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CHAPTER 4
        Part ….3
  The Time Value of Money
         Created By
Eng. Maysa Faroon Gharaybeh
Quiz:

• Chapter4 (part2 + part3)
• 55, 60, 62, 68, 72, 95, 99, 100, 103, 112,
  113, 115, 116.
Interest Rates That Vary With Time
• Find the present equivalent value given a future
  value and a varying interest rate over the period of
  the loan ik : the interest rate of the kth period
•       FN                                           P
  = -----------------    eq.(4-31)
        N (1 + ik)
• (P/F,i%,N)= 1/(1+i)N eq.(4-2)
        k+1
You can use (F/P,i%,N)= (1+i)N
Example:
If F4 = $1,000 and i1 = 10% , i2 = 12%, i3= 13%
   and i4=10% then
P = $1,000* (P/F, 10%, 1)* (P/F, 12%, 1)* (P/F,
   13%, 1)* (P/F, 10%, 1)
P = $1,000 (0.9091)(0.8929)(0.8850)(0.9091)
Nominal And Effective Interest Rates
• Nominal Interest Rate (r ) For rates compounded
  more frequently than one time a year, the stated
  annual interest rate.
• Effective Interest Rate ( i ) For rates compounded
  more frequently than one year, the actual amount
  of interest paid.
• i = ( 1 + r / M )M - 1
   M : the number of compounding periods per year
• Annual Percentage Rate ( APR ) percentage rate per
  period times number of periods.
  APR = (r/M) x M
Method1


  Method2


This kind of problems can be solved with two ways :
1. get the effective interest rate which is compatible with the period for
example i = 16.14 per year compounded yearly and N = 10 years
OR
2. use the effective interest rate per quarter = 6%(nominal per year) / 4
(compounded times per year) = 1.5% per quarter compounded quarterly
and N = 10 years * 4 = 40 quarter periods
Continuous Compounding and Discrete Cash Flows

• Continuous compounding assumes cash flows occur at
  discrete intervals, but compounding is continuous
  throughout the interval.
• Given nominal per year interest rate r, compounding per
  year M one unit of principal = [ 1 + (r / M ) ] M
• Given M / r = p,           [ 1 + (r / M ) ] M = [1 + (1/p) ] rp
• Given lim (p        ∞) = [ 1 + (1 / p) ] rp = er
• ( F / P, r%, N ) = (1+i)N = e rN
                           Then i = e r - 1
• End of Chapter 4 PART 3
• See you next lecture with a very important
  revision !!!
• Don’t, miss it !!!!!

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economy Chapter4 part3_by louy al hami

  • 1. CHAPTER 4 Part ….3 The Time Value of Money Created By Eng. Maysa Faroon Gharaybeh
  • 2. Quiz: • Chapter4 (part2 + part3) • 55, 60, 62, 68, 72, 95, 99, 100, 103, 112, 113, 115, 116.
  • 3. Interest Rates That Vary With Time • Find the present equivalent value given a future value and a varying interest rate over the period of the loan ik : the interest rate of the kth period • FN P = ----------------- eq.(4-31) N (1 + ik) • (P/F,i%,N)= 1/(1+i)N eq.(4-2) k+1
  • 4.
  • 5. You can use (F/P,i%,N)= (1+i)N
  • 6. Example: If F4 = $1,000 and i1 = 10% , i2 = 12%, i3= 13% and i4=10% then P = $1,000* (P/F, 10%, 1)* (P/F, 12%, 1)* (P/F, 13%, 1)* (P/F, 10%, 1) P = $1,000 (0.9091)(0.8929)(0.8850)(0.9091)
  • 7. Nominal And Effective Interest Rates • Nominal Interest Rate (r ) For rates compounded more frequently than one time a year, the stated annual interest rate. • Effective Interest Rate ( i ) For rates compounded more frequently than one year, the actual amount of interest paid. • i = ( 1 + r / M )M - 1 M : the number of compounding periods per year • Annual Percentage Rate ( APR ) percentage rate per period times number of periods. APR = (r/M) x M
  • 8.
  • 9.
  • 10.
  • 11. Method1 Method2 This kind of problems can be solved with two ways : 1. get the effective interest rate which is compatible with the period for example i = 16.14 per year compounded yearly and N = 10 years OR 2. use the effective interest rate per quarter = 6%(nominal per year) / 4 (compounded times per year) = 1.5% per quarter compounded quarterly and N = 10 years * 4 = 40 quarter periods
  • 12.
  • 13. Continuous Compounding and Discrete Cash Flows • Continuous compounding assumes cash flows occur at discrete intervals, but compounding is continuous throughout the interval. • Given nominal per year interest rate r, compounding per year M one unit of principal = [ 1 + (r / M ) ] M • Given M / r = p, [ 1 + (r / M ) ] M = [1 + (1/p) ] rp • Given lim (p ∞) = [ 1 + (1 / p) ] rp = er • ( F / P, r%, N ) = (1+i)N = e rN Then i = e r - 1
  • 14.
  • 15.
  • 16.
  • 17.
  • 18. • End of Chapter 4 PART 3 • See you next lecture with a very important revision !!! • Don’t, miss it !!!!!