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Dr. Bob Hummel
Potomac Institute for Policy Studies




          hummel@PotomacInstitute.org

          ORCON: Ask permission before redistributing
                Not intended for publication
STEM: Science, Technology,
Engineering, & Mathematics
ž  STEM   includes mathematics
ž  But when you call it STEM, do
    you think “mathematics”?
ž  Math is at the tail end




            Are these people learning math?

                                   The Art of Number Theory
February 4, 2013                       Dr. Bob Hummel         2
The Phenomenon of Math Phobia
ž  Math is cumulative
ž  For most of the math curriculum
       —  If you fall behind, you remain
           behind
       —  Answers in math are generally right or wrong



                           Why do we even bother to teach math?
                           Don’t calculators and computers obviate math?



                            The Art of Number Theory
February 4, 2013                Dr. Bob Hummel                             3
What we teach
ž  Arithmetic                                    2+2=   7X6=   4–6=–2   0+5=5

ž  Word problems                Sally has 23 cents.             She…

ž  Algebra                      5+x=8

ž  Geometry
ž  Graphing, pre-calc
ž  Calculus          f ' (x )dx = f (b) − f (a )
                              ∫
                   Mostly builds one topic to the next.
                   Parents reinforce children phobia.
                              The Art of Number Theory
February 4, 2013                  Dr. Bob Hummel                                 4
Why do we teach these?
They are useful…
ž  Arithmetic         in daily life

ž  Word           problems are about thinking



ž  Calculus   for
      engineering



February 4, 2013              The Art of Number Theory   5
But few actually ever use higher
mathematics
ž  Riemann  Surfaces
ž  Category Theory
ž  Homotopy Theory




                   ž  Lipschitz Functions
                   ž  Riemann-Roch
                       Theorem
                   ž  Algebraic Topology
                         The Art of Number Theory
February 4, 2013             Dr. Bob Hummel         6
Some higher math ends up being
very important
ž    Riemannian geometry is the
      key to General Relativity
                    Partial Differential Equations
                    leads to Computational Fluid
                                                       Bernard Riemann
                    Dynamics, and then flight           b. 1826
                    control
                                              And number
                                               theory, and
                                                 theory of
                                            primes, leads
                                                         to
                                             cryptography

                                                                Lehmer Sieve
                             The Art of Number Theory
 February 4, 2013                Dr. Bob Hummel                                7
But the real point is to teach
logical thinking
ž  We  justify math education as
    a route to logical thinking
ž  Proofs
ž  Analysis, vice arguments
ž  Brain exercises




                    The Art of Number Theory
February 4, 2013        Dr. Bob Hummel         8
And those STEM fields benefit from
mathematical thinking
ž  Mathematics    is about analytic
    thinking
ž  Proofs
ž  Intuition: What is provable?




                      The Art of Number Theory
February 4, 2013          Dr. Bob Hummel         9
Let us think
Deeply of Simple Things
ž  Arnold         E. Ross
       —  The Ross Math Program
           ○  1957 to 2000
           ○  Dan Shapiro continues the program
       —  The Ohio State Math program
           for High School Students
       —  Based on Number Theory




                             The Art of Number Theory
February 4, 2013                 Dr. Bob Hummel         10
Outcome of the Ross Program
ž  A rather  large percentage of
      graduates became practicing
      mathematicians
       —  Also some famous physicists
ž  The            big advantage of number theory:
       —  After some basics, many topics are
           independent of one another
       —  And the basics are simple



                              The Art of Number Theory
February 4, 2013                  Dr. Bob Hummel         11
Clock Arithmetic
                              Example: 10:00 + 3hr = 1:00




                   10+3≡1 mod 12
                   10+2≡0 mod 12                  10+9=7 mod 12
                           The Art of Number Theory
February 4, 2013               Dr. Bob Hummel                     12
Clock Arithmetic with a different clock

                       7
                   6
                               1                      4:00 mod 7
                                                                      Add 5 “hours”
           5
                                   2
                                                                           7
                   4       3                                      6
                                                                                   1


                                                             5
                                                                                       2
        4+5≡2 mod 7
                                                                  4            3
       4+3≡0 mod 7
                                       The Art of Number Theory
February 4, 2013                           Dr. Bob Hummel                                  13
Addition table mod 7

                   +	
   0	
   1	
   2	
   3	
   4	
   5	
   6	
  
                   0	
   0	
   1	
   2	
   3	
   4	
   5	
   6	
  
                   1	
   1	
   2	
   3	
   4	
   5	
   6	
   0	
  
                   2	
   2	
   3	
   4	
   5	
   6	
   0	
   1	
  
                   3	
   3	
   4	
   5	
   6	
   0	
   1	
   2	
  
                   4	
   4	
   5	
   6	
   0	
   1	
   2	
   3	
  
                   5	
   5	
   6	
   0	
   1	
   2	
   3	
   4	
  
                   6	
   6	
   0	
   1	
   2	
   3	
   4	
   5	
  

                             The Art of Number Theory
February 4, 2013                 Dr. Bob Hummel                      14
But what about multiplication?

                   X	
     0	
      1	
     2	
     3	
     4	
     5	
     6	
     Examples:
                   0	
     0	
      0	
     0	
     0	
     0	
     0	
     0	
  
                   1	
     0	
      1	
     2	
     3	
     4	
     5	
     6	
     3X5≡1 mod 15
                   2	
     0	
      2	
     4	
     6	
     1	
     3	
     5	
     2X5≡3 mod 7
                   3	
     0	
      3	
     6	
     2	
     5	
     1	
     4	
  
                   4	
     0	
      4	
     1	
     5	
     2	
     6	
     3	
     5X5≡4 mod 7
                   5	
     0	
      5	
     3	
     1	
     6	
     4	
     2	
     6X6≡1 mod 7
                   6	
     0	
      6	
     5	
     4	
     3	
     2	
     1	
  

                                   The Art of Number Theory
February 4, 2013                       Dr. Bob Hummel                                             15
Under multiplication, Up is an
Abeilian Group
ž  Zp, p a prime, = {0,1,2,3,… p–1}
ž  Up, p a prime, = {1,2,3,… p–1}


ž  All  group properties inherited from R,
      except:
       —  Multiplicative inverses
ž  For  any a in Up, other than 0, find a–1
      such that a X a–1=1 mod p
                                            Z7, Z17, Z213466917–1
February 4, 2013             The Art of Number Theory               16
Greatest common divisor, also called
the greatest common factor
ž  gcd(6,9)=3
ž  gcd(55,121)=11
ž  gcd(35,49)=7
ž  In  general, a common divisor larger than
    every other common divisor
ž  a and b are “relatively prime” if gcd(a,b)=1
ž  If p is prime, then gcd(a,p)=1 unless a=np
       —  I.e., unless a ≡ 0 mod p


February 4, 2013            The Art of Number Theory   17
Diophantine Equation
ž  Given  a, b nonzero integers, find x, y
    such that ax+by=gcd(a,b)
ž  Theorem: There always exist an x and
    y, integers, that solve the Diophantine
    Equation
ž  Examples
       —  6X(-1)+9X(1)=3
       —  55X(-2)+121X(1)=11
       —  35X(3)+49X(-2)=7

February 4, 2013            The Art of Number Theory   18
A lovely math theorem
ž  LetUn = { x | gcd(x,n)=1}, under
    multiplication mod n
ž  Then Un is an Abelian Group


ž  n      a prime is a special case

ž  The            proof is constructive!



February 4, 2013                The Art of Number Theory   19
Some examples
ž  U21 = { 1, 2, 4, 5, 8, 10, 11, 13, 16, 17, 19, 20}
ž  Inverses:
    —  1, 2, 4, 5, 8, 10, 11, 13, 16, 17, 19, 20
    —  1, 11, 16, 17, 8, 19, 2, 13, 4, 5, 10, 20


ž  Check  it out
ž  How come this works?
ž  And, incidentally, this will be important for
    encryption

  February 4, 2013        The Art of Number Theory       20
Euclid’s Algorithm to find gcd’s
                   1
                                 gcd( 35, 49) = 7
        35 49
           35           2
               14      35
                       28
                             2
                                                                              b.325 BC
                        7   14

                            14
  This is the gcd                              And 1, 2, 2 are the partial quotients
                             0
                                                                1
                                             1+                         Continued fraction!
                                                        2+          1
                                                                    2

February 4, 2013                     The Art of Number Theory                                 21
Another Example
            2                                                          p=563

 230 563                                                               a=230
     460           2
          103 230                                                      2 2 4 3 2 3
              206       4
                   24 103
                                             563                         1
                       96   3                          = 2+
                       7    24               230                             1
                            21   2                               2+
                                                                                 1
                             3   7                                      4+
                                                                                      1
                                 6         3                                     3+
                                                                                           1
                                                                                      2+
                                 1         3                                               3
                                           3

                                           0                2, 5/2, 22/9, 71/29, 164/67, 563/230
February 4, 2013                     The Art of Number Theory                                  22
So, what is the inverse of 230 mod 563
                                                                        p=563
       Answer: −164 = 399
                                                                        a=230

Diophantine: – 164 · 230 + 67 · 563 = 1
                                                                        2 2 4 3 2 3



       So      (– 164) · 230 = 1 mod 563                                  1
                                                             2+
                                                                              1
       I.e., 230 – 1 = 399 mod 563                                2+
                                                                                  1
                                                                         4+
                                                                                       1
 Check: 230 · 399 = 91770 = 563 · 163 + 1                                         3+
                                                                                            1
                                                                                       2+
                                                                                            3

                                                             2, 5/2, 22/9, 71/29, 164/67, 563/230
  February 4, 2013                    The Art of Number Theory                                  23
A faster way of computing partial
quotients
                                                                         p=563
                                                                         a=230



                   2   2   4   3   2   3

 0     1       2       5   22 71 164 563
                                                                           1
 1     0       1       2    9 29 67 230                       2+
                                                                               1
                                                                   2+
                                                                                   1
                                                                          4+
                                                                                        1
                                                                                   3+
                                                                                             1
                                                                                        2+
               Inverse is either 164 or –164                                                 3

                                                              2, 5/2, 22/9, 71/29, 164/67, 563/230
February 4, 2013                       The Art of Number Theory                                  24
Fermat’s Theorem
ž  For  any a other than 0 mod p,
    a p = a mod p
ž  Equivalently
    a p–1 ≡ 1 mod p




                                               b. 1601 (or maybe 1607)




February 4, 2013    The Art of Number Theory                         25
Euler’s Theorem
ž  Generalizes          Fermat’s Theorem

           If gcd(a,n) = 1
          a φ(n) ≡ 1 mod n
           where φ(n) is the number in the set Un

                                                         b. 1707




February 4, 2013              The Art of Number Theory             26
This would seem to have little to
do with encryption
ž  After   all, the simplest encryption is a
      letter cipher:
                    A→N
                    B→O
                    C→P
                    D→Q
                     …
                    M→Z


ž  This  encryption method, indeed, any
      simple cipher, is easily broken

February 4, 2013          The Art of Number Theory   27
Public key encryption is
completely different concept
ž  I  tell you how to encrypt a message to
      me              Encryption key
                       Me                                        You



ž  You            encrypt, and send the message to
      me                      Encrypted message
                       Me                                        You



ž  Only           I know how to decrypt                               A variation allows
                                                                       one to “sign”
                       Me                                        You   messages to
                                                                       prove authentication
                            Decrypt

February 4, 2013                      The Art of Number Theory                            28
RSA Public Key encryption
ž  Uses   number theory!
ž  First, I need to tell you how to encrypt a
    message
           I choose two prime numbers, p and q

            Set N = p·q
               Choose any E such that gcd(E, (p–1)·(q–1)) = 1

                   I send you N and E

                                Me
                                                      N and E   You

February 4, 2013                  The Art of Number Theory            29
Quick Aside
ž  Finding          primes p and q is quick and easy
       —  Uses a probabilistic algorithm
       —  Works even if p and q involve hundreds of
           digits


ž  Also,          choosing an E is quick and easy




February 4, 2013              The Art of Number Theory   30
RSA Public Key encryption
ž  Next,you encrypt the message
ž  You have N and E
       —  As does everyone else
 Your message is m1, m2, m3, …                                Converted to numbers

            You compute ni ≡ miE mod N for each mi

                   You send me ni for each i

                                         ni
                         Me                                  You



February 4, 2013                  The Art of Number Theory                           31
Quick aside 2
ž  Computing xE   mod N is easy and fast, by
      repeatedly squaring




February 4, 2013      The Art of Number Theory   32
In order to decrypt, I need to use the
algorithm to find inverses
ž  Recall:         E satisfies gcd(E, (p–1)·(q–1)) = 1
ž  So   I can use the continued fraction
      algorithm to find D such that:

                   ED ≡ 1 mod (p–1)·(q–1)




February 4, 2013           The Art of Number Theory       33
And now I can decrypt the message

ž  To         decrypt: I compute

                       niD mod N for each ni
ž  Amazingly,

                      mi ≡ niD mod N for each ni

ž  But   if someone else doesn’t know D,
      they can’t decrypt

February 4, 2013             The Art of Number Theory   34
How to factor N

ž  Given    N=p·q, find p and q
ž  I.e., factorization
ž  Believed to be “hard”
ž  But no one knows for sure




February 4, 2013      The Art of Number Theory   35
So, the big outstanding question:
How to factor large numbers that are
a product of two primes?


ž  As         of right now, there is no good way

ž  There          is also no proof that it can’t be done




February 4, 2013              The Art of Number Theory      36
But if we had a quantum computer,
there is a reasonably fast way
     ž    Based on Shor’s Algorithm
            —  A probabilistic algorithm, specifically for a
                   quantum computer
     ž    Uses number theory:
                   1. Choose any a in UN (mod N)

                   2. Find r = o(a) mod N                 Smallest r such that ar ≡ 1 mod N

                   3. If r is odd, go back to 1, and try again

                   4. Compute gcd(ar/2 – 1, N), which be a divisor of N            I.e., 1, p, or q

                   5. If it is 1, then try again (at step 1)

                                            The Art of Number Theory
February 4, 2013                                Dr. Bob Hummel                                        37
Quantum Computer role in
breaking RSA
ž  Powers              of a form a periodic series:

                   a, a2, a3, a4, a5, …, ar, a, a2, … ar, a, a2, …


ž  A quantum      computer can quickly do an FFT
      to find the period of a periodic series
       —  The periodic series can be held in log2N qubits



                                    The Art of Number Theory
February 4, 2013                        Dr. Bob Hummel               38
Prognosis
ž  Bob’s          opinion:
       —  Breakthrough’s are coming too fast to
           believe there won’t be a practical quantum
           computer soon
       —  RSA will get broken, but some time later
            ○  Needs a lot of qubits
            ○  Needs control and a good programming ability
       —  Quantum computers will mostly be used to
           break RSA
            ○  And for quantum key distribution

                                The Art of Number Theory
February 4, 2013                    Dr. Bob Hummel            39
Greater prognosis
ž  Can            we get over math phobia?


  Yes, I hope so.
  Enthusiastic, energetic teachers

          Who encourage thinking deeply of simple
          things




ž  But            maybe not today
                                The Art of Number Theory
February 4, 2013                    Dr. Bob Hummel         40

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The art of number theory v7b[1]

  • 1. Dr. Bob Hummel Potomac Institute for Policy Studies hummel@PotomacInstitute.org ORCON: Ask permission before redistributing Not intended for publication
  • 2. STEM: Science, Technology, Engineering, & Mathematics ž  STEM includes mathematics ž  But when you call it STEM, do you think “mathematics”? ž  Math is at the tail end Are these people learning math? The Art of Number Theory February 4, 2013 Dr. Bob Hummel 2
  • 3. The Phenomenon of Math Phobia ž  Math is cumulative ž  For most of the math curriculum —  If you fall behind, you remain behind —  Answers in math are generally right or wrong Why do we even bother to teach math? Don’t calculators and computers obviate math? The Art of Number Theory February 4, 2013 Dr. Bob Hummel 3
  • 4. What we teach ž  Arithmetic 2+2= 7X6= 4–6=–2 0+5=5 ž  Word problems Sally has 23 cents. She… ž  Algebra 5+x=8 ž  Geometry ž  Graphing, pre-calc ž  Calculus f ' (x )dx = f (b) − f (a ) ∫ Mostly builds one topic to the next. Parents reinforce children phobia. The Art of Number Theory February 4, 2013 Dr. Bob Hummel 4
  • 5. Why do we teach these? They are useful… ž  Arithmetic in daily life ž  Word problems are about thinking ž  Calculus for engineering February 4, 2013 The Art of Number Theory 5
  • 6. But few actually ever use higher mathematics ž  Riemann Surfaces ž  Category Theory ž  Homotopy Theory ž  Lipschitz Functions ž  Riemann-Roch Theorem ž  Algebraic Topology The Art of Number Theory February 4, 2013 Dr. Bob Hummel 6
  • 7. Some higher math ends up being very important ž  Riemannian geometry is the key to General Relativity Partial Differential Equations leads to Computational Fluid Bernard Riemann Dynamics, and then flight b. 1826 control And number theory, and theory of primes, leads to cryptography Lehmer Sieve The Art of Number Theory February 4, 2013 Dr. Bob Hummel 7
  • 8. But the real point is to teach logical thinking ž  We justify math education as a route to logical thinking ž  Proofs ž  Analysis, vice arguments ž  Brain exercises The Art of Number Theory February 4, 2013 Dr. Bob Hummel 8
  • 9. And those STEM fields benefit from mathematical thinking ž  Mathematics is about analytic thinking ž  Proofs ž  Intuition: What is provable? The Art of Number Theory February 4, 2013 Dr. Bob Hummel 9
  • 10. Let us think Deeply of Simple Things ž  Arnold E. Ross —  The Ross Math Program ○  1957 to 2000 ○  Dan Shapiro continues the program —  The Ohio State Math program for High School Students —  Based on Number Theory The Art of Number Theory February 4, 2013 Dr. Bob Hummel 10
  • 11. Outcome of the Ross Program ž  A rather large percentage of graduates became practicing mathematicians —  Also some famous physicists ž  The big advantage of number theory: —  After some basics, many topics are independent of one another —  And the basics are simple The Art of Number Theory February 4, 2013 Dr. Bob Hummel 11
  • 12. Clock Arithmetic Example: 10:00 + 3hr = 1:00 10+3≡1 mod 12 10+2≡0 mod 12 10+9=7 mod 12 The Art of Number Theory February 4, 2013 Dr. Bob Hummel 12
  • 13. Clock Arithmetic with a different clock 7 6 1 4:00 mod 7 Add 5 “hours” 5 2 7 4 3 6 1 5 2 4+5≡2 mod 7 4 3 4+3≡0 mod 7 The Art of Number Theory February 4, 2013 Dr. Bob Hummel 13
  • 14. Addition table mod 7 +   0   1   2   3   4   5   6   0   0   1   2   3   4   5   6   1   1   2   3   4   5   6   0   2   2   3   4   5   6   0   1   3   3   4   5   6   0   1   2   4   4   5   6   0   1   2   3   5   5   6   0   1   2   3   4   6   6   0   1   2   3   4   5   The Art of Number Theory February 4, 2013 Dr. Bob Hummel 14
  • 15. But what about multiplication? X   0   1   2   3   4   5   6   Examples: 0   0   0   0   0   0   0   0   1   0   1   2   3   4   5   6   3X5≡1 mod 15 2   0   2   4   6   1   3   5   2X5≡3 mod 7 3   0   3   6   2   5   1   4   4   0   4   1   5   2   6   3   5X5≡4 mod 7 5   0   5   3   1   6   4   2   6X6≡1 mod 7 6   0   6   5   4   3   2   1   The Art of Number Theory February 4, 2013 Dr. Bob Hummel 15
  • 16. Under multiplication, Up is an Abeilian Group ž  Zp, p a prime, = {0,1,2,3,… p–1} ž  Up, p a prime, = {1,2,3,… p–1} ž  All group properties inherited from R, except: —  Multiplicative inverses ž  For any a in Up, other than 0, find a–1 such that a X a–1=1 mod p Z7, Z17, Z213466917–1 February 4, 2013 The Art of Number Theory 16
  • 17. Greatest common divisor, also called the greatest common factor ž  gcd(6,9)=3 ž  gcd(55,121)=11 ž  gcd(35,49)=7 ž  In general, a common divisor larger than every other common divisor ž  a and b are “relatively prime” if gcd(a,b)=1 ž  If p is prime, then gcd(a,p)=1 unless a=np —  I.e., unless a ≡ 0 mod p February 4, 2013 The Art of Number Theory 17
  • 18. Diophantine Equation ž  Given a, b nonzero integers, find x, y such that ax+by=gcd(a,b) ž  Theorem: There always exist an x and y, integers, that solve the Diophantine Equation ž  Examples —  6X(-1)+9X(1)=3 —  55X(-2)+121X(1)=11 —  35X(3)+49X(-2)=7 February 4, 2013 The Art of Number Theory 18
  • 19. A lovely math theorem ž  LetUn = { x | gcd(x,n)=1}, under multiplication mod n ž  Then Un is an Abelian Group ž  n a prime is a special case ž  The proof is constructive! February 4, 2013 The Art of Number Theory 19
  • 20. Some examples ž  U21 = { 1, 2, 4, 5, 8, 10, 11, 13, 16, 17, 19, 20} ž  Inverses: —  1, 2, 4, 5, 8, 10, 11, 13, 16, 17, 19, 20 —  1, 11, 16, 17, 8, 19, 2, 13, 4, 5, 10, 20 ž  Check it out ž  How come this works? ž  And, incidentally, this will be important for encryption February 4, 2013 The Art of Number Theory 20
  • 21. Euclid’s Algorithm to find gcd’s 1 gcd( 35, 49) = 7 35 49 35 2 14 35 28 2 b.325 BC 7 14 14 This is the gcd And 1, 2, 2 are the partial quotients 0 1 1+ Continued fraction! 2+ 1 2 February 4, 2013 The Art of Number Theory 21
  • 22. Another Example 2 p=563 230 563 a=230 460 2 103 230 2 2 4 3 2 3 206 4 24 103 563 1 96 3 = 2+ 7 24 230 1 21 2 2+ 1 3 7 4+ 1 6 3 3+ 1 2+ 1 3 3 3 0 2, 5/2, 22/9, 71/29, 164/67, 563/230 February 4, 2013 The Art of Number Theory 22
  • 23. So, what is the inverse of 230 mod 563 p=563 Answer: −164 = 399 a=230 Diophantine: – 164 · 230 + 67 · 563 = 1 2 2 4 3 2 3 So (– 164) · 230 = 1 mod 563 1 2+ 1 I.e., 230 – 1 = 399 mod 563 2+ 1 4+ 1 Check: 230 · 399 = 91770 = 563 · 163 + 1 3+ 1 2+ 3 2, 5/2, 22/9, 71/29, 164/67, 563/230 February 4, 2013 The Art of Number Theory 23
  • 24. A faster way of computing partial quotients p=563 a=230 2 2 4 3 2 3 0 1 2 5 22 71 164 563 1 1 0 1 2 9 29 67 230 2+ 1 2+ 1 4+ 1 3+ 1 2+ Inverse is either 164 or –164 3 2, 5/2, 22/9, 71/29, 164/67, 563/230 February 4, 2013 The Art of Number Theory 24
  • 25. Fermat’s Theorem ž  For any a other than 0 mod p, a p = a mod p ž  Equivalently a p–1 ≡ 1 mod p b. 1601 (or maybe 1607) February 4, 2013 The Art of Number Theory 25
  • 26. Euler’s Theorem ž  Generalizes Fermat’s Theorem If gcd(a,n) = 1 a φ(n) ≡ 1 mod n where φ(n) is the number in the set Un b. 1707 February 4, 2013 The Art of Number Theory 26
  • 27. This would seem to have little to do with encryption ž  After all, the simplest encryption is a letter cipher: A→N B→O C→P D→Q … M→Z ž  This encryption method, indeed, any simple cipher, is easily broken February 4, 2013 The Art of Number Theory 27
  • 28. Public key encryption is completely different concept ž  I tell you how to encrypt a message to me Encryption key Me You ž  You encrypt, and send the message to me Encrypted message Me You ž  Only I know how to decrypt A variation allows one to “sign” Me You messages to prove authentication Decrypt February 4, 2013 The Art of Number Theory 28
  • 29. RSA Public Key encryption ž  Uses number theory! ž  First, I need to tell you how to encrypt a message I choose two prime numbers, p and q Set N = p·q Choose any E such that gcd(E, (p–1)·(q–1)) = 1 I send you N and E Me N and E You February 4, 2013 The Art of Number Theory 29
  • 30. Quick Aside ž  Finding primes p and q is quick and easy —  Uses a probabilistic algorithm —  Works even if p and q involve hundreds of digits ž  Also, choosing an E is quick and easy February 4, 2013 The Art of Number Theory 30
  • 31. RSA Public Key encryption ž  Next,you encrypt the message ž  You have N and E —  As does everyone else Your message is m1, m2, m3, … Converted to numbers You compute ni ≡ miE mod N for each mi You send me ni for each i ni Me You February 4, 2013 The Art of Number Theory 31
  • 32. Quick aside 2 ž  Computing xE mod N is easy and fast, by repeatedly squaring February 4, 2013 The Art of Number Theory 32
  • 33. In order to decrypt, I need to use the algorithm to find inverses ž  Recall: E satisfies gcd(E, (p–1)·(q–1)) = 1 ž  So I can use the continued fraction algorithm to find D such that: ED ≡ 1 mod (p–1)·(q–1) February 4, 2013 The Art of Number Theory 33
  • 34. And now I can decrypt the message ž  To decrypt: I compute niD mod N for each ni ž  Amazingly, mi ≡ niD mod N for each ni ž  But if someone else doesn’t know D, they can’t decrypt February 4, 2013 The Art of Number Theory 34
  • 35. How to factor N ž  Given N=p·q, find p and q ž  I.e., factorization ž  Believed to be “hard” ž  But no one knows for sure February 4, 2013 The Art of Number Theory 35
  • 36. So, the big outstanding question: How to factor large numbers that are a product of two primes? ž  As of right now, there is no good way ž  There is also no proof that it can’t be done February 4, 2013 The Art of Number Theory 36
  • 37. But if we had a quantum computer, there is a reasonably fast way ž  Based on Shor’s Algorithm —  A probabilistic algorithm, specifically for a quantum computer ž  Uses number theory: 1. Choose any a in UN (mod N) 2. Find r = o(a) mod N Smallest r such that ar ≡ 1 mod N 3. If r is odd, go back to 1, and try again 4. Compute gcd(ar/2 – 1, N), which be a divisor of N I.e., 1, p, or q 5. If it is 1, then try again (at step 1) The Art of Number Theory February 4, 2013 Dr. Bob Hummel 37
  • 38. Quantum Computer role in breaking RSA ž  Powers of a form a periodic series: a, a2, a3, a4, a5, …, ar, a, a2, … ar, a, a2, … ž  A quantum computer can quickly do an FFT to find the period of a periodic series —  The periodic series can be held in log2N qubits The Art of Number Theory February 4, 2013 Dr. Bob Hummel 38
  • 39. Prognosis ž  Bob’s opinion: —  Breakthrough’s are coming too fast to believe there won’t be a practical quantum computer soon —  RSA will get broken, but some time later ○  Needs a lot of qubits ○  Needs control and a good programming ability —  Quantum computers will mostly be used to break RSA ○  And for quantum key distribution The Art of Number Theory February 4, 2013 Dr. Bob Hummel 39
  • 40. Greater prognosis ž  Can we get over math phobia? Yes, I hope so. Enthusiastic, energetic teachers Who encourage thinking deeply of simple things ž  But maybe not today The Art of Number Theory February 4, 2013 Dr. Bob Hummel 40