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TUGAS PRA UAS
NAMA : NURHAYAH
NPM : 2011030278
JURUSAN : AKUNTANSI
1. Tentukan factor kombinasi untuk kedua factor tersebut agar menghasilkan isoquant dan buatlah
kurva isoquannya?
K Q
8 28 12 12 28 36 40 6 3
7 24 5 12 28 36 40 12 14
6 10 9 10 23 33 36 33 9
5 6 24 7 18 28 30 33 6
4 12 8 5 10 40 9 8 5
3 5 36 24 12 36 6 10 7
2 28 5 6 9 30 28 28 33
1 3 8 9 5 24 8 3 10
1 2 3 4 5 6 7 8 L
Isoquant 3
Output
Isoquant 4
Output
Isoquant 5
Output
Isoquant 6
Output
(Q) = 5 (Q) = 12 (Q) = 28 (Q) = 36
L K L K L K L K
1 3 1 4 1 2 2 3
2 2 2 8 1 8 5 3
2 7 3 7 4 7 5 7
3 8 3 8 4 8 5 8
3 4 4 3 5 5 6 6
4 1 7 7 6 2
8 4 7 2
K
1 2 3 4 5 6 7 8 L
I1 I2 I3 I4
36
unit
28
unit
12
unit
5
unit
8
7
6
5
4
3
2
1
0
2. Diket : Fungsi Produksi P = 1125 - 75P
Produk Q = 15
Jawab :
AR, TR, dan MR
 Jika Q = 0, maka nilai AR = P, 1125 - (75 x 0) = 1125
dan nilai TR, 1125 x 0 = 0
 Jika Q = 1 unit, maka nilai AR = P, 1125 - (75 x 1) = 1050
dan nilai TR, 1050 x 1 = 1050
Maka MR = ∆TR : ∆Q
= (1050 - 0) : (1 - 0) = 1050 : 1 = 1050
 Jika Q = 2 unit, maka nilai AR = P, 1125 - (75 x 2) = 975
dan nilai TR, 975 x 2 = 1950
Maka MR = ∆TR : ∆Q
= (1950 - 1050) : (2 - 1) = 900 : 1 = 900
 Jika Q = 3 unit, maka nilai AR = P, 1125 - (75 x 3) = 900
dan nilai TR, 900 x 3 = 2700
Maka MR = ∆TR : ∆Q
= (2700 - 1950) : (3 - 2) = 750 : 1 = 750
 Jika Q = 4 unit, maka nilai AR = P, 1125 - (75 x 4) = 825
dan nilai TR, 825 x 4 = 3300
Maka MR = ∆TR : ∆Q
= (3300 - 2700) : (4 - 3) = 600 : 1 = 600
 Jika Q = 5 unit, maka nilai AR = P, 1125 - (75 x 5) = 750
dan nilai TR, 750 x 5 = 3750
Maka MR = ∆TR : ∆Q
= (3750 - 3300) : (5 - 4) = 450 : 1 = 450
 Jika Q = 6 unit, maka nilai AR = P, 1125 - (75 x 6) = 675
dan nilai TR, 675 x 6 = 4050
Maka MR = ∆TR : ∆Q
= (4050 - 3750) : (6 - 5) = 300 : 1 = 300
 Jika Q = 7 unit, maka nilai AR = P, 1125 - (75 x 7) = 600
dan nilai TR, 600 x 7 = 4200
Maka MR = ∆TR : ∆Q
= (4200 - 4050) : (7 - 6) = 150 : 1 = 150
 Jika Q = 8 unit, maka nilai AR = P, 1125 - (75 x 8) = 525
dan nilai TR, 525 x 8 = 4200
Maka MR = ∆TR : ∆Q
= (4200 - 4200) : (8 - 7) = 0 : 1 = 0
 Jika Q = 9 unit, maka nilai AR = P, 1125 - (75 x 9) = 450
dan nilai TR, 450 x 9 = 4050
Maka MR = ∆TR : ∆Q
= (4050 - 4200) : (9 - 8) = -150 : 1 = -150
 Jika Q = 10 unit, maka nilai AR = P, 1125 - (75 x 10) = 375
dan nilai TR, 375 x 10 = 3750
Maka MR = ∆TR : ∆Q
= (3750 - 4050) : (10 - 9) = -300 : 1 = -300
 Jika Q = 11 unit, maka nilai AR = P, 1125 - (75 x 11) = 300
dan nilai TR, 300 x 11 = 3300
Maka MR = ∆TR : ∆Q
= (3300 - 3750) : (11 - 10) = -450 : 1 = -450
 Jika Q = 12 unit, maka nilai AR = P, 1125 - (75 x 12) = 225
dan nilai TR, 225 x 12 = 2700
Maka MR = ∆TR : ∆Q
= (2700 - 3300) : (12 - 11) = -600 : 1 = -600
 Jika Q = 13 unit, maka nilai AR = P, 1125 - (75 x 13) = 150
dan nilai TR, 150 x 13 = 1950
Maka MR = ∆TR : ∆Q
= (1950 - 2700) : (13 - 12) = -750 : 1 = -750
 Jika Q = 14 unit, maka nilai AR = P, 1125 - (75 x 14) = 75
dan nilai TR, 75 x 14 = 1050
Maka MR = ∆TR : ∆Q
= (1050 - 1950) : (14 - 13) = -900 : 1 = -900
 Jika Q = 15 unit, maka nilai AR = P, 1125 - (75 x 15) = 0
dan nilai TR, 0 x 15 = 0
Maka MR = ∆TR : ∆Q
= (0 - 1050) : (15 - 14) = -1050 : 1 = -1050
TABEL
Output AR TR MR
(Q) (P) (PxQ) (∆TR :
∆Q)
0 1125 -
1050
1 1050 1050
900
2 975 1950
750
3 900 2700
600
4 825 3300
450
5 750 3750
300
6 675 4050
150
7 600 4200
0
8 525 4200
-150
9 450 4050
-300
10 375 3750
-450
11 300 3300
-600
12 225 2700
-750
13 150 1950
-900
14 75 1050
-1050
15 0 0

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Appendix E
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Tugas pra uas

  • 1. TUGAS PRA UAS NAMA : NURHAYAH NPM : 2011030278 JURUSAN : AKUNTANSI 1. Tentukan factor kombinasi untuk kedua factor tersebut agar menghasilkan isoquant dan buatlah kurva isoquannya? K Q 8 28 12 12 28 36 40 6 3 7 24 5 12 28 36 40 12 14 6 10 9 10 23 33 36 33 9 5 6 24 7 18 28 30 33 6 4 12 8 5 10 40 9 8 5 3 5 36 24 12 36 6 10 7 2 28 5 6 9 30 28 28 33 1 3 8 9 5 24 8 3 10 1 2 3 4 5 6 7 8 L Isoquant 3 Output Isoquant 4 Output Isoquant 5 Output Isoquant 6 Output (Q) = 5 (Q) = 12 (Q) = 28 (Q) = 36 L K L K L K L K 1 3 1 4 1 2 2 3 2 2 2 8 1 8 5 3 2 7 3 7 4 7 5 7 3 8 3 8 4 8 5 8 3 4 4 3 5 5 6 6 4 1 7 7 6 2 8 4 7 2
  • 2. K 1 2 3 4 5 6 7 8 L I1 I2 I3 I4 36 unit 28 unit 12 unit 5 unit 8 7 6 5 4 3 2 1 0
  • 3. 2. Diket : Fungsi Produksi P = 1125 - 75P Produk Q = 15 Jawab : AR, TR, dan MR  Jika Q = 0, maka nilai AR = P, 1125 - (75 x 0) = 1125 dan nilai TR, 1125 x 0 = 0  Jika Q = 1 unit, maka nilai AR = P, 1125 - (75 x 1) = 1050 dan nilai TR, 1050 x 1 = 1050 Maka MR = ∆TR : ∆Q = (1050 - 0) : (1 - 0) = 1050 : 1 = 1050  Jika Q = 2 unit, maka nilai AR = P, 1125 - (75 x 2) = 975 dan nilai TR, 975 x 2 = 1950 Maka MR = ∆TR : ∆Q = (1950 - 1050) : (2 - 1) = 900 : 1 = 900  Jika Q = 3 unit, maka nilai AR = P, 1125 - (75 x 3) = 900 dan nilai TR, 900 x 3 = 2700 Maka MR = ∆TR : ∆Q = (2700 - 1950) : (3 - 2) = 750 : 1 = 750  Jika Q = 4 unit, maka nilai AR = P, 1125 - (75 x 4) = 825 dan nilai TR, 825 x 4 = 3300 Maka MR = ∆TR : ∆Q = (3300 - 2700) : (4 - 3) = 600 : 1 = 600  Jika Q = 5 unit, maka nilai AR = P, 1125 - (75 x 5) = 750 dan nilai TR, 750 x 5 = 3750 Maka MR = ∆TR : ∆Q = (3750 - 3300) : (5 - 4) = 450 : 1 = 450  Jika Q = 6 unit, maka nilai AR = P, 1125 - (75 x 6) = 675 dan nilai TR, 675 x 6 = 4050 Maka MR = ∆TR : ∆Q = (4050 - 3750) : (6 - 5) = 300 : 1 = 300  Jika Q = 7 unit, maka nilai AR = P, 1125 - (75 x 7) = 600 dan nilai TR, 600 x 7 = 4200 Maka MR = ∆TR : ∆Q = (4200 - 4050) : (7 - 6) = 150 : 1 = 150
  • 4.  Jika Q = 8 unit, maka nilai AR = P, 1125 - (75 x 8) = 525 dan nilai TR, 525 x 8 = 4200 Maka MR = ∆TR : ∆Q = (4200 - 4200) : (8 - 7) = 0 : 1 = 0  Jika Q = 9 unit, maka nilai AR = P, 1125 - (75 x 9) = 450 dan nilai TR, 450 x 9 = 4050 Maka MR = ∆TR : ∆Q = (4050 - 4200) : (9 - 8) = -150 : 1 = -150  Jika Q = 10 unit, maka nilai AR = P, 1125 - (75 x 10) = 375 dan nilai TR, 375 x 10 = 3750 Maka MR = ∆TR : ∆Q = (3750 - 4050) : (10 - 9) = -300 : 1 = -300  Jika Q = 11 unit, maka nilai AR = P, 1125 - (75 x 11) = 300 dan nilai TR, 300 x 11 = 3300 Maka MR = ∆TR : ∆Q = (3300 - 3750) : (11 - 10) = -450 : 1 = -450  Jika Q = 12 unit, maka nilai AR = P, 1125 - (75 x 12) = 225 dan nilai TR, 225 x 12 = 2700 Maka MR = ∆TR : ∆Q = (2700 - 3300) : (12 - 11) = -600 : 1 = -600  Jika Q = 13 unit, maka nilai AR = P, 1125 - (75 x 13) = 150 dan nilai TR, 150 x 13 = 1950 Maka MR = ∆TR : ∆Q = (1950 - 2700) : (13 - 12) = -750 : 1 = -750  Jika Q = 14 unit, maka nilai AR = P, 1125 - (75 x 14) = 75 dan nilai TR, 75 x 14 = 1050 Maka MR = ∆TR : ∆Q = (1050 - 1950) : (14 - 13) = -900 : 1 = -900  Jika Q = 15 unit, maka nilai AR = P, 1125 - (75 x 15) = 0 dan nilai TR, 0 x 15 = 0 Maka MR = ∆TR : ∆Q = (0 - 1050) : (15 - 14) = -1050 : 1 = -1050
  • 5. TABEL Output AR TR MR (Q) (P) (PxQ) (∆TR : ∆Q) 0 1125 - 1050 1 1050 1050 900 2 975 1950 750 3 900 2700 600 4 825 3300 450 5 750 3750 300 6 675 4050 150 7 600 4200 0 8 525 4200 -150 9 450 4050 -300 10 375 3750 -450 11 300 3300 -600 12 225 2700 -750 13 150 1950 -900 14 75 1050 -1050 15 0 0