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Organic Chemistry 
 Cover introduction, alkanes, & 
cycloalkanes 
 There will be two quizzes
Standards Covered Today: 
1. Describe the features of a homologous series. 
2. State names and draw structural formulas for 
organic compounds using the IUPAC Naming 
System. 
3. Draw structural formulas and state names of non-cyclic 
(straight chain) alkanes up to C10, including 
isomers. 
4. Draw structural formulas and state names of cyclic 
structures up to C10
Introduction 
 In all organic compounds, 
 all carbon atoms must make four bonds, 
 all oxygen atoms must make two bonds, 
 all nitrogen atoms must make three bonds, 
 all hydrogen atoms must make one bond, 
 and all halogens must make one bond.
Names of Structures 
 Lewis Structures 
 Structural Formulas 
 Condensed Formulas & 
Structures 
 Line Structures C6H14 or CH3(CH2)4CH3
Notes on Structures 
 Structural Formula: shows all bonds including 
hydrogen 
 Condensed Formula: These are generally written 
without lines indicating bonds, or showing lone pairs, 
and parentheses are used for identical groups. 
 Line Formula: Bonds are represented by lines, 
carbon atoms are assumed to be present at the start 
and finish of a line. 
 Nitrogen, oxygen and halogens are labeled, but hydrogens 
are only shown when bonded to a drawn atom. 
 Each atom is assumed to have sufficient hydrogen atoms 
around it to make it neutral.
Isomers 
 Draw a structural formula for C4H10 
 An isomer is a compound that has the same 
molecular formula as another. 
 Structural Isomers: these are isomers that differ in 
their bonding sequence. They have different bond 
connectivity. 
CH3 
CH3 CH2 CH2 CH3 CH3 CH 
CH3 
n-butane isobutane
Introduction to Nomenclature 
of Organic Molecules 
 Four Categories: 
 Alkanes 
 Alkenes 
 Alkynes 
 Cyclic Structures
Alkanes 
 Alkanes are the simplest organic molecules, 
they only contain C and hydrogen, and only 
contain single bonds. 
 Considered to be hydrocarbons 
 Compounds that have the maximum number 
of bonded hydrogens, are said to be 
saturated. 
 Therefore, alkanes are the most saturated 
compounds 
 General Formula: CnH2n + 2
Nomenclature for compounds 
 The root name of the compound is based upon the 
number of carbon atoms in the longest continuous 
chain. 
Number of C atoms Root 
1 Meth- 
2 Eth- 
3 Prop- 
4 But- 
5 Pent- 
6 Hex- 
7 Hept- 
8 Oct- 
9 Non- 
10 Dec-
 Any series that differs only by an increasing 
number of –CH2- groups is known as a 
homologous series. The individual members 
are said to be homologs of each other. 
 The series must contain the same functional 
group. 
H 
C C 
H 
C 
H H 
H 
C 
H 
C 
H 
H 
H 
H 
H 
CH3 
H C C 
H 
H C 
H3C C 
H H 
H 
C 
H 
H 
H 
H 
CH3 
CH3 
CH3 
pentane 
C5H12 
isopentane 
C5H12 
neopentane 
C5H12
IUPAC Naming System: 
Alkanes 
1) Find the longest continuous chain of carbon atoms. This is the 
base name of the compound. 
2) Number the longest chain beginning with the end nearest a 
substituent. 
3) Name the substituent groups attached to the longest chain as 
alkyl groups. Also state the location of each alkyl group 
according to its numbered carbon on the main chain. 
4) When two or more substituents are present, list them in 
alphabetical order. If two or more of the same alkyl groups are 
present, use the prefixes di-, tri- etc. to avoid repetition.
Alkane Nomenclature 
Examples 
1) CH2CH3 
H3C CH-CH2-CH2-CH3 
3-methylhexane 
3-methyl hexane 
• If there are two chains of equal length, choose the 
chain that has the highest number of substituents. 
CH3 
CH2 
HC 
HC 
H3C 
HC 
H3C HC 
CH2CH3 
CH3 
CH3 
CH3 
CH2 
HC 
HC 
H3C 
HC 
H3C HC 
CH2CH3 
CH3 
CH3
 Numbering starts at the end nearest a 
substituent so that the alkyl substituents have 
as low numbers as possible. 
CH3 
CH2 
HC 
HC 
H3C 
HC H3C HC 
CH2CH3 
CH3 
CH3 
CH3 
CH2 
HC 
HC 
H3C 
HC 
H3C HC 
CH2CH3 
CH3 
CH3 
Alkyl groups are named by replacing the –ane suffix of the alkane 
name with –yl. 
E.g. CH3CH3 Ethane CH3CH2- Ethyl group 
CH3CH2CH3 PropaneCH3CH2CH2- Propyl group
 Prefixes are used when there are more 
than one type of alkyl substituent. 
 Di = 2 
 Tri = 3 
 Tetra = 4 
 Penta = 5 
 The prefixes do not count when 
alphabetizing.
CH3 
CH2 
HC 
HC 
H3C 
HC 
H3C HC 
CH2CH3 
CH3 
CH3 
3-ethyl-2,4,5-trimethylheptane
Recognizing Types of 
Substitution 
H 
R C 
H 
R 
R C 
H 
R 
R C 
R 
Primary 
1o carbon 
Secondary 
2o carbon 
Tertiary 
3o carbon
Cycloalkanes 
 Cycloalkanes are simply alkanes that are cyclic. 
 Just add cyclo-before their name. 
 Notice the general formula for cycloalkanes is CnH2n 
H2 
C H2C 
H2C CH2 
CH2 
H2 
C 
H2C CH2 
cyclopropane 
C3H6 
cyclopentane 
C5H10
Two simple rules of 
cycloalkanes 
 Rule A: Decide whether the cyclic or acyclic (non-cyclic) 
portion contains more carbons. This 
determines the base name. (Alkyl substituted 
cycloalkane or cycloalkane substituted alkane). 
 Rule B: Carbons are numbered to give the lowest 
numbers for substituted carbons. 
CH3 
CH3 
CH 
CH3 
CH 
CH3 
methylcyclopentane (1,2-dimethylpropyl)cyclohexane
 Numbering starts at the most substituted carbon, 
and goes around in order to give the lowest 
numbers. 
H 
CH3 
H3C 
CH3 
1,1,3-trimethylcyclopentane 
1,1,3-trimethylcyclopentane 
• When there are more acyclic than cyclic carbons, the cyclic 
part becomes a cycloalkyl substituent. 
4-cyclopropyl-3-methyloctane 
4-cyclopropyl-3-methyloctane
Complex Substituents 
These are named as follows: 
(a) The base alkyl group is numbered staring with the carbon 
bonded to the main chain. 
(b)The substituents are listed with the appropriate numbers, and 
parentheses are used to separate the substituent name. 
CH3 
C-CH2 
CH3 
CH3 
CH-CH3 
a (1,1,3-trimethylbutyl) group
Examples 
 Draw structures for the 
following compounds: 
1.) 3-ethyl-3-methylpentane 
2.) 3-methyl-5-propylnonane 
3.) 2,2,4,4- 
tetramethylhexane 
4.) pentylcyclohexane 
5.) 2,3-dimethyl-4- 
propylnonane 
 Give the IUPAC names of the 
following alkanes: 
1.) (CH3)2CHCH2CH(C2H5)C(CH3)3 
2.) 
3.) (CH3CH2)3CH 
4.) (CH3)2CH(CH2)3CH3
Physical Properties of Alkanes 
 Nonpolar 
 What type of intermolecular forces? 
Dispersion Forces 
 Since weak interactions….so low boiling point and 
melting point 
 As molecular weight increases, interactions 
increase 
 As interactions b/w molecules increase, so does the 
strength of the interactions…. 
 So what conclusions can we make?
 The higher molecular weights….. 
Leads to liquids, then solids 
 The more branches… 
More compact structure, surface area 
decreases 
Less contact between molecules, dispersion 
forces decrease, so lower boiling point
Try these: 
 Arrange in increasing boiling point: 
a. CH3CH2CH2CH3, CH3CH2CH2CH2CH2CH3, 
CH3(CH2)8CH3 
b. CH3(CH2)6CH3, CH3C(CH3)2CH2CH(CH3)2, 
CH3CHCH3(CH2)4CH3 
c. 2-methyl butane, 2,2-dimethylpropane, 
pentane
 Alkene and Alkyne Nomenclature 
Make sure you study the different functional 
groups over the break (sheet of paper with 
table on it) 
 This will need to be memorized for the quiz 
and test. 
 Quiz when we get back!
Elements of Unsaturation 
 A saturated hydrocarbon: CnH2n+2 
 Each multiple bond (and each ring) 
decreases the number of H’s by two. 
 Each of these is an element of unsaturation. 
 To calculate: find number of H’s if it were 
saturated, subtract the actual number of H’s, 
then divide by 2.
Propose a Structure for C5H8 
First calculate the number of elements 
of unsaturation. 
Remember: 
A double bond is one element of 
unsaturation. 
A ring is one element of unsaturation. 
A triple bond is two elements of 
unsaturation.
Alkene Nomenclature 
 Parent is longest chain containing the double 
bond. 
 -ane changes to -ene. (or -diene, -triene) 
 Number the chain so that the double bond 
has the lowest possible number. 
 In a ring, the double bond is assumed to be 
between carbon 1 and carbon 2.
Try these: 
CH2 CH CH2 CH3 
1-butene 
CH3 C 
CH CH3 
CH3 
2-methyl-2-butene 
CH3 
3-methylcyclopentene 
CHCH2CH3 
H3C 
2-(1-methyl propyl)-1,3-cyclohexadiene 
3-propyl-1-heptene
Geometric Isomerism 
 Similar groups on same side of double bond, 
alkene is cis. 
 Similar groups on opposite sides of double bond, 
alkene is trans. 
C C 
CH3 
H 
H 
CH3CH2 
C C 
Br 
H 
Br 
H 
trans-2-pentene cis-1,2-dibromoethene
Alkynes 
 Alkynes contain a triple bond. 
 General formula is CnH2n-2 
 Two elements of unsaturation for each triple 
bond.
Alkyne Nomenclature 
 Find the longest chain containing the triple 
bond. 
 Change -ane ending to -yne. 
 Number the chain, starting at the end closest 
to the triple bond. 
 Give branches or other substituents a 
number to locate their position.
Try these 
CH3 C CH 
CH3 C C CH2 CH2 Br 
CH3 
CH3 CH 
CH3 
CH2 C C CH 
CH3 
propyne 
5-bromo-2-pentyne 
2,6-dimethyl-3-heptyne 
CH3 
CH2 CH CH2 CH 
C CH 3-methyl-1-hexyn-5-ene
Practice Problems 
 Two worksheets
Agenda 
 Review of alkanes, alkenes, alkynes, & cyclic 
structures 
 Nomenclature of Functional Groups
Alcohols 
Simple alcohols are named as derivatives of the 
parent alkane, using the suffix -ol, using the 
following simple rules: 
 Select the longest continuous carbon chain, 
containing the hydroxyl group, and derive the parent 
name by replacing the -e ending with -ol. 
 Number the carbon chain, beginning at the end 
nearest to the hydroxyl group. 
 Number the substituents and write the name, listing 
substituents alphabetically.
Alcohol Examples
Ether Nomenclature 
 Simple ethers are named either by identifying 
the two organic residues and adding the 
word ether . 
CH3—O—CH3 
Dimethyl ether 
CH3CH2OCH2CH3 
Diethyl ether
Aldehydes Nomenclature 
 Aldehydes are named by replacing the 
terminal -e of the parent alkane with the 
suffix -al 
 The parent chain selected must contain the 
carbonyl group. 
 Number the carbon chain, beginning at the 
end nearest to the carbonyl group.
Aldehyde Example 
methanal 
butanal 
2-methyl butanal
Ketone Nomenclature 
 The suffix for ketones is -one. 
 The parent chain selected must contain the 
carbonyl group. 
 Number the carbon chain, beginning at the 
end nearest to the carbonyl group.
Ketone Examples 
3-pentanone propanone 
3-methyl-2-butanone
Carboxylic Acid Nomenclature 
Simple carboxylic acids are named as derivatives of 
the parent alkane, using the suffix -oic acid 
 Select the longest continuous carbon chain, 
containing the carboxylic acid group, and derive the 
parent name by replacing the -e ending with -oic 
acid. 
 Number the carbon chain, beginning at the end 
nearest to the carboxylic acid group. 
 Number the substituents and write the name, listing 
substituents alphabetically. 
 Carboxylic acid substituents attached to rings are 
named using the suffix -carboxylic acid.
Carboxylic Acid Examples
Ester Nomenclature 
 Esters are named by replacing the terminal of 
end with the suffix -oate 
 The parent chain selected must contain the 
 Number the end of the carbon chain (after the 
second O), and give it an –yl ending. 
 Practice Problems
Amine Nomenclature 
 RNH2 , R2NH, R3N 
 In amines, a nitrogen is bonded to one, two 
or three carbon atoms. 
 Practice Problems
Functional Groups as Isomers 
 Some functional groups can exist as isomers 
of each other. 
 Example: C4H8O2
Try the following:

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Organic Chemistry Concepts and Nomenclature

  • 1. Organic Chemistry  Cover introduction, alkanes, & cycloalkanes  There will be two quizzes
  • 2. Standards Covered Today: 1. Describe the features of a homologous series. 2. State names and draw structural formulas for organic compounds using the IUPAC Naming System. 3. Draw structural formulas and state names of non-cyclic (straight chain) alkanes up to C10, including isomers. 4. Draw structural formulas and state names of cyclic structures up to C10
  • 3. Introduction  In all organic compounds,  all carbon atoms must make four bonds,  all oxygen atoms must make two bonds,  all nitrogen atoms must make three bonds,  all hydrogen atoms must make one bond,  and all halogens must make one bond.
  • 4. Names of Structures  Lewis Structures  Structural Formulas  Condensed Formulas & Structures  Line Structures C6H14 or CH3(CH2)4CH3
  • 5. Notes on Structures  Structural Formula: shows all bonds including hydrogen  Condensed Formula: These are generally written without lines indicating bonds, or showing lone pairs, and parentheses are used for identical groups.  Line Formula: Bonds are represented by lines, carbon atoms are assumed to be present at the start and finish of a line.  Nitrogen, oxygen and halogens are labeled, but hydrogens are only shown when bonded to a drawn atom.  Each atom is assumed to have sufficient hydrogen atoms around it to make it neutral.
  • 6. Isomers  Draw a structural formula for C4H10  An isomer is a compound that has the same molecular formula as another.  Structural Isomers: these are isomers that differ in their bonding sequence. They have different bond connectivity. CH3 CH3 CH2 CH2 CH3 CH3 CH CH3 n-butane isobutane
  • 7. Introduction to Nomenclature of Organic Molecules  Four Categories:  Alkanes  Alkenes  Alkynes  Cyclic Structures
  • 8. Alkanes  Alkanes are the simplest organic molecules, they only contain C and hydrogen, and only contain single bonds.  Considered to be hydrocarbons  Compounds that have the maximum number of bonded hydrogens, are said to be saturated.  Therefore, alkanes are the most saturated compounds  General Formula: CnH2n + 2
  • 9. Nomenclature for compounds  The root name of the compound is based upon the number of carbon atoms in the longest continuous chain. Number of C atoms Root 1 Meth- 2 Eth- 3 Prop- 4 But- 5 Pent- 6 Hex- 7 Hept- 8 Oct- 9 Non- 10 Dec-
  • 10.  Any series that differs only by an increasing number of –CH2- groups is known as a homologous series. The individual members are said to be homologs of each other.  The series must contain the same functional group. H C C H C H H H C H C H H H H H CH3 H C C H H C H3C C H H H C H H H H CH3 CH3 CH3 pentane C5H12 isopentane C5H12 neopentane C5H12
  • 11. IUPAC Naming System: Alkanes 1) Find the longest continuous chain of carbon atoms. This is the base name of the compound. 2) Number the longest chain beginning with the end nearest a substituent. 3) Name the substituent groups attached to the longest chain as alkyl groups. Also state the location of each alkyl group according to its numbered carbon on the main chain. 4) When two or more substituents are present, list them in alphabetical order. If two or more of the same alkyl groups are present, use the prefixes di-, tri- etc. to avoid repetition.
  • 12. Alkane Nomenclature Examples 1) CH2CH3 H3C CH-CH2-CH2-CH3 3-methylhexane 3-methyl hexane • If there are two chains of equal length, choose the chain that has the highest number of substituents. CH3 CH2 HC HC H3C HC H3C HC CH2CH3 CH3 CH3 CH3 CH2 HC HC H3C HC H3C HC CH2CH3 CH3 CH3
  • 13.  Numbering starts at the end nearest a substituent so that the alkyl substituents have as low numbers as possible. CH3 CH2 HC HC H3C HC H3C HC CH2CH3 CH3 CH3 CH3 CH2 HC HC H3C HC H3C HC CH2CH3 CH3 CH3 Alkyl groups are named by replacing the –ane suffix of the alkane name with –yl. E.g. CH3CH3 Ethane CH3CH2- Ethyl group CH3CH2CH3 PropaneCH3CH2CH2- Propyl group
  • 14.  Prefixes are used when there are more than one type of alkyl substituent.  Di = 2  Tri = 3  Tetra = 4  Penta = 5  The prefixes do not count when alphabetizing.
  • 15. CH3 CH2 HC HC H3C HC H3C HC CH2CH3 CH3 CH3 3-ethyl-2,4,5-trimethylheptane
  • 16. Recognizing Types of Substitution H R C H R R C H R R C R Primary 1o carbon Secondary 2o carbon Tertiary 3o carbon
  • 17. Cycloalkanes  Cycloalkanes are simply alkanes that are cyclic.  Just add cyclo-before their name.  Notice the general formula for cycloalkanes is CnH2n H2 C H2C H2C CH2 CH2 H2 C H2C CH2 cyclopropane C3H6 cyclopentane C5H10
  • 18. Two simple rules of cycloalkanes  Rule A: Decide whether the cyclic or acyclic (non-cyclic) portion contains more carbons. This determines the base name. (Alkyl substituted cycloalkane or cycloalkane substituted alkane).  Rule B: Carbons are numbered to give the lowest numbers for substituted carbons. CH3 CH3 CH CH3 CH CH3 methylcyclopentane (1,2-dimethylpropyl)cyclohexane
  • 19.  Numbering starts at the most substituted carbon, and goes around in order to give the lowest numbers. H CH3 H3C CH3 1,1,3-trimethylcyclopentane 1,1,3-trimethylcyclopentane • When there are more acyclic than cyclic carbons, the cyclic part becomes a cycloalkyl substituent. 4-cyclopropyl-3-methyloctane 4-cyclopropyl-3-methyloctane
  • 20. Complex Substituents These are named as follows: (a) The base alkyl group is numbered staring with the carbon bonded to the main chain. (b)The substituents are listed with the appropriate numbers, and parentheses are used to separate the substituent name. CH3 C-CH2 CH3 CH3 CH-CH3 a (1,1,3-trimethylbutyl) group
  • 21. Examples  Draw structures for the following compounds: 1.) 3-ethyl-3-methylpentane 2.) 3-methyl-5-propylnonane 3.) 2,2,4,4- tetramethylhexane 4.) pentylcyclohexane 5.) 2,3-dimethyl-4- propylnonane  Give the IUPAC names of the following alkanes: 1.) (CH3)2CHCH2CH(C2H5)C(CH3)3 2.) 3.) (CH3CH2)3CH 4.) (CH3)2CH(CH2)3CH3
  • 22. Physical Properties of Alkanes  Nonpolar  What type of intermolecular forces? Dispersion Forces  Since weak interactions….so low boiling point and melting point  As molecular weight increases, interactions increase  As interactions b/w molecules increase, so does the strength of the interactions….  So what conclusions can we make?
  • 23.  The higher molecular weights….. Leads to liquids, then solids  The more branches… More compact structure, surface area decreases Less contact between molecules, dispersion forces decrease, so lower boiling point
  • 24. Try these:  Arrange in increasing boiling point: a. CH3CH2CH2CH3, CH3CH2CH2CH2CH2CH3, CH3(CH2)8CH3 b. CH3(CH2)6CH3, CH3C(CH3)2CH2CH(CH3)2, CH3CHCH3(CH2)4CH3 c. 2-methyl butane, 2,2-dimethylpropane, pentane
  • 25.  Alkene and Alkyne Nomenclature Make sure you study the different functional groups over the break (sheet of paper with table on it)  This will need to be memorized for the quiz and test.  Quiz when we get back!
  • 26. Elements of Unsaturation  A saturated hydrocarbon: CnH2n+2  Each multiple bond (and each ring) decreases the number of H’s by two.  Each of these is an element of unsaturation.  To calculate: find number of H’s if it were saturated, subtract the actual number of H’s, then divide by 2.
  • 27. Propose a Structure for C5H8 First calculate the number of elements of unsaturation. Remember: A double bond is one element of unsaturation. A ring is one element of unsaturation. A triple bond is two elements of unsaturation.
  • 28. Alkene Nomenclature  Parent is longest chain containing the double bond.  -ane changes to -ene. (or -diene, -triene)  Number the chain so that the double bond has the lowest possible number.  In a ring, the double bond is assumed to be between carbon 1 and carbon 2.
  • 29. Try these: CH2 CH CH2 CH3 1-butene CH3 C CH CH3 CH3 2-methyl-2-butene CH3 3-methylcyclopentene CHCH2CH3 H3C 2-(1-methyl propyl)-1,3-cyclohexadiene 3-propyl-1-heptene
  • 30. Geometric Isomerism  Similar groups on same side of double bond, alkene is cis.  Similar groups on opposite sides of double bond, alkene is trans. C C CH3 H H CH3CH2 C C Br H Br H trans-2-pentene cis-1,2-dibromoethene
  • 31. Alkynes  Alkynes contain a triple bond.  General formula is CnH2n-2  Two elements of unsaturation for each triple bond.
  • 32. Alkyne Nomenclature  Find the longest chain containing the triple bond.  Change -ane ending to -yne.  Number the chain, starting at the end closest to the triple bond.  Give branches or other substituents a number to locate their position.
  • 33. Try these CH3 C CH CH3 C C CH2 CH2 Br CH3 CH3 CH CH3 CH2 C C CH CH3 propyne 5-bromo-2-pentyne 2,6-dimethyl-3-heptyne CH3 CH2 CH CH2 CH C CH 3-methyl-1-hexyn-5-ene
  • 34. Practice Problems  Two worksheets
  • 35. Agenda  Review of alkanes, alkenes, alkynes, & cyclic structures  Nomenclature of Functional Groups
  • 36. Alcohols Simple alcohols are named as derivatives of the parent alkane, using the suffix -ol, using the following simple rules:  Select the longest continuous carbon chain, containing the hydroxyl group, and derive the parent name by replacing the -e ending with -ol.  Number the carbon chain, beginning at the end nearest to the hydroxyl group.  Number the substituents and write the name, listing substituents alphabetically.
  • 38. Ether Nomenclature  Simple ethers are named either by identifying the two organic residues and adding the word ether . CH3—O—CH3 Dimethyl ether CH3CH2OCH2CH3 Diethyl ether
  • 39. Aldehydes Nomenclature  Aldehydes are named by replacing the terminal -e of the parent alkane with the suffix -al  The parent chain selected must contain the carbonyl group.  Number the carbon chain, beginning at the end nearest to the carbonyl group.
  • 40. Aldehyde Example methanal butanal 2-methyl butanal
  • 41. Ketone Nomenclature  The suffix for ketones is -one.  The parent chain selected must contain the carbonyl group.  Number the carbon chain, beginning at the end nearest to the carbonyl group.
  • 42. Ketone Examples 3-pentanone propanone 3-methyl-2-butanone
  • 43. Carboxylic Acid Nomenclature Simple carboxylic acids are named as derivatives of the parent alkane, using the suffix -oic acid  Select the longest continuous carbon chain, containing the carboxylic acid group, and derive the parent name by replacing the -e ending with -oic acid.  Number the carbon chain, beginning at the end nearest to the carboxylic acid group.  Number the substituents and write the name, listing substituents alphabetically.  Carboxylic acid substituents attached to rings are named using the suffix -carboxylic acid.
  • 45. Ester Nomenclature  Esters are named by replacing the terminal of end with the suffix -oate  The parent chain selected must contain the  Number the end of the carbon chain (after the second O), and give it an –yl ending.  Practice Problems
  • 46. Amine Nomenclature  RNH2 , R2NH, R3N  In amines, a nitrogen is bonded to one, two or three carbon atoms.  Practice Problems
  • 47. Functional Groups as Isomers  Some functional groups can exist as isomers of each other.  Example: C4H8O2