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Elektronika AgusSetyo Budi, Dr. M.Sc Sesion#02 JurusanFisika FakultasMatematikadanIlmuPengetahuanAlam
Ohm’s Law The Linear Proportion between V and I Electric Power Power Dissipation in Resistance Power Formulas Choosing a Resistor for a Circuit Electric Shock Open-Circuit and Short-Circuit Troubles 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 2
07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 3 Ohm’s Law
Ohm’s Law Formulas There are three forms of Ohm’s Law: I = V/R  V = IR  R = V/I where:  I = Current  V = Voltage  R = Resistance Fig. 3-4: A circle diagram to help in memorizing the Ohm’s Law formulas V = IR,  I = V/R, and R= V/I. The V is always at the top.  07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 4
The Current I = V/R I = V/R In practical units, this law may be stated as: amperes = volts / ohms Fig. 3-1: Increasing the applied voltage V produces more current I to light the bulb with more intensity.  07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 5
Practical Units The three forms of Ohm’s law can be used to define the practical units of current, voltage, and resistance: 1 ampere = 1 volt / 1 ohm 1 volt = 1 ampere × 1 ohm  1 ohm = 1 volt / 1 ampere 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 6
20 V I  =  20 V 4 W 4 W ? 12 W V = 1A×12 W = 12 V 6 V 6 V ? =2 W R= 3 A Practical Units Applying Ohm’s Law V I R ? = 5 A 1 A 3 A 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 7
Multiple and Submultiple Units Units of Voltage The basic unit of voltage is the volt (V). Multiple units of voltage are: kilovolt (kV)1 thousand volts or 103 V megavolt (MV)1 million volts or 106 V Submultiple units of voltage are: millivolt (mV)1-thousandth of a volt or 10-3 V microvolt (μV)1-millionth of a volt or 10-6 V 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 8
Multiple and Submultiple Units Units of Current The basic unit of current is the ampere (A). Submultipleunits of current are: milliampere (mA)1-thousandth of an ampere or 10-3 A microampere (μA)1-millionth of an ampere or 10-6 A 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 9
Multiple and Submultiple Units Units of Resistance The basic unit of resistance is the Ohm (Ω). Multiple units of resistance are: kilohm (kW)1 thousand ohms or 103Ω Megohm (MW)1 million ohms or 106Ω 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 10
the Linear Proportion between V and I The Ohm’s Law formula I = V/R states that V and I are directly proportional for any one value of R. Fig. 3.5: Experiment to show that I increases in direct proportion to V with the same R. (a) Circuit with variable V but constant R. (b) Table of increasing I for higher V. (c) Graph of V and I values. This is a linear volt-ampere characteristic. It shows a direct proportion between V and I. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 11
The Linear Proportion between V and I When V is constant: I decreases as R increases. I increases as R decreases. Examples:  If R doubles, I is reduced by half.  If R is reduced to ¼, I increases by 4. This is known as an inverse relationship. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 12
The Linear Proportion between V and I Linear Resistance A linear resistance has a constant value of ohms. Its R does not change with the applied voltage, so V and I are directly proportional. Carbon-film and metal-film resistors are examples of linear resistors. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 13
2 W 1 W 4 3 + 4 W Amperes 2 0 to 9 Volts 2 W _ 1 0  1  2  3  4  5  6  7  8  9 Volts The Linear Proportion between V and I The smaller the resistor, the steeper the slope. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 14
The Linear Proportion between V and I Nonlinear Resistance In a nonlinear resistance, increasing the applied V produces more current, but I does not increase in the same proportion as the increase in V. Example of a Nonlinear Volt–Ampere Relationship: As the tungsten filament in a light bulb gets hot, its resistance increases. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 15
The Linear Proportion between V and I Another nonlinear resistance is a thermistor.  A thermistor is a resistor whose resistance value changes with its operating temperature.  As an NTC(negative temperature coefficient) thermistor gets hot, its resistance decreases.  07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 16
Electric Power The basic unit of power is the watt (W). Multiple units of power are: kilowatt (kW):1000 watts or 103 W megawatt (MW):1 million watts or 106 W Submultiple units of power are: milliwatt (mW):1-thousandth of a watt or 10-3 W microwatt (μW):1-millionth of a watt or 10-6 W 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 17
Electric Power Work and energy are basically the same, with identical units.  Power is different. It is the time rate of doing work. Power = work / time. Work = power × time. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 18
1 joule 1 coulomb 1 ampere = and 1 volt = 1 second 1 coulomb Electric Power Practical Units of Power and Work: The rate at which work is done (power) equals the product of voltage and current. This is derived as follows: First, recall that: 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 19
1 joule × = Power (1 watt) = 1 joule 1 coulomb 1 second 1 coulomb 1 second Electric Power Power = Volts × Amps, or P = V × I 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 20
3-7: Electric Power Kilowatt Hours The kilowatt hour (kWh) is a unit commonly used for large amounts of electrical work or energy.  For example, electric bills are calculated in kilowatt hours. The kilowatt hour is the billing unit. The amount of work (energy) can be found by multiplying power (in kilowatts) × time in hours. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 21
Electric Power To calculate electric cost, start with the power: An air conditioner operates at 240 volts and 20 amperes. The power is P = V × I = 240 × 20 = 4800 watts.  Convert to kilowatts:  4800 watts = 4.8 kilowatts Multiply by hours: (Assume it runs half the day)  energy = 4.8 kW × 12 hours =  57.6 kWh  Multiply by rate:(Assume a rate of $0.08/ kWh)  cost = 57.6 × $0.08 = $4.61 per day 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 22
Power Dissipation in Resistance When current flows in a resistance, heat is produced from the friction between the moving free electrons and the atoms obstructing their path.  Heat is evidence that power is used in producing current. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 23
Power Dissipation in Resistance The amount of power dissipated in a resistance may be calculated using any one of three formulas, depending on which factors are known:  P = I2×R P = V2 / R P = V×I 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 24
Power Formulas There are three basic power formulas, but each can be in three forms for nine combinations. Where: P = Power	V = Voltage	I = Current	R=Resistance 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 25
P = VI V = IR V I = R Power Formulas Combining Ohm’s Law and the Power Formula All nine power formulas are based on Ohm’s Law. Substitute IR for V to obtain: P  = VI     = (IR)I      =  I2R 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 26
Power Formulas Combining Ohm’s Law and the Power Formula Substitute V/R for I to obtain: P = VI   = V × V/ R       = V2 / R 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 27
5 A 20 V 4 W P = VI = 20 × 5 = 100 W P = I2R = 25 × 4 = 100 W V2 400 =  = 100 W P =  R 4 Power Formulas Applying Power Formulas: 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 28
Choosing a Resistor  for a Circuit Follow these steps when choosing a resistor for a circuit: Determine the required resistance value as R = V / I. Calculate the power dissipated by the resistor using any of the power formulas. Select a wattage rating for the resistor that will provide an adequate cushion between the actual power dissipation and the resistor’s power rating. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 29
3-10: Choosing a Resistor for a Circuit Maximum Working Voltage Rating A resistor’s maximum working voltage rating is the maximum voltage a resistor can withstand without internal arcing. The higher the wattage rating of the resistor, the higher the maximum working voltage rating. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 30
Prating × R 3-10: Choosing a Resistor for a Circuit Maximum Working Voltage Rating With very large resistance values, the maximum working voltage rating may be exceeded before the power rating is exceeded. For any resistor, the maximum voltage which produces the rated power dissipation is: Vmax =  07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 31
3-11: Electric Shock When possible, work only on circuits that have the power shut off. If the power must be on, use only one hand when making voltage measurements. Keep yourself insulated from earth ground. Hand-to-hand shocks can be very dangerous because current is likely to flow through the heart! 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 32
3-12: Open-Circuit and Short-Circuit Troubles An open circuit has zero current flow. 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 33
3-12: Open-Circuit and Short-Circuit Troubles A short circuit has excessive current flow.  As R approaches 0, I approaches . 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 34
TERIMA KASIH 07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 35
07/01/2011 ©  2010 Universitas Negeri Jakarta   |  www.unj.ac.id                      | 36 TerimaKasih

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Elektronika (2)

  • 1. Elektronika AgusSetyo Budi, Dr. M.Sc Sesion#02 JurusanFisika FakultasMatematikadanIlmuPengetahuanAlam
  • 2. Ohm’s Law The Linear Proportion between V and I Electric Power Power Dissipation in Resistance Power Formulas Choosing a Resistor for a Circuit Electric Shock Open-Circuit and Short-Circuit Troubles 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 2
  • 3. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 3 Ohm’s Law
  • 4. Ohm’s Law Formulas There are three forms of Ohm’s Law: I = V/R V = IR R = V/I where: I = Current V = Voltage R = Resistance Fig. 3-4: A circle diagram to help in memorizing the Ohm’s Law formulas V = IR, I = V/R, and R= V/I. The V is always at the top. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 4
  • 5. The Current I = V/R I = V/R In practical units, this law may be stated as: amperes = volts / ohms Fig. 3-1: Increasing the applied voltage V produces more current I to light the bulb with more intensity. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 5
  • 6. Practical Units The three forms of Ohm’s law can be used to define the practical units of current, voltage, and resistance: 1 ampere = 1 volt / 1 ohm 1 volt = 1 ampere × 1 ohm 1 ohm = 1 volt / 1 ampere 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 6
  • 7. 20 V I = 20 V 4 W 4 W ? 12 W V = 1A×12 W = 12 V 6 V 6 V ? =2 W R= 3 A Practical Units Applying Ohm’s Law V I R ? = 5 A 1 A 3 A 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 7
  • 8. Multiple and Submultiple Units Units of Voltage The basic unit of voltage is the volt (V). Multiple units of voltage are: kilovolt (kV)1 thousand volts or 103 V megavolt (MV)1 million volts or 106 V Submultiple units of voltage are: millivolt (mV)1-thousandth of a volt or 10-3 V microvolt (μV)1-millionth of a volt or 10-6 V 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 8
  • 9. Multiple and Submultiple Units Units of Current The basic unit of current is the ampere (A). Submultipleunits of current are: milliampere (mA)1-thousandth of an ampere or 10-3 A microampere (μA)1-millionth of an ampere or 10-6 A 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 9
  • 10. Multiple and Submultiple Units Units of Resistance The basic unit of resistance is the Ohm (Ω). Multiple units of resistance are: kilohm (kW)1 thousand ohms or 103Ω Megohm (MW)1 million ohms or 106Ω 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 10
  • 11. the Linear Proportion between V and I The Ohm’s Law formula I = V/R states that V and I are directly proportional for any one value of R. Fig. 3.5: Experiment to show that I increases in direct proportion to V with the same R. (a) Circuit with variable V but constant R. (b) Table of increasing I for higher V. (c) Graph of V and I values. This is a linear volt-ampere characteristic. It shows a direct proportion between V and I. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 11
  • 12. The Linear Proportion between V and I When V is constant: I decreases as R increases. I increases as R decreases. Examples: If R doubles, I is reduced by half. If R is reduced to ¼, I increases by 4. This is known as an inverse relationship. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 12
  • 13. The Linear Proportion between V and I Linear Resistance A linear resistance has a constant value of ohms. Its R does not change with the applied voltage, so V and I are directly proportional. Carbon-film and metal-film resistors are examples of linear resistors. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 13
  • 14. 2 W 1 W 4 3 + 4 W Amperes 2 0 to 9 Volts 2 W _ 1 0 1 2 3 4 5 6 7 8 9 Volts The Linear Proportion between V and I The smaller the resistor, the steeper the slope. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 14
  • 15. The Linear Proportion between V and I Nonlinear Resistance In a nonlinear resistance, increasing the applied V produces more current, but I does not increase in the same proportion as the increase in V. Example of a Nonlinear Volt–Ampere Relationship: As the tungsten filament in a light bulb gets hot, its resistance increases. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 15
  • 16. The Linear Proportion between V and I Another nonlinear resistance is a thermistor. A thermistor is a resistor whose resistance value changes with its operating temperature. As an NTC(negative temperature coefficient) thermistor gets hot, its resistance decreases. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 16
  • 17. Electric Power The basic unit of power is the watt (W). Multiple units of power are: kilowatt (kW):1000 watts or 103 W megawatt (MW):1 million watts or 106 W Submultiple units of power are: milliwatt (mW):1-thousandth of a watt or 10-3 W microwatt (μW):1-millionth of a watt or 10-6 W 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 17
  • 18. Electric Power Work and energy are basically the same, with identical units. Power is different. It is the time rate of doing work. Power = work / time. Work = power × time. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 18
  • 19. 1 joule 1 coulomb 1 ampere = and 1 volt = 1 second 1 coulomb Electric Power Practical Units of Power and Work: The rate at which work is done (power) equals the product of voltage and current. This is derived as follows: First, recall that: 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 19
  • 20. 1 joule × = Power (1 watt) = 1 joule 1 coulomb 1 second 1 coulomb 1 second Electric Power Power = Volts × Amps, or P = V × I 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 20
  • 21. 3-7: Electric Power Kilowatt Hours The kilowatt hour (kWh) is a unit commonly used for large amounts of electrical work or energy. For example, electric bills are calculated in kilowatt hours. The kilowatt hour is the billing unit. The amount of work (energy) can be found by multiplying power (in kilowatts) × time in hours. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 21
  • 22. Electric Power To calculate electric cost, start with the power: An air conditioner operates at 240 volts and 20 amperes. The power is P = V × I = 240 × 20 = 4800 watts. Convert to kilowatts: 4800 watts = 4.8 kilowatts Multiply by hours: (Assume it runs half the day) energy = 4.8 kW × 12 hours = 57.6 kWh Multiply by rate:(Assume a rate of $0.08/ kWh) cost = 57.6 × $0.08 = $4.61 per day 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 22
  • 23. Power Dissipation in Resistance When current flows in a resistance, heat is produced from the friction between the moving free electrons and the atoms obstructing their path. Heat is evidence that power is used in producing current. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 23
  • 24. Power Dissipation in Resistance The amount of power dissipated in a resistance may be calculated using any one of three formulas, depending on which factors are known: P = I2×R P = V2 / R P = V×I 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 24
  • 25. Power Formulas There are three basic power formulas, but each can be in three forms for nine combinations. Where: P = Power V = Voltage I = Current R=Resistance 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 25
  • 26. P = VI V = IR V I = R Power Formulas Combining Ohm’s Law and the Power Formula All nine power formulas are based on Ohm’s Law. Substitute IR for V to obtain: P = VI = (IR)I = I2R 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 26
  • 27. Power Formulas Combining Ohm’s Law and the Power Formula Substitute V/R for I to obtain: P = VI = V × V/ R = V2 / R 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 27
  • 28. 5 A 20 V 4 W P = VI = 20 × 5 = 100 W P = I2R = 25 × 4 = 100 W V2 400 = = 100 W P = R 4 Power Formulas Applying Power Formulas: 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 28
  • 29. Choosing a Resistor for a Circuit Follow these steps when choosing a resistor for a circuit: Determine the required resistance value as R = V / I. Calculate the power dissipated by the resistor using any of the power formulas. Select a wattage rating for the resistor that will provide an adequate cushion between the actual power dissipation and the resistor’s power rating. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 29
  • 30. 3-10: Choosing a Resistor for a Circuit Maximum Working Voltage Rating A resistor’s maximum working voltage rating is the maximum voltage a resistor can withstand without internal arcing. The higher the wattage rating of the resistor, the higher the maximum working voltage rating. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 30
  • 31. Prating × R 3-10: Choosing a Resistor for a Circuit Maximum Working Voltage Rating With very large resistance values, the maximum working voltage rating may be exceeded before the power rating is exceeded. For any resistor, the maximum voltage which produces the rated power dissipation is: Vmax = 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 31
  • 32. 3-11: Electric Shock When possible, work only on circuits that have the power shut off. If the power must be on, use only one hand when making voltage measurements. Keep yourself insulated from earth ground. Hand-to-hand shocks can be very dangerous because current is likely to flow through the heart! 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 32
  • 33. 3-12: Open-Circuit and Short-Circuit Troubles An open circuit has zero current flow. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 33
  • 34. 3-12: Open-Circuit and Short-Circuit Troubles A short circuit has excessive current flow. As R approaches 0, I approaches . 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 34
  • 35. TERIMA KASIH 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 35
  • 36. 07/01/2011 © 2010 Universitas Negeri Jakarta | www.unj.ac.id | 36 TerimaKasih