4. r n −2
n∑ X 1 X 2 − (∑ X 1 )(∑ X 2 ) thitung = =
r12 = = 0.82 1 −r 2
{n∑ X 12 − (∑ X 1 )2 }{n∑ X 2 − (∑ X 2 )2 }
2
R pembilang = 0.16
R penyebut = 0.33
2
R x1 x 2 y
0.702024
ry21 + ry22 − 2ry1ry 2 r12 0.7 Fhitung = k = 2
Ry.12 = = (1 − R x1 x 2 y ) /( n − k −1) 1 − (0.702024 )
2 2
1 − r12
2
2
Korelasi Parsial
rx 2 y − rx1 y .rx1x 2
rx1( x 2 y ) = = -0.03
(1 − r )(1 − r
2
x1 y
2
x1 x 2 )
rx1 y − rx 2 y .rx1x 2 0,702 - (0,564).(0,820))
rx 2 ( x1 y ) = = =
(1 − r 2
x2 y )(1 − r 2
x1 x 2 ) 2
(1 - (0,564) (1 - (0,820) ) 2
5. X1.X2
8640
8580
8848
9200
10890
10680
8162
7904
8658
8316
8502
8848
8736
9440
7140
6968
6890
6825
8580
8162
169969
169969
604.81
169969
28889460961
r n −2
hitung = = 4.18
1 −r 2
r n −2
t hitung = = 2.9
1 −r 2
r n −2
thitung = =
1 −r 2
6. r n −2 6.07
thitung = =
1 −r 2
2y
0.702024
= 2 = 8.26
( n − k −1) 1 − (0.702024 ) 2
20 − 2 −1
r n −2 -0.11
thitung = =
1 −r 2
r n −2
0.51 thitung = = 2.49
1 −r 2
7. Perhitungan Persamaan Regresi Tabel Bantu Uji Per
No X Y X.Y X^2 Y^2 X
1 108 6.25 675 11664 39.06 102
2 110 4.5 495 12100 20.25 104
3 112 6.5 728 12544 42.25 104
4 115 5.75 661.25 13225 33.06 105
5 121 7.25 877.25 14641 52.56 106
6 120 6.5 780 14400 42.25 106
7 106 5 530 11236 25 106
8 104 5.25 546 10816 27.56 108
9 111 4.75 527.25 12321 22.56 108
10 108 5 540 11664 25 109
11 109 4 436 11881 16 110
12 112 6 672 12544 36 110
13 112 5.75 644 12544 33.06 111
14 118 6 708 13924 36 112
15 102 4.25 433.5 10404 18.06 112
16 104 4.5 468 10816 20.25 112
17 106 5.75 609.5 11236 33.06 115
18 105 5.25 551.25 11025 27.56 118
19 110 5.5 605 12100 30.25 120
20 106 8 848 11236 64 121
2199 111.75 12335 242321 643.81
∑X = 2199 ∑Y= 111.75 ∑XY= 12335
242321
∑X2 = ∑Y2 = 643.81
(∑X )2 ### (∑Y)2 = 12488.06 109.95
(∑Yi )(∑ X i2 ) − (∑ X i )(∑ X i Yi ) -4.19
a= =
n ∑ X − (∑ X i )
i
2 2
n∑ X i Yi − (∑ X i )(∑Yi ) 0.09
b= =
n∑ X − (∑ X i )
i
2 2
Persamaan Regresinya : Y= -4.19 Plus 0.09 X