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Induced emf
• Experiment:




  – When the switch is closed, the ammeter deflects
    momentarily
  – There is an induced emf in the secondary coil (producing
    an induced current) due to the changing magnetic field
    through this coil
• When there is a steady current in the primary coil, the
  ammeter reads zero current
  – Steady magnetic fields cannot produce a current
Magnetic Flux
• In general, induced emf is actually due to a change
  in magnetic flux
• Magnetic flux is defined similarly
     to electric flux:
           Φ B = B⊥ A = BA cos θ

   – Units of flux are T⋅m2 (or Wb)
   – Flux can be positive or negative
• The value of the magnetic flux
  through a loop/surface is
  proportional to the total number
  of field lines passing through the
     loop/surface
Faraday’s Law
• Faraday’s Law says that the magnitude of the
  induced emf in a circuit is equal to the time rate of
  change of the magnetic flux through the circuit
• The average emf ε induced in a circuit containing N
  tightly wound loops is given by:               ∆Φ B
   – Magnetic flux changes by amount ∆ΦB  ε = −N
                                                                ∆t
     during the time interval ∆t
• The minus sign in the equation concerns the sense
  of the polarity of the induced emf in the loop (and
  how it makes current flow in the loop)
  – The direction follows Lenz's law:
     • The direction of the induced emf is such that it produces a current
       whose magnetic field opposes the change in magnetic flux through
       the loop
     • The induced current tends to maintain the original flux through the
       loop
Example Problem #20.58
The square loop shown is made
of wires with a total series
resistance of 10.0 Ω. It is placed
in a uniform 0.100-T magnetic
field directed perpendicular into
the plane of the paper. The loop,
which is hinged at each corner,
is pulled as shown until the
separation between points A and
B is 3.00 m. If this process takes
0.100 s, what is the average
current generated in the loop?
What is the direction of the
current?



                      Solution (details given in class):
                      0.121 A clockwise
Interactive Example Problem:
           Flux and Induced emf in a Loop

   Animation and solution details given in class.




(PHYSLET Physics Exploration 29.3, copyright Pearson Prentice Hall, 2004)
Example Problem #20.29




Find the direction of the current in the resistor R shown in the figure after each
of the following steps (taken in the order given): (a) The switch is closed. (b)
The variable resistance in series with the battery is decreased. (c) The circuit
containing resistor R is moved to the left. (d) The switch is opened.
                    Solution (details given in class):
                    (a) Right to left
                    (b) Right to left
                    (c) Left to right
                    (d) Left to right
Interactive Example Problem:
                   Lenz’s Law

   Animation and solution details given in class.




(PHYSLET Physics Exploration 29.1, copyright Pearson Prentice Hall, 2004)
Applications of Faraday’s Law
• Ground fault interrupter (GFI)




• Electric guitar pickups




• Magnetoencephalography (brain),
  magnetocardiograms (heart and surrounding nerves)
Motional emf
• Consider a straight conducting bar
  moving perpendicularly to the direction                 l
  of a uniform external magnetic field
  – Free charges (e–) experience downward
    force F
  – Creates a charge separation in the conductor
  – Charge separation leads to a downward electric field E
  – Eventually equilibrium is reached and the (downward)
    magnetic force qvB on the electrons balances the (upward)
    electric force qE
     • qE = qvB  E = vB
     • ∆V = El (since E uniform)      ∆V = El = Blv
  – A potential difference is maintained across the conductor as
    long as there is motion through the field
     • If motion is reversed, polarity of potential difference is also reversed
Motional emf
• Now consider the same bar as part of
    a closed conducting path
  – Since the area of the current loop changes
    as the bar moves, an induced emf is
    created due to a changing magnetic flux
    through the loop
  – An induced current is created
  – The direction of the current is counterclockwise (Lenz’s law)
  – Assume bar moves a distance ∆x in time ∆t
     • ∆ΦB = B∆A = Bl∆x
     • From Faraday’s Law (and noting that N = 1):
                      ∆Φ B      ∆x
                  ε =      = Bl    = Blv
                       ∆t       ∆t
                       (motional emf)
Motional emf
• Notes on this experiment:
  – The moving bar acts like a battery with an emf given by the
    previous formula
  – Although the current tends to deplete the
    accumulated charge at each end of the
       bar, the magnetic force pumps more
      charge to maintain a constant potential
    difference
  – At right is the equivalent circuit diagram
  – The work done by the force pulling the rod is the source of
    the electrical energy
  – This setup is not practical; a more practical use of motional
    emf is through a rotating coil of wire (electric generators)
  – Note that a battery can be used to drive a current, which
    establishes a magnetic field, which can propel the bar
Inductive Magnetoreception in Sharks




Physics Today, March 2008
Launching Mechanism (“Rail Gun”)
Example Problem #20.21
A car has a vertical radio antenna 1.20 m long. The
car travels at 65.0 km/h on a horizontal road where the
Earth’s magnetic field is 50.0 µT, directed toward the
north and downwards at an angle of 65.0° below the
horizontal. (a) Specify the direction the car should
move in order to generate the maximum motional emf
in the antenna, with the top of the antenna positive
relative to the bottom. (b) Calculate the magnitude of
this induced emf.

  Solution (details given in class):
  (a) Toward the east
  (b) 4.58 × 10–4 V
Electric Generators
• Alternating current (AC) generators          f = 60 Hz (U.S.)

 ε = NBAω sin ωt                               (ω = 2πf )
 N = # turns in loop coil
 B = magnetic field strength
 A = Area of the loop coil
 ω = angular rotation speed
εmax = NBAω (plane of loop
parallel to magnetic field)
                          (θ = ωt)
εmin = 0 (plane of loop
perpendicular to magnetic field)
• Direct current (DC) generators

(note similarity to DC
motor – Chap. 19)
Motors and Back emf
• Generators convert mechanical energy to electrical
  energy
• Motors convert electrical
    energy to mechanical energy
        generators run in reverse
• As the coil in the motor
  rotates, the changing
  magnetic flux through it
  induces an emf
  – This emf acts to reduce the current in the coil (in
    agreement with Lenz’s law)
  – For this reason, the emf is called a back emf
  – Power requirements for starting a motor or running it under
    heavy loads larger than running under average loads
Self-Inductance
• Consider the effect of current flow in
   a simple circuit with a battery and a
  resistor
   – Faraday’s law prevents the current from
     reaching its maximum value (ε / R)
     immediately after switch is closed
      • Magnetic flux through the loop changes as current increases
      • Resulting induced emf acts to reduce total emf of circuit
   – When the rate of current change lessens as current
     increases, induced emf decreases
• Another example:
  increasing and
  decreasing current in
      a solenoid coil
Self-Inductance
• These effects are called self-induction
• The emf that is produced is called self-induced emf
  (or back emf)               ∆I
                       ε = −L
                                ∆t
  – L is a constant called the inductance
  – The minus sign indicates that a changing current induces
    an emf that is in opposition to that change
  – Units of inductance is the henry (H)  1 H = 1 V⋅s / A
• An expression for inductance can be found by
  equating Faraday’s law with the above:
                        ∆Φ B    ΦB
                    L=N      =N
                         ∆I      I
RL Circuits
• A circuit element having a large inductance is called
  an inductor
                 ∆I
• From ε L = − L ∆t we see that an inductor acts as a
  current stabilizer
  – The larger the inductance in a circuit, the larger the
    opposition to the rate of change of the current
  – Remember that resistance is a measure of the opposition
    to current
• Consider a series circuit
  consisting of a battery,
  resistor, and inductor
  – Current changes most rapidly
    when switch is first closed
     • Back emf largest at this point   (Series RL circuit)
RL Circuits
• Using calculus, we can derive an
  expression for the current in the
  circuit as a function of time
                      ε
   (rise of        I=
                        R
                          (1 − e
                            − Rt / L
                                       )
   current)
  – Similar to charge q as a function of
     time for a charging capacitor
  – Like RC circuits, there is a time constant for the circuit:
                                      L
                                   τ=
                                      R
• When the switch is opened, the current in the circuit
  decreases exponentially with time        ε − Rt / L
                                                       I=       e
                                   (decay of current        R
                                   )
Example Problem #20.53
An 820-turn wire coil of resistance 24.0 Ω is
placed on top of a 12500-turn, 7.00-cm-long
solenoid as shown. Both coil and solenoid have
cross-sectional areas of 1.00×10–4 m2. (a) How
long does it take the solenoid current to reach
0.632 times its maximum value? (b) Determine
the average back emf caused by the self-
inductance of the solenoid during this interval.
(c) The magnetic field produced by the solenoid
at the location of the coil is ½ as strong as the
field at the center of the solenoid. Determine the
average rate of change in magnetic flux through
each turn of the coil during the stated interval.
(d) Find the magnitude of the average             Solution (details given in class):
induced current in the coil.                      (a) 20.0 ms
                                                  (b) 37.9 V
                                                  (c) 1.52 mV
                                                  (d) 51.8 mA

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Inductance

  • 1. Induced emf • Experiment: – When the switch is closed, the ammeter deflects momentarily – There is an induced emf in the secondary coil (producing an induced current) due to the changing magnetic field through this coil • When there is a steady current in the primary coil, the ammeter reads zero current – Steady magnetic fields cannot produce a current
  • 2. Magnetic Flux • In general, induced emf is actually due to a change in magnetic flux • Magnetic flux is defined similarly to electric flux: Φ B = B⊥ A = BA cos θ – Units of flux are T⋅m2 (or Wb) – Flux can be positive or negative • The value of the magnetic flux through a loop/surface is proportional to the total number of field lines passing through the loop/surface
  • 3. Faraday’s Law • Faraday’s Law says that the magnitude of the induced emf in a circuit is equal to the time rate of change of the magnetic flux through the circuit • The average emf ε induced in a circuit containing N tightly wound loops is given by: ∆Φ B – Magnetic flux changes by amount ∆ΦB ε = −N ∆t during the time interval ∆t • The minus sign in the equation concerns the sense of the polarity of the induced emf in the loop (and how it makes current flow in the loop) – The direction follows Lenz's law: • The direction of the induced emf is such that it produces a current whose magnetic field opposes the change in magnetic flux through the loop • The induced current tends to maintain the original flux through the loop
  • 4. Example Problem #20.58 The square loop shown is made of wires with a total series resistance of 10.0 Ω. It is placed in a uniform 0.100-T magnetic field directed perpendicular into the plane of the paper. The loop, which is hinged at each corner, is pulled as shown until the separation between points A and B is 3.00 m. If this process takes 0.100 s, what is the average current generated in the loop? What is the direction of the current? Solution (details given in class): 0.121 A clockwise
  • 5. Interactive Example Problem: Flux and Induced emf in a Loop Animation and solution details given in class. (PHYSLET Physics Exploration 29.3, copyright Pearson Prentice Hall, 2004)
  • 6. Example Problem #20.29 Find the direction of the current in the resistor R shown in the figure after each of the following steps (taken in the order given): (a) The switch is closed. (b) The variable resistance in series with the battery is decreased. (c) The circuit containing resistor R is moved to the left. (d) The switch is opened. Solution (details given in class): (a) Right to left (b) Right to left (c) Left to right (d) Left to right
  • 7. Interactive Example Problem: Lenz’s Law Animation and solution details given in class. (PHYSLET Physics Exploration 29.1, copyright Pearson Prentice Hall, 2004)
  • 8. Applications of Faraday’s Law • Ground fault interrupter (GFI) • Electric guitar pickups • Magnetoencephalography (brain), magnetocardiograms (heart and surrounding nerves)
  • 9. Motional emf • Consider a straight conducting bar moving perpendicularly to the direction l of a uniform external magnetic field – Free charges (e–) experience downward force F – Creates a charge separation in the conductor – Charge separation leads to a downward electric field E – Eventually equilibrium is reached and the (downward) magnetic force qvB on the electrons balances the (upward) electric force qE • qE = qvB  E = vB • ∆V = El (since E uniform)  ∆V = El = Blv – A potential difference is maintained across the conductor as long as there is motion through the field • If motion is reversed, polarity of potential difference is also reversed
  • 10. Motional emf • Now consider the same bar as part of a closed conducting path – Since the area of the current loop changes as the bar moves, an induced emf is created due to a changing magnetic flux through the loop – An induced current is created – The direction of the current is counterclockwise (Lenz’s law) – Assume bar moves a distance ∆x in time ∆t • ∆ΦB = B∆A = Bl∆x • From Faraday’s Law (and noting that N = 1): ∆Φ B ∆x ε = = Bl = Blv ∆t ∆t (motional emf)
  • 11. Motional emf • Notes on this experiment: – The moving bar acts like a battery with an emf given by the previous formula – Although the current tends to deplete the accumulated charge at each end of the bar, the magnetic force pumps more charge to maintain a constant potential difference – At right is the equivalent circuit diagram – The work done by the force pulling the rod is the source of the electrical energy – This setup is not practical; a more practical use of motional emf is through a rotating coil of wire (electric generators) – Note that a battery can be used to drive a current, which establishes a magnetic field, which can propel the bar
  • 12. Inductive Magnetoreception in Sharks Physics Today, March 2008
  • 14. Example Problem #20.21 A car has a vertical radio antenna 1.20 m long. The car travels at 65.0 km/h on a horizontal road where the Earth’s magnetic field is 50.0 µT, directed toward the north and downwards at an angle of 65.0° below the horizontal. (a) Specify the direction the car should move in order to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom. (b) Calculate the magnitude of this induced emf. Solution (details given in class): (a) Toward the east (b) 4.58 × 10–4 V
  • 15. Electric Generators • Alternating current (AC) generators f = 60 Hz (U.S.) ε = NBAω sin ωt (ω = 2πf ) N = # turns in loop coil B = magnetic field strength A = Area of the loop coil ω = angular rotation speed εmax = NBAω (plane of loop parallel to magnetic field) (θ = ωt) εmin = 0 (plane of loop perpendicular to magnetic field) • Direct current (DC) generators (note similarity to DC motor – Chap. 19)
  • 16. Motors and Back emf • Generators convert mechanical energy to electrical energy • Motors convert electrical energy to mechanical energy  generators run in reverse • As the coil in the motor rotates, the changing magnetic flux through it induces an emf – This emf acts to reduce the current in the coil (in agreement with Lenz’s law) – For this reason, the emf is called a back emf – Power requirements for starting a motor or running it under heavy loads larger than running under average loads
  • 17. Self-Inductance • Consider the effect of current flow in a simple circuit with a battery and a resistor – Faraday’s law prevents the current from reaching its maximum value (ε / R) immediately after switch is closed • Magnetic flux through the loop changes as current increases • Resulting induced emf acts to reduce total emf of circuit – When the rate of current change lessens as current increases, induced emf decreases • Another example: increasing and decreasing current in a solenoid coil
  • 18. Self-Inductance • These effects are called self-induction • The emf that is produced is called self-induced emf (or back emf) ∆I ε = −L ∆t – L is a constant called the inductance – The minus sign indicates that a changing current induces an emf that is in opposition to that change – Units of inductance is the henry (H)  1 H = 1 V⋅s / A • An expression for inductance can be found by equating Faraday’s law with the above: ∆Φ B ΦB L=N =N ∆I I
  • 19. RL Circuits • A circuit element having a large inductance is called an inductor ∆I • From ε L = − L ∆t we see that an inductor acts as a current stabilizer – The larger the inductance in a circuit, the larger the opposition to the rate of change of the current – Remember that resistance is a measure of the opposition to current • Consider a series circuit consisting of a battery, resistor, and inductor – Current changes most rapidly when switch is first closed • Back emf largest at this point (Series RL circuit)
  • 20. RL Circuits • Using calculus, we can derive an expression for the current in the circuit as a function of time ε (rise of I= R (1 − e − Rt / L ) current) – Similar to charge q as a function of time for a charging capacitor – Like RC circuits, there is a time constant for the circuit: L τ= R • When the switch is opened, the current in the circuit decreases exponentially with time ε − Rt / L I= e (decay of current R )
  • 21. Example Problem #20.53 An 820-turn wire coil of resistance 24.0 Ω is placed on top of a 12500-turn, 7.00-cm-long solenoid as shown. Both coil and solenoid have cross-sectional areas of 1.00×10–4 m2. (a) How long does it take the solenoid current to reach 0.632 times its maximum value? (b) Determine the average back emf caused by the self- inductance of the solenoid during this interval. (c) The magnetic field produced by the solenoid at the location of the coil is ½ as strong as the field at the center of the solenoid. Determine the average rate of change in magnetic flux through each turn of the coil during the stated interval. (d) Find the magnitude of the average Solution (details given in class): induced current in the coil. (a) 20.0 ms (b) 37.9 V (c) 1.52 mV (d) 51.8 mA