9
  • 10. V-Representation of a Polyhedron October 3, 2012 Jayant Apte. ASPITRG 10
  • 11. Example (0.5,0.5,1.5) (1,1,1) (0,1,1) (0,0,1) (1,1,0) (0,1,0) (1,0,0) (0,0,0) October 3, 2012 Jayant Apte. ASPITRG 11
  • 12. Switching between the two representations : Representation Conversion Problem ● H-representation V-representation: The Vertex Enumeration problem ● Methods: ● Reverse Search, Lexicographic Reverse Search ● Double-description method ● V-representation H-representation The Facet Enumeration Problem ● Facet enumeration can be accomplished by using polarity and doing Vertex Enumeration October 3, 2012 Jayant Apte. ASPITRG 12
  • 13. Polyhedral Cone October 3, 2012 Jayant Apte. ASPITRG 13
  • 14. A cone in October 3, 2012 Jayant Apte. ASPITRG 14
  • 15. Homogenization October 3, 2012 Jayant Apte. ASPITRG 15
  • 16. H-polyhedra October 3, 2012 Jayant Apte. ASPITRG 16
  • 17. Example(d=2,d+1=3) October 3, 2012 Jayant Apte. ASPITRG 17
  • 18. Example October 3, 2012 Jayant Apte. ASPITRG 18
  • 19. V-polyhedra October 3, 2012 Jayant Apte. ASPITRG 19
  • 20. Polar of a convex cone October 3, 2012 Jayant Apte. ASPITRG 20
  • 21. Polar of a convex cone Looks like an H-representation!!! Our ticket back to the original cone!!! October 3, 2012 Jayant Apte. ASPITRG 21
  • 22. Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 22
  • 23. Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 23
  • 24. Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 24
  • 25. Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 25
  • 26. Use of Polar ● Representation Conversion ● No need to have two different algorithms i.e. for and . ● Redundancy removal ● No need to have two different algorithms for removing redundancies from H-representation and V-representation ● Safely assume that input is always an H- representation for both these problems October 3, 2012 Jayant Apte. ASPITRG 26
  • 27. Polarity: Intuition October 3, 2012 Jayant Apte. ASPITRG 27
  • 28. Polar: Intuition Then take polar again to get facets of this cone Perform Vertex Enumeration on this cone. October 3, 2012 Jayant Apte. ASPITRG 28
  • 29. Problem #1 Representation Conversion October 3, 2012 Jayant Apte. ASPITRG 29
  • 30. Review of Lexicographic Reverse Search October 3, 2012 Jayant Apte. ASPITRG 30
  • 31. Reverse Search: High Level Idea ● Start with dictionary corresponding to the optimal vertex ● Ask yourself 'What pivot would have landed me at this dictionary if i was running simplex?' ● Go to that dictionary by applying reverse pivot to current dictionary ● Ask the same question again ● Generate the so-called 'reverse search tree' October 3, 2012 Jayant Apte. ASPITRG 31
  • 32. Reverse Search on a Cube Ref.David Avis, lrs: A Revised Implementation of the Reverse Search Vertex Enumeration Algorithm October 3, 2012 Jayant Apte. ASPITRG 32
  • 33. Double Description Method ● First introduced in: “ Motzkin, T. S.; Raiffa, H.; Thompson, G. L.; Thrall, R. M. (1953). "The double description method". Contributions to the theory of games. Annals of Mathematics Studies. Princeton, N. J.: Princeton University Press. pp. 51–73” ● The primitive algorithm in this paper is very inefficient. (How? We will see later) ● Several authors came up with their own efficient implementation(viz. Fukuda, Padberg) ● Fukuda's implementation is called cdd October 3, 2012 Jayant Apte. ASPITRG 33
  • 34. Some Terminology October 3, 2012 Jayant Apte. ASPITRG 34
  • 35. Double Description Method: The High Level Idea ● An Incremental Algorithm ● Starts with certain subset of rows of H-representation of a cone to form initial H-representation ● Adds rest of the inequalities one by one constructing the corresponding V-representation every iteration ● Thus, constructing the V-representation incrementally. October 3, 2012 Jayant Apte. ASPITRG 35
  • 36. How it works? October 3, 2012 Jayant Apte. ASPITRG 36
  • 37. How it works? October 3, 2012 Jayant Apte. ASPITRG 37
  • 38. Initialization October 3, 2012 Jayant Apte. ASPITRG 38
  • 39. Initialization Very trivial and inefficient October 3, 2012 Jayant Apte. ASPITRG 39
  • 40. Example: Initialization October 3, 2012 Jayant Apte. ASPITRG 40
  • 41. Example: Initialization October 3, 2012 Jayant Apte. ASPITRG 41
  • 42. Example : Initialization -1 -1 18 1 -1 0 0 1 -4 A B C 4.0000 14.0000 9.0000 4.0000 4.0000 9.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 42
  • 43. How it works? October 3, 2012 Jayant Apte. ASPITRG 43
  • 44. Iteration: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 44
  • 45. Iteration 1 A B C 4.0000 14.0000 9.0000 4.0000 4.0000 9.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 45
  • 46. Iteration 1: Insert a new constraint Constraint 2 October 3, 2012 Jayant Apte. ASPITRG 46
  • 47. Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 47
  • 48. Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 48
  • 49. Main Lemma for DD Method October 3, 2012 Jayant Apte. ASPITRG 49
  • 50. Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 50
  • 51. Iteration 1: Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 10.0000 12.0000 4.0000 9.0000 4.0000 6.0000 4.0000 9.0000 1.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 51
  • 52. Iteration 2 October 3, 2012 Jayant Apte. ASPITRG 52
  • 53. Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 53
  • 54. Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 54
  • 55. Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 55
  • 56. Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 0 -1 8 9.2000 10.0000 8.0000 10.0000 12.0000 4.0000 8.0000 8.0000 8.0000 4.0000 6.0000 4.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 56
  • 57. Iteration 3 October 3, 2012 Jayant Apte. ASPITRG 57
  • 58. Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 0 -1 8 1 1 -12 A B C D E F G H I J 6.2609 6.4000 6.0000 8.0000 7.2000 9.2000 10.0000 8.0000 10.0000 12.0000 5.7391 5.6000 6.0000 4.0000 4.8000 8.0000 8.0000 8.0000 4.0000 6.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 58
  • 59. Termination October 3, 2012 Jayant Apte. ASPITRG 59
  • 60. Efficiency Issues ● Is the implementation I just described good enough? October 3, 2012 Jayant Apte. ASPITRG 60
  • 61. Efficiency Issues ● Is the implementation I just described good enough? ● Hell no! – The implementation just described suffers from profusion of redundancy October 3, 2012 Jayant Apte. ASPITRG 61
  • 62. Efficiency Issues We can totally do without this one!! October 3, 2012 Jayant Apte. ASPITRG 62
  • 63. Efficiency Issues And without all these!!! October 3, 2012 Jayant Apte. ASPITRG 63
  • 64. Efficiency Issues October 3, 2012 Jayant Apte. ASPITRG 64
  • 65. The Primitive DD method October 3, 2012 Jayant Apte. ASPITRG 65
  • 66. What to do? ● Add some more structure ● Strengthen the Main Lemma October 3, 2012 Jayant Apte. ASPITRG 66
  • 67. Add some more structure October 3, 2012 Jayant Apte. ASPITRG 67
  • 68. Some definitions October 3, 2012 Jayant Apte. ASPITRG 68
  • 69. October 3, 2012 Jayant Apte. ASPITRG 69
  • 70. October 3, 2012 Jayant Apte. ASPITRG 70
  • 71. Algebraic Characterization of adjacency October 3, 2012 Jayant Apte. ASPITRG 71
  • 72. Combinatorial Characterization of adjacency (Combinatorial Oracle) October 3, 2012 Jayant Apte. ASPITRG 72
  • 73. Example: Combinatorial Adjacency Oracle October 3, 2012 Jayant Apte. ASPITRG 73
  • 74. Example: Combinatorial Adjacency Oracle Only the pairs and will be used to generate new rays October 3, 2012 Jayant Apte. ASPITRG 74
  • 75. Strengthened Main Lemma for DD Method October 3, 2012 Jayant Apte. ASPITRG 75
  • 76. Procedural Description October 3, 2012 Jayant Apte. ASPITRG 76
  • 77. Part 2 October 3, 2012 Jayant Apte. ASPITRG 77
  • 78. Projection of polyhedral sets – Fourier-Motzkin Elimination – Block Elimination – Convex Hull Method (CHM) ● Redundancy removal – Redundancy removal using linear programming October 3, 2012 Jayant Apte. ASPITRG 78
  • 79. Projection of a Polyhedra October 3, 2012 Jayant Apte. ASPITRG 79
  • 80. Fourier-Motzkin Elimination ● Named after Joseph Fourier and Theodore Motzkin October 3, 2012 Jayant Apte. ASPITRG 80
  • 81. How it works? October 3, 2012 Jayant Apte. ASPITRG 81
  • 82. How it works? Contd... October 3, 2012 Jayant Apte. ASPITRG 82
  • 83. Efficiency of FM algorithm October 3, 2012 Jayant Apte. ASPITRG 83
  • 84. Convex Hull Method(CHM) ● First appears in “C. Lassez and J.-L. Lassez, Quantifier elimination for conjunctions of linear constraints via aconvex hull algorithm, IBM Research Report, T.J. Watson Research Center (1991)” ● Found to be better than most other existing algorithms when dimension of projection is small ● Cited by Weidong Xu, Jia Wang, Jun Sun in their ISIT 2008 paper “A Projection Method for Derivation of Non- Shannon-Type Information Inequalities” October 3, 2012 Jayant Apte. ASPITRG 84
  • 85. CHM intuition October 3, 2012 Jayant Apte. ASPITRG 85
  • 86. CHM intuition October 3, 2012 Jayant Apte. ASPITRG 86
  • 87. CHM intuition (12,6,6) (12,6) October 3, 2012 Jayant Apte. ASPITRG 87
  • 88. CHM intuition October 3, 2012 Jayant Apte. ASPITRG 88
  • 89. Moral of the story ● We can make decisions about without actually having its H-representation. ● It suffices to have , the original polyhedron ● We run linear programs on to make these decisions October 3, 2012 Jayant Apte. ASPITRG 89
  • 90. Input: Faces A of P Construct an initial Approximation of extreme points of Perform Facet Update by adding r to it Enumeration on to get Convex Hull Method: Flowchart Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In faces No Of ? Yes Stop October 3, 2012 Jayant Apte. ASPITRG 90
  • 91. Example October 3, 2012 Jayant Apte. ASPITRG 91
  • 92. Example October 3, 2012 Jayant Apte. ASPITRG 92
  • 93. Example October 3, 2012 Jayant Apte. ASPITRG 93
  • 94. Input: Faces A of P Construct an initial Approximation of extreme points of Perform Facet Update by adding r to it Enumeration on Convex Hull Method: to get Flowchart Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In facets Of ? Stop October 3, 2012 Jayant Apte. ASPITRG 94
  • 95. How to get the extreme points of initial approximation? October 3, 2012 Jayant Apte. ASPITRG 95
  • 96. Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 96
  • 97. Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 97
  • 98. Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 98
  • 99. Get rest of the points so you have a total of d+1 points October 3, 2012 Jayant Apte. ASPITRG 99
  • 100. Get the rest of the points so you have a total of d+1 points October 3, 2012 Jayant Apte. ASPITRG 100
  • 101. Get the rest of the points so you have a total d+1 points October 3, 2012 Jayant Apte. ASPITRG 101
  • 102. How to get the initial facets of the projection? October 3, 2012 Jayant Apte. ASPITRG 102
  • 103. How to get the initial facets of the projection? October 3, 2012 Jayant Apte. ASPITRG 103
  • 104. Input: Faces A of P Construct an initial Approximation of extreme points of Incrementally update Update by adding r to it The Convex Hull Convex Hull Method: (Perform Facet Enumeration on Flowchart to get ) Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In faces No Of ? Yes Stop October 3, 2012 Jayant Apte. ASPITRG 104
  • 105. Input: Faces A of P Construct an initial Approximation of extreme points of Incrementally update Update by adding r to it The Convex Hull Convex Hull Method: (Perform Facet Enumeration on Flowchart to get ) Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In faces No Of ? Yes Stop October 3, 2012 Jayant Apte. ASPITRG 105
  • 106. Input: Faces A of P Construct an initial Approximation of extreme points of Incrementally update Update by adding r to it The Convex Hull Convex Hull Method: (Perform Facet Enumeration on Flowchart to get ) Take an inequality from that is not a facet of and move it outward To find a new extreme point r Are all inequalities In faces No Of ? Yes Stop October 3, 2012 Jayant Apte. ASPITRG 106
  • 107. Incremental refinement ● Find a facet in current approximation of that is not actually the facet of ● How to do that? October 3, 2012 Jayant Apte. ASPITRG 107
  • 108. Incremental refinement This inequality is Not a facet of October 3, 2012 Jayant Apte. ASPITRG 108
  • 109. Incremental refinement October 3, 2012 Jayant Apte. ASPITRG 109
  • 110. Input: Faces A of P Construct an initial Approximation of extreme points of Incrementally update Update by adding r to it The Convex Hull Convex Hull Method: (Perform Facet Enumeration on Flowchart to get ) Take an inequality from that is not a facet of and move it outward To find a new extreme point r Are all inequalities No In faces Of ? Yes Stop October 3, 2012 Jayant Apte. ASPITRG 110
  • 111. How to update the H-representation to accommodate new point ? October 3, 2012 Jayant Apte. ASPITRG 111
  • 112. Example October 3, 2012 Jayant Apte. ASPITRG 112
  • 113. Example October 3, 2012 Jayant Apte. ASPITRG 113
  • 114. Example: New candidate facets October 3, 2012 Jayant Apte. ASPITRG 114
  • 115. How to update the H-representation to accommodate new point ? Determine validity of The candidate facet And also its sign October 3, 2012 Jayant Apte. ASPITRG 115
  • 116. Example October 3, 2012 Jayant Apte. ASPITRG 116
  • 117. Example October 3, 2012 Jayant Apte. ASPITRG 117
  • 118. How to update the H-representation to accommodate new point ? October 3, 2012 Jayant Apte. ASPITRG 118
  • 119. Example October 3, 2012 Jayant Apte. ASPITRG 119
  • 120. Example October 3, 2012 Jayant Apte. ASPITRG 120
  • 121. Example October 3, 2012 Jayant Apte. ASPITRG 121
  • 122. nd 2 iteration Not a facet of October 3, 2012 Jayant Apte. ASPITRG 122
  • 123. rd 3 iteration Not a facet of October 3, 2012 Jayant Apte. ASPITRG 123
  • 124. th 4 iteration: Done!!! October 3, 2012 Jayant Apte. ASPITRG 124
  • 125. Comparison of Projection Algorithms ● Fourier Motzkin Elimination and Block Elimination doesn't work well when used on big problems ● CHM works very well when the dimension of projection is relatively small as compared to the dimention of original polyhedron. ● Weidong Xu, Jia Wang, Jun Sun have already used CHM to get non-Shannon inequalities. October 3, 2012 Jayant Apte. ASPITRG 125
  • 126. Computation of minimal representation/Redundancy Removal October 3, 2012 Jayant Apte. ASPITRG 126
  • 127. Definitions October 3, 2012 Jayant Apte. ASPITRG 127
  • 128. References ● K. Fukuda and A. Prodon. Double description method revisited. Technical report, Department of Mathematics, Swiss Federal Institute of Technology, Lausanne, Switzerland, 1995 ● G. Ziegler, Lectures on Polytopes, Springer, 1994, revised 1998. Graduate Texts in Mathematics. ● Tien Huynh, Catherine Lassez, and Jean-Louis Lassez. Practical issues on the projection of polyhedral sets. Annals of mathematics and artificial intelligence, November 1992 ● Catherine Lassez and Jean-Louis Lassez. Quantifier elimination for conjunctions of linear constraints via a convex hull algorithm. In Bruce Donald, Deepak Kapur, and Joseph Mundy, editors, Symbolic and Numerical Computation for Artificial Intelligence. Academic Press, 1992. ● R. T. Rockafellar. Convex Analysis (Princeton Mathematical Series). Princeton Univ Pr. ● W. Xu, J. Wang, J. Sun. A projection method for derivation of non-Shannon-type information inequalities. In IEEE International Symposiumon Information Theory (ISIT), pp. 2116 – 2120, 2008. October 3, 2012 Jayant Apte. ASPITRG 128
  • 129. Minkowski's Theorem for Polyhedral Cones Weyl's Theorem for Polyhedral Cones October 3, 2012 Jayant Apte. ASPITRG 129