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Circles - Special Cases

                        Mathematics 4


                       August 16, 2011




Mathematics 4 ()         Circles - Special Cases   August 16, 2011   1/8
Circle Equations




What is strange about the following circle equations?
Hint: Convert the equations into standard form.
  1   x2 + y 2 − 8x + 6y + 25 = 0
  2   x2 + y 2 + 10x − 14y + 78 = 0




      Mathematics 4 ()        Circles - Special Cases   August 16, 2011   2/8
Circle Equations




What is strange about the following circle equations?
Hint: Convert the equations into standard form.
  1   x2 + y 2 − 8x + 6y + 25 = 0 → (x − 4)2 + (y + 3)2 = 0
  2   x2 + y 2 + 10x − 14y + 78 = 0 → (x + 5)2 + (y − 7)2 = −4




      Mathematics 4 ()        Circles - Special Cases     August 16, 2011   3/8
Degenerate Sets



Degenerate Sets
A case where a mathematical object belonging to a certain class (circles)
belongs also to a different, simpler class (point).

Degenerate Circles
A point is a degenerate circle (circle equation with zero radius).
e.g. (x − 4)2 + (y + 3)2 = 0




     Mathematics 4 ()          Circles - Special Cases       August 16, 2011   4/8
Null Sets




Null Set Circle Equations
A circle equation with an imaginary radius is a null set.
e.g. (x + 5)2 + (y − 7)2 = −4




     Mathematics 4 ()           Circles - Special Cases     August 16, 2011   5/8
Examples




Circle Equations
Find the values of k so that the graph of x2 + y 2 + 8x − 12y = k + 3 is:
  1   a circle
  2   a point
  3   a null set




      Mathematics 4 ()        Circles - Special Cases       August 16, 2011   6/8
Examples




Circle Equations
Find the values of k so that the graph of x2 + y 2 + 8x − 12y = k + 3 is:
  1   a circle → k > −55
  2   a point → k = −55
  3   a null set → k < −55




      Mathematics 4 ()        Circles - Special Cases       August 16, 2011   7/8
Pair Seatwork 1


Part I.
Identify if the following equations are circles, points, or null sets. Show all
solutions.
  1   2x2 + 2y 2 − 6x + 10y + 9 = 0
  2   9x2 + 9y 2 + 6x − 24y + 17 = 0
  3   6x2 + 6y 2 − 9x + 4y + 7 = 0

Part II. Previous Topics
Find the equations of all circles having a radius whose endpoints are
(−4, 5) and (2, −4). Show all solutions.




      Mathematics 4 ()          Circles - Special Cases         August 16, 2011   8/8

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Circles - Degenerate and Null cases

  • 1. Circles - Special Cases Mathematics 4 August 16, 2011 Mathematics 4 () Circles - Special Cases August 16, 2011 1/8
  • 2. Circle Equations What is strange about the following circle equations? Hint: Convert the equations into standard form. 1 x2 + y 2 − 8x + 6y + 25 = 0 2 x2 + y 2 + 10x − 14y + 78 = 0 Mathematics 4 () Circles - Special Cases August 16, 2011 2/8
  • 3. Circle Equations What is strange about the following circle equations? Hint: Convert the equations into standard form. 1 x2 + y 2 − 8x + 6y + 25 = 0 → (x − 4)2 + (y + 3)2 = 0 2 x2 + y 2 + 10x − 14y + 78 = 0 → (x + 5)2 + (y − 7)2 = −4 Mathematics 4 () Circles - Special Cases August 16, 2011 3/8
  • 4. Degenerate Sets Degenerate Sets A case where a mathematical object belonging to a certain class (circles) belongs also to a different, simpler class (point). Degenerate Circles A point is a degenerate circle (circle equation with zero radius). e.g. (x − 4)2 + (y + 3)2 = 0 Mathematics 4 () Circles - Special Cases August 16, 2011 4/8
  • 5. Null Sets Null Set Circle Equations A circle equation with an imaginary radius is a null set. e.g. (x + 5)2 + (y − 7)2 = −4 Mathematics 4 () Circles - Special Cases August 16, 2011 5/8
  • 6. Examples Circle Equations Find the values of k so that the graph of x2 + y 2 + 8x − 12y = k + 3 is: 1 a circle 2 a point 3 a null set Mathematics 4 () Circles - Special Cases August 16, 2011 6/8
  • 7. Examples Circle Equations Find the values of k so that the graph of x2 + y 2 + 8x − 12y = k + 3 is: 1 a circle → k > −55 2 a point → k = −55 3 a null set → k < −55 Mathematics 4 () Circles - Special Cases August 16, 2011 7/8
  • 8. Pair Seatwork 1 Part I. Identify if the following equations are circles, points, or null sets. Show all solutions. 1 2x2 + 2y 2 − 6x + 10y + 9 = 0 2 9x2 + 9y 2 + 6x − 24y + 17 = 0 3 6x2 + 6y 2 − 9x + 4y + 7 = 0 Part II. Previous Topics Find the equations of all circles having a radius whose endpoints are (−4, 5) and (2, −4). Show all solutions. Mathematics 4 () Circles - Special Cases August 16, 2011 8/8