1. Applied Electrical Technology Two
1 1 1 1
=
RT R1 + R2 + R3

2. Applied Electrical Technology Two
x -1 OR recip

3. Applied Electrical Technology Two
6 9 18
1/RT = 1/6 + 1/9 + 1/18
= 6/18
= .33 Ω (=1/3)
x -1
=3Ω

4. Applied Electrical Technology Two
6 9 18
1/RT = 1/6 + 1/9 + 1/18
= 6/18
= .33 Ω (=1/3)
x -1
=3Ω
3 is smaller
then all the
resistors

5. Applied Electrical Technology Two
6 9 18
1/RT = 1/6 + 1/9 + 1/18
Lowest
= 6/18
6÷3 No. of
= .33 Ω (=1/3)
Resistors
x -1
=2
=3Ω
3 is between 6 & 2!