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Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
Mr Harish Chandra Rajpoot
M.M.M. University of Technology, Gorakhpur-273010 (UP), India Dec, 2014
Introduction: A cuboctahedron is a solid which has 8 congruent equilateral triangular & 6 congruent square
faces each having equal edge length. It is made/generated either by cutting off all the vertices (corners) of a
cube (having 8 vertices & 6 congruent square faces) or by cutting off all the vertices (corners) of a regular
octahedron (having 6 vertices & 8 congruent equilateral triangular faces) to generate 8 equilateral triangular &
6 square faces of equal edge length such that all the vertices lie on a sphere. For calculating all the parameters
of a cuboctahedron, we would use the equations of right pyramid & cube (regular hexahedron). When a cube
is cut off from the vertex, a right pyramid, with base as an equilateral triangle & certain normal height, is
obtained. Since a cube has 8 vertices hence we obtain 8 congruent cut off right pyramids each with an
equilateral triangular base.
Cutting off a cube: For ease of calculations, let there be a cube with edge length & its centre
at the point C. Now all its 8 vertices are cut off to obtain a cuboctahedron. Thus each of the congruent square
faces with edge length is changed into a new reduced square face with edge length (see figure
1) & we obtain 8 congruent cut off right pyramids with base as an equilateral triangle corresponding to 8
vertices of the parent solid. (See figure 1 which shows one square face & a right pyramid with equilateral
triangular base & normal height being cut off from the cube).
Calculation of edge length of parent cube:
Let be the edge length of each face of a cuboctahedron to be
generated by cutting off all the vertices of a parent cube with edge
length PQ (unknown).
In right
⇒
√
√
√
√
Figure 1: Each of 12 congruent square faces with edge
length 𝒂√𝟐 of a cube is changed into a new reduced
square face with edge length 𝒂 by cutting off all the
vertices. A right pyramid with base as an equilateral
triangle with side length 𝒂 & normal height h is being
cut off from a cube with edge length 𝒂√𝟐
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
Above result shows that if we are to generate a cuboctahedron with edge length then we have to cut off all 8
vertices of a cube of edge length √
Analysis of cuboctahedron by using equations of right pyramid & cube
Now consider any of 8 congruent cut off right pyramids having base as an equilateral triangle ABD with side
length , normal height & right angle between any two consecutive lateral edges (see figure 2 below)
Normal height ( ) of cut off right pyramid: We know that the normal height of any right pyramid with
regular polygonal base, having n no. of sides each of length & an angle between any two consecutive
lateral edges, is given as
√
Figure 2: Normal distance of equilateral triangular faces is always greater than the normal distance of square
faces measured from the centre C of any cuboctahedron.
√ √
⇒ √
√
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
√
Volume ( ) of cut off right pyramid: We know that the volume of a right pyramid is given as
( * ( *
√
√ √ √
√
Normal distance of equilateral triangular faces from the centre of cuboctahedron: The normal
distance of each of the equilateral triangular faces from the centre C of cuboctahedron is given as
⇒
⇒
√ ( √ )
√
√ √
√
⇒ √
It’s clear that all 8 congruent equilateral triangular faces are at an equal normal distance from the centre
of any cuboctahedron.
Solid angle subtended by each of the equilateral triangular faces at the centre of
cuboctahedron: we know that the solid angle subtended by any regular polygon with each side of length
at any point lying at a distance H on the vertical axis passing through the centre of plane is given by “HCR’s
Theory of Polygon” as follows
(
√
)
Hence, by substituting the corresponding values in the above expression, we get the solid angle subtended by
each equilateral triangular face at the centre of cuboctahedron as follows
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
(
( √ )
√ ( √ )
)
(
√ √
√
)
(
√
√
) (√ )
(√ )
Normal distance of square faces from the centre of cuboctahedron: The normal distance of
each of the square faces from the centre C of cuboctahedron is given as
⇒
⇒
( √ )
√
⇒
√
It’s clear that all 6 congruent square faces are at an equal normal distance from the centre of any
cuboctahedron.
It’s also clear from eq(III) & (V) i.e. the normal distance ( ) of equilateral triangular faces is greater
than the normal distance ( ) of square faces from the centre of cuboctahedron i.e. square faces are much
closer to the centre as compared to the equilateral triangular faces in any cuboctahedron.
Solid angle subtended by each of the square faces at the centre of cuboctahedron: we know
that the solid angle subtended by any regular polygon is given by “HCR’s Theory of Polygon” as follows
(
√
)
Hence, by substituting the corresponding value of normal distance in the above expression, we get the
solid angle subtended by each square face at the centre of cuboctahedron as follows
(
(
√
*
√ (
√
*
)
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
(
√
√
√
) (
√
*
(
√
*
It’s clear that the solid angle subtended by each of the square faces is greater than the solid angle subtended
by each of the equilateral triangular faces at the centre of any cuboctahedron.
Important parameters of a cuboctahedron:
1. Inner (inscribed) radius : It is the radius of the largest sphere inscribed (trapped inside) by
cuboctahedron. The largest inscribed sphere always touches all 6 congruent square faces but does not
touch any of 8 congruent equilateral triangular faces at all since all 6 square faces are closer to the
centre as compared to all 8 triangular faces. Thus, inner radius is always equal to the normal distance
( ) of square faces from the centre of a cuboctahedron & is given from the eq(V) as follows
√
Hence, the volume of inscribed sphere is given as
(
√
*
2. Outer (circumscribed) radius : It is the radius of the smallest sphere circumscribing a given
cuboctahedron or it’s the radius of a spherical surface passing through all 12 vertices of a given
cuboctahedron. It is calculated as follows (See figure 2 above).
In right
⇒
( )
(
√
)
√
( *
In right
⇒ √ √(
√
* ( √ )
√
Hence, the outer radius of cuboctahedron is given as
Hence, the volume of circumscribed sphere is given as
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
3. Surface area : We know that a cuboctahedron has 8 congruent equilateral triangular & 6
congruent square faces each of edge length . Hence, its surface area is given as follows
We know that area of any regular n-polygon with each side of length is given as
Hence, by substituting all the corresponding values in the above expression, we get
( * ( *
√
( √ )
( √ )
4. Volume : We know that a cuboctahedron with edge length is obtained by cutting a cube with
edge length √ at all its 8 vertices. Thus, 8 congruent right pyramids with equilateral triangular base
are cut off from the parent cube. Hence, the volume (V) of the cuboctahedron is given as follows
( √ )
√
√
√
√ ( √ √ ) √
√
5. Mean radius : It is the radius of the sphere having a volume equal to that of a given
cuboctahedron. It is calculated as follows
√
⇒
√
(
√
*
(
√
*
It’s clear from above results that
Construction of a solid cuboctahedron: In order to construct a solid cuboctahedron with edge length
there are two methods
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
1. Construction from elementary right pyramids: In this method, first we construct all elementary right
pyramids as follows
Construct 8 congruent right pyramids with equilateral triangular base of side length & normal height ( )
√
Construct 6 congruent right pyramids with square base of side length & normal height ( )
√
Now, paste/bond by joining all these elementary right pyramids by overlapping their lateral surfaces & keeping
their apex points coincident with each other such that all the edges of each equilateral triangular base (face)
coincide with the edges of three square bases (faces). Thus, a solid cuboctahedron, with 8 congruent
equilateral triangular & 6 congruent square faces each of edge length , is obtained.
2. Facing a solid sphere: It is a method of facing, first we select a blank as a solid sphere of certain material
(i.e. metal, alloy, composite material etc.) & with suitable diameter in order to obtain the maximum desired
edge length of cuboctahedron. Then, we perform facing operations on the solid sphere to generate 8
congruent equilateral triangular & 6 congruent square faces each of equal edge length.
Let there be a blank as a solid sphere with a diameter D. Then the edge length , of a cuboctahedron of the
maximum volume to be produced, can be co-related with the diameter D by relation of outer radius with
edge length of a cuboctahedron as follows
Now, substituting ⁄ in the above expression, we have
Above relation is very useful for determining the edge length of a cuboctahedron to be produced from a
solid sphere with known diameter D for manufacturing purpose.
Hence, the maximum volume of cuboctahedron produced from the solid sphere is given as follows
√ √
( *
√
√
√
Minimum volume of material removed is given as
√
(
√
*
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
(
√
*
Percentage of minimum volume of material removed
(
√
*
(
√
*
It’s obvious that when a cuboctahedron of the maximum volume is produced from a solid sphere then about
of material is removed as scraps. Thus, we can select optimum diameter of blank as a solid sphere to
produce a solid cuboctahedron of the maximum volume (or with maximum desired edge length)
Conclusions: let there be any cuboctahedron having 8 congruent equilateral triangular & 6 congruent
square faces each with edge length then all its important parameters are calculated/determined as
tabulated below
Congruent
polygonal faces
No. of
faces
Normal distance of each face from the
centre of the given cuboctahedron
Solid angle subtended by each face at the
centre of the given cuboctahedron
Equilateral
triangle
8
√ (√ )
Square 6
√
(
√
*
Inner (inscribed) radius
√
Outer (circumscribed) radius
Mean radius (
√
*
Surface area ( √ )
Volume √
Mathematical analysis of Cuboctahedron (Archimedean solid)
Application of HCR’s formula for regular polyhedrons (all five platonic solids)
Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014)
©All rights reserved
Note: Above articles had been developed & illustrated by Mr H.C. Rajpoot (B Tech, Mechanical Engineering)
M.M.M. University of Technology, Gorakhpur-273010 (UP) India Dec, 2014
Email: rajpootharishchandra@gmail.com
Author’s Home Page: https://notionpress.com/author/HarishChandraRajpoot
Courtesy: Advanced Geometry by Harish Chandra Rajpoot

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Mathematical analysis of cuboctahedron/Archimedean solid by HCR

  • 1. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved Mr Harish Chandra Rajpoot M.M.M. University of Technology, Gorakhpur-273010 (UP), India Dec, 2014 Introduction: A cuboctahedron is a solid which has 8 congruent equilateral triangular & 6 congruent square faces each having equal edge length. It is made/generated either by cutting off all the vertices (corners) of a cube (having 8 vertices & 6 congruent square faces) or by cutting off all the vertices (corners) of a regular octahedron (having 6 vertices & 8 congruent equilateral triangular faces) to generate 8 equilateral triangular & 6 square faces of equal edge length such that all the vertices lie on a sphere. For calculating all the parameters of a cuboctahedron, we would use the equations of right pyramid & cube (regular hexahedron). When a cube is cut off from the vertex, a right pyramid, with base as an equilateral triangle & certain normal height, is obtained. Since a cube has 8 vertices hence we obtain 8 congruent cut off right pyramids each with an equilateral triangular base. Cutting off a cube: For ease of calculations, let there be a cube with edge length & its centre at the point C. Now all its 8 vertices are cut off to obtain a cuboctahedron. Thus each of the congruent square faces with edge length is changed into a new reduced square face with edge length (see figure 1) & we obtain 8 congruent cut off right pyramids with base as an equilateral triangle corresponding to 8 vertices of the parent solid. (See figure 1 which shows one square face & a right pyramid with equilateral triangular base & normal height being cut off from the cube). Calculation of edge length of parent cube: Let be the edge length of each face of a cuboctahedron to be generated by cutting off all the vertices of a parent cube with edge length PQ (unknown). In right ⇒ √ √ √ √ Figure 1: Each of 12 congruent square faces with edge length 𝒂√𝟐 of a cube is changed into a new reduced square face with edge length 𝒂 by cutting off all the vertices. A right pyramid with base as an equilateral triangle with side length 𝒂 & normal height h is being cut off from a cube with edge length 𝒂√𝟐
  • 2. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved Above result shows that if we are to generate a cuboctahedron with edge length then we have to cut off all 8 vertices of a cube of edge length √ Analysis of cuboctahedron by using equations of right pyramid & cube Now consider any of 8 congruent cut off right pyramids having base as an equilateral triangle ABD with side length , normal height & right angle between any two consecutive lateral edges (see figure 2 below) Normal height ( ) of cut off right pyramid: We know that the normal height of any right pyramid with regular polygonal base, having n no. of sides each of length & an angle between any two consecutive lateral edges, is given as √ Figure 2: Normal distance of equilateral triangular faces is always greater than the normal distance of square faces measured from the centre C of any cuboctahedron. √ √ ⇒ √ √
  • 3. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved √ Volume ( ) of cut off right pyramid: We know that the volume of a right pyramid is given as ( * ( * √ √ √ √ √ Normal distance of equilateral triangular faces from the centre of cuboctahedron: The normal distance of each of the equilateral triangular faces from the centre C of cuboctahedron is given as ⇒ ⇒ √ ( √ ) √ √ √ √ ⇒ √ It’s clear that all 8 congruent equilateral triangular faces are at an equal normal distance from the centre of any cuboctahedron. Solid angle subtended by each of the equilateral triangular faces at the centre of cuboctahedron: we know that the solid angle subtended by any regular polygon with each side of length at any point lying at a distance H on the vertical axis passing through the centre of plane is given by “HCR’s Theory of Polygon” as follows ( √ ) Hence, by substituting the corresponding values in the above expression, we get the solid angle subtended by each equilateral triangular face at the centre of cuboctahedron as follows
  • 4. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved ( ( √ ) √ ( √ ) ) ( √ √ √ ) ( √ √ ) (√ ) (√ ) Normal distance of square faces from the centre of cuboctahedron: The normal distance of each of the square faces from the centre C of cuboctahedron is given as ⇒ ⇒ ( √ ) √ ⇒ √ It’s clear that all 6 congruent square faces are at an equal normal distance from the centre of any cuboctahedron. It’s also clear from eq(III) & (V) i.e. the normal distance ( ) of equilateral triangular faces is greater than the normal distance ( ) of square faces from the centre of cuboctahedron i.e. square faces are much closer to the centre as compared to the equilateral triangular faces in any cuboctahedron. Solid angle subtended by each of the square faces at the centre of cuboctahedron: we know that the solid angle subtended by any regular polygon is given by “HCR’s Theory of Polygon” as follows ( √ ) Hence, by substituting the corresponding value of normal distance in the above expression, we get the solid angle subtended by each square face at the centre of cuboctahedron as follows ( ( √ * √ ( √ * )
  • 5. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved ( √ √ √ ) ( √ * ( √ * It’s clear that the solid angle subtended by each of the square faces is greater than the solid angle subtended by each of the equilateral triangular faces at the centre of any cuboctahedron. Important parameters of a cuboctahedron: 1. Inner (inscribed) radius : It is the radius of the largest sphere inscribed (trapped inside) by cuboctahedron. The largest inscribed sphere always touches all 6 congruent square faces but does not touch any of 8 congruent equilateral triangular faces at all since all 6 square faces are closer to the centre as compared to all 8 triangular faces. Thus, inner radius is always equal to the normal distance ( ) of square faces from the centre of a cuboctahedron & is given from the eq(V) as follows √ Hence, the volume of inscribed sphere is given as ( √ * 2. Outer (circumscribed) radius : It is the radius of the smallest sphere circumscribing a given cuboctahedron or it’s the radius of a spherical surface passing through all 12 vertices of a given cuboctahedron. It is calculated as follows (See figure 2 above). In right ⇒ ( ) ( √ ) √ ( * In right ⇒ √ √( √ * ( √ ) √ Hence, the outer radius of cuboctahedron is given as Hence, the volume of circumscribed sphere is given as
  • 6. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved 3. Surface area : We know that a cuboctahedron has 8 congruent equilateral triangular & 6 congruent square faces each of edge length . Hence, its surface area is given as follows We know that area of any regular n-polygon with each side of length is given as Hence, by substituting all the corresponding values in the above expression, we get ( * ( * √ ( √ ) ( √ ) 4. Volume : We know that a cuboctahedron with edge length is obtained by cutting a cube with edge length √ at all its 8 vertices. Thus, 8 congruent right pyramids with equilateral triangular base are cut off from the parent cube. Hence, the volume (V) of the cuboctahedron is given as follows ( √ ) √ √ √ √ ( √ √ ) √ √ 5. Mean radius : It is the radius of the sphere having a volume equal to that of a given cuboctahedron. It is calculated as follows √ ⇒ √ ( √ * ( √ * It’s clear from above results that Construction of a solid cuboctahedron: In order to construct a solid cuboctahedron with edge length there are two methods
  • 7. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved 1. Construction from elementary right pyramids: In this method, first we construct all elementary right pyramids as follows Construct 8 congruent right pyramids with equilateral triangular base of side length & normal height ( ) √ Construct 6 congruent right pyramids with square base of side length & normal height ( ) √ Now, paste/bond by joining all these elementary right pyramids by overlapping their lateral surfaces & keeping their apex points coincident with each other such that all the edges of each equilateral triangular base (face) coincide with the edges of three square bases (faces). Thus, a solid cuboctahedron, with 8 congruent equilateral triangular & 6 congruent square faces each of edge length , is obtained. 2. Facing a solid sphere: It is a method of facing, first we select a blank as a solid sphere of certain material (i.e. metal, alloy, composite material etc.) & with suitable diameter in order to obtain the maximum desired edge length of cuboctahedron. Then, we perform facing operations on the solid sphere to generate 8 congruent equilateral triangular & 6 congruent square faces each of equal edge length. Let there be a blank as a solid sphere with a diameter D. Then the edge length , of a cuboctahedron of the maximum volume to be produced, can be co-related with the diameter D by relation of outer radius with edge length of a cuboctahedron as follows Now, substituting ⁄ in the above expression, we have Above relation is very useful for determining the edge length of a cuboctahedron to be produced from a solid sphere with known diameter D for manufacturing purpose. Hence, the maximum volume of cuboctahedron produced from the solid sphere is given as follows √ √ ( * √ √ √ Minimum volume of material removed is given as √ ( √ *
  • 8. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved ( √ * Percentage of minimum volume of material removed ( √ * ( √ * It’s obvious that when a cuboctahedron of the maximum volume is produced from a solid sphere then about of material is removed as scraps. Thus, we can select optimum diameter of blank as a solid sphere to produce a solid cuboctahedron of the maximum volume (or with maximum desired edge length) Conclusions: let there be any cuboctahedron having 8 congruent equilateral triangular & 6 congruent square faces each with edge length then all its important parameters are calculated/determined as tabulated below Congruent polygonal faces No. of faces Normal distance of each face from the centre of the given cuboctahedron Solid angle subtended by each face at the centre of the given cuboctahedron Equilateral triangle 8 √ (√ ) Square 6 √ ( √ * Inner (inscribed) radius √ Outer (circumscribed) radius Mean radius ( √ * Surface area ( √ ) Volume √
  • 9. Mathematical analysis of Cuboctahedron (Archimedean solid) Application of HCR’s formula for regular polyhedrons (all five platonic solids) Applications of “HCR’s Theory of Polygon” proposed by Mr H.C. Rajpoot (year-2014) ©All rights reserved Note: Above articles had been developed & illustrated by Mr H.C. Rajpoot (B Tech, Mechanical Engineering) M.M.M. University of Technology, Gorakhpur-273010 (UP) India Dec, 2014 Email: rajpootharishchandra@gmail.com Author’s Home Page: https://notionpress.com/author/HarishChandraRajpoot Courtesy: Advanced Geometry by Harish Chandra Rajpoot