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March
  6, 2013

             Today:

  Review all Factoring Methods
             Covered
Test Grades Posted Today: V6Math
Quarter Grades Posted Tomorrow:
              V6Math
New Factor Method: Difference of
             Squares
 New Khan Academy Topics(2) for
              3/10/13
           Class Work
This is a good time to step back,

       Take a deep breath..

             (Quietly)

And review what we've covered thus
      far in the factoring unit.
Greatest Common
                Factor
Example: Find the GCF of each list of numbers.
 1) 6, 8 and 46
     6=2·3
     8=2·2·2
    46 = 2 · 23
    So the GCF is 2.
 2) 144, 256 and 300
    144 = 2 · 2 · 2 · 3 · 3
    256 = 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2
    300 = 2 · 2 · 3 · 5 · 5
    So the GCF is 2 · 2 = 4.
Greatest Common Factor
Example:       Find the GCF of each list of terms.
  1)    x3 and x7
       x3 = x · x · x
       x7 = x · x · x · x · x · x · x
       So the GCF is x · x · x = x3
  2)    6x5 and 4x3
       6x5 = 2 · 3 · x · x · x
       4x3 = 2 · 2 · x · x · x
       So the GCF is 2 · x · x · x = 2x3
Greatest Common Factor
Example: Find the GCF of the following list of terms.

   a3b2, a2b5 and a4b7
     a3b2 = a · a · a · b · b
     a2b5 = a · a · b · b · b · b · b
     a4b7 = a · a · a · a · b · b · b · b · b · b · b
   So the GCF is a · a · b · b = a2b2
Notice that the GCF of terms containing variables
will use the smallest exponent found amongst the
individual terms for each variable.
Factor Using GCF

 Most factoring using GCF is done with binomials.

 Factor using GCF:
     1. 32x3 – 4x2   2. 18x2y + 5xy2

Sometimes, factoring using GCF is just the first step.

  3. 18x2 – 50        4. x3 – 49x
factor by Grouping
 When a polynomial has 4 or more terms, grouping
 is the factor method used.
Factor: xy + 2x + y + 2
   It should be clear that we need to rearrange the
   terms since there is nothing that can be factored
   from the 3rd & 4th terms.
   (xy + y) + (2x + 2) =
   y(x + 1) + 2(x + 1) =
                     (x + 1)(y + 2)
factor by Grouping

1. xy – 4x + 3y - 12


2. 2xy - 6x - y + 3


3. 2x3 – x2 – 10x + 5


4. 2x + 18 – 9y – xy
Factoring: x       2
                                 + bx + c
Factor c, using those factors whose sum equals b

  1. x2 – 2x – 35          3. x2 + 5x + 1

  2. x2 – 7x + 10          4. x2 + x - 2
Factoring ax2 + bx + c trinomials

First, multiply ac, then, factor c using those factors
whose sum is equivalent to b. Finally, use grouping
to factor the trinomial

 1. 2x2 + 7x + 6       3. 3x2 + 17x + 1

 2. 3x2 + 14x - 5      4. 8x2 + 2x - 3

 5. 6x2 + 7x - 3
Solving Equations by Factoring
Zero Factor Theorem
  • If a and b are real numbers and ab =
    0, then a = 0 or b = 0.

1. x2 + 6x + 8 = 0   3. 6x2 - 14x = -8
  x = -4, x = -2         x = 1, x = 11/3
2. x2 - 25 = 0       4. 4x2 - 4x = 24
  x = 5, x = -5         x = -2, x = 3
Difference of Two Squares
Another shortcut for factoring a trinomial is when
we want to factor the difference of two squares.
    a2 – b2 = (a + b)(a – b)
  A binomial is the difference of two squares if:
     1.Both terms are squares and
     2.The signs of the terms are different.
                9x2 – 25y2
                – c4 + d4
Difference of Two Squares

1. b2 - 49                3. 1 - 16x10 =

(b- 7)(b+ 7)              (1 - 4x5)(1 + 4x5)

2. 7g3h2 - 28g5 =         4. x2y2 - 25 =

   7g3(h2 - 4g2) =          (xy - 5)(xy + 5)
   7g3(h - 2g)(h + 2g)   5. 144 - x8 =
                         (12 - x4)(12 + x4)
March 6
March 6

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March 6

  • 1. March 6, 2013 Today: Review all Factoring Methods Covered Test Grades Posted Today: V6Math Quarter Grades Posted Tomorrow: V6Math New Factor Method: Difference of Squares New Khan Academy Topics(2) for 3/10/13 Class Work
  • 2. This is a good time to step back, Take a deep breath.. (Quietly) And review what we've covered thus far in the factoring unit.
  • 3. Greatest Common Factor Example: Find the GCF of each list of numbers. 1) 6, 8 and 46 6=2·3 8=2·2·2 46 = 2 · 23 So the GCF is 2. 2) 144, 256 and 300 144 = 2 · 2 · 2 · 3 · 3 256 = 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 300 = 2 · 2 · 3 · 5 · 5 So the GCF is 2 · 2 = 4.
  • 4. Greatest Common Factor Example: Find the GCF of each list of terms. 1) x3 and x7 x3 = x · x · x x7 = x · x · x · x · x · x · x So the GCF is x · x · x = x3 2) 6x5 and 4x3 6x5 = 2 · 3 · x · x · x 4x3 = 2 · 2 · x · x · x So the GCF is 2 · x · x · x = 2x3
  • 5. Greatest Common Factor Example: Find the GCF of the following list of terms. a3b2, a2b5 and a4b7 a3b2 = a · a · a · b · b a2b5 = a · a · b · b · b · b · b a4b7 = a · a · a · a · b · b · b · b · b · b · b So the GCF is a · a · b · b = a2b2 Notice that the GCF of terms containing variables will use the smallest exponent found amongst the individual terms for each variable.
  • 6. Factor Using GCF Most factoring using GCF is done with binomials. Factor using GCF: 1. 32x3 – 4x2 2. 18x2y + 5xy2 Sometimes, factoring using GCF is just the first step. 3. 18x2 – 50 4. x3 – 49x
  • 7. factor by Grouping When a polynomial has 4 or more terms, grouping is the factor method used. Factor: xy + 2x + y + 2 It should be clear that we need to rearrange the terms since there is nothing that can be factored from the 3rd & 4th terms. (xy + y) + (2x + 2) = y(x + 1) + 2(x + 1) = (x + 1)(y + 2)
  • 8. factor by Grouping 1. xy – 4x + 3y - 12 2. 2xy - 6x - y + 3 3. 2x3 – x2 – 10x + 5 4. 2x + 18 – 9y – xy
  • 9. Factoring: x 2 + bx + c Factor c, using those factors whose sum equals b 1. x2 – 2x – 35 3. x2 + 5x + 1 2. x2 – 7x + 10 4. x2 + x - 2
  • 10. Factoring ax2 + bx + c trinomials First, multiply ac, then, factor c using those factors whose sum is equivalent to b. Finally, use grouping to factor the trinomial 1. 2x2 + 7x + 6 3. 3x2 + 17x + 1 2. 3x2 + 14x - 5 4. 8x2 + 2x - 3 5. 6x2 + 7x - 3
  • 11. Solving Equations by Factoring Zero Factor Theorem • If a and b are real numbers and ab = 0, then a = 0 or b = 0. 1. x2 + 6x + 8 = 0 3. 6x2 - 14x = -8 x = -4, x = -2 x = 1, x = 11/3 2. x2 - 25 = 0 4. 4x2 - 4x = 24 x = 5, x = -5 x = -2, x = 3
  • 12. Difference of Two Squares Another shortcut for factoring a trinomial is when we want to factor the difference of two squares. a2 – b2 = (a + b)(a – b) A binomial is the difference of two squares if: 1.Both terms are squares and 2.The signs of the terms are different. 9x2 – 25y2 – c4 + d4
  • 13. Difference of Two Squares 1. b2 - 49 3. 1 - 16x10 = (b- 7)(b+ 7) (1 - 4x5)(1 + 4x5) 2. 7g3h2 - 28g5 = 4. x2y2 - 25 = 7g3(h2 - 4g2) = (xy - 5)(xy + 5) 7g3(h - 2g)(h + 2g) 5. 144 - x8 = (12 - x4)(12 + x4)