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Reactions of Aldehydes  and  Ketones
[object Object],[object Object],[object Object],[object Object],[object Object],Reactions  of Aldehydes  and  ketones
[object Object],[object Object],[object Object]
Sodium Borohydride Reduction  Of Aldehydes and Ketones - workup step alcohol aldehyde and ketones workup step H BH 3
ADDITION IS  CONCERTED   AND  SYN   STEREOSPECIFIC reacts three more times
[object Object],These are both strong nucleophiles. secondary alcohols
LITHIUM ALUMINUM HYDRIDE REDUCTIONS
LiAlH 4  reduces anything with a  polar  multiple bond! aldehyde ketone LiAlH 4  (LAH) IS NOT SELECTIVE As with NaBH 4  these compounds give alcohols: C=Y:   or C  Y:   ..
Under acidic conditions,  weaker  nucleophiles such as water and alcohols can add. The carbonyl group is a weak base, and in acidic solution it can become protonated.
This makes the carbon very electrophilic (see resonance structures), and so it will react with poor nucleophiles. E.g. the acid catalyzed nucleophilic addition of water to acetone to produce the acetone hydrate.
Summary The base catalyzed addition reactions to carbonyl compounds result from initial attack of a strong nucleophile, whereas the acid catalyzed reactions begin with the protonation of the oxygen, followed by attack of the weaker nucleophile.
Aldehydes are more reactive than ketones.  This (like all things) stems from two factors: (1) electronics (2) sterics   Relative Reactivity
Electronic Effect Ketones have two alkyl substituents whereas aldehydes only have one. Carbonyl compounds undergo reaction with nucleophiles because of the polarization of the C=O bond.
Alkyl groups are electron donating, and so ketones have their effective partial positive charge reduced more than aldehydes (two alkyl substituents vs. one alkyl substituent).   ( Aldehydes  more reactive than ketones)
Steric Reason  ,[object Object],[object Object],[object Object],[object Object],[object Object]
Nucleophilic Addition of Water (Hydration) In aqueous solution, ketones (and aldehydes) are in equilibrium with their hydrates (gem diols).
Most ketones have the equilibrium in favor of the unhydrated form. Hydration proceeds through the two classic nucleophilic addition mechanisms with water (in acid) or hydroxide (in base) acting as the nucleophile.
(Acid)
(Base)
Aldehydes are more likely to form hydrates since they have the larger partial positive charge on the carbonyl carbon (larger charge = less stable = more reactive).   This is borne out by the following equilibrium constants .
 
Nucleophilic Addition of Hydrogen Cyanide (Cyanohydrins) Hydrogen cyanide is toxic volatile liquid (b.p.26°C)  H-CN   +   H 2 O     H 3 O +   +   - CN  pK a  = 9.2 Cyanide is a strong base (HCN weak acid) and a good nucleophile. Cyanide reacts rapidly with carbonyl compounds producing cyanohydrins, via the base catalyzed nucleophilic addition mechanism.
Like hydrate formation, cyanohydrin formation is an equilibrium governed reaction (i.e. reversible reaction), and accordingly aldehydes are more reactive than ketones.
Formation of Imines (Condensation Reactions) Under appropriate conditions, primary amines (and ammonia) react with ketones or aldehydes to generate imines.
[object Object],[object Object],[object Object],[object Object]
The mechanism of imine formation starts with the basic addition of the amine to the carbonyl group. Protonation of the oxyanion and deprotonation of the nitrogen cation generates an unstable intermediate called  a carbinolamine.
The carbinolamine has its oxygen protonated, and then water acts as the good leaving group.
[object Object],[object Object],[object Object],[object Object],[object Object]
Condensations with Hydroxylamines and Hydrazines   ,[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object]
Oxidation  ,[object Object],Even weak oxidants like silver (I) oxide can perform this reaction, and this is a good, mild selective way to prepare carboxylic acids in the presence of other (oxidizable) functionalities.  E.g.
Oxidation  (Could not use permanganate, etc for this transformation).
Silver Mirror Test (Tollen's Test) This type of oxidation reaction is the basis of the most common chemical test for aldehydes - the Silver Mirror Test. Tollen's reagent is added to an unknown compound, and if an aldehyde is present, it is oxidized. R-CHO + 2Ag(NH 3 ) 2 + +   3OH -    2Ag + RCO 2 - +   4NH 3 + 2H 2 O   This process reduces the Ag +  to Ag, and the Ag precipitates - it sticks to the flask wall, and forms a 'silver mirror'.
Reduction of Ketone and Aldehydes Aldehydes and ketones are most commonly reduced by sodium borohydride.   NaBH 4  reduces ketones to secondary alcohols, and aldehydes to primary alcohols.   Other Reductions Catalytic Hydrogenation Just as C=C double bonds can be reduced by the addition of hydrogen across the double bond, so can C=O double bonds.
Reduction of Ketone and Aldehydes Carbonyl double bonds are reduced much more slowly than alkene double bonds. Therefore, you cannot reduce a C=O in the presence of a C=C without reducing both (by this method).  E.g. The most common catalyst for these hydrogenations is Raney nickel, although Pt and Rh can also be used.
Deoxygenation of Ketones and Aldehydes  Deoxygenation involves the removal of oxygen, and its replacement with two hydrogen atoms. This reduction takes the carbonyl (past the alcohol) to a methylene group. Compare the following reduction processes:
Deoxygenation of Ketones and Aldehydes
Clemmensen Reduction (recap?) This was used in the reduction of acyl benzenes into alkyl benzenes, but it also works for other aldehydes and ketones.  E.g.
Wolff-Kishner Sometimes the acidic conditions used in the Clemmensen reduction are unsuitable for a given molecule. In these cases, Wolff-Kishner reduction is employed. The ketone or aldehyde is converted to its hydrazone (by reaction with hydrazine) and is then treated with a strong base, which generates the reduced product, for example:
Wolff-Kishner The mechanism of hydrazone formation is analogous to imine formation. The strongly basic conditions then deprotonate the hydrazone, and the anion produced is resonance stabilized.
Wolff-Kishner The carbanionic form picks up a proton, and another deprotonation of the nitrogen generates an intermediate which is set up to eliminate a molecule of nitrogen (N 2 ) and produce a carbanion.
Wolff-Kishner This carbanion is quickly protonated, giving the final reduced product.
Formation of Acetals  (Addition of Alcohols) In a similar fashion to the formation of hydrates with water, aldehydes and ketones form acetals through reaction with alcohols. In the formation of an acetal, two molecules of alcohol add to the carbonyl group, and one mole of water is eliminated. Acetal formation only occurs with acid catalysis.
Mechanism of Acetal Formation  The first step is the typical acid catalyzed addition to the carbonyl group.
The hemiacetal reacts further to produce the more stable acetal: The second half of the mechanism starts with protonation of the hydroxyl group, followed by its leaving.
The carbocation thus generated is resonance stabilized, and attack of the alcohol, after proton loss, produces the final acetal.   The second step (and therefore overall transformation) requires the acidic conditions to aid the replacement of  the hydroxyl group (-OH is a bad leaving group, yet -OH 2 + ) is a good leaving group.
Cyclic Acetals More commonly, instead of two molecules of alcohols being used, a diol is used (entropically more favorable). This produces cyclic acetals. E.g. 1,2-Ethanediol (ethylene glycol) is usually the diol of choice, and the products are called ethylene acetals. (Dithiane is a sulfur analogue of a cyclic acetal).
Acetals as Protecting Groups Acetals will hydrolyze under acidic conditions, but are stable to strong bases and nucleophiles. They are also easily formed from aldehydes and ketones, and also easily converted back to the parent carbonyl compounds. These characteristics make acetals ideal protecting groups for aldehydes and ketones.   They can be used to 'protect' aldehydes and ketones from reacting with strong bases and nucleophiles.
Consider the strategy to prepare the following compound: We might decide to use the Grignard reaction as shown above. However, having a  Grignard  functionality and an  aldehyde  in the same molecule is bad news since they will react with one another. The strategy is still okay, we just need to 'protect' the aldehyde as some unreactive group - an acetal. The acetal group is unreactive towards Grignard reagents (strong nucleophiles), and therefore this would be a viable reagent .
The "masked" aldehyde can be safely converted to the Grignard reagent, and then this can react with cyclohexanone   The acetal is easily removed with acidic hydrolysis (which is also required to remove the MgBr +  from the oxyanion), giving the final product.
Selective Acetal Formation   We have previously seen that aldehydes are more reactive than ketones (two reasons), and therefore aldehydes will react to form acetals preferentially over ketones. This means we can selectively protect aldehydes in the presence of ketones. (Remember to use only 1 equivalent!) E.g.
This is a useful way to perform reactions on ketone functionalities in molecules that contain both aldehyde and ketone groups.   (To selectively do reactions on the aldehyde, just do them!)
Other Reactions of Carbonyl Compounds   ,[object Object],In 1954 Wittig discovered that the addition of a phosphorus stabilized anion to a carbonyl compound did not generate an alcohol, but an alkene! (Nobel prize in 1979).
The phosphorus stabilized anion is called an YLIDE, which is a molecule that is overall neutral, but exists as a carbanion bound to a positively charged heteroatom. Wittig Reaction
Phosphorus ylides are produced from the reaction of triphenylphosphine and alkyl halides. base
[object Object],[object Object],[object Object]
The double bond resonance form requires 10 electrons around the P atom. This is achievable through use of its d electrons (3 rd  row element), but the    bond to carbon is weak, and this is only a minor contributor. The  carbanionic  character of the ylide makes it a very powerful nucleophile, and so it reacts rapidly with a carbonyl group. This produces an intermediate which has charge separation - a betaine.
 
 
[object Object],[object Object],[object Object],[object Object],[object Object]
Wittig Strategy By dividing a target molecule at the double bond, you can decide which of the two components should best come from the carbonyl, and which from the ylide.
In general, the ylide should come from an unhindered alkyl halide since triphenyl phosphine is so bulky. For Example:-

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Carbonyl Compounds 2

  • 2.
  • 3.
  • 4. Sodium Borohydride Reduction Of Aldehydes and Ketones - workup step alcohol aldehyde and ketones workup step H BH 3
  • 5. ADDITION IS CONCERTED AND SYN STEREOSPECIFIC reacts three more times
  • 6.
  • 8. LiAlH 4 reduces anything with a polar multiple bond! aldehyde ketone LiAlH 4 (LAH) IS NOT SELECTIVE As with NaBH 4 these compounds give alcohols: C=Y:   or C Y:   ..
  • 9. Under acidic conditions, weaker nucleophiles such as water and alcohols can add. The carbonyl group is a weak base, and in acidic solution it can become protonated.
  • 10. This makes the carbon very electrophilic (see resonance structures), and so it will react with poor nucleophiles. E.g. the acid catalyzed nucleophilic addition of water to acetone to produce the acetone hydrate.
  • 11. Summary The base catalyzed addition reactions to carbonyl compounds result from initial attack of a strong nucleophile, whereas the acid catalyzed reactions begin with the protonation of the oxygen, followed by attack of the weaker nucleophile.
  • 12. Aldehydes are more reactive than ketones.  This (like all things) stems from two factors: (1) electronics (2) sterics Relative Reactivity
  • 13. Electronic Effect Ketones have two alkyl substituents whereas aldehydes only have one. Carbonyl compounds undergo reaction with nucleophiles because of the polarization of the C=O bond.
  • 14. Alkyl groups are electron donating, and so ketones have their effective partial positive charge reduced more than aldehydes (two alkyl substituents vs. one alkyl substituent).   ( Aldehydes more reactive than ketones)
  • 15.
  • 16. Nucleophilic Addition of Water (Hydration) In aqueous solution, ketones (and aldehydes) are in equilibrium with their hydrates (gem diols).
  • 17. Most ketones have the equilibrium in favor of the unhydrated form. Hydration proceeds through the two classic nucleophilic addition mechanisms with water (in acid) or hydroxide (in base) acting as the nucleophile.
  • 20. Aldehydes are more likely to form hydrates since they have the larger partial positive charge on the carbonyl carbon (larger charge = less stable = more reactive).   This is borne out by the following equilibrium constants .
  • 21.  
  • 22. Nucleophilic Addition of Hydrogen Cyanide (Cyanohydrins) Hydrogen cyanide is toxic volatile liquid (b.p.26°C) H-CN + H 2 O   H 3 O + + - CN pK a = 9.2 Cyanide is a strong base (HCN weak acid) and a good nucleophile. Cyanide reacts rapidly with carbonyl compounds producing cyanohydrins, via the base catalyzed nucleophilic addition mechanism.
  • 23. Like hydrate formation, cyanohydrin formation is an equilibrium governed reaction (i.e. reversible reaction), and accordingly aldehydes are more reactive than ketones.
  • 24. Formation of Imines (Condensation Reactions) Under appropriate conditions, primary amines (and ammonia) react with ketones or aldehydes to generate imines.
  • 25.
  • 26. The mechanism of imine formation starts with the basic addition of the amine to the carbonyl group. Protonation of the oxyanion and deprotonation of the nitrogen cation generates an unstable intermediate called a carbinolamine.
  • 27. The carbinolamine has its oxygen protonated, and then water acts as the good leaving group.
  • 28.
  • 29.
  • 30.
  • 31.
  • 32. Oxidation (Could not use permanganate, etc for this transformation).
  • 33. Silver Mirror Test (Tollen's Test) This type of oxidation reaction is the basis of the most common chemical test for aldehydes - the Silver Mirror Test. Tollen's reagent is added to an unknown compound, and if an aldehyde is present, it is oxidized. R-CHO + 2Ag(NH 3 ) 2 + + 3OH -  2Ag + RCO 2 - + 4NH 3 + 2H 2 O   This process reduces the Ag + to Ag, and the Ag precipitates - it sticks to the flask wall, and forms a 'silver mirror'.
  • 34. Reduction of Ketone and Aldehydes Aldehydes and ketones are most commonly reduced by sodium borohydride.   NaBH 4 reduces ketones to secondary alcohols, and aldehydes to primary alcohols.   Other Reductions Catalytic Hydrogenation Just as C=C double bonds can be reduced by the addition of hydrogen across the double bond, so can C=O double bonds.
  • 35. Reduction of Ketone and Aldehydes Carbonyl double bonds are reduced much more slowly than alkene double bonds. Therefore, you cannot reduce a C=O in the presence of a C=C without reducing both (by this method).  E.g. The most common catalyst for these hydrogenations is Raney nickel, although Pt and Rh can also be used.
  • 36. Deoxygenation of Ketones and Aldehydes Deoxygenation involves the removal of oxygen, and its replacement with two hydrogen atoms. This reduction takes the carbonyl (past the alcohol) to a methylene group. Compare the following reduction processes:
  • 37. Deoxygenation of Ketones and Aldehydes
  • 38. Clemmensen Reduction (recap?) This was used in the reduction of acyl benzenes into alkyl benzenes, but it also works for other aldehydes and ketones.  E.g.
  • 39. Wolff-Kishner Sometimes the acidic conditions used in the Clemmensen reduction are unsuitable for a given molecule. In these cases, Wolff-Kishner reduction is employed. The ketone or aldehyde is converted to its hydrazone (by reaction with hydrazine) and is then treated with a strong base, which generates the reduced product, for example:
  • 40. Wolff-Kishner The mechanism of hydrazone formation is analogous to imine formation. The strongly basic conditions then deprotonate the hydrazone, and the anion produced is resonance stabilized.
  • 41. Wolff-Kishner The carbanionic form picks up a proton, and another deprotonation of the nitrogen generates an intermediate which is set up to eliminate a molecule of nitrogen (N 2 ) and produce a carbanion.
  • 42. Wolff-Kishner This carbanion is quickly protonated, giving the final reduced product.
  • 43. Formation of Acetals (Addition of Alcohols) In a similar fashion to the formation of hydrates with water, aldehydes and ketones form acetals through reaction with alcohols. In the formation of an acetal, two molecules of alcohol add to the carbonyl group, and one mole of water is eliminated. Acetal formation only occurs with acid catalysis.
  • 44. Mechanism of Acetal Formation The first step is the typical acid catalyzed addition to the carbonyl group.
  • 45. The hemiacetal reacts further to produce the more stable acetal: The second half of the mechanism starts with protonation of the hydroxyl group, followed by its leaving.
  • 46. The carbocation thus generated is resonance stabilized, and attack of the alcohol, after proton loss, produces the final acetal.   The second step (and therefore overall transformation) requires the acidic conditions to aid the replacement of the hydroxyl group (-OH is a bad leaving group, yet -OH 2 + ) is a good leaving group.
  • 47. Cyclic Acetals More commonly, instead of two molecules of alcohols being used, a diol is used (entropically more favorable). This produces cyclic acetals. E.g. 1,2-Ethanediol (ethylene glycol) is usually the diol of choice, and the products are called ethylene acetals. (Dithiane is a sulfur analogue of a cyclic acetal).
  • 48. Acetals as Protecting Groups Acetals will hydrolyze under acidic conditions, but are stable to strong bases and nucleophiles. They are also easily formed from aldehydes and ketones, and also easily converted back to the parent carbonyl compounds. These characteristics make acetals ideal protecting groups for aldehydes and ketones.   They can be used to 'protect' aldehydes and ketones from reacting with strong bases and nucleophiles.
  • 49. Consider the strategy to prepare the following compound: We might decide to use the Grignard reaction as shown above. However, having a Grignard functionality and an aldehyde in the same molecule is bad news since they will react with one another. The strategy is still okay, we just need to 'protect' the aldehyde as some unreactive group - an acetal. The acetal group is unreactive towards Grignard reagents (strong nucleophiles), and therefore this would be a viable reagent .
  • 50. The "masked" aldehyde can be safely converted to the Grignard reagent, and then this can react with cyclohexanone The acetal is easily removed with acidic hydrolysis (which is also required to remove the MgBr + from the oxyanion), giving the final product.
  • 51. Selective Acetal Formation We have previously seen that aldehydes are more reactive than ketones (two reasons), and therefore aldehydes will react to form acetals preferentially over ketones. This means we can selectively protect aldehydes in the presence of ketones. (Remember to use only 1 equivalent!) E.g.
  • 52. This is a useful way to perform reactions on ketone functionalities in molecules that contain both aldehyde and ketone groups.   (To selectively do reactions on the aldehyde, just do them!)
  • 53.
  • 54. The phosphorus stabilized anion is called an YLIDE, which is a molecule that is overall neutral, but exists as a carbanion bound to a positively charged heteroatom. Wittig Reaction
  • 55. Phosphorus ylides are produced from the reaction of triphenylphosphine and alkyl halides. base
  • 56.
  • 57. The double bond resonance form requires 10 electrons around the P atom. This is achievable through use of its d electrons (3 rd row element), but the  bond to carbon is weak, and this is only a minor contributor. The carbanionic character of the ylide makes it a very powerful nucleophile, and so it reacts rapidly with a carbonyl group. This produces an intermediate which has charge separation - a betaine.
  • 58.  
  • 59.  
  • 60.
  • 61. Wittig Strategy By dividing a target molecule at the double bond, you can decide which of the two components should best come from the carbonyl, and which from the ylide.
  • 62. In general, the ylide should come from an unhindered alkyl halide since triphenyl phosphine is so bulky. For Example:-