SlideShare una empresa de Scribd logo
1 de 61
Descargar para leer sin conexión
1


        Modeling in the Frequency
                Domain
•   Review of the Laplace transform

•   Learn how to find a mathematical model, called a transfer
    function, for linear, time-invariant electrical, mechanical,
    and electromechanical systems

•   Learn how to linearize a nonlinear system in order to find
    the transfer function




                                                  Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                    Copyright © 2004 by John Wiley & Sons. All rights reserved.
2

                    Introduction to Modeling
•       we look for a mathematical representation where the input, output, and
        system are distinct and separate parts




    •    also, we would like to represent conveniently the interconnection of
         several subsystems. For example, we would like to represent cascaded
         interconnections, where a mathematical function, called a transfer
         function, is inside each block




                                                            Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                              Copyright © 2004 by John Wiley & Sons. All rights reserved.
3

                  Laplace Transform Review

•   a system represented by a differential equation is difficult to model
    as a block diagram
•   on the other hand, a system represented by a Laplace transformed
    differential equation is easier to model as a block diagram



    The Laplace transform is defined as




     where s = σ + jω, is a complex variable.



                                                        Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                          Copyright © 2004 by John Wiley & Sons. All rights reserved.
4

              Laplace Transform Review

The inverse Laplace transform, which allows us
to find f (t) given F(s), is




   where




                                            Control Systems Engineering, Fourth Edition by Norman S. Nise
                                              Copyright © 2004 by John Wiley & Sons. All rights reserved.
5

Laplace Transform Review
  Laplace transform table




                            Control Systems Engineering, Fourth Edition by Norman S. Nise
                              Copyright © 2004 by John Wiley & Sons. All rights reserved.
6



Problem: Find the Laplace transform of


Solution:




                                         Control Systems Engineering, Fourth Edition by Norman S. Nise
                                           Copyright © 2004 by John Wiley & Sons. All rights reserved.
7

Laplace Transform Review
 Laplace transform theorems




                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
8

Laplace Transform Review
 Laplace transform theorems




                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
9
                 Partial-Fraction Expansion

•      To find the inverse Laplace transform of a complicated function,
       we can convert the function to a sum of simpler terms for which we
       know the Laplace transform of each term.

                                       N ( s)
                            F ( s) =
                                       D( s)

    Case 1: Roots of the Denominator of F(s) Are Real and Distinct

    Case 2: Roots of the Denominator of F(s) Are Real and Repeated

    Case 3: Roots of the Denominator of F(s) Are Complex or Imaginary




                                                         Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                           Copyright © 2004 by John Wiley & Sons. All rights reserved.
10

Case 1: Roots of the Denominator of F(s) Are Real and Distinct

  If the order of N(s) is less than the order of D(s), then




 Thus, if we want to find Km, we multiply above equation by ( s + pm )




                                                         Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                           Copyright © 2004 by John Wiley & Sons. All rights reserved.
11




If we substitute s = − pm in the above equation, then we can find Km




                                                    Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                      Copyright © 2004 by John Wiley & Sons. All rights reserved.
12


Problem Given the following differential equation, solve for y(t) if
all initial conditions are zero. Use the Laplace transform.




 Solution




                                                    Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                      Copyright © 2004 by John Wiley & Sons. All rights reserved.
13




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
14

Case 2: Roots of the Denominator of F(s) Are Real and Repeated




 First, we multiply by (s+ p )r and we can solve immediately for K1 if s= - p1
                            1




                                                          Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                            Copyright © 2004 by John Wiley & Sons. All rights reserved.
15




•   we can solve for K2 if we differentiate F1(s) with respect to s and
    then let s approach –p1

•   subsequent differentiation allows to find K3 through Kr

•   the general expression for K1 through Kr for the multiple roots is




                                                      Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                        Copyright © 2004 by John Wiley & Sons. All rights reserved.
16
Case 3: Roots of the Denominator of F(s) Are Complex or Imaginary




                                           has complex or pure imaginary roots

 •   the coefficients K2, K3 are found through balancing the coefficients
     of the equation after clearing fractions

      (K 2s + K3 )
                   is put in the form of                            by completing
     ( s + as + b)
        2



     the squares on ( s 2 + as + b) and adjusting the numerator


                                                          Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                            Copyright © 2004 by John Wiley & Sons. All rights reserved.
17




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
18


                   The Transfer Function (1)
Let us consider a general nth-order, linear, time-invariant differential
equation is given as:




where c(t) is the output, r(t) is the input, and ai, bi are coefficients.


Taking the Laplace transform of both sides (assuming all initial
conditions are zero) we obtain




                                                        Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                          Copyright © 2004 by John Wiley & Sons. All rights reserved.
19


                The Transfer Function (2)
Transfer function is the ratio G(s) of the output transform, C(s),
divided by the input transform, R(s)




               C ( s)            (bm s m + bm −1s m −1 + ... + b0 )
                      = G ( s) =
               R( s)             (an s n + an −1s n −1 + ... + a0 )




                                                                  Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                    Copyright © 2004 by John Wiley & Sons. All rights reserved.
20

         Electric Network Transfer Functions

Voltage-current, voltage-charge, and impedance relationships for capacitors,
resistors, and inductors




                                                             Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                               Copyright © 2004 by John Wiley & Sons. All rights reserved.
21


Problem Find the transfer function relating the capacitor voltage,
Vc(s), to the input voltage, V(s)




 Solution:




                                                    Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                      Copyright © 2004 by John Wiley & Sons. All rights reserved.
22




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
23

Transfer function-single loop via transform methods




                                               Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                 Copyright © 2004 by John Wiley & Sons. All rights reserved.
24

Complex Electric Circuits via Mesh Analysis

 1. Replace passive element values with their impedances.

 2. Replace all sources and time variables with their Laplace
    transform.

 3. Assume a transform current and a current direction in each
    mesh.

 4. Write Kirchhoff's voltage law around each mesh.

 5. Solve the simultaneous equations for the output.

 6. Form the transfer function



                                                 Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                   Copyright © 2004 by John Wiley & Sons. All rights reserved.
25
Problem: find the transfer function, I2(s)/V(s)




                                                  Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                    Copyright © 2004 by John Wiley & Sons. All rights reserved.
26




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
27


Complex Electric Circuits via Nodal Analysis

1. Replace passive element values with their admittances

2. Replace all sources and time variables with their Laplace
   transform.

3. Replace transformed voltage sources with transformed current
   sources.

4. Write Kirchhoff's current law at each node.

5. Solve the simultaneous equations for the output.

6. Form the transfer function.


                                                      Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                        Copyright © 2004 by John Wiley & Sons. All rights reserved.
28


                   Operational Amplifiers




Inverting OP AMP




                                        Control Systems Engineering, Fourth Edition by Norman S. Nise
                                          Copyright © 2004 by John Wiley & Sons. All rights reserved.
29

Non-inverting OP AMP




                       Control Systems Engineering, Fourth Edition by Norman S. Nise
                         Copyright © 2004 by John Wiley & Sons. All rights reserved.
30

Example




          Control Systems Engineering, Fourth Edition by Norman S. Nise
            Copyright © 2004 by John Wiley & Sons. All rights reserved.
31

  Translational Mechanical System Transfer
                  Functions
Newton's law: The sum of forces on a body equals zero; the sum of
moments on a body equals zero.




                                                                           K… spring
                                                                           constant




                                                                           fv … coefficient of
                                                                           viscious friction



                                                                           M … mass




                                                 Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                   Copyright © 2004 by John Wiley & Sons. All rights reserved.
32




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
33

Problem Find the transfer function, X(s)/F(s), for the system




Solution:




                                                   Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                     Copyright © 2004 by John Wiley & Sons. All rights reserved.
34


    Translational Mechanical System Transfer
                    Functions

•   The required number of equations of motion is equal to the
    number of linearly independent motions. Linear independence
    implies that a point of motion in a system can still move if all
    other points of motion are held still.

•   Another name for the number of linearly independent motions
    is the number of degrees of freedom.




                                                      Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                        Copyright © 2004 by John Wiley & Sons. All rights reserved.
35

    Problem: Find the transfer function, X2(s)/F(s), of the system




Solution
•      we draw the free-body diagram for each point of motion and then use
       superposition

•      for each free-body diagram we begin by holding all other points of
       motion still and finding the forces acting on the body due only to its
       own motion.

•      then we hold the body still and activate the other points of motion one
       at a time, placing on the original body the forces created by the
       adjacent motion


                                                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
36




a. Forces on M1 due only
to motion of M1




b. forces on M1 due only to
motion of M2




   c. all forces on M1


                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
37




a. Forces on M2 due only
to motion of M2;




 b. forces on M2 due only
 to motion




  c. all forces on M2




                            Control Systems Engineering, Fourth Edition by Norman S. Nise
                              Copyright © 2004 by John Wiley & Sons. All rights reserved.
38




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
39




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
40


          Rotational Mechanical System Transfer
                        Functions
Torque-angular velocity, torque-angular displacement, and
impedance rotational relationships for springs, viscous
dampers, and inertia




                                                       •    the mass is replaced by inertia

                                                       •    the values of K, D, and J are
                                                            called spring constant, coefficient
                                                            of viscous friction, and moment of
                                                            inertia, respectively
                                                       •    the concept of degrees of freedom
                                                            is the same as for translational
                                                            movement



                                                                      Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                        Copyright © 2004 by John Wiley & Sons. All rights reserved.
41


Problem Find the transfer function




Solution
           a. Torques on J1
           due only to the
           motion of J1




                                     Control Systems Engineering, Fourth Edition by Norman S. Nise
                                       Copyright © 2004 by John Wiley & Sons. All rights reserved.
42




b. torques on J1
due only to the
motion of J2




c. final free-body
diagram for J1




                     Control Systems Engineering, Fourth Edition by Norman S. Nise
                       Copyright © 2004 by John Wiley & Sons. All rights reserved.
43




a. Torques on J1
due only to the
motion of J1
b. torques on J1
due only to the
motion of J2
c. final free-body
diagram for J1




                     Control Systems Engineering, Fourth Edition by Norman S. Nise
                       Copyright © 2004 by John Wiley & Sons. All rights reserved.
44




a. Torques on J2
due only to the
motion of J2
b. torques on J2
due only to the
motion of J1
c. final free-body
diagram for J2




                     Control Systems Engineering, Fourth Edition by Norman S. Nise
                       Copyright © 2004 by John Wiley & Sons. All rights reserved.
45




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
46




Control Systems Engineering, Fourth Edition by Norman S. Nise
  Copyright © 2004 by John Wiley & Sons. All rights reserved.
47

Transfer Functions for Systems with Gears




- the distance travelled along each gear's circumference is the same

                        θ 2 r1 N1
                           = =
                        θ1 r2 N 2

- the energy into Gear 1 equals the energy out of Gear 2

                        T2 θ1 N 2
                          =   =
                        T1 θ 2 N1




                                                  Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                    Copyright © 2004 by John Wiley & Sons. All rights reserved.
48




T2 θ1 N 2
  =   =
T1 θ 2 N1




            Control Systems Engineering, Fourth Edition by Norman S. Nise
              Copyright © 2004 by John Wiley & Sons. All rights reserved.
49




Rotational mechanical impedances can be reflected through gear
trains by multiplying the mechanical impedance by the ratio




                                                  Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                    Copyright © 2004 by John Wiley & Sons. All rights reserved.
50


A gear train is used to implement large gear ratios by cascading
smaller gear ratios.




                                                   Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                     Copyright © 2004 by John Wiley & Sons. All rights reserved.
51

Problem Find the transfer function,




 Solution:




                                      Control Systems Engineering, Fourth Edition by Norman S. Nise
                                        Copyright © 2004 by John Wiley & Sons. All rights reserved.
52

Electromechanical System Transfer Functions
Electromechanical systems: robots, hard disk drives, …

Motor is an electromechanical component that yields a displacement output
for a voltage input, that is, a mechanical output generated by an electrical
input.




                                                         Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                           Copyright © 2004 by John Wiley & Sons. All rights reserved.
53

    Derivation of the Transfer Function of Motor




Back electromotive force (back emf):




               where Kb is a constant of proportionality called the back emf constant;

                       dθ m / dt = ωm (t ) is the angular velocity of the motor

Taking the Laplace transform, we get:


                             Torque:
                                                                Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                  Copyright © 2004 by John Wiley & Sons. All rights reserved.
54




The relationship between the armature current, ia(t), the applied armature voltage,
ea(t), and the back emf, vb(t),




                       Tm ( s )
          I a ( s) =
                        Kt



                                                               Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                 Copyright © 2004 by John Wiley & Sons. All rights reserved.
55




We assume that the armature inductance, La, is small compared to the armature
resistance, Ra,




                                                          Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                            Copyright © 2004 by John Wiley & Sons. All rights reserved.
56




   The mechanical constants Jm and Dm can be found as:




Electrical constants Kt/Ra and Kb can be found through a dynamometer test of
the motor.




                                                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
57




K t Tstall
   =
Ra   ea




                       ea
             Kb =
                    ωno −load




                                Control Systems Engineering, Fourth Edition by Norman S. Nise
                                  Copyright © 2004 by John Wiley & Sons. All rights reserved.
58

                         Nonlinearities

A linear system possesses two properties: superposition and homogeneity.

              Superposition - the output response of a system to the sum of
              inputs is the sum of the responses to the individual inputs.

              Homogeneity - describes the response of the system to a
              multiplication of the input by a scalar. Multiplication of an input
              by a scalar yields a response that is multiplied by the same
              scalar.




                      Linear system                     Nonlinear system
                                                              Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                                Copyright © 2004 by John Wiley & Sons. All rights reserved.
59

Nonlinearities




                 Control Systems Engineering, Fourth Edition by Norman S. Nise
                   Copyright © 2004 by John Wiley & Sons. All rights reserved.
60

                        Linearization
•   if any nonlinear components are present, we must linearize the system
    before we can find the transfer function

•   we linearize nonlinear differential equation for small-signal inputs about
    the steady-state solution when the small signal input is equal to zero




                                        ma is the slope of the curve at point A




                                                            Control Systems Engineering, Fourth Edition by Norman S. Nise
                                                              Copyright © 2004 by John Wiley & Sons. All rights reserved.
61




Solution:



  At π/2 df/dx = - 5




                       Control Systems Engineering, Fourth Edition by Norman S. Nise
                         Copyright © 2004 by John Wiley & Sons. All rights reserved.

Más contenido relacionado

Destacado

01 elec3114
01 elec311401 elec3114
01 elec3114
Vin Voro
 
09 elec3114
09 elec311409 elec3114
09 elec3114
Vin Voro
 
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
Khalil Abu Haltam
 
Tele3113 wk11tue
Tele3113 wk11tueTele3113 wk11tue
Tele3113 wk11tue
Vin Voro
 
Tele3113 wk11wed
Tele3113 wk11wedTele3113 wk11wed
Tele3113 wk11wed
Vin Voro
 
Tele3113 wk10tue
Tele3113 wk10tueTele3113 wk10tue
Tele3113 wk10tue
Vin Voro
 
Tele3113 wk10wed
Tele3113 wk10wedTele3113 wk10wed
Tele3113 wk10wed
Vin Voro
 
Tele3113 tut6
Tele3113 tut6Tele3113 tut6
Tele3113 tut6
Vin Voro
 

Destacado (16)

01 elec3114
01 elec311401 elec3114
01 elec3114
 
09 elec3114
09 elec311409 elec3114
09 elec3114
 
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
Solutions control system sengineering by normannice 6ed 130502172814-phpapp02
 
Pe 3032 wk 1 introduction to control system march 04e
Pe 3032 wk 1 introduction to control system  march 04ePe 3032 wk 1 introduction to control system  march 04e
Pe 3032 wk 1 introduction to control system march 04e
 
Tele3113 wk11tue
Tele3113 wk11tueTele3113 wk11tue
Tele3113 wk11tue
 
Tele3113 wk11wed
Tele3113 wk11wedTele3113 wk11wed
Tele3113 wk11wed
 
Tele3113 wk10tue
Tele3113 wk10tueTele3113 wk10tue
Tele3113 wk10tue
 
Tele3113 wk10wed
Tele3113 wk10wedTele3113 wk10wed
Tele3113 wk10wed
 
Aircraft system integration
Aircraft system integrationAircraft system integration
Aircraft system integration
 
Aircraft System Integration
Aircraft System IntegrationAircraft System Integration
Aircraft System Integration
 
RF Basics & Getting Started Guide by Anaren
RF Basics & Getting Started Guide by AnarenRF Basics & Getting Started Guide by Anaren
RF Basics & Getting Started Guide by Anaren
 
Tele3113 tut6
Tele3113 tut6Tele3113 tut6
Tele3113 tut6
 
Basic electronics vocabulary
Basic electronics vocabularyBasic electronics vocabulary
Basic electronics vocabulary
 
An Electrical Engineers Guide to EMC/EMI.
An Electrical Engineers Guide to EMC/EMI.An Electrical Engineers Guide to EMC/EMI.
An Electrical Engineers Guide to EMC/EMI.
 
Rf basics part1
Rf basics part1Rf basics part1
Rf basics part1
 
Overview Of Unmanned Aircraft Systems (UAS)
Overview Of Unmanned Aircraft Systems (UAS)Overview Of Unmanned Aircraft Systems (UAS)
Overview Of Unmanned Aircraft Systems (UAS)
 

Más de Vin Voro

Tele3113 tut5
Tele3113 tut5Tele3113 tut5
Tele3113 tut5
Vin Voro
 
Tele3113 tut4
Tele3113 tut4Tele3113 tut4
Tele3113 tut4
Vin Voro
 
Tele3113 tut1
Tele3113 tut1Tele3113 tut1
Tele3113 tut1
Vin Voro
 
Tele3113 tut3
Tele3113 tut3Tele3113 tut3
Tele3113 tut3
Vin Voro
 
Tele3113 tut2
Tele3113 tut2Tele3113 tut2
Tele3113 tut2
Vin Voro
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
Vin Voro
 
Tele3113 wk9tue
Tele3113 wk9tueTele3113 wk9tue
Tele3113 wk9tue
Vin Voro
 
Tele3113 wk8wed
Tele3113 wk8wedTele3113 wk8wed
Tele3113 wk8wed
Vin Voro
 
Tele3113 wk9wed
Tele3113 wk9wedTele3113 wk9wed
Tele3113 wk9wed
Vin Voro
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
Vin Voro
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
Vin Voro
 
Tele3113 wk7tue
Tele3113 wk7tueTele3113 wk7tue
Tele3113 wk7tue
Vin Voro
 
Tele3113 wk6wed
Tele3113 wk6wedTele3113 wk6wed
Tele3113 wk6wed
Vin Voro
 
Tele3113 wk6tue
Tele3113 wk6tueTele3113 wk6tue
Tele3113 wk6tue
Vin Voro
 
Tele3113 wk5tue
Tele3113 wk5tueTele3113 wk5tue
Tele3113 wk5tue
Vin Voro
 
Tele3113 wk4wed
Tele3113 wk4wedTele3113 wk4wed
Tele3113 wk4wed
Vin Voro
 
Tele3113 wk4tue
Tele3113 wk4tueTele3113 wk4tue
Tele3113 wk4tue
Vin Voro
 
Tele3113 wk5wed
Tele3113 wk5wedTele3113 wk5wed
Tele3113 wk5wed
Vin Voro
 
Tele3113 wk2tue
Tele3113 wk2tueTele3113 wk2tue
Tele3113 wk2tue
Vin Voro
 
Tele3113 wk1tue
Tele3113 wk1tueTele3113 wk1tue
Tele3113 wk1tue
Vin Voro
 

Más de Vin Voro (20)

Tele3113 tut5
Tele3113 tut5Tele3113 tut5
Tele3113 tut5
 
Tele3113 tut4
Tele3113 tut4Tele3113 tut4
Tele3113 tut4
 
Tele3113 tut1
Tele3113 tut1Tele3113 tut1
Tele3113 tut1
 
Tele3113 tut3
Tele3113 tut3Tele3113 tut3
Tele3113 tut3
 
Tele3113 tut2
Tele3113 tut2Tele3113 tut2
Tele3113 tut2
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
 
Tele3113 wk9tue
Tele3113 wk9tueTele3113 wk9tue
Tele3113 wk9tue
 
Tele3113 wk8wed
Tele3113 wk8wedTele3113 wk8wed
Tele3113 wk8wed
 
Tele3113 wk9wed
Tele3113 wk9wedTele3113 wk9wed
Tele3113 wk9wed
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
 
Tele3113 wk7wed
Tele3113 wk7wedTele3113 wk7wed
Tele3113 wk7wed
 
Tele3113 wk7tue
Tele3113 wk7tueTele3113 wk7tue
Tele3113 wk7tue
 
Tele3113 wk6wed
Tele3113 wk6wedTele3113 wk6wed
Tele3113 wk6wed
 
Tele3113 wk6tue
Tele3113 wk6tueTele3113 wk6tue
Tele3113 wk6tue
 
Tele3113 wk5tue
Tele3113 wk5tueTele3113 wk5tue
Tele3113 wk5tue
 
Tele3113 wk4wed
Tele3113 wk4wedTele3113 wk4wed
Tele3113 wk4wed
 
Tele3113 wk4tue
Tele3113 wk4tueTele3113 wk4tue
Tele3113 wk4tue
 
Tele3113 wk5wed
Tele3113 wk5wedTele3113 wk5wed
Tele3113 wk5wed
 
Tele3113 wk2tue
Tele3113 wk2tueTele3113 wk2tue
Tele3113 wk2tue
 
Tele3113 wk1tue
Tele3113 wk1tueTele3113 wk1tue
Tele3113 wk1tue
 

Último

Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdf
ciinovamais
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
QucHHunhnh
 
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
kauryashika82
 
Seal of Good Local Governance (SGLG) 2024Final.pptx
Seal of Good Local Governance (SGLG) 2024Final.pptxSeal of Good Local Governance (SGLG) 2024Final.pptx
Seal of Good Local Governance (SGLG) 2024Final.pptx
negromaestrong
 

Último (20)

ICT role in 21st century education and it's challenges.
ICT role in 21st century education and it's challenges.ICT role in 21st century education and it's challenges.
ICT role in 21st century education and it's challenges.
 
ComPTIA Overview | Comptia Security+ Book SY0-701
ComPTIA Overview | Comptia Security+ Book SY0-701ComPTIA Overview | Comptia Security+ Book SY0-701
ComPTIA Overview | Comptia Security+ Book SY0-701
 
Spatium Project Simulation student brief
Spatium Project Simulation student briefSpatium Project Simulation student brief
Spatium Project Simulation student brief
 
Mehran University Newsletter Vol-X, Issue-I, 2024
Mehran University Newsletter Vol-X, Issue-I, 2024Mehran University Newsletter Vol-X, Issue-I, 2024
Mehran University Newsletter Vol-X, Issue-I, 2024
 
SOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning PresentationSOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning Presentation
 
Application orientated numerical on hev.ppt
Application orientated numerical on hev.pptApplication orientated numerical on hev.ppt
Application orientated numerical on hev.ppt
 
Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdf
 
Sociology 101 Demonstration of Learning Exhibit
Sociology 101 Demonstration of Learning ExhibitSociology 101 Demonstration of Learning Exhibit
Sociology 101 Demonstration of Learning Exhibit
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
 
Micro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdfMicro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdf
 
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
 
Seal of Good Local Governance (SGLG) 2024Final.pptx
Seal of Good Local Governance (SGLG) 2024Final.pptxSeal of Good Local Governance (SGLG) 2024Final.pptx
Seal of Good Local Governance (SGLG) 2024Final.pptx
 
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
Magic bus Group work1and 2 (Team 3).pptx
Magic bus Group work1and 2 (Team 3).pptxMagic bus Group work1and 2 (Team 3).pptx
Magic bus Group work1and 2 (Team 3).pptx
 
PROCESS RECORDING FORMAT.docx
PROCESS      RECORDING        FORMAT.docxPROCESS      RECORDING        FORMAT.docx
PROCESS RECORDING FORMAT.docx
 
UGC NET Paper 1 Mathematical Reasoning & Aptitude.pdf
UGC NET Paper 1 Mathematical Reasoning & Aptitude.pdfUGC NET Paper 1 Mathematical Reasoning & Aptitude.pdf
UGC NET Paper 1 Mathematical Reasoning & Aptitude.pdf
 
Accessible Digital Futures project (20/03/2024)
Accessible Digital Futures project (20/03/2024)Accessible Digital Futures project (20/03/2024)
Accessible Digital Futures project (20/03/2024)
 
Kodo Millet PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
Kodo Millet  PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...Kodo Millet  PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
Kodo Millet PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
 
How to Manage Global Discount in Odoo 17 POS
How to Manage Global Discount in Odoo 17 POSHow to Manage Global Discount in Odoo 17 POS
How to Manage Global Discount in Odoo 17 POS
 

02 elec3114

  • 1. 1 Modeling in the Frequency Domain • Review of the Laplace transform • Learn how to find a mathematical model, called a transfer function, for linear, time-invariant electrical, mechanical, and electromechanical systems • Learn how to linearize a nonlinear system in order to find the transfer function Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 2. 2 Introduction to Modeling • we look for a mathematical representation where the input, output, and system are distinct and separate parts • also, we would like to represent conveniently the interconnection of several subsystems. For example, we would like to represent cascaded interconnections, where a mathematical function, called a transfer function, is inside each block Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 3. 3 Laplace Transform Review • a system represented by a differential equation is difficult to model as a block diagram • on the other hand, a system represented by a Laplace transformed differential equation is easier to model as a block diagram The Laplace transform is defined as where s = σ + jω, is a complex variable. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 4. 4 Laplace Transform Review The inverse Laplace transform, which allows us to find f (t) given F(s), is where Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 5. 5 Laplace Transform Review Laplace transform table Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 6. 6 Problem: Find the Laplace transform of Solution: Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 7. 7 Laplace Transform Review Laplace transform theorems Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 8. 8 Laplace Transform Review Laplace transform theorems Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 9. 9 Partial-Fraction Expansion • To find the inverse Laplace transform of a complicated function, we can convert the function to a sum of simpler terms for which we know the Laplace transform of each term. N ( s) F ( s) = D( s) Case 1: Roots of the Denominator of F(s) Are Real and Distinct Case 2: Roots of the Denominator of F(s) Are Real and Repeated Case 3: Roots of the Denominator of F(s) Are Complex or Imaginary Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 10. 10 Case 1: Roots of the Denominator of F(s) Are Real and Distinct If the order of N(s) is less than the order of D(s), then Thus, if we want to find Km, we multiply above equation by ( s + pm ) Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 11. 11 If we substitute s = − pm in the above equation, then we can find Km Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 12. 12 Problem Given the following differential equation, solve for y(t) if all initial conditions are zero. Use the Laplace transform. Solution Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 13. 13 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 14. 14 Case 2: Roots of the Denominator of F(s) Are Real and Repeated First, we multiply by (s+ p )r and we can solve immediately for K1 if s= - p1 1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 15. 15 • we can solve for K2 if we differentiate F1(s) with respect to s and then let s approach –p1 • subsequent differentiation allows to find K3 through Kr • the general expression for K1 through Kr for the multiple roots is Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 16. 16 Case 3: Roots of the Denominator of F(s) Are Complex or Imaginary has complex or pure imaginary roots • the coefficients K2, K3 are found through balancing the coefficients of the equation after clearing fractions (K 2s + K3 ) is put in the form of by completing ( s + as + b) 2 the squares on ( s 2 + as + b) and adjusting the numerator Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 17. 17 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 18. 18 The Transfer Function (1) Let us consider a general nth-order, linear, time-invariant differential equation is given as: where c(t) is the output, r(t) is the input, and ai, bi are coefficients. Taking the Laplace transform of both sides (assuming all initial conditions are zero) we obtain Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 19. 19 The Transfer Function (2) Transfer function is the ratio G(s) of the output transform, C(s), divided by the input transform, R(s) C ( s) (bm s m + bm −1s m −1 + ... + b0 ) = G ( s) = R( s) (an s n + an −1s n −1 + ... + a0 ) Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 20. 20 Electric Network Transfer Functions Voltage-current, voltage-charge, and impedance relationships for capacitors, resistors, and inductors Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 21. 21 Problem Find the transfer function relating the capacitor voltage, Vc(s), to the input voltage, V(s) Solution: Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 22. 22 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 23. 23 Transfer function-single loop via transform methods Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 24. 24 Complex Electric Circuits via Mesh Analysis 1. Replace passive element values with their impedances. 2. Replace all sources and time variables with their Laplace transform. 3. Assume a transform current and a current direction in each mesh. 4. Write Kirchhoff's voltage law around each mesh. 5. Solve the simultaneous equations for the output. 6. Form the transfer function Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 25. 25 Problem: find the transfer function, I2(s)/V(s) Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 26. 26 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 27. 27 Complex Electric Circuits via Nodal Analysis 1. Replace passive element values with their admittances 2. Replace all sources and time variables with their Laplace transform. 3. Replace transformed voltage sources with transformed current sources. 4. Write Kirchhoff's current law at each node. 5. Solve the simultaneous equations for the output. 6. Form the transfer function. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 28. 28 Operational Amplifiers Inverting OP AMP Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 29. 29 Non-inverting OP AMP Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 30. 30 Example Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 31. 31 Translational Mechanical System Transfer Functions Newton's law: The sum of forces on a body equals zero; the sum of moments on a body equals zero. K… spring constant fv … coefficient of viscious friction M … mass Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 32. 32 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 33. 33 Problem Find the transfer function, X(s)/F(s), for the system Solution: Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 34. 34 Translational Mechanical System Transfer Functions • The required number of equations of motion is equal to the number of linearly independent motions. Linear independence implies that a point of motion in a system can still move if all other points of motion are held still. • Another name for the number of linearly independent motions is the number of degrees of freedom. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 35. 35 Problem: Find the transfer function, X2(s)/F(s), of the system Solution • we draw the free-body diagram for each point of motion and then use superposition • for each free-body diagram we begin by holding all other points of motion still and finding the forces acting on the body due only to its own motion. • then we hold the body still and activate the other points of motion one at a time, placing on the original body the forces created by the adjacent motion Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 36. 36 a. Forces on M1 due only to motion of M1 b. forces on M1 due only to motion of M2 c. all forces on M1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 37. 37 a. Forces on M2 due only to motion of M2; b. forces on M2 due only to motion c. all forces on M2 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 38. 38 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 39. 39 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 40. 40 Rotational Mechanical System Transfer Functions Torque-angular velocity, torque-angular displacement, and impedance rotational relationships for springs, viscous dampers, and inertia • the mass is replaced by inertia • the values of K, D, and J are called spring constant, coefficient of viscous friction, and moment of inertia, respectively • the concept of degrees of freedom is the same as for translational movement Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 41. 41 Problem Find the transfer function Solution a. Torques on J1 due only to the motion of J1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 42. 42 b. torques on J1 due only to the motion of J2 c. final free-body diagram for J1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 43. 43 a. Torques on J1 due only to the motion of J1 b. torques on J1 due only to the motion of J2 c. final free-body diagram for J1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 44. 44 a. Torques on J2 due only to the motion of J2 b. torques on J2 due only to the motion of J1 c. final free-body diagram for J2 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 45. 45 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 46. 46 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 47. 47 Transfer Functions for Systems with Gears - the distance travelled along each gear's circumference is the same θ 2 r1 N1 = = θ1 r2 N 2 - the energy into Gear 1 equals the energy out of Gear 2 T2 θ1 N 2 = = T1 θ 2 N1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 48. 48 T2 θ1 N 2 = = T1 θ 2 N1 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 49. 49 Rotational mechanical impedances can be reflected through gear trains by multiplying the mechanical impedance by the ratio Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 50. 50 A gear train is used to implement large gear ratios by cascading smaller gear ratios. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 51. 51 Problem Find the transfer function, Solution: Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 52. 52 Electromechanical System Transfer Functions Electromechanical systems: robots, hard disk drives, … Motor is an electromechanical component that yields a displacement output for a voltage input, that is, a mechanical output generated by an electrical input. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 53. 53 Derivation of the Transfer Function of Motor Back electromotive force (back emf): where Kb is a constant of proportionality called the back emf constant; dθ m / dt = ωm (t ) is the angular velocity of the motor Taking the Laplace transform, we get: Torque: Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 54. 54 The relationship between the armature current, ia(t), the applied armature voltage, ea(t), and the back emf, vb(t), Tm ( s ) I a ( s) = Kt Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 55. 55 We assume that the armature inductance, La, is small compared to the armature resistance, Ra, Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 56. 56 The mechanical constants Jm and Dm can be found as: Electrical constants Kt/Ra and Kb can be found through a dynamometer test of the motor. Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 57. 57 K t Tstall = Ra ea ea Kb = ωno −load Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 58. 58 Nonlinearities A linear system possesses two properties: superposition and homogeneity. Superposition - the output response of a system to the sum of inputs is the sum of the responses to the individual inputs. Homogeneity - describes the response of the system to a multiplication of the input by a scalar. Multiplication of an input by a scalar yields a response that is multiplied by the same scalar. Linear system Nonlinear system Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 59. 59 Nonlinearities Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 60. 60 Linearization • if any nonlinear components are present, we must linearize the system before we can find the transfer function • we linearize nonlinear differential equation for small-signal inputs about the steady-state solution when the small signal input is equal to zero ma is the slope of the curve at point A Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.
  • 61. 61 Solution: At π/2 df/dx = - 5 Control Systems Engineering, Fourth Edition by Norman S. Nise Copyright © 2004 by John Wiley & Sons. All rights reserved.