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 "A hundred years from now, it will
not matter what kind of car I drove,
what kind of house I lived in, how
much money I had in the bank...but
the world may be a better place
because I made a difference in the
life of a child." -- Forest Witcraft
 "Education would be much more
effective if its purpose was to ensure
that by the time they leave school
every boy and girl should know how
much they do not know and be
imbued with a lifelong desire to
know it." -- William Haley
 "One looks back with appreciation to
the brilliant teachers, but with
gratitude to those who touched our
human feelings. The curriculum is so
much necessary material, but
warmth is the vital element for the
growing plant and for the soul of the
child." -- Carl Jung
 There are two good
reasons to be a
teacher – June and
July.
 "We spend the first twelve
months of our children's lives
teaching them to walk and talk,
and the next twelve years telling
them to sit down and shut up."
 "A statistician can have his head
in an oven and his feet in ice, and
he will say that on the average
he feels fine."
• I have heard that parallel
lines do meet, but they are
very discrete
BY:
Mrs.ROOHI JILANI
Measuring Angles : In Degrees or Radians
θ
The angle, θ, can be
measured in degrees. This
represents the turn required
to move from one line to the
other in the direction shown.
This turn is measured in
degrees. Degrees are a unit
measuring turning where 360o
is a full turn.
360o
If we imagine a circle of
radius 1 unit, then a full
turn would be a full
circle and the point A
moves would be the
same as the
circumference of the
circle
Radians is another
measure for angles.
This time you represent
the angle as the
distance point A moves
around the
circumference of an
imaginary circle.
A
⇒360o
= 2π radians (or 2π c
)
⇒1o
= 2π c
360o
⇒1 c
= 360o
2π
θ
r
r
Length of arc, L
L = (2π r) θ
360o
Area of sector, A
A = (πr 2
) θ
360o
L = (2π r) θ = r θ
2π
A = (πr2
) θ = ½ r2
θ
2π
In degrees …In radians …
Here we have a sector
draw with angle θ. This
sector has an arc
length of L and an area
of A.
L
Area,A
Uses of radians
1. Convert from degrees to radians
1. 30o
2. 145o
3. 500o
4. -60o
2. Convert from radians to degrees
1. 2
/3 π rads
2. 7
/5 π rads
3. -5
/8 π rads
4. 0.5 rads
Calculate length of the arc and areas for these sectors,
a)
b)
c)
Radius = 4cm
θ = 2
/9 π
Radius = 6.3cm
θ = 3
/7 π
Radius = 14cm
θ = 4.1
Note : angles in radians
Adjacent
Opposite
Hypotenuse
sine θ = opposite ÷ hypotenuse
cosine θ = adjacent ÷ hypotenuse
tangent θ = opposite ÷ adjacent
0o
90o
45o
60o
60o
60o
30o
Hypotenuse = Adjacent
Opposite = 0
sin 0o
= 0 cos 0o
= 1 tan 0o
= 0
Hypotenuse = Opposite
Adjacent = 0
sin 90o
= 1 cos 90o
= 0 tan 90o
=
undefined
Adjacent = Opposite = x
Hypotenuse = x√2
sin 45o
= 1/√2 cos 45o
= 1/√2 tan 45o
= 1
x
x
x
x
x
For 60o
Hypotenuse = x
Adjacent = x Opposite = x √3
2 2
sin 60o
= √3 cos 60o
= 1 tan 60o
= √3
2 2
For 30o
Hypotenuse = x
Opposite = x Adjacent = x √3
2 2
sin 30o
= 1 cos 30o
= √3 tan 30o
= 1
2 2 √3
Some Standard Solutions …
θ
(deg)
0 30 45 60 90
θ
(rads)
0 π
6
π
4
π
3
π
2
sin θ 0 ½ 1
√2
√3
2
1
cos θ 1 √3
2
1
√2
½ 0
tan θ 0 1
√3
1 √3 -
0o
180o
90o
270o
0o180o
90o
270o
0o
180o
90o
270o
0o180o
90o
270o
Opposite = +
Adjacent = +
Opposite = +
Adjacent = -
Opposite = -
Adjacent = -
Opposite = -
Adjacent = +
+
+
+
+
+
+
- -
-
-
-
-
Images from BBC AS Guru
Sin + All +
Tan + Cos +
CAST Diagram
Sin + All +
Tan + Cos +
Solve : sin x = 0.5 for the range 0 ≤ x ≤ 360o
∴ x = arcsin 0.5 = 30o
but sin is positive in two quadrants so
x = 30o
or (180 – 30)=150o
Solve : sin x = 0.5 for the range 0 ≤ x ≤ 360o
∴ x = arcsin 0.5 = 30o
but sin is positive in two quadrants so
x = 30o
or (180 – 30)=150o
Find all the angles (in degrees) in the given range
1. Sin x = - ½ for the range 0 ≤ x ≤ 360o
2. Cos 2x = √3
/2 for the range -360o
≤ x ≤ 360o
3. Tan (2x+40o
) = √3 for the range -180o
≤ x ≤ 180o
Find all the angles (in radian) in the given range
1. Sin x = √3
/2 for the range 0 ≤ x ≤ 2π
2. Cos 2x = -1
/2 for the range -2π ≤ x ≤ 2π
3. Tan (2x+ ½π) = 1 for the range -π ≤ x ≤ π
 A physicist and an engineer are in a hot-air
balloon. Soon, they find themselves lost in a
canyon somewhere. They yell out for help:
"Helllloooooo! Where are we?" 
15 minutes later, they hear an echoing voice:
"Helllloooooo! You're in a hot-air balloon!!" 
The physicist says, "That must have been a
mathematician." 
The engineer asks, "Why do you say that?" 
The physicist replied: "The answer was
absolutely correct, and it was utterly useless." 
Roohi jilani

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Roohi jilani

  • 1.  "A hundred years from now, it will not matter what kind of car I drove, what kind of house I lived in, how much money I had in the bank...but the world may be a better place because I made a difference in the life of a child." -- Forest Witcraft
  • 2.  "Education would be much more effective if its purpose was to ensure that by the time they leave school every boy and girl should know how much they do not know and be imbued with a lifelong desire to know it." -- William Haley
  • 3.  "One looks back with appreciation to the brilliant teachers, but with gratitude to those who touched our human feelings. The curriculum is so much necessary material, but warmth is the vital element for the growing plant and for the soul of the child." -- Carl Jung
  • 4.  There are two good reasons to be a teacher – June and July.
  • 5.  "We spend the first twelve months of our children's lives teaching them to walk and talk, and the next twelve years telling them to sit down and shut up."
  • 6.  "A statistician can have his head in an oven and his feet in ice, and he will say that on the average he feels fine."
  • 7. • I have heard that parallel lines do meet, but they are very discrete
  • 9. Measuring Angles : In Degrees or Radians θ The angle, θ, can be measured in degrees. This represents the turn required to move from one line to the other in the direction shown. This turn is measured in degrees. Degrees are a unit measuring turning where 360o is a full turn. 360o
  • 10. If we imagine a circle of radius 1 unit, then a full turn would be a full circle and the point A moves would be the same as the circumference of the circle Radians is another measure for angles. This time you represent the angle as the distance point A moves around the circumference of an imaginary circle. A ⇒360o = 2π radians (or 2π c ) ⇒1o = 2π c 360o ⇒1 c = 360o 2π
  • 11. θ r r Length of arc, L L = (2π r) θ 360o Area of sector, A A = (πr 2 ) θ 360o L = (2π r) θ = r θ 2π A = (πr2 ) θ = ½ r2 θ 2π In degrees …In radians … Here we have a sector draw with angle θ. This sector has an arc length of L and an area of A. L Area,A Uses of radians
  • 12. 1. Convert from degrees to radians 1. 30o 2. 145o 3. 500o 4. -60o 2. Convert from radians to degrees 1. 2 /3 π rads 2. 7 /5 π rads 3. -5 /8 π rads 4. 0.5 rads
  • 13. Calculate length of the arc and areas for these sectors, a) b) c) Radius = 4cm θ = 2 /9 π Radius = 6.3cm θ = 3 /7 π Radius = 14cm θ = 4.1 Note : angles in radians
  • 14. Adjacent Opposite Hypotenuse sine θ = opposite ÷ hypotenuse cosine θ = adjacent ÷ hypotenuse tangent θ = opposite ÷ adjacent
  • 15. 0o 90o 45o 60o 60o 60o 30o Hypotenuse = Adjacent Opposite = 0 sin 0o = 0 cos 0o = 1 tan 0o = 0 Hypotenuse = Opposite Adjacent = 0 sin 90o = 1 cos 90o = 0 tan 90o = undefined Adjacent = Opposite = x Hypotenuse = x√2 sin 45o = 1/√2 cos 45o = 1/√2 tan 45o = 1 x x x x x For 60o Hypotenuse = x Adjacent = x Opposite = x √3 2 2 sin 60o = √3 cos 60o = 1 tan 60o = √3 2 2 For 30o Hypotenuse = x Opposite = x Adjacent = x √3 2 2 sin 30o = 1 cos 30o = √3 tan 30o = 1 2 2 √3 Some Standard Solutions …
  • 16. θ (deg) 0 30 45 60 90 θ (rads) 0 π 6 π 4 π 3 π 2 sin θ 0 ½ 1 √2 √3 2 1 cos θ 1 √3 2 1 √2 ½ 0 tan θ 0 1 √3 1 √3 -
  • 17. 0o 180o 90o 270o 0o180o 90o 270o 0o 180o 90o 270o 0o180o 90o 270o Opposite = + Adjacent = + Opposite = + Adjacent = - Opposite = - Adjacent = - Opposite = - Adjacent = +
  • 19. Sin + All + Tan + Cos + CAST Diagram
  • 20. Sin + All + Tan + Cos + Solve : sin x = 0.5 for the range 0 ≤ x ≤ 360o ∴ x = arcsin 0.5 = 30o but sin is positive in two quadrants so x = 30o or (180 – 30)=150o
  • 21. Solve : sin x = 0.5 for the range 0 ≤ x ≤ 360o ∴ x = arcsin 0.5 = 30o but sin is positive in two quadrants so x = 30o or (180 – 30)=150o
  • 22. Find all the angles (in degrees) in the given range 1. Sin x = - ½ for the range 0 ≤ x ≤ 360o 2. Cos 2x = √3 /2 for the range -360o ≤ x ≤ 360o 3. Tan (2x+40o ) = √3 for the range -180o ≤ x ≤ 180o Find all the angles (in radian) in the given range 1. Sin x = √3 /2 for the range 0 ≤ x ≤ 2π 2. Cos 2x = -1 /2 for the range -2π ≤ x ≤ 2π 3. Tan (2x+ ½π) = 1 for the range -π ≤ x ≤ π
  • 23.  A physicist and an engineer are in a hot-air balloon. Soon, they find themselves lost in a canyon somewhere. They yell out for help: "Helllloooooo! Where are we?"  15 minutes later, they hear an echoing voice: "Helllloooooo! You're in a hot-air balloon!!"  The physicist says, "That must have been a mathematician."  The engineer asks, "Why do you say that?"  The physicist replied: "The answer was absolutely correct, and it was utterly useless."