SlideShare a Scribd company logo
1 of 93
The Basic Language of Functions
Frank Ma Β© 2011
The Basic Language of Functions
A function is a procedure that assigns each input
exactly one output.
The Basic Language of Functions
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…
The Basic Language of Functions
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Example A:
a. Input a number x, the output is (are)
whole number(s) within ΒΎ of x. Is this a function?
The Basic Language of Functions
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Example A:
a. Input a number x, the output is (are)
whole number(s) within ΒΎ of x. Is this a function?
No, this is not a function because if x = Β½, there'll be
two different outputs 0 or 1.
The Basic Language of Functions
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Example A:
a. Input a number x, the output is (are)
whole number(s) within ΒΎ of x. Is this a function?
No, this is not a function because if x = Β½, there'll be
two different outputs 0 or 1.
The Basic Language of Functions
b. Input a number x, the output is the largest integer
less than or equal to x. Is this a function?
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Example A:
a. Input a number x, the output is (are)
whole number(s) within ΒΎ of x. Is this a function?
No, this is not a function because if x = Β½, there'll be
two different outputs 0 or 1.
The Basic Language of Functions
b. Input a number x, the output is the largest integer
less than or equal to x. Is this a function?
This is a function. Its called the greatest integer
function and it’s denoted as [x].
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Example A:
a. Input a number x, the output is (are)
whole number(s) within ΒΎ of x. Is this a function?
No, this is not a function because if x = Β½, there'll be
two different outputs 0 or 1.
The Basic Language of Functions
b. Input a number x, the output is the largest integer
less than or equal to x. Is this a function?
This is a function. Its called the greatest integer
function and it’s denoted as [x]. (so [3.1] = [3] = 3.).
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and we let x represent the input
and y represent the output y.
Given a function, the set D of all the inputs is called
the domain of the function,
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above. Functions may be
given a table as shown.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above. Functions may be
given a table as shown. With this
table we see that 3 is the output for
the input 2,
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above. Functions may be
given a table as shown. With this
table we see that 3 is the output for
the input 2, and
the domain D = {–1, 2, 5, 6, 7},
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above. Functions may be
given a table as shown. With this
table we see that 3 is the output for
the input 2, and
the domain D = {–1, 2, 5, 6, 7},
the range is R = {4, 3, –3, 2}.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function, the set R of all the outputs
is called the range of the function. The domain D of
[x] is the set of all real numbers. The range R of [x] is
the set of all integers. There are many ways to define
functions. Functions may be defined by written
instructions such as [x] above. Functions may be
given a table as shown. With this
table we see that 3 is the output for
the input 2, and
the domain D = {–1, 2, 5, 6, 7},
the range is R = {4, 3, –3, 2}.
Note that we may have the same output
4 for two different inputs –1 and 6.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Functions may be given graphically:
The Basic Language of Functions
Functions may be given graphically:
For instance, Nominal Price(1975) β‰ˆ $0.50
The Basic Language of Functions
Functions may be given graphically:
Domain = {year 1918 οƒ  2005}
For instance, Nominal Price(1975) β‰ˆ $0.50
The Basic Language of Functions
Functions may be given graphically:
Domain = {year 1918 οƒ  2005}
Range (Nominal Price) = {$0.20οƒ $2.51}
For instance, Nominal Price(1975) β‰ˆ $1.00
The Basic Language of Functions
The Basic Language of Functions
Functions may be given graphically:
Inflation Adjusted Price(1975) β‰ˆ $1.85
The Basic Language of Functions
Functions may be given graphically:
Domain = {year 1918 οƒ  2005}
Inflation Adjusted Price(1975) β‰ˆ $1.85
The Basic Language of Functions
Functions may be given graphically:
Domain = {year 1918 οƒ  2005}
Range (Inflation Adjusted Price) = {$1.25οƒ $3.50}
Inflation Adjusted Price(1975) β‰ˆ $1.85
The Basic Language of Functions
Most functions are given by mathematics formulas.
For example,
f(X) = X2
– 2X + 3 = y
The Basic Language of Functions
Most functions are given by mathematics formulas.
For example,
f(X) = X2
– 2X + 3 = y
name of
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
For example,
f(X) = X2
– 2X + 3 = y
name of
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2
– 2(2) + 3 = 3 = y.
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2
– 2(2) + 3 = 3 = y.
The domain of this f(x) is the set of all real numbers.
For example,
f(X) = X2
– 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2
– 2(2) + 3 = 3 = y.
The above function notation is used with the +, –, /,
and * with the obvious interpretation.
The domain of this f(x) is the set of all real numbers.
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
f(x) = –3x + 2
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
copy the input then paste the input
at where the x is
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2) = –3(–2) + 2
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2
– 3x + 1
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2
– 3x + 1
g(–2)
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2
– 3x + 1
g(–2)
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2
– 3x + 1
g(–2)
copy the input
then paste the input
at where the x’s are
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2
– 3x + 1
g(–2) = –2(–2)2
– 3(–2) + 1
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
=
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The function f(x) = c where c is a number is called
a constant function.
The Basic Language of Functions
Example B. Let f(x) = –3x - 3, g(x) = –2x2
– 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2
– 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The function f(x) = c where c is a number is called
a constant function. The outputs of such functions
do not change.
There are two main things to consider when
determining the domains of functions of real numbers.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
b. f (X) = √ 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0
b. f (X) = √ 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3
b. f (X) = √ 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = √ 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = √ 2x + 6
We must have square root of nonnegative numbers.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = √ 2x + 6
We must have square root of nonnegative numbers.
Hence 2x + 6 > 0 οƒ  x > -3
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = √ 2x + 6
We must have square root of nonnegative numbers.
Hence 2x + 6 > 0 οƒ  x > -3
So the domain = {all numbers x > -3}
The Basic Language of Functions
The Basic Language of Functions
Graphs of Functions
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1,
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line.
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line.
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line. Note that the graph of a function may cross any
vertical line at most at one point because for each x
there is only one corresponding output y.
The Basic Language of Functions
Graphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line. Note that the graph of a function may cross any
vertical line at most at one point because for each x
there is only one corresponding output y.
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
,
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2.
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2. So x = y2
is
not a function.
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2. So x = y2
is
not a function.
Plot the graph by the table
shown.
x 0 1 1 4 4
y 0 1 -1 2 -2
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2. So x = y2
is
not a function.
Plot the graph by the table
shown.
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2. So x = y2
is
not a function.
Plot the graph by the table
shown. In particular that if we
draw the vertical line x = 4,
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
it intersects the graph at two points (4, 2) and (4, –2).
The Basic Language of Functions
The equation x = y2
, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs
y’s that satisfy 4 = y2
, namely
y = 2 and y = –2. So x = y2
is
not a function.
Plot the graph by the table
shown. In particular that if we
draw the vertical line x = 4,
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
it intersects the graph at two points (4, 2) and (4, –2).
In general if any vertical line crosses a graph at two
or more points then the graph does not represent any
function.
The Basic Language of Functions
Since for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
The Basic Language of Functions
Since for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
The Basic Language of Functions
Since for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2
),
The Basic Language of Functions
Since for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2
),
then the graph must not be
the graph of a function.
The Basic Language of Functions
Since for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
x 0 1 1 4 4
y 0 1 -1 2 -2
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2
),
then the graph must not be
the graph of a function.
The Basic Language of Functions
Exercise A. For problems 1 – 6, determine if the
given represents a function. If it’s not a function,
give a reason why it’s not.
x y
2 4
2 3
4 3
1. x y
2 4
3 4
4 4
2. 3. 4.
x
y y
6. For any real number input x that is a rational
number, the output is 0, otherwise the output is 1
5. For any input x that is a positive integer, the
outputs are it’s factors.
x
All the (x, y)’s on the curve
The Basic Language of Functions
Exercise B.
Given the functions
f, g and h, find the
outcomes of the
following expressions.
If it’s not defined,
state so.
x y = g(x)
–1 4
2 3
5 –3
6 4
7 2
y = h(x)
f(x) = –3x + 7
7. f(–1) 8.g(–1) 9.h(–1)
10. –f(3) 11. –g(3) 12. –h(3)
13. 3g(6) 14.2f(2) 15. h(3) + h(0)
16. 2f(4) + 3g(2) 17. –f(4) + f(–4) 18. h(6)*[f(2)]2
The Basic Language of Functions
19. f(x) =
1
2x – 6 20. f (x) = √ 2x – 6
Exercise C. Find the domain of the following functions.
23. f(x) =
1
(x – 2)(x + 6) 24. f (x) = √ (x – 2)(x + 6)
21. f(x) =
1
3 – 2x 22. f (x) = √ 3 – 2x
25. f(x) =
1
x2
– 1 26. f (x) = √ 1 – x2
The Basic Language of Functions
27. –f(3) 28. –g(3) 29. –h(3)
30. 3g(2) 31.2f(2) 32. h(3) + h(0)
33. 2f(4) + 3g(2) 34. f(–3/2) 35. g(1/2)
39. f(3a) 40. g(3a) 41. 3g(a)
42. g(a – b) 43. 2f(a – b)
44. f( )a
1 45. f(a)
1
37. h(–3/2) 38. g(–1/2)36. 1/g(2)
Exercise D. Given the functions f, g and h, find the
outcomes of the following expressions. If it’s not
defined, state so.
f(x) = –2x + 3 g(x) = –x2
+ 3x – 2 h(x) =
x + 2
x – 3

More Related Content

What's hot

Application of Integrals
Application of IntegralsApplication of Integrals
Application of Integrals
sarcia
Β 
project
projectproject
project
Vishnu V
Β 
Angles and shapes
Angles and shapesAngles and shapes
Angles and shapes
yuvan80
Β 
CLASS VII -operations on rational numbers(1).pptx
CLASS VII -operations on rational numbers(1).pptxCLASS VII -operations on rational numbers(1).pptx
CLASS VII -operations on rational numbers(1).pptx
Rajkumarknms
Β 
algebraic expression class VIII
algebraic expression class VIIIalgebraic expression class VIII
algebraic expression class VIII
Himani Priya
Β 
3D Coordinate Geometry
3D Coordinate Geometry 3D Coordinate Geometry
3D Coordinate Geometry
ParasKulhari
Β 

What's hot (20)

Application of Integrals
Application of IntegralsApplication of Integrals
Application of Integrals
Β 
Egyptian mathematics
Egyptian mathematicsEgyptian mathematics
Egyptian mathematics
Β 
Fuzzy mathematics:An application oriented introduction
Fuzzy mathematics:An application oriented introductionFuzzy mathematics:An application oriented introduction
Fuzzy mathematics:An application oriented introduction
Β 
project
projectproject
project
Β 
Eulers totient
Eulers totientEulers totient
Eulers totient
Β 
Euler's polyhedron theorem
Euler's polyhedron theoremEuler's polyhedron theorem
Euler's polyhedron theorem
Β 
Linear Equation In one variable class 7
 Linear Equation In one variable class 7 Linear Equation In one variable class 7
Linear Equation In one variable class 7
Β 
MATHEMATICIANS
MATHEMATICIANSMATHEMATICIANS
MATHEMATICIANS
Β 
What is mathematics?
What is mathematics? What is mathematics?
What is mathematics?
Β 
Angles and shapes
Angles and shapesAngles and shapes
Angles and shapes
Β 
Real Numbers
Real NumbersReal Numbers
Real Numbers
Β 
Remainder theorem
Remainder theoremRemainder theorem
Remainder theorem
Β 
CLASS VII -operations on rational numbers(1).pptx
CLASS VII -operations on rational numbers(1).pptxCLASS VII -operations on rational numbers(1).pptx
CLASS VII -operations on rational numbers(1).pptx
Β 
History numbers
History numbersHistory numbers
History numbers
Β 
Simplifying radicals
Simplifying radicalsSimplifying radicals
Simplifying radicals
Β 
algebraic expression class VIII
algebraic expression class VIIIalgebraic expression class VIII
algebraic expression class VIII
Β 
Cartesian coordinate plane
Cartesian coordinate planeCartesian coordinate plane
Cartesian coordinate plane
Β 
3D Coordinate Geometry
3D Coordinate Geometry 3D Coordinate Geometry
3D Coordinate Geometry
Β 
Algebraic expression
Algebraic expressionAlgebraic expression
Algebraic expression
Β 
Cube Root by Prime Factorisation
Cube Root by Prime FactorisationCube Root by Prime Factorisation
Cube Root by Prime Factorisation
Β 

Viewers also liked

51 the basic language of functions
51 the basic language of functions51 the basic language of functions
51 the basic language of functions
math126
Β 
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
UCsanatadharma
Β 
Power point presentation unit 1
Power point presentation unit 1Power point presentation unit 1
Power point presentation unit 1
escobarpaulina
Β 
Reciprocal teaching
Reciprocal teachingReciprocal teaching
Reciprocal teaching
Yeshey Nidup
Β 
Reciprocal teaching day 1
Reciprocal teaching day 1Reciprocal teaching day 1
Reciprocal teaching day 1
Jennifer Evans
Β 
Celtic Languages by Chris Hall
Celtic Languages by Chris HallCeltic Languages by Chris Hall
Celtic Languages by Chris Hall
montathomas
Β 
Reciprocal Teaching
Reciprocal TeachingReciprocal Teaching
Reciprocal Teaching
dawnreynolds
Β 
Language functions and notions
Language functions and notionsLanguage functions and notions
Language functions and notions
Ian Lao
Β 

Viewers also liked (20)

Language functions
Language functionsLanguage functions
Language functions
Β 
51 the basic language of functions
51 the basic language of functions51 the basic language of functions
51 the basic language of functions
Β 
Function of language
Function of languageFunction of language
Function of language
Β 
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
How Drilling Helps The Students On Semester 2 Elesp Sanata Dharma University ...
Β 
Power point presentation unit 1
Power point presentation unit 1Power point presentation unit 1
Power point presentation unit 1
Β 
Translation, interpreting and mediation services in language integration proc...
Translation, interpreting and mediation services in language integration proc...Translation, interpreting and mediation services in language integration proc...
Translation, interpreting and mediation services in language integration proc...
Β 
Reciprocal teaching
Reciprocal teachingReciprocal teaching
Reciprocal teaching
Β 
Language and Identity of United Kingdom
Language and Identity of United KingdomLanguage and Identity of United Kingdom
Language and Identity of United Kingdom
Β 
Reciprocal teaching day 1
Reciprocal teaching day 1Reciprocal teaching day 1
Reciprocal teaching day 1
Β 
Celtic Languages by Chris Hall
Celtic Languages by Chris HallCeltic Languages by Chris Hall
Celtic Languages by Chris Hall
Β 
The ten most spoken languages in the world
The ten most spoken languages in the worldThe ten most spoken languages in the world
The ten most spoken languages in the world
Β 
Reciprocal Teaching
Reciprocal TeachingReciprocal Teaching
Reciprocal Teaching
Β 
English language ppt
English language pptEnglish language ppt
English language ppt
Β 
Reciprocal Teaching
Reciprocal TeachingReciprocal Teaching
Reciprocal Teaching
Β 
Language functions
Language functionsLanguage functions
Language functions
Β 
Languages of the world
Languages of the worldLanguages of the world
Languages of the world
Β 
Language functions
Language functionsLanguage functions
Language functions
Β 
Language functions
Language functionsLanguage functions
Language functions
Β 
Language functions and notions
Language functions and notionsLanguage functions and notions
Language functions and notions
Β 
The Uk Slideshare
The Uk   SlideshareThe Uk   Slideshare
The Uk Slideshare
Β 

Similar to 1.4 the basic language of functions

9 the basic language of functions
9 the basic language of functions 9 the basic language of functions
9 the basic language of functions
math260
Β 
3_-_Graphs_and_Functions v3
3_-_Graphs_and_Functions v33_-_Graphs_and_Functions v3
3_-_Graphs_and_Functions v3
Carlos da Maia
Β 
A1 11 functions
A1 11 functionsA1 11 functions
A1 11 functions
vhiggins1
Β 
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdflecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
HebaEng
Β 
Five Languages in a Moment
Five Languages in a MomentFive Languages in a Moment
Five Languages in a Moment
Sergio Gil
Β 

Similar to 1.4 the basic language of functions (20)

1 functions
1 functions1 functions
1 functions
Β 
9 the basic language of functions
9 the basic language of functions 9 the basic language of functions
9 the basic language of functions
Β 
9 the basic language of functions x
9 the basic language of functions x9 the basic language of functions x
9 the basic language of functions x
Β 
2.1 the basic language of functions x
2.1 the basic language of functions x2.1 the basic language of functions x
2.1 the basic language of functions x
Β 
9 the basic language of functions x
9 the basic language of functions x9 the basic language of functions x
9 the basic language of functions x
Β 
Different types of functions
Different types of functionsDifferent types of functions
Different types of functions
Β 
3_-_Graphs_and_Functions v3
3_-_Graphs_and_Functions v33_-_Graphs_and_Functions v3
3_-_Graphs_and_Functions v3
Β 
Domain-and-Range-of-a-Function
Domain-and-Range-of-a-FunctionDomain-and-Range-of-a-Function
Domain-and-Range-of-a-Function
Β 
A1 11 functions
A1 11 functionsA1 11 functions
A1 11 functions
Β 
Functions and Relations
Functions and RelationsFunctions and Relations
Functions and Relations
Β 
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdflecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
lecrfigfdtj x6 I f I ncccfyuggggrst3.pdf
Β 
Function notation by sadiq
Function notation by sadiqFunction notation by sadiq
Function notation by sadiq
Β 
Intro f# functional_programming
Intro f# functional_programmingIntro f# functional_programming
Intro f# functional_programming
Β 
7 functions
7   functions7   functions
7 functions
Β 
Lesson 1
Lesson 1Lesson 1
Lesson 1
Β 
Lesson 1
Lesson 1Lesson 1
Lesson 1
Β 
Five Languages in a Moment
Five Languages in a MomentFive Languages in a Moment
Five Languages in a Moment
Β 
Edsc 304 lesson 1
Edsc 304 lesson 1Edsc 304 lesson 1
Edsc 304 lesson 1
Β 
237654933 mathematics-t-form-6
237654933 mathematics-t-form-6237654933 mathematics-t-form-6
237654933 mathematics-t-form-6
Β 
functions-1.pdf
functions-1.pdffunctions-1.pdf
functions-1.pdf
Β 

More from math123c

123c test 4 review b
123c test  4 review b123c test  4 review b
123c test 4 review b
math123c
Β 
6 binomial theorem
6 binomial theorem6 binomial theorem
6 binomial theorem
math123c
Β 
5.5 permutations and combinations
5.5 permutations and combinations5.5 permutations and combinations
5.5 permutations and combinations
math123c
Β 
5.4 trees and factorials
5.4 trees and factorials5.4 trees and factorials
5.4 trees and factorials
math123c
Β 
5.3 geometric sequences
5.3 geometric sequences5.3 geometric sequences
5.3 geometric sequences
math123c
Β 
5.2 arithmetic sequences
5.2 arithmetic sequences5.2 arithmetic sequences
5.2 arithmetic sequences
math123c
Β 
5.1 sequences
5.1 sequences5.1 sequences
5.1 sequences
math123c
Β 
4.5 matrix notation
4.5 matrix notation4.5 matrix notation
4.5 matrix notation
math123c
Β 
4.4 system of linear equations 2
4.4 system of linear equations 24.4 system of linear equations 2
4.4 system of linear equations 2
math123c
Β 
4.3 system of linear equations 1
4.3 system of linear equations 14.3 system of linear equations 1
4.3 system of linear equations 1
math123c
Β 
4.2 stem parabolas revisited
4.2 stem parabolas revisited4.2 stem parabolas revisited
4.2 stem parabolas revisited
math123c
Β 
4.1 stem hyperbolas
4.1 stem hyperbolas4.1 stem hyperbolas
4.1 stem hyperbolas
math123c
Β 
3.4 ellipses
3.4 ellipses3.4 ellipses
3.4 ellipses
math123c
Β 
3.3 conic sections circles
3.3 conic sections circles3.3 conic sections circles
3.3 conic sections circles
math123c
Β 
3.2 more on log and exponential equations
3.2 more on log and exponential equations3.2 more on log and exponential equations
3.2 more on log and exponential equations
math123c
Β 
3.1 properties of logarithm
3.1 properties of logarithm3.1 properties of logarithm
3.1 properties of logarithm
math123c
Β 
2.5 calculation with log and exp
2.5 calculation with log and exp2.5 calculation with log and exp
2.5 calculation with log and exp
math123c
Β 
2.4 introduction to logarithm
2.4 introduction to logarithm2.4 introduction to logarithm
2.4 introduction to logarithm
math123c
Β 
2.3 continuous compound interests
2.3 continuous compound interests2.3 continuous compound interests
2.3 continuous compound interests
math123c
Β 

More from math123c (20)

0. exponents y
0. exponents y0. exponents y
0. exponents y
Β 
123c test 4 review b
123c test  4 review b123c test  4 review b
123c test 4 review b
Β 
6 binomial theorem
6 binomial theorem6 binomial theorem
6 binomial theorem
Β 
5.5 permutations and combinations
5.5 permutations and combinations5.5 permutations and combinations
5.5 permutations and combinations
Β 
5.4 trees and factorials
5.4 trees and factorials5.4 trees and factorials
5.4 trees and factorials
Β 
5.3 geometric sequences
5.3 geometric sequences5.3 geometric sequences
5.3 geometric sequences
Β 
5.2 arithmetic sequences
5.2 arithmetic sequences5.2 arithmetic sequences
5.2 arithmetic sequences
Β 
5.1 sequences
5.1 sequences5.1 sequences
5.1 sequences
Β 
4.5 matrix notation
4.5 matrix notation4.5 matrix notation
4.5 matrix notation
Β 
4.4 system of linear equations 2
4.4 system of linear equations 24.4 system of linear equations 2
4.4 system of linear equations 2
Β 
4.3 system of linear equations 1
4.3 system of linear equations 14.3 system of linear equations 1
4.3 system of linear equations 1
Β 
4.2 stem parabolas revisited
4.2 stem parabolas revisited4.2 stem parabolas revisited
4.2 stem parabolas revisited
Β 
4.1 stem hyperbolas
4.1 stem hyperbolas4.1 stem hyperbolas
4.1 stem hyperbolas
Β 
3.4 ellipses
3.4 ellipses3.4 ellipses
3.4 ellipses
Β 
3.3 conic sections circles
3.3 conic sections circles3.3 conic sections circles
3.3 conic sections circles
Β 
3.2 more on log and exponential equations
3.2 more on log and exponential equations3.2 more on log and exponential equations
3.2 more on log and exponential equations
Β 
3.1 properties of logarithm
3.1 properties of logarithm3.1 properties of logarithm
3.1 properties of logarithm
Β 
2.5 calculation with log and exp
2.5 calculation with log and exp2.5 calculation with log and exp
2.5 calculation with log and exp
Β 
2.4 introduction to logarithm
2.4 introduction to logarithm2.4 introduction to logarithm
2.4 introduction to logarithm
Β 
2.3 continuous compound interests
2.3 continuous compound interests2.3 continuous compound interests
2.3 continuous compound interests
Β 

Recently uploaded

Recently uploaded (20)

EMPOWERMENT TECHNOLOGY GRADE 11 QUARTER 2 REVIEWER
EMPOWERMENT TECHNOLOGY GRADE 11 QUARTER 2 REVIEWEREMPOWERMENT TECHNOLOGY GRADE 11 QUARTER 2 REVIEWER
EMPOWERMENT TECHNOLOGY GRADE 11 QUARTER 2 REVIEWER
Β 
Automating Google Workspace (GWS) & more with Apps Script
Automating Google Workspace (GWS) & more with Apps ScriptAutomating Google Workspace (GWS) & more with Apps Script
Automating Google Workspace (GWS) & more with Apps Script
Β 
Exploring the Future Potential of AI-Enabled Smartphone Processors
Exploring the Future Potential of AI-Enabled Smartphone ProcessorsExploring the Future Potential of AI-Enabled Smartphone Processors
Exploring the Future Potential of AI-Enabled Smartphone Processors
Β 
Strategies for Landing an Oracle DBA Job as a Fresher
Strategies for Landing an Oracle DBA Job as a FresherStrategies for Landing an Oracle DBA Job as a Fresher
Strategies for Landing an Oracle DBA Job as a Fresher
Β 
ICT role in 21st century education and its challenges
ICT role in 21st century education and its challengesICT role in 21st century education and its challenges
ICT role in 21st century education and its challenges
Β 
TrustArc Webinar - Stay Ahead of US State Data Privacy Law Developments
TrustArc Webinar - Stay Ahead of US State Data Privacy Law DevelopmentsTrustArc Webinar - Stay Ahead of US State Data Privacy Law Developments
TrustArc Webinar - Stay Ahead of US State Data Privacy Law Developments
Β 
presentation ICT roal in 21st century education
presentation ICT roal in 21st century educationpresentation ICT roal in 21st century education
presentation ICT roal in 21st century education
Β 
A Beginners Guide to Building a RAG App Using Open Source Milvus
A Beginners Guide to Building a RAG App Using Open Source MilvusA Beginners Guide to Building a RAG App Using Open Source Milvus
A Beginners Guide to Building a RAG App Using Open Source Milvus
Β 
Navi Mumbai Call Girls πŸ₯° 8617370543 Service Offer VIP Hot Model
Navi Mumbai Call Girls πŸ₯° 8617370543 Service Offer VIP Hot ModelNavi Mumbai Call Girls πŸ₯° 8617370543 Service Offer VIP Hot Model
Navi Mumbai Call Girls πŸ₯° 8617370543 Service Offer VIP Hot Model
Β 
Web Form Automation for Bonterra Impact Management (fka Social Solutions Apri...
Web Form Automation for Bonterra Impact Management (fka Social Solutions Apri...Web Form Automation for Bonterra Impact Management (fka Social Solutions Apri...
Web Form Automation for Bonterra Impact Management (fka Social Solutions Apri...
Β 
Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)
Β 
Boost Fertility New Invention Ups Success Rates.pdf
Boost Fertility New Invention Ups Success Rates.pdfBoost Fertility New Invention Ups Success Rates.pdf
Boost Fertility New Invention Ups Success Rates.pdf
Β 
Strategies for Unlocking Knowledge Management in Microsoft 365 in the Copilot...
Strategies for Unlocking Knowledge Management in Microsoft 365 in the Copilot...Strategies for Unlocking Knowledge Management in Microsoft 365 in the Copilot...
Strategies for Unlocking Knowledge Management in Microsoft 365 in the Copilot...
Β 
AWS Community Day CPH - Three problems of Terraform
AWS Community Day CPH - Three problems of TerraformAWS Community Day CPH - Three problems of Terraform
AWS Community Day CPH - Three problems of Terraform
Β 
Data Cloud, More than a CDP by Matt Robison
Data Cloud, More than a CDP by Matt RobisonData Cloud, More than a CDP by Matt Robison
Data Cloud, More than a CDP by Matt Robison
Β 
Artificial Intelligence Chap.5 : Uncertainty
Artificial Intelligence Chap.5 : UncertaintyArtificial Intelligence Chap.5 : Uncertainty
Artificial Intelligence Chap.5 : Uncertainty
Β 
ProductAnonymous-April2024-WinProductDiscovery-MelissaKlemke
ProductAnonymous-April2024-WinProductDiscovery-MelissaKlemkeProductAnonymous-April2024-WinProductDiscovery-MelissaKlemke
ProductAnonymous-April2024-WinProductDiscovery-MelissaKlemke
Β 
How to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected WorkerHow to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected Worker
Β 
Manulife - Insurer Transformation Award 2024
Manulife - Insurer Transformation Award 2024Manulife - Insurer Transformation Award 2024
Manulife - Insurer Transformation Award 2024
Β 
AXA XL - Insurer Innovation Award Americas 2024
AXA XL - Insurer Innovation Award Americas 2024AXA XL - Insurer Innovation Award Americas 2024
AXA XL - Insurer Innovation Award Americas 2024
Β 

1.4 the basic language of functions

  • 1. The Basic Language of Functions Frank Ma Β© 2011
  • 2. The Basic Language of Functions A function is a procedure that assigns each input exactly one output.
  • 3. The Basic Language of Functions A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…
  • 4. The Basic Language of Functions A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 5. Example A: a. Input a number x, the output is (are) whole number(s) within ΒΎ of x. Is this a function? The Basic Language of Functions A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 6. Example A: a. Input a number x, the output is (are) whole number(s) within ΒΎ of x. Is this a function? No, this is not a function because if x = Β½, there'll be two different outputs 0 or 1. The Basic Language of Functions A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 7. Example A: a. Input a number x, the output is (are) whole number(s) within ΒΎ of x. Is this a function? No, this is not a function because if x = Β½, there'll be two different outputs 0 or 1. The Basic Language of Functions b. Input a number x, the output is the largest integer less than or equal to x. Is this a function? A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 8. Example A: a. Input a number x, the output is (are) whole number(s) within ΒΎ of x. Is this a function? No, this is not a function because if x = Β½, there'll be two different outputs 0 or 1. The Basic Language of Functions b. Input a number x, the output is the largest integer less than or equal to x. Is this a function? This is a function. Its called the greatest integer function and it’s denoted as [x]. A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 9. Example A: a. Input a number x, the output is (are) whole number(s) within ΒΎ of x. Is this a function? No, this is not a function because if x = Β½, there'll be two different outputs 0 or 1. The Basic Language of Functions b. Input a number x, the output is the largest integer less than or equal to x. Is this a function? This is a function. Its called the greatest integer function and it’s denoted as [x]. (so [3.1] = [3] = 3.). A function is a procedure that assigns each input exactly one output. In mathematics, usually we name functions as f, g, h…and we let x represent the input and y represent the output y.
  • 10. Given a function, the set D of all the inputs is called the domain of the function, The Basic Language of Functions
  • 11. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The Basic Language of Functions
  • 12. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The Basic Language of Functions
  • 13. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. The Basic Language of Functions
  • 14. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. The Basic Language of Functions
  • 15. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. The Basic Language of Functions
  • 16. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. Functions may be given a table as shown. The Basic Language of Functions x y –1 4 2 3 5 –3 6 4 7 2
  • 17. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. Functions may be given a table as shown. With this table we see that 3 is the output for the input 2, The Basic Language of Functions x y –1 4 2 3 5 –3 6 4 7 2
  • 18. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. Functions may be given a table as shown. With this table we see that 3 is the output for the input 2, and the domain D = {–1, 2, 5, 6, 7}, The Basic Language of Functions x y –1 4 2 3 5 –3 6 4 7 2
  • 19. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. Functions may be given a table as shown. With this table we see that 3 is the output for the input 2, and the domain D = {–1, 2, 5, 6, 7}, the range is R = {4, 3, –3, 2}. The Basic Language of Functions x y –1 4 2 3 5 –3 6 4 7 2
  • 20. Given a function, the set D of all the inputs is called the domain of the function, the set R of all the outputs is called the range of the function. The domain D of [x] is the set of all real numbers. The range R of [x] is the set of all integers. There are many ways to define functions. Functions may be defined by written instructions such as [x] above. Functions may be given a table as shown. With this table we see that 3 is the output for the input 2, and the domain D = {–1, 2, 5, 6, 7}, the range is R = {4, 3, –3, 2}. Note that we may have the same output 4 for two different inputs –1 and 6. The Basic Language of Functions x y –1 4 2 3 5 –3 6 4 7 2
  • 21. Functions may be given graphically: The Basic Language of Functions
  • 22. Functions may be given graphically: For instance, Nominal Price(1975) β‰ˆ $0.50 The Basic Language of Functions
  • 23. Functions may be given graphically: Domain = {year 1918 οƒ  2005} For instance, Nominal Price(1975) β‰ˆ $0.50 The Basic Language of Functions
  • 24. Functions may be given graphically: Domain = {year 1918 οƒ  2005} Range (Nominal Price) = {$0.20οƒ $2.51} For instance, Nominal Price(1975) β‰ˆ $1.00 The Basic Language of Functions
  • 25. The Basic Language of Functions Functions may be given graphically: Inflation Adjusted Price(1975) β‰ˆ $1.85
  • 26. The Basic Language of Functions Functions may be given graphically: Domain = {year 1918 οƒ  2005} Inflation Adjusted Price(1975) β‰ˆ $1.85
  • 27. The Basic Language of Functions Functions may be given graphically: Domain = {year 1918 οƒ  2005} Range (Inflation Adjusted Price) = {$1.25οƒ $3.50} Inflation Adjusted Price(1975) β‰ˆ $1.85
  • 28. The Basic Language of Functions Most functions are given by mathematics formulas.
  • 29. For example, f(X) = X2 – 2X + 3 = y The Basic Language of Functions Most functions are given by mathematics formulas.
  • 30. For example, f(X) = X2 – 2X + 3 = y name of the function The Basic Language of Functions Most functions are given by mathematics formulas.
  • 31. For example, f(X) = X2 – 2X + 3 = y name of the function The Basic Language of Functions Most functions are given by mathematics formulas. input box
  • 32. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The Basic Language of Functions Most functions are given by mathematics formulas. input box
  • 33. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The output The Basic Language of Functions Most functions are given by mathematics formulas. input box
  • 34. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The output The Basic Language of Functions Most functions are given by mathematics formulas. input box The input box holds the input for the formula.
  • 35. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The output The Basic Language of Functions Most functions are given by mathematics formulas. input box The input box holds the input for the formula. Hence f (2) means to replace x by (2) in the formula, so f(2) = (2)2 – 2(2) + 3 = 3 = y.
  • 36. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The output The Basic Language of Functions Most functions are given by mathematics formulas. input box The input box holds the input for the formula. Hence f (2) means to replace x by (2) in the formula, so f(2) = (2)2 – 2(2) + 3 = 3 = y. The domain of this f(x) is the set of all real numbers.
  • 37. For example, f(X) = X2 – 2X + 3 = y name of actual formula the function The output The Basic Language of Functions Most functions are given by mathematics formulas. input box The input box holds the input for the formula. Hence f (2) means to replace x by (2) in the formula, so f(2) = (2)2 – 2(2) + 3 = 3 = y. The above function notation is used with the +, –, /, and * with the obvious interpretation. The domain of this f(x) is the set of all real numbers.
  • 38. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2)
  • 39. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2) f(x) = –3x + 2
  • 40. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2) f(x) = –3x + 2 f(–2)
  • 41. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2) f(x) = –3x + 2 f(–2) copy the input
  • 42. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2) f(x) = –3x + 2 f(–2) copy the input then paste the input at where the x is
  • 43. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3. a. Evaluate f(–2) f(x) = –3x + 2 f(–2) = –3(–2) + 2
  • 44. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3
  • 45. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2).
  • 46. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(x) = –2x2 – 3x + 1
  • 47. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(x) = –2x2 – 3x + 1 g(–2)
  • 48. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(x) = –2x2 – 3x + 1 g(–2) copy the input
  • 49. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(x) = –2x2 – 3x + 1 g(–2) copy the input then paste the input at where the x’s are
  • 50. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(x) = –2x2 – 3x + 1 g(–2) = –2(–2)2 – 3(–2) + 1 copy the input
  • 51. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1
  • 52. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1
  • 53. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1 c. Evaluate f(–2) – g(–2).
  • 54. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1 c. Evaluate f(–2) – g(–2). Using the outputs of parts a and b we’ve f(–2) – g(–2) =
  • 55. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1 c. Evaluate f(–2) – g(–2). Using the outputs of parts a and b we’ve f(–2) – g(–2) = 3 – (–1) = 4
  • 56. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1 c. Evaluate f(–2) – g(–2). Using the outputs of parts a and b we’ve f(–2) – g(–2) = 3 – (–1) = 4 The function f(x) = c where c is a number is called a constant function.
  • 57. The Basic Language of Functions Example B. Let f(x) = –3x - 3, g(x) = –2x2 – 3x + 1. a. Evaluate f(–2). f(–2) = –3(–2) – 3 = 3 b. Evaluate g(–2). g(–2) = –2(–2)2 – 3(–2) + 1 = –8 + 6 + 1 = –1 c. Evaluate f(–2) – g(–2). Using the outputs of parts a and b we’ve f(–2) – g(–2) = 3 – (–1) = 4 The function f(x) = c where c is a number is called a constant function. The outputs of such functions do not change.
  • 58. There are two main things to consider when determining the domains of functions of real numbers. The Basic Language of Functions
  • 59. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 The Basic Language of Functions
  • 60. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. The Basic Language of Functions
  • 61. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) b. f (X) = √ 2x + 6 The Basic Language of Functions
  • 62. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 b. f (X) = √ 2x + 6 The Basic Language of Functions
  • 63. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3 b. f (X) = √ 2x + 6 The Basic Language of Functions
  • 64. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3 So the domain = {all numbers except x = -3}. b. f (X) = √ 2x + 6 The Basic Language of Functions
  • 65. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3 So the domain = {all numbers except x = -3}. b. f (X) = √ 2x + 6 We must have square root of nonnegative numbers. The Basic Language of Functions
  • 66. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3 So the domain = {all numbers except x = -3}. b. f (X) = √ 2x + 6 We must have square root of nonnegative numbers. Hence 2x + 6 > 0 οƒ  x > -3 The Basic Language of Functions
  • 67. There are two main things to consider when determining the domains of functions of real numbers. 1. The denominators can't be 0 2. The radicand of square root (or any even root) can't be negative. Example C. Find the domain of the following functions. a. f(x) = 1/(2x + 6) The denominator can’t be 0 i.e. 2x + 6 = 0 οƒ  x = -3 So the domain = {all numbers except x = -3}. b. f (X) = √ 2x + 6 We must have square root of nonnegative numbers. Hence 2x + 6 > 0 οƒ  x > -3 So the domain = {all numbers x > -3} The Basic Language of Functions
  • 68. The Basic Language of Functions Graphs of Functions
  • 69. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x).
  • 70. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1,
  • 71. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x).
  • 72. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x). x 0 1 2 3 y = f(x) 1 2 3 4
  • 73. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x). x 0 1 2 3 y = f(x) 1 2 3 4 Plot the (x, y)’s and we have the graph of f(x) = x + 1, a line.
  • 74. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x). x 0 1 2 3 y = f(x) 1 2 3 4 y = x + 1 Plot the (x, y)’s and we have the graph of f(x) = x + 1, a line.
  • 75. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x). x 0 1 2 3 y = f(x) 1 2 3 4 y = x + 1 Plot the (x, y)’s and we have the graph of f(x) = x + 1, a line. Note that the graph of a function may cross any vertical line at most at one point because for each x there is only one corresponding output y.
  • 76. The Basic Language of Functions Graphs of Functions The plot of all points (x, y)’s that satisfy a given function y = f(x) is the graph of the function y = f(x). For example, let the function f(x) = x + 1, set y = f(x) and make a table of few of the ordered pairs (x, y)’s that satisfy the equation y = f(x). x 0 1 2 3 y = f(x) 1 2 3 4 y = x + 1 Plot the (x, y)’s and we have the graph of f(x) = x + 1, a line. Note that the graph of a function may cross any vertical line at most at one point because for each x there is only one corresponding output y.
  • 77. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function.
  • 78. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 ,
  • 79. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2.
  • 80. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2. So x = y2 is not a function.
  • 81. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2. So x = y2 is not a function. Plot the graph by the table shown. x 0 1 1 4 4 y 0 1 -1 2 -2
  • 82. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2. So x = y2 is not a function. Plot the graph by the table shown. x 0 1 1 4 4 y 0 1 -1 2 -2 x 0 1 1 4 4 y 0 1 -1 2 -2 x = y2
  • 83. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2. So x = y2 is not a function. Plot the graph by the table shown. In particular that if we draw the vertical line x = 4, x 0 1 1 4 4 y 0 1 -1 2 -2 x 0 1 1 4 4 y 0 1 -1 2 -2 x = y2 it intersects the graph at two points (4, 2) and (4, –2).
  • 84. The Basic Language of Functions The equation x = y2 , treating x as the input, is not a function. For instance, for the input x = 4, there are two outputs y’s that satisfy 4 = y2 , namely y = 2 and y = –2. So x = y2 is not a function. Plot the graph by the table shown. In particular that if we draw the vertical line x = 4, x 0 1 1 4 4 y 0 1 -1 2 -2 x 0 1 1 4 4 y 0 1 -1 2 -2 x = y2 it intersects the graph at two points (4, 2) and (4, –2). In general if any vertical line crosses a graph at two or more points then the graph does not represent any function.
  • 85. The Basic Language of Functions Since for functions each input x has exactly one output, therefore each vertical line can only intersect it’s graph at exactly one location (e.g. y = x + 1).
  • 86. The Basic Language of Functions Since for functions each input x has exactly one output, therefore each vertical line can only intersect it’s graph at exactly one location (e.g. y = x + 1). y = x + 1
  • 87. The Basic Language of Functions Since for functions each input x has exactly one output, therefore each vertical line can only intersect it’s graph at exactly one location (e.g. y = x + 1). y = x + 1 However, if any vertical line intersects a graph at two or more points, i.e. there are two or more outputs y associated to one input x (eg. x = y2 ),
  • 88. The Basic Language of Functions Since for functions each input x has exactly one output, therefore each vertical line can only intersect it’s graph at exactly one location (e.g. y = x + 1). y = x + 1 However, if any vertical line intersects a graph at two or more points, i.e. there are two or more outputs y associated to one input x (eg. x = y2 ), then the graph must not be the graph of a function.
  • 89. The Basic Language of Functions Since for functions each input x has exactly one output, therefore each vertical line can only intersect it’s graph at exactly one location (e.g. y = x + 1). x 0 1 1 4 4 y 0 1 -1 2 -2 y = x + 1 However, if any vertical line intersects a graph at two or more points, i.e. there are two or more outputs y associated to one input x (eg. x = y2 ), then the graph must not be the graph of a function.
  • 90. The Basic Language of Functions Exercise A. For problems 1 – 6, determine if the given represents a function. If it’s not a function, give a reason why it’s not. x y 2 4 2 3 4 3 1. x y 2 4 3 4 4 4 2. 3. 4. x y y 6. For any real number input x that is a rational number, the output is 0, otherwise the output is 1 5. For any input x that is a positive integer, the outputs are it’s factors. x All the (x, y)’s on the curve
  • 91. The Basic Language of Functions Exercise B. Given the functions f, g and h, find the outcomes of the following expressions. If it’s not defined, state so. x y = g(x) –1 4 2 3 5 –3 6 4 7 2 y = h(x) f(x) = –3x + 7 7. f(–1) 8.g(–1) 9.h(–1) 10. –f(3) 11. –g(3) 12. –h(3) 13. 3g(6) 14.2f(2) 15. h(3) + h(0) 16. 2f(4) + 3g(2) 17. –f(4) + f(–4) 18. h(6)*[f(2)]2
  • 92. The Basic Language of Functions 19. f(x) = 1 2x – 6 20. f (x) = √ 2x – 6 Exercise C. Find the domain of the following functions. 23. f(x) = 1 (x – 2)(x + 6) 24. f (x) = √ (x – 2)(x + 6) 21. f(x) = 1 3 – 2x 22. f (x) = √ 3 – 2x 25. f(x) = 1 x2 – 1 26. f (x) = √ 1 – x2
  • 93. The Basic Language of Functions 27. –f(3) 28. –g(3) 29. –h(3) 30. 3g(2) 31.2f(2) 32. h(3) + h(0) 33. 2f(4) + 3g(2) 34. f(–3/2) 35. g(1/2) 39. f(3a) 40. g(3a) 41. 3g(a) 42. g(a – b) 43. 2f(a – b) 44. f( )a 1 45. f(a) 1 37. h(–3/2) 38. g(–1/2)36. 1/g(2) Exercise D. Given the functions f, g and h, find the outcomes of the following expressions. If it’s not defined, state so. f(x) = –2x + 3 g(x) = –x2 + 3x – 2 h(x) = x + 2 x – 3