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Rules of Integration

            By

Oladokun Sulaiman Olanrewaju
Area Under A Curve

• The area under a curve is the area bounded by
  the curve y = f(x), the x-axis and the vertical
  lines x = a and x = b.
       y                       y = f(x)

                                          Suppose we
                                          want to know
                                          the area of the
                                          shaded region
                                      x

           x=a        x=b
Area and the Definite Integral

• If a function has only positive values in an
  interval [a,b] then the area between the curve
  y=f(x) and the x-axis over the interval [a,b] is
  expressed by the definite integral,
                      b
                  a
                          f ( x)dx

• It is called the definite integral because the
  solution is an explicit numerical value.
f(x) < 0 for some interval in [a,b]
     b
 
 a
         f ( x)dx  Area of R1  Area of R2  Area of R3
     y

                                                           y = f(x)


                                          R3
              R1
                                                           x
                        R2
           x=a                                 x=b
y
                    To find
                    the area                  y = f(x)
                    below
                    the x-
                    axis           R3
             R1     place a
                    negative
                    sign                      x
                       R2
                    before
                    the                 x=b
           x=a    x=c
                    integral x=d
Alternatively,
Area of R1  Area of R2  Area of R3
       c                d          b
  f ( x)dx   f ( x)dx   f ( x)dx
   a                   c           d
Area Between Two Curves
Let f and g be continuous functions such that f(x)>g(x)
on the interval [a,b]. Then the area of the region
bounded above by y=f(x) and below by y=g(x) on [a,b]
is given by                 y
                                                     y = g(x)

    f ( x)  g ( x)dx
 b
a                                                   y = f(x)




                                                          x
                            x=a       x=b
Fundamental Theorem of Calculus


• If f is continuous on [a,b], then the definite
  integral is
               b
           a
                   f ( x)dx  F (b)  F (a)
where F(x) is any antiderivative of f on [a,b]
such that F ' ( x)  f ( x).
Evaluating Definite Integrals

          b
To find  f ( x)dx
         a

First find the indefinite Integral  f ( x)dx F ( x)  C
Then find F (a) and F (b).
                               b
          b
Finally,  f ( x)dx  F ( x)        F (b)  F (a)
         a
                               a
Consumer Surplus
Price, p                   Consumer surplus is a measure
                           of consumer welfare. The area
                           of this shaded region is
                                      x*
           Consumer               0
                                           D( x)dx  p * x *
           Surplus
                                             p = p*

                                            Demand function
                                            p = D(x)

       0              x*                           Quantity, x
Producer Surplus
Price, p              Supply function
                      p = S(x)      Producer surplus is the area of
                                    this shaded region which is
                                                    x*
                                          p * x *  S ( x)dx
                                                   0


                                                p = p*
           Producer
           Surplus
                                               Demand function
                                               p = D(x)

       0                x*                               Quantity, x

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Integration. area undera curve

  • 1. Rules of Integration By Oladokun Sulaiman Olanrewaju
  • 2. Area Under A Curve • The area under a curve is the area bounded by the curve y = f(x), the x-axis and the vertical lines x = a and x = b. y y = f(x) Suppose we want to know the area of the shaded region x x=a x=b
  • 3. Area and the Definite Integral • If a function has only positive values in an interval [a,b] then the area between the curve y=f(x) and the x-axis over the interval [a,b] is expressed by the definite integral, b a f ( x)dx • It is called the definite integral because the solution is an explicit numerical value.
  • 4. f(x) < 0 for some interval in [a,b] b  a f ( x)dx  Area of R1  Area of R2  Area of R3 y y = f(x) R3 R1 x R2 x=a x=b
  • 5. y To find the area y = f(x) below the x- axis R3 R1 place a negative sign x R2 before the x=b x=a x=c integral x=d Alternatively, Area of R1  Area of R2  Area of R3 c d b   f ( x)dx   f ( x)dx   f ( x)dx a c d
  • 6. Area Between Two Curves Let f and g be continuous functions such that f(x)>g(x) on the interval [a,b]. Then the area of the region bounded above by y=f(x) and below by y=g(x) on [a,b] is given by y y = g(x)  f ( x)  g ( x)dx b a y = f(x) x x=a x=b
  • 7. Fundamental Theorem of Calculus • If f is continuous on [a,b], then the definite integral is b a f ( x)dx  F (b)  F (a) where F(x) is any antiderivative of f on [a,b] such that F ' ( x)  f ( x).
  • 8. Evaluating Definite Integrals b To find  f ( x)dx a First find the indefinite Integral  f ( x)dx F ( x)  C Then find F (a) and F (b). b b Finally,  f ( x)dx  F ( x)  F (b)  F (a) a a
  • 9. Consumer Surplus Price, p Consumer surplus is a measure of consumer welfare. The area of this shaded region is x* Consumer 0 D( x)dx  p * x * Surplus p = p* Demand function p = D(x) 0 x* Quantity, x
  • 10. Producer Surplus Price, p Supply function p = S(x) Producer surplus is the area of this shaded region which is x* p * x *  S ( x)dx 0 p = p* Producer Surplus Demand function p = D(x) 0 x* Quantity, x