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IT2001PA
Engineering Essentials (1/2)


Chapter 6 – Power, Energy and Efficiency

 Lecturer Name
lecturer_email@ite.edu.sg
                              Aug 16, 2012
Contact Number
Chapter 6 – Power, Energy and Efficiency


Lesson Objectives
Upon completion of this topic, you should be able to:
   Calculate power and energy in electrical circuits..




    IT2001PA Engineering Essentials (1/2)                 2
Chapter 6 – Power, Energy and Efficiency


Specific Objectives
  1.       State the units for :
             Quantity of electricity
             Energy
             Power
  2.       Establish the following equations :
            Q=Ixt
            E=Pxt
  3.       Establish the following equations of power
            P = I2 x R = V2/R = V x I

    IT2001PA Engineering Essentials (1/2)               3
Chapter 6 – Power, Energy and Efficiency


 Specific Objectives
4.   Solve simple problems involving a maximum of three
     resistors relating to :
        Quantity of electricity
        Electrical energy
        Electrical power
4.   Calculate energy consumption of an electrical load in
     kWh.
5.   Calculate the cost of energy consumed by an electrical
     load for a given power and time.
6.   Convert the unit from kWh to Joules and vice versa.

     IT2001PA Engineering Essentials (1/2)                    4
Chapter 6 – Power, Energy and Efficiency


Units

          Recall
          units
                          Unit of Voltage :   Volts (v)

                          Unit of Current :   Ampere
                           (A)

                          Unit of Resistance : Ohms
                           (Ω)



    IT2001PA Engineering Essentials (1/2)                  5
Chapter 6 – Power, Energy and Efficiency


Units

    Unit of Charge: Coulomb (Q)

    Unit of Energy :        Joules (J)

    Unit of Power :        Watts or J/s (W)




     IT2001PA Engineering Essentials (1/2)     6
Chapter 6 – Power, Energy and Efficiency


Alternative Unit for Energy
   Energy (Joules, J) can also be expressed in kilowatt-
    hours (kWh).

    1 kWh = 1000 Watt-hours
             = 1000 x 3600 watt-seconds     Watt-seconds=Joules
             = 3,600,000 Joules
             = 3.6 MJ




    IT2001PA Engineering Essentials (1/2)                7
Chapter 6 – Power, Energy and Efficiency


What is Energy

    Energy is ability or capacity for doing work.

    Work cannot be done without energy being used.

    Mechanical, electrical and heat energy are all
     measured in joules (J)




     IT2001PA Engineering Essentials (1/2)            8
Chapter 6 – Power, Energy and Efficiency


Energy
   Energy may exist in several forms and may be
    changed from one form to another.
   A lead-acid cell changes chemical energy to electrical
    energy on discharge and vice-versa on charge.
   A generator changes mechanical energy to electrical
    energy;
   An electric radiator converts electrical energy to heat
    energy, and etc



    IT2001PA Engineering Essentials (1/2)              9
Chapter 6 – Power, Energy and Efficiency


What is Energy
     When current passes through a resistance, the
      collisions of the electrons gives off heat, a form of
      energy.



                                              heat produced by
                                               current through
                                                  resistance
                                                is energy loss
                                VS
                            +    -

      IT2001PA Engineering Essentials (1/2)                      10
Chapter 6 – Power, Energy and Efficiency


What is Energy
    Heat energy produced in the resistor is proportional
     to :


       a)   square of the current - I 2
       b)   resistance of the resistor -     R
       c)   duration of time       - t in seconds


                 Energy = I2Rt joules
                            = Power x Time


     IT2001PA Engineering Essentials (1/2)           11
Chapter 6 – Power, Energy and Efficiency


Cost of Energy
   The cost of electrical energy is calculated by
    multiplying the number of units of energy consumed in
    kWh and the cost per unit.


            1 unit = 1 kWh




    IT2001PA Engineering Essentials (1/2)           12
Chapter 6 – Power, Energy and Efficiency


Example 6-1 (Cost of Energy)
A colour television rated at 1600 W operates for 5 hours
  a day for 30 days.
    (a) What is the total energy consumed?
    (b) What is the monthly consumption cost if the cost per
      unit is 18 cents?

    Solution :
    (a) Energy = 1600 x 5 x 30 = 240 kWh
    (b) cost = 240 x $ 0.18 = $ 43.2


    IT2001PA Engineering Essentials (1/2)                13
Chapter 6 – Power, Energy and Efficiency


What is Electrical Power?
    Power is the rate of doing work.

    Power is measured by how fast energy is
     being used.

    Power = work done in joules/time taken in
     seconds

    One watt of power is obtained when a
     current of one ampere passes through a
     potential difference of one volt.

                   Unit: J / s or watts

     IT2001PA Engineering Essentials (1/2)       14
Chapter 6 – Power, Energy and Efficiency




               Low power
               consumption


                           High power
                          consumption




    IT2001PA Engineering Essentials (1/2)   15
Chapter 6 – Power, Energy and Efficiency


Equations of Power
    As power is work done per sec therefore
                  P =                IR2t
                                       t


                   P = I2R
                  P=         V   2
                                     R =    V2
                                                 Ohm’s law
                             R              R
                                                  I = V/ R
                                                  R = V/ I
                    = I
                       2     V          =   VI
                             I




     IT2001PA Engineering Essentials (1/2)                   16
Chapter 6 – Power, Energy and Efficiency


Total Power

       The total power for both series and parallel circuits,
       is equal to the sum of the powers in each resistor :

                 PT = P1 + P2 + P3 + … … + Pn




    IT2001PA Engineering Essentials (1/2)                   17
Chapter 6 – Power, Energy and Efficiency


Comparison

                    SERIES                       PARALLEL
          IT = I1 = I2 = I3 = … =   In   IT = I 1 + I 2 + I 3 + … + I n
          VS = V1 + V2 + V3 + … + Vn     VS = V1 = V2 = V3 = … = Vn

         RT = R1 + R2 + R3 + … + Rn      1        1        1     1      1
                                              =        +        +    …+
                                         RT       R1       R2   R3    Rn
                        PT = P1 + P2 + P3 + … … + Pn




    IT2001PA Engineering Essentials (1/2)                                   18
Chapter 6 – Power, Energy and Efficiency


Efficiency
   The efficiency of an electric circuit is the ratio of output to
    the input expressed in percentage. It is symbolized by η.
   Efficiency of electric circuit,




   Output power is always smaller than input due to losses 
       Efficiency is always < 100%



    IT2001PA Engineering Essentials (1/2)                      19
Chapter 6 – Power, Energy and Efficiency


Problem Solving



      Power
      Calculations




    IT2001PA Engineering Essentials (1/2)   20
Chapter 6 – Power, Energy and Efficiency


Example 6-2 (Efficiency)
The output of a generator is 1500W and the input is
  equivalent to 1900W.
Calculate its percentage efficiency.


              η= (1500/1900)x100 = 78.9%




    IT2001PA Engineering Essentials (1/2)             21
Chapter 6 – Power, Energy and Efficiency


Example 6-3

        Calculate the total power consumed by the circuit
         below (i.e. the power dissipated in R).


                      Vs +
                                                 R
                                                       R=20Ω
                     60V
                           -



        Power dissipated in R
                                     V2     602V2
                               P =        =       = 180W
                                     R       20Ω




       IT2001PA Engineering Essentials (1/2)                   22
Chapter 6 – Power, Energy and Efficiency




   Example 6-3
   … cont”d


                   Vs                         R
                  60V                       20Ω

                           V    60V
                     I =     =      = 3A
                           R   20Ω

                 Power dissipated in R
                 P = I2 x R = 32A x 20Ω = 180W




    IT2001PA Engineering Essentials (1/2)         23
Chapter 6 – Power, Energy and Efficiency


Example 6-4

       Calculate the power dissipated in R1 , R2 and
        the total power consumed by the circuit below.


                           R1 = 10Ω    R2 = 20Ω




                                 +      -
                                  VS = 60V




    IT2001PA Engineering Essentials (1/2)                24
Chapter 6 – Power, Energy and Efficiency




   Example 6-4
   …….cont”d
                         R1 = 10Ω    R2 = 20Ω




                                +     -
                                VS = 60V
                    RT = R1 + R2 = 10Ω + 20Ω = 30 Ω
                    IT = VS = 60V = 2A
                         RT    30Ω




    IT2001PA Engineering Essentials (1/2)             25
Chapter 6 – Power, Energy and Efficiency




  Example 6-
  4
  ….cont”d                   R1 = 10Ω    R2 = 20Ω



                                    +    -

                                    VS = 60V
           Power dissipated in R1
                     P1 = IT2 x R1 = 22A2 x 10Ω     = 40W
           Power dissipated in R2
                     P2 = IT2 x R2 = 22A2 x 20Ω     = 80W




    IT2001PA Engineering Essentials (1/2)                   26
Chapter 6 – Power, Energy and Efficiency




Example 6-4
….. Cont”d
                     R1 = 10Ω    R2 = 20Ω




                            +     -
                            VS = 60V

              Total power dissipated
              PT = IT x VS = 2A x 60V = 120W
            or PT = P1 + P2 = 40W + 80W = 120W




    IT2001PA Engineering Essentials (1/2)        27
Chapter 6 – Power, Energy and Efficiency


Example 6-5

      Calculate the power dissipated in R1 , R2 and the
       total power consumed by the circuit below.

                        +
                    VS           R1          R2
                   60V -       10Ω         20Ω




    IT2001PA Engineering Essentials (1/2)             28
Chapter 6 – Power, Energy and Efficiency




Example 6-5
…. Cont”d

                  VS +          R1         R2
                 60V -        10Ω        20Ω


                   Power dissipated in R1
                         V1 2    VS2      602V2    = 360W
                   P1 =       =        = 10Ω
                         R1      R1
                   Power dissipated in R2
                         V22      VS 2     602V2
                   P2 =       =        =           = 180W
                         R2      R2       20Ω



    IT2001PA Engineering Essentials (1/2)                   29
Chapter 6 – Power, Energy and Efficiency




  Example 6-5
           c
            o            +         R1         R2
            n         VS
                                 10Ω        20Ω
            t        60V -
            i
            n             R1 x R 2    10Ω x 20Ω
            u     RT =              =           = 6.67 Ω
                         R1 + R 2     10Ω + 20Ω
            e
                  Total power dissipated
                            VS 2        602V2
            …      PT =           =
                            RT         6.67Ω = 540W
            .O   PT = P1 + P2 = 360W + 180W = 540W
            .R
            .

    IT2001PA Engineering Essentials (1/2)                  30
Chapter 6 – Power, Energy and Efficiency


Next Lesson




    IT2001PA Engineering Essentials (1/2)   31

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Ee1 chapter6 power_energy&efficiency

  • 1. IT2001PA Engineering Essentials (1/2) Chapter 6 – Power, Energy and Efficiency Lecturer Name lecturer_email@ite.edu.sg Aug 16, 2012 Contact Number
  • 2. Chapter 6 – Power, Energy and Efficiency Lesson Objectives Upon completion of this topic, you should be able to:  Calculate power and energy in electrical circuits.. IT2001PA Engineering Essentials (1/2) 2
  • 3. Chapter 6 – Power, Energy and Efficiency Specific Objectives 1. State the units for :  Quantity of electricity  Energy  Power 2. Establish the following equations :  Q=Ixt  E=Pxt 3. Establish the following equations of power  P = I2 x R = V2/R = V x I IT2001PA Engineering Essentials (1/2) 3
  • 4. Chapter 6 – Power, Energy and Efficiency Specific Objectives 4. Solve simple problems involving a maximum of three resistors relating to :  Quantity of electricity  Electrical energy  Electrical power 4. Calculate energy consumption of an electrical load in kWh. 5. Calculate the cost of energy consumed by an electrical load for a given power and time. 6. Convert the unit from kWh to Joules and vice versa. IT2001PA Engineering Essentials (1/2) 4
  • 5. Chapter 6 – Power, Energy and Efficiency Units Recall units  Unit of Voltage : Volts (v)  Unit of Current : Ampere (A)  Unit of Resistance : Ohms (Ω) IT2001PA Engineering Essentials (1/2) 5
  • 6. Chapter 6 – Power, Energy and Efficiency Units  Unit of Charge: Coulomb (Q)  Unit of Energy : Joules (J)  Unit of Power : Watts or J/s (W) IT2001PA Engineering Essentials (1/2) 6
  • 7. Chapter 6 – Power, Energy and Efficiency Alternative Unit for Energy  Energy (Joules, J) can also be expressed in kilowatt- hours (kWh). 1 kWh = 1000 Watt-hours = 1000 x 3600 watt-seconds Watt-seconds=Joules = 3,600,000 Joules = 3.6 MJ IT2001PA Engineering Essentials (1/2) 7
  • 8. Chapter 6 – Power, Energy and Efficiency What is Energy  Energy is ability or capacity for doing work.  Work cannot be done without energy being used.  Mechanical, electrical and heat energy are all measured in joules (J) IT2001PA Engineering Essentials (1/2) 8
  • 9. Chapter 6 – Power, Energy and Efficiency Energy  Energy may exist in several forms and may be changed from one form to another.  A lead-acid cell changes chemical energy to electrical energy on discharge and vice-versa on charge.  A generator changes mechanical energy to electrical energy;  An electric radiator converts electrical energy to heat energy, and etc IT2001PA Engineering Essentials (1/2) 9
  • 10. Chapter 6 – Power, Energy and Efficiency What is Energy  When current passes through a resistance, the collisions of the electrons gives off heat, a form of energy. heat produced by current through resistance is energy loss VS + - IT2001PA Engineering Essentials (1/2) 10
  • 11. Chapter 6 – Power, Energy and Efficiency What is Energy  Heat energy produced in the resistor is proportional to : a) square of the current - I 2 b) resistance of the resistor - R c) duration of time - t in seconds Energy = I2Rt joules = Power x Time IT2001PA Engineering Essentials (1/2) 11
  • 12. Chapter 6 – Power, Energy and Efficiency Cost of Energy  The cost of electrical energy is calculated by multiplying the number of units of energy consumed in kWh and the cost per unit. 1 unit = 1 kWh IT2001PA Engineering Essentials (1/2) 12
  • 13. Chapter 6 – Power, Energy and Efficiency Example 6-1 (Cost of Energy) A colour television rated at 1600 W operates for 5 hours a day for 30 days. (a) What is the total energy consumed? (b) What is the monthly consumption cost if the cost per unit is 18 cents? Solution : (a) Energy = 1600 x 5 x 30 = 240 kWh (b) cost = 240 x $ 0.18 = $ 43.2 IT2001PA Engineering Essentials (1/2) 13
  • 14. Chapter 6 – Power, Energy and Efficiency What is Electrical Power?  Power is the rate of doing work.  Power is measured by how fast energy is being used.  Power = work done in joules/time taken in seconds  One watt of power is obtained when a current of one ampere passes through a potential difference of one volt. Unit: J / s or watts IT2001PA Engineering Essentials (1/2) 14
  • 15. Chapter 6 – Power, Energy and Efficiency Low power consumption High power consumption IT2001PA Engineering Essentials (1/2) 15
  • 16. Chapter 6 – Power, Energy and Efficiency Equations of Power  As power is work done per sec therefore P = IR2t t P = I2R P= V 2 R = V2 Ohm’s law R R I = V/ R R = V/ I = I 2 V = VI I IT2001PA Engineering Essentials (1/2) 16
  • 17. Chapter 6 – Power, Energy and Efficiency Total Power  The total power for both series and parallel circuits, is equal to the sum of the powers in each resistor : PT = P1 + P2 + P3 + … … + Pn IT2001PA Engineering Essentials (1/2) 17
  • 18. Chapter 6 – Power, Energy and Efficiency Comparison SERIES PARALLEL IT = I1 = I2 = I3 = … = In IT = I 1 + I 2 + I 3 + … + I n VS = V1 + V2 + V3 + … + Vn VS = V1 = V2 = V3 = … = Vn RT = R1 + R2 + R3 + … + Rn 1 1 1 1 1 = + + …+ RT R1 R2 R3 Rn PT = P1 + P2 + P3 + … … + Pn IT2001PA Engineering Essentials (1/2) 18
  • 19. Chapter 6 – Power, Energy and Efficiency Efficiency  The efficiency of an electric circuit is the ratio of output to the input expressed in percentage. It is symbolized by η.  Efficiency of electric circuit,  Output power is always smaller than input due to losses   Efficiency is always < 100% IT2001PA Engineering Essentials (1/2) 19
  • 20. Chapter 6 – Power, Energy and Efficiency Problem Solving Power Calculations IT2001PA Engineering Essentials (1/2) 20
  • 21. Chapter 6 – Power, Energy and Efficiency Example 6-2 (Efficiency) The output of a generator is 1500W and the input is equivalent to 1900W. Calculate its percentage efficiency. η= (1500/1900)x100 = 78.9% IT2001PA Engineering Essentials (1/2) 21
  • 22. Chapter 6 – Power, Energy and Efficiency Example 6-3  Calculate the total power consumed by the circuit below (i.e. the power dissipated in R). Vs + R R=20Ω 60V - Power dissipated in R V2 602V2 P = = = 180W R 20Ω IT2001PA Engineering Essentials (1/2) 22
  • 23. Chapter 6 – Power, Energy and Efficiency Example 6-3 … cont”d Vs R 60V 20Ω V 60V I = = = 3A R 20Ω Power dissipated in R P = I2 x R = 32A x 20Ω = 180W IT2001PA Engineering Essentials (1/2) 23
  • 24. Chapter 6 – Power, Energy and Efficiency Example 6-4  Calculate the power dissipated in R1 , R2 and the total power consumed by the circuit below. R1 = 10Ω R2 = 20Ω + - VS = 60V IT2001PA Engineering Essentials (1/2) 24
  • 25. Chapter 6 – Power, Energy and Efficiency Example 6-4 …….cont”d R1 = 10Ω R2 = 20Ω + - VS = 60V RT = R1 + R2 = 10Ω + 20Ω = 30 Ω IT = VS = 60V = 2A RT 30Ω IT2001PA Engineering Essentials (1/2) 25
  • 26. Chapter 6 – Power, Energy and Efficiency Example 6- 4 ….cont”d R1 = 10Ω R2 = 20Ω + - VS = 60V Power dissipated in R1 P1 = IT2 x R1 = 22A2 x 10Ω = 40W Power dissipated in R2 P2 = IT2 x R2 = 22A2 x 20Ω = 80W IT2001PA Engineering Essentials (1/2) 26
  • 27. Chapter 6 – Power, Energy and Efficiency Example 6-4 ….. Cont”d R1 = 10Ω R2 = 20Ω + - VS = 60V Total power dissipated PT = IT x VS = 2A x 60V = 120W or PT = P1 + P2 = 40W + 80W = 120W IT2001PA Engineering Essentials (1/2) 27
  • 28. Chapter 6 – Power, Energy and Efficiency Example 6-5  Calculate the power dissipated in R1 , R2 and the total power consumed by the circuit below. + VS R1 R2 60V - 10Ω 20Ω IT2001PA Engineering Essentials (1/2) 28
  • 29. Chapter 6 – Power, Energy and Efficiency Example 6-5 …. Cont”d VS + R1 R2 60V - 10Ω 20Ω Power dissipated in R1 V1 2 VS2 602V2 = 360W P1 = = = 10Ω R1 R1 Power dissipated in R2 V22 VS 2 602V2 P2 = = = = 180W R2 R2 20Ω IT2001PA Engineering Essentials (1/2) 29
  • 30. Chapter 6 – Power, Energy and Efficiency Example 6-5  c o + R1 R2 n VS 10Ω 20Ω t 60V - i n R1 x R 2 10Ω x 20Ω u RT = = = 6.67 Ω R1 + R 2 10Ω + 20Ω e Total power dissipated VS 2 602V2 … PT = = RT 6.67Ω = 540W .O PT = P1 + P2 = 360W + 180W = 540W .R . IT2001PA Engineering Essentials (1/2) 30
  • 31. Chapter 6 – Power, Energy and Efficiency Next Lesson IT2001PA Engineering Essentials (1/2) 31