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 A magnet is a material
or object that produces a
magnetic field with a
North and South Pole.

Magnetism:   an invisible
force that pushes or pulls
magnetic material.
H
I
S
T
O
R
Y

O
F

M
A
G
N
E
T
S
   Regions of atoms that
    have the same magnetic
    polarity (N/S Alignment).
   Mini-magnets.
   Unmagnetized Iron
       Magnetic domains point
        in different directions.
       Magnetic fields cancel
        each other out.
   Magnetized Iron
       Magnetic domains are
        lined up in the same
        direction
       Magnetic fields amplify
        each other.
The direction of the magnetic force is
       from NORTH to SOUTH
TWO UNLIKE POLES GIVE A              TWO LIKE POLES
  FORCE OF ATTRACTION               TOGETHER WILL HAVE A
                                         FORCE OF
                                        REPULSION
Can you explain what the lines of
  force show?
Where is the strongest part of
  the field?

Where is the weakest part of
  the field?
Small particles of iron filings are pushed into patterns by
a magnetic field. If we sprinkle iron filings on a piece of
paper over a magnet we can see...

The lines of force are very
close together here – the field
is very strong.



The lines of force are further
apart here – the field is weaker.




A line of force links one pole of a magnet to the other pole.
FOR EACH PICTURE IDENTIFY THE FORCE
ILLUSTRATED……………

A)




 B)
MAGNETIC COMPASS

CONTAINS A MAGNET
THAT INTERACTS WITH
THE EARTH'S MAGNETIC
FIELD AND ALIGNS ITSELF
TO POINT TO THE
MAGNETIC NORTH AND
SOUTH POLES.
North magnetic
 pole located at
south geographic
       pole



 South magnetic
 pole located at
north geographic
      pole.
Magnetic declination
 •is the angle between
 magnetic north and
 geographic true north.
 •Angle varies by location
 •Ranges from 0⁰ to 25 ⁰
Electromagnet

   coil of wire that acts as a magnet when
    an Electric
    current is passed through
    it.

   stops being a magnet when the current
    stops.


   Often, the coil is wrapped around a core
    of
    ferromagnetic material like steel, this
    enhances the
    coils magnetic field.
an object made from a
material that is magnetized
              &
creates its own persistent
       magnetic field.

   Example
    refrigerator magnet
 Levitating   trains
  (MagLev)

 Treatdepression &
  chronic headaches

 Electric   motors

 Stereo   Speakers

 Credit   Cards
•Produced by electric currents
•Defined as a Region where magnetic forces
 can be detected.
•Has a North & South magnetic pole
•The SI unit for a large magnetic field is the Tesla
•The SI unit for a smaller magnetic field is the Gauss

•(1 Tesla = 10,000 Gauss).
The strength of a magnetic field (B) is
related to the amount of magnetic force (F)
that is applied to a moving test charge when
it is at a given location in the field.

              B = F magnetic
                    qv

q = test charge magnitude
v = speed of the charge
A proton moving east experiences an upward force of 8.8 x
10-19 N due to the Earth’s magnetic field. The field has a
strength of 5.5 x 10-5 Teslas (T) to the north.


Find the speed of the proton.
q = 1.60 x 10-19 C                   B = Fmagnetic
B = 5.5 x 10-5 T                           qv
Fmagnetic = 8.8 x 10 10-19 N
                                     v = Fmagnetic
                                            qB

                           Fmagnetic = qvb SinѲ
Solution

v =
            8.8 x 10-19 N
      (1.60 x 10-19 C) (5.5 x 10-5 T)


            1.0 x 10 5 m/s
The direction of the
   magnetic force is
  perpendicular to the
 plane of the magnetic
    field and to the
direction of the charge.

  USE THE RIGHT
   HAND RULE!!!
Current carrying wires that are placed
in a magnetic field also experience a
magnetic force.



                             I – CURRENT

           F- FORCE




                      WIRE
The magnitude of the magnetic force can
be written in terms of the current (I)
flowing through the length of the wire (L).

Magnetic Force in a Current Carrying wire

                F = BIL
A 10.0 m long power line carries a current of 20.0 A
perpendicular to the Earth’s magnetic field of
5.5 x 10 10-5 T.
What is the magnetic force experienced by the power
line?

I = 20.0 A
B = 5.5 x 10 10-5 T
L = 10.0 m

                       F = BIL

      F = (5.5 x 10 10-5 T)(20.0 A)(10.0 m) = 0.011 N
Charges that are in motion (an electrical current)
produce magnetic fields.


    Magnetic field moves
    around a wire with a
    current in a circular
    fashion.

    Which direction???
Right Hand Rule

1. Thumb goes in the
direction of the current.

2. Fingers wrap around wire
in the direction of the
magnetic field.
Arranging wire in a coil and running a current
through produces a magnetic field that is similar
                to a bar magnet.
• A coil wound
into a tightly
packed helix.

•Produces a
uniform
magnetic field
when a charge
is applied to it.
1. A particle with a positive charge of q moves with a speed v and passes
   through a magnetic field B parallel with the speed v. What is the magnitude
   of the magnetic force on the particle?



  a) F = qvB
  b) F = -qvB
  c) F = 0
  d) F = qvB/2
  e) F = -qvB/2



  2. In the figure below, a magnetic field of .01 T is applied locally to a wire
  carrying a current of intensity I = 10A. What is the magnitude of the
  magnetic force applied to the wire?



  a) F = .3N
  b) F = .4N
  c) F = .5N
  d) F = 1N
  e) F = 3N
   A wire 36 m long carries a current of 22A from east to west. If the
    maximum magnetic force on the wire at this point is
    downward(toward Earth) and has a magnitude of 4.0 X 10-2 N, find
    the magnitude and direction of the magnetic field at this location.

   Given: l = 36 m I = 22A Fmagnetic = 4.0 X 10 -2 N
   Unknown: B = ???

   Fmagnetic = B ∙ I ∙ l   then       B = Fmagnetic
                                              Il

                                       B=
1. A particle with a positive charge of q moves with a speed v and passes through a magnetic field B parallel with the speed v. What is
     the magnitude of the magnetic force on the particle?
     a) F = qvB
     b) F = -qvB
     c) F = 0
     d) F = qvB/2
     e) F = -qvB/2

     Solution: c)
     The force F, on the charge q moving with a velocity v in a magnetic field b is F = q(v x B).
     The magnitude of F is F = q·v·B·sinθ where θ is the angle between v and B.
     In our case the v and B vectors are parallel, so sinθ = 0. In conclusion F = 0.

2. In the figure below, a magnetic field of .01 T is applied locally to a wire carrying a current of intensity I = 10A. What is the magnitude
      of the magnetic force applied to the wire?
     a) F = .3N
     b) F = .4N
     c) F = .5N
     d) F = 1N
     e) F = 3N

     Solution: b)
     The magnitude of a magnetic force applied to a current-carrying wire situated in a magnetic field is
                                                F = I·B·l·sinθ
      where:
     ·   l is the length of the wire,
     ·   B is the magnetic field strength
     ·   I is the current in the wire,
     ·   θ is the angle between the wire and the magnetic field.
          In our case sinθ = 4/l so l·sinθ = 4m.
                                                  F = 10A·.01T·4m = .4N
   A wire 36 m long carries a current of 22A from east to
    west. If the maximum magnetic force on the wire at this
    point is downward(toward Earth) and has a magnitude of
    4.0 X 10-2 N, find the magnitude and direction of the
    magnetic field at this location.

   Given: l = 36 m I = 22A Fmagnetic = 4.0 X 10 -2 N
   Unknown: B = ???

   Fmagnetic = B ∙ I ∙ l   then        B = Fmagnetic
                                                Il

                                   B = 4.0 X 10-2 N = 5.0 X 10-5 T
                                        (22A)(36m)

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Magnetism physics

  • 1.  A magnet is a material or object that produces a magnetic field with a North and South Pole. Magnetism: an invisible force that pushes or pulls magnetic material.
  • 3. Regions of atoms that have the same magnetic polarity (N/S Alignment).  Mini-magnets.  Unmagnetized Iron  Magnetic domains point in different directions.  Magnetic fields cancel each other out.  Magnetized Iron  Magnetic domains are lined up in the same direction  Magnetic fields amplify each other.
  • 4. The direction of the magnetic force is from NORTH to SOUTH
  • 5. TWO UNLIKE POLES GIVE A TWO LIKE POLES FORCE OF ATTRACTION TOGETHER WILL HAVE A FORCE OF REPULSION Can you explain what the lines of force show? Where is the strongest part of the field? Where is the weakest part of the field?
  • 6. Small particles of iron filings are pushed into patterns by a magnetic field. If we sprinkle iron filings on a piece of paper over a magnet we can see... The lines of force are very close together here – the field is very strong. The lines of force are further apart here – the field is weaker. A line of force links one pole of a magnet to the other pole.
  • 7. FOR EACH PICTURE IDENTIFY THE FORCE ILLUSTRATED…………… A) B)
  • 8. MAGNETIC COMPASS CONTAINS A MAGNET THAT INTERACTS WITH THE EARTH'S MAGNETIC FIELD AND ALIGNS ITSELF TO POINT TO THE MAGNETIC NORTH AND SOUTH POLES.
  • 9. North magnetic pole located at south geographic pole South magnetic pole located at north geographic pole.
  • 10. Magnetic declination •is the angle between magnetic north and geographic true north. •Angle varies by location •Ranges from 0⁰ to 25 ⁰
  • 11. Electromagnet  coil of wire that acts as a magnet when an Electric current is passed through it.  stops being a magnet when the current stops.  Often, the coil is wrapped around a core of ferromagnetic material like steel, this enhances the coils magnetic field.
  • 12. an object made from a material that is magnetized & creates its own persistent magnetic field.  Example refrigerator magnet
  • 13.  Levitating trains (MagLev)  Treatdepression & chronic headaches  Electric motors  Stereo Speakers  Credit Cards
  • 14.
  • 15. •Produced by electric currents •Defined as a Region where magnetic forces can be detected. •Has a North & South magnetic pole •The SI unit for a large magnetic field is the Tesla •The SI unit for a smaller magnetic field is the Gauss •(1 Tesla = 10,000 Gauss).
  • 16. The strength of a magnetic field (B) is related to the amount of magnetic force (F) that is applied to a moving test charge when it is at a given location in the field. B = F magnetic qv q = test charge magnitude v = speed of the charge
  • 17. A proton moving east experiences an upward force of 8.8 x 10-19 N due to the Earth’s magnetic field. The field has a strength of 5.5 x 10-5 Teslas (T) to the north. Find the speed of the proton. q = 1.60 x 10-19 C B = Fmagnetic B = 5.5 x 10-5 T qv Fmagnetic = 8.8 x 10 10-19 N v = Fmagnetic qB Fmagnetic = qvb SinѲ
  • 18. Solution v = 8.8 x 10-19 N (1.60 x 10-19 C) (5.5 x 10-5 T) 1.0 x 10 5 m/s
  • 19. The direction of the magnetic force is perpendicular to the plane of the magnetic field and to the direction of the charge. USE THE RIGHT HAND RULE!!!
  • 20. Current carrying wires that are placed in a magnetic field also experience a magnetic force. I – CURRENT F- FORCE WIRE
  • 21. The magnitude of the magnetic force can be written in terms of the current (I) flowing through the length of the wire (L). Magnetic Force in a Current Carrying wire F = BIL
  • 22. A 10.0 m long power line carries a current of 20.0 A perpendicular to the Earth’s magnetic field of 5.5 x 10 10-5 T. What is the magnetic force experienced by the power line? I = 20.0 A B = 5.5 x 10 10-5 T L = 10.0 m F = BIL F = (5.5 x 10 10-5 T)(20.0 A)(10.0 m) = 0.011 N
  • 23. Charges that are in motion (an electrical current) produce magnetic fields. Magnetic field moves around a wire with a current in a circular fashion. Which direction???
  • 24. Right Hand Rule 1. Thumb goes in the direction of the current. 2. Fingers wrap around wire in the direction of the magnetic field.
  • 25. Arranging wire in a coil and running a current through produces a magnetic field that is similar to a bar magnet.
  • 26. • A coil wound into a tightly packed helix. •Produces a uniform magnetic field when a charge is applied to it.
  • 27. 1. A particle with a positive charge of q moves with a speed v and passes through a magnetic field B parallel with the speed v. What is the magnitude of the magnetic force on the particle? a) F = qvB b) F = -qvB c) F = 0 d) F = qvB/2 e) F = -qvB/2 2. In the figure below, a magnetic field of .01 T is applied locally to a wire carrying a current of intensity I = 10A. What is the magnitude of the magnetic force applied to the wire? a) F = .3N b) F = .4N c) F = .5N d) F = 1N e) F = 3N
  • 28. A wire 36 m long carries a current of 22A from east to west. If the maximum magnetic force on the wire at this point is downward(toward Earth) and has a magnitude of 4.0 X 10-2 N, find the magnitude and direction of the magnetic field at this location.  Given: l = 36 m I = 22A Fmagnetic = 4.0 X 10 -2 N  Unknown: B = ???  Fmagnetic = B ∙ I ∙ l then B = Fmagnetic Il B=
  • 29. 1. A particle with a positive charge of q moves with a speed v and passes through a magnetic field B parallel with the speed v. What is the magnitude of the magnetic force on the particle? a) F = qvB b) F = -qvB c) F = 0 d) F = qvB/2 e) F = -qvB/2 Solution: c) The force F, on the charge q moving with a velocity v in a magnetic field b is F = q(v x B). The magnitude of F is F = q·v·B·sinθ where θ is the angle between v and B. In our case the v and B vectors are parallel, so sinθ = 0. In conclusion F = 0. 2. In the figure below, a magnetic field of .01 T is applied locally to a wire carrying a current of intensity I = 10A. What is the magnitude of the magnetic force applied to the wire? a) F = .3N b) F = .4N c) F = .5N d) F = 1N e) F = 3N Solution: b) The magnitude of a magnetic force applied to a current-carrying wire situated in a magnetic field is F = I·B·l·sinθ where: · l is the length of the wire, · B is the magnetic field strength · I is the current in the wire, · θ is the angle between the wire and the magnetic field. In our case sinθ = 4/l so l·sinθ = 4m. F = 10A·.01T·4m = .4N
  • 30. A wire 36 m long carries a current of 22A from east to west. If the maximum magnetic force on the wire at this point is downward(toward Earth) and has a magnitude of 4.0 X 10-2 N, find the magnitude and direction of the magnetic field at this location.  Given: l = 36 m I = 22A Fmagnetic = 4.0 X 10 -2 N  Unknown: B = ???  Fmagnetic = B ∙ I ∙ l then B = Fmagnetic Il B = 4.0 X 10-2 N = 5.0 X 10-5 T (22A)(36m)