2. Probability using not. What is the probability of not dying in a fatal airplane crash in 1980?
3. Answer There was a total of 5,479 airplane departures in 1980. Among these departures 19 airplanes crashed. The probability of being in a fatal accident in 1980 is 19/5,479. in order to find the probability of not crash you subtract 1 from 19/5,479 which is 5,460/5479.
4. Prbability using not. What is the probability of not dying in a fatal airplane crash in 1990?
5. Answer There was a total of 8,092 airplane departures in 1990. Among these departures 39 airplanes crashed. The probability of being in a fatal accident in 1990 is 39/8,092. In order to find the probability of not crash you subtract 1 from 39/8,092 which is 8053/8092.
6. Probability of two mutually exclusive events. What is the Probability of dying in a fatal airplane crash in 2001 or 2003?
7. Answer The probability of dying in a fatal airplane crash in 2001 is 92/11,468 and in 2003 was 22/10,508. in order to find the probability of to exclusively mutual situations you have to add the two probability. 92/11,468 plus 22/10,508 is .0101159659.
8. Probability of two mutually exclusive events. What is the probability of dying in a fatal airplane crash in 1997 or 1996?
9. Answer The probability of dying in a fatal airplane crash in 1996 is 380/8,229 and in 1997 was 8/10,980. In order to find the probability of to exclusively mutual situations you have to add the two probability.380/8,229 plus 8/10,980 is .0469067479.
10. Probability using and What is the probability of the same amount of crash will occur in a consecutive years (1966 and 1967)?
11. Answer When finding the probability using add you multiply the total outcomes. 8,229 times 10,318 =84,906,822
12. Work cited National Transportation Statistics http://www.bts.gov/publications/national_transportation_statistics/html/table_02_09.html Budge text “Thinking Mathematically” Third edition. Blitzer (pg.579-604)
