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- 2. Delivered by Mr. Ashwin S. Ghonmode Mr. Sachin Gayakawad Mr. Anup Jose Mr. Sachit Rawale Mr. Gopal Malu Mr. Saurabh Singh Mr. Kalim Khan Mr. Shishir Damke Mr. Srinivas Rebbawar Guided by Prof. N.R. Gandlewar Department of Mechanical Engg. R.C.E.R.T. Chandrapur
- 29. Calculation for one kg of wood 1.Mass of water to be evaporated M w = W*(M i -M f )/(100-M f ) where , W = wt. of teak lumber (for1 kg) Initial moisture = M i Final moisture = M f
- 30. 2. Heat required to evaporate Mw = M w *L (L = Latent heat) 3. Area required for Drying timber = Mw*L / It* efficiency
- 32. Time Temp.
- 33. Time Temperature
- 34. Time Temperature
- 35. Days Weight Loss
Notas del editor
- Mass of water to be evaporated M w =W(M i -M f )/(100-M f ) where W- wt. of mahagony timber (for1 kg) M w =1*(35-11)/(100-11) M w =0.2696 kg
- 2. Heat required to evaporate M w = M w *L(L = Latent heat) =0.2696*2.8*10 6 =754880 MJ