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ELECRONIC STRUCTURE OF ATOM ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Bohr’s Atom  Bohr’s Atomic Theory: Explain 1.The stability of atom as opposed to Rutherford’s atomic model. 2. The formation of line spectrum in hydrogen atom. ,[object Object],[object Object]
2. The energy at each  permitted orbit is quantized (only certain specific quantity is allowed) i.e. energy level with a quantum number, n. Energy of electron at energy level n,  E n  = - A / n 2   (Bohr equation)   where A = Rydberg constant. Note:  n = Principle quantum no.  ( n = 1, 2, 3…   )   identifies and determines the the orbit and energy of its electron.
3. At its normal condition, a H atom is at its ground state ( lowest energy state where n =1) 3. If energy is supplied, an electron may absorb a certain amount of energy  to move to a higher energy state called the excited state. 4. Electron at the excited state (i.e. at a higher energy state, E i ) is unstable , tends to return to a lower energy state ( E f ).
[object Object],[object Object],[object Object],[object Object],Planck relates energy of a radiation to its frequency by, E = h   -------------( 2 ) Where h = Planck constant,    = frequency of light
Subst. (2) into (1). Then  h    = - A/ n f 2  – (- A./n i 2  )  E  = A( 1/n i 2  – 1/n f 2  )---------   (i) =  E f  – E i   ----------------------------------------------(ii) Where A = Rch = Rydberg constant =  2.178 x 10 -18   J
But  velocity of light (radiation),  c   =   λ  x     where  λ =  wavelength  &    =   frequency Hence,  E = h x (c/  λ ) Planck relates energy of a radiation to its frequency by, E = h   Where h = Planck constant,    = frequency of light Planck Equation:
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
i.  Energy of an electron  E 2  =  - 2.18 x 10 -18  J / 2 2   =  -5.45 x 10  -19  J E 4  = -  2.18 x 10 -18  J / 4 2   =  -1.36 x 10 - 19  J ii.  Energy given out  Δ  E = E f  – E i   = E 2  – E 4    =  -5.45 x 10  -19  J – (-1.36 x 10  -19  J) =  - 4.09 x 10  -19  J   ANS:
[object Object],[object Object],[object Object],iv.  energy required  for e translation,  n =2    n = 4. =   4.09 x 10  -19  J
e.g. 2.  Find the a quantum of  energy of orange light having a frequency of 4.92 x 10 14  s -1 . What is the wavelength of the light? By Planck equation,  E  = h      =  6.634 x 10 -34  J-s x 4.92 x 10 14  s -1   =  3.264 x 10 -19  J Using velocity of light  c =  λ    , wavelength  λ = c /   =  3.00 x 10 8  m/s /  4.92 x 10 14  s -1 =  6.098 x 10 -7   m ANS:
Exercise: 1.  An electron in a H atom is excited from energy level n= 1 to energy level n= 5.[Rydberg constant, A = 2.18 x 10-18 J, ] Calculate :  a) energy of electron at energy levels, n= 1 and n=5.   b) The energy released when electron translate from n =5 to n=1.   c) the wavelength of the radiation emitted when electron translate from n= 5 to n= 1? 2. Find the quantum of energy of radiation emitted with a wavelength of  6.500 x 10 -10  m.
2. Find the energy of radiation when a mole of electron falls from energy level n =5 to energy level n = 2 in H atoms. Draw the energy levels diagram to show the  translation of an electron involved.
[object Object],[object Object],[object Object],Weaknesses  of Bohr’s atomic Theory of H. ,[object Object],[object Object]
[object Object],[object Object],[object Object],3. Heisenberg Uncertainty Principle: It is impossible to know simultaneously the position and momentum of any moving particle.
[object Object],[object Object],[object Object],[object Object]
Concept of orbital ,[object Object],[object Object],Examples of orbitals: S orbital One of the p orbitals How scientists describe fully an electron in an orbital of an atom?
The four Quantum Numbers (QN)of an electron in an atom ,[object Object],[object Object],[object Object],[object Object],[object Object]
1. The Principal Quantum Number, n ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
2. The Azimuthal Quantum Number  / Angular momentum quantum No.,  l ,[object Object],[object Object],[object Object],[object Object],[object Object],What do we know from the value of quantum no. n and  L  ?
value of  l     0   1  2  3  4 Name of subshell   s   p d f g   S =sharp, p = principal, d = diffuse, f= fundamental ,[object Object]
Sub shells of a quantum shell 5s, 5p,5d, 5f 5g 5 5 4s, 4p, 4d,4f 4 4 3s, 3p, 3d 3 3 2s, 2p 2 2 1s 1 1 Symbol No. of sub-shell Electron shell n
Exercise:  1. State the no. of sub shells /sub energy levels for quantum shell n = 4.  Name the sub shells. 2.i. How many orbital types/sub shells are there for n =1 ?  Name it. ii. For energy  level n = 4.  State the no. of sub shells and name them. e.g.  An electron with quantum no. n =3,  how many subshells does it have? Name them. Ans:  3 subshells, I.e. 3s, 3p, 3d
3. The magnetic Quantum Number ( m   L   ) ,[object Object],[object Object],Quiz:  For n =1, state the no. of  values of  I)  L , ii) m  L   & .iii) the no. of subshells/orbital type, iv) no. of orbitals. i.e.  No. of orbitals = 2   L +  1 for  a certain value of  L .
What do we know from the value of quantum no.  L  and  m   L   ? d x y  d xz   d yz   d x 2 - y 2   d z 2 5 d P x ,  p y , p z 3 p s 1 s Symbol No. of orbitals Sub-shell
4.. The Electron spin quantum Number ( m s   ) ,[object Object],[object Object],+ ½ -½ Max. no. of e in 1 orbital = 2
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
The shapes of atomic orbitals 1s 2s 3s z x y z z y y x x 2p x 2p y 2p z
y x z y z z y x x z y x z x y d xy   d xz   d yz d x 2 - y 2 d z 2
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Exercise 4. Sketch the shape of the the orbitals below: 1s, 2s,  3p x , 4p y , 5p z :, 3d xy , 3d x2-y2 Give one similarity and one difference between: a) 1s and 2s b)  3p x , 4p y , 5p z c)   3d xy ,, 3d x2-y2 5. For quantum shell n = 3, write the symbols of all the subshells in it. Hence the symbols of all the orbitals present.
The relative energy levels of orbitals E n=4 n=3 n=2 n=1 1s 2s 2p (3 degerate orbitals) 3s 4s 3p (3 degerate orbitals) 3d (5 degerate orbitals) 4d (5 degerate orbitals) 4p (3 degerate orbitals) Order of energy levels:  1s < 2s < 2p < 3s < 3p < 4s < 3d
Electronic configuration of the elements describes the arrangement of of electrons, by filling them in the orbitals, of a atom. ,[object Object],[object Object],1s ,[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],1s 2s 1s 1s
The order of filling the atomic subshells ( orbitals) are in the foll. Sequence: 1s 2s 2p 3s 3p 3d 4s 4p 4d 4f 5s 5p 5d 5f 6s 6p 6d 7s 7p List the order of increase in energy of the above orbitals. 1s < 2s < 2p <3s  < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],2s
3. Hund’s Rule: When electrons are added to orbitals of equivalent energy (degenerate orbitals), Each orbital is filled with a single electron of the same spin 1st before it is paired. e.g. The elect. Config.  of  7 N  1s 2  2s 2  2p 3 1s 2s 2p x   2p y   2p z The elect. config of  8  O  1s 2  2s 2  2p 4 1s 2s 2p x   2p y   2p z Exercise: Write electronic conf. of F and Ne by continuing  the process above using Hund’s Rule and Pauli Exclusion Principle..
Writing electronic configuration of an element ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],1s    2s   2p x   2p y   2p z    3s 1s 2   2s 2  2p 6  3s 1 Valence e. config.  3s 1
e.g.  Write electronic configuration  of I.  26 Fe ii.  26 Fe 2+  iii.  24 Cr 3+   ANS: i.  26 Fe  :  1s 2  2s 2 2p 6  3s 2 3p 6  4s 2  3d 6 Remember and use orbitals’ E level in ascending order list : 1s < 2s < 2p <3s  < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s   ii. Rearrange  i .  to be 1s 2  2s 2 2p 6  3s 2 3p 6  3d 6  4s 2  Then  26 Fe 2+  e -  config .  : 1s 2  2s 2 2p 6  3s 2 3p 6  3d 6  4s 0 ,[object Object],[object Object],-  3e - 2e
Exercise: 1. Write the electronic configuration of the following species by using:  I.  the s, p, d,f notation ii. An orbital diagram.: a) Cl (Z= 17) d) Zn 2+ (Z = 30) b) K +  ( Z = 19) e) Mn 4+  (Z =24) c)  S 2-  ( Z = 16) d) Cu + (Z = 29) 2. Write the electronic configuration in orbital notation of : a) Na b) N c)  B d) Se Underline the electronic configuration of their respective valence shells.
Anomalous E. conf. – exception to the Aufbau Principle In terms of orbital diagram: Cr [Ar] 3d   4s Reason: a half –filled 3d subshell has extra added stability. In terms of orbital diagram: Cu [Ar] 3d   4s Reason: a filled 3d subshell has extra added stability. [Ar]3d 5   4s 1 [Ar]3d 10  4s 1 [Ar]3d 4  4s 2 [Ar]3d 9  4s 2 Cr (Z =24) Cu( z = 29) Observed Expected Element
Short revision quiz ,[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],6. Write orbital diagram  for  P. State the total no. of paired electrons and unpaired electrons in  it. 7. Write electronic and orbital diagram for Ti (Z= 22). Name the 2 Principles and one rule used. 8. How many electrons in: i.. 2p subshell,  ii 3d orbitals,  iii. 4s orbital and iv. Quantum shell  n = 4 ?
Formulae to remember and apply 1.Energy of electron at energy level n,  E n  = - A / n 2   (Bohr equation) 2. Amount of energy released or absorbed by electron(photon) :    E  = E f  – E i   = A( 1/n i 2  – 1/n f 2  )   3. Planck relate energy of a radiation to its frequency or wavelength  :   E = h    or   E = h c/ 
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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Elect

  • 1.
  • 2.
  • 3. 2. The energy at each permitted orbit is quantized (only certain specific quantity is allowed) i.e. energy level with a quantum number, n. Energy of electron at energy level n, E n = - A / n 2 (Bohr equation) where A = Rydberg constant. Note: n = Principle quantum no. ( n = 1, 2, 3…  ) identifies and determines the the orbit and energy of its electron.
  • 4. 3. At its normal condition, a H atom is at its ground state ( lowest energy state where n =1) 3. If energy is supplied, an electron may absorb a certain amount of energy to move to a higher energy state called the excited state. 4. Electron at the excited state (i.e. at a higher energy state, E i ) is unstable , tends to return to a lower energy state ( E f ).
  • 5.
  • 6. Subst. (2) into (1). Then h  = - A/ n f 2 – (- A./n i 2 )  E = A( 1/n i 2 – 1/n f 2 )--------- (i) = E f – E i ----------------------------------------------(ii) Where A = Rch = Rydberg constant = 2.178 x 10 -18 J
  • 7. But velocity of light (radiation), c = λ x  where λ = wavelength &  = frequency Hence, E = h x (c/ λ ) Planck relates energy of a radiation to its frequency by, E = h  Where h = Planck constant,  = frequency of light Planck Equation:
  • 8.
  • 9. i. Energy of an electron E 2 = - 2.18 x 10 -18 J / 2 2 = -5.45 x 10 -19 J E 4 = - 2.18 x 10 -18 J / 4 2 = -1.36 x 10 - 19 J ii. Energy given out Δ E = E f – E i = E 2 – E 4 = -5.45 x 10 -19 J – (-1.36 x 10 -19 J) = - 4.09 x 10 -19 J ANS:
  • 10.
  • 11. e.g. 2. Find the a quantum of energy of orange light having a frequency of 4.92 x 10 14 s -1 . What is the wavelength of the light? By Planck equation, E = h  = 6.634 x 10 -34 J-s x 4.92 x 10 14 s -1 = 3.264 x 10 -19 J Using velocity of light c = λ  , wavelength λ = c /  = 3.00 x 10 8 m/s / 4.92 x 10 14 s -1 = 6.098 x 10 -7 m ANS:
  • 12. Exercise: 1. An electron in a H atom is excited from energy level n= 1 to energy level n= 5.[Rydberg constant, A = 2.18 x 10-18 J, ] Calculate : a) energy of electron at energy levels, n= 1 and n=5. b) The energy released when electron translate from n =5 to n=1. c) the wavelength of the radiation emitted when electron translate from n= 5 to n= 1? 2. Find the quantum of energy of radiation emitted with a wavelength of 6.500 x 10 -10 m.
  • 13. 2. Find the energy of radiation when a mole of electron falls from energy level n =5 to energy level n = 2 in H atoms. Draw the energy levels diagram to show the translation of an electron involved.
  • 14.
  • 15.
  • 16.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 22. Sub shells of a quantum shell 5s, 5p,5d, 5f 5g 5 5 4s, 4p, 4d,4f 4 4 3s, 3p, 3d 3 3 2s, 2p 2 2 1s 1 1 Symbol No. of sub-shell Electron shell n
  • 23. Exercise: 1. State the no. of sub shells /sub energy levels for quantum shell n = 4. Name the sub shells. 2.i. How many orbital types/sub shells are there for n =1 ? Name it. ii. For energy level n = 4. State the no. of sub shells and name them. e.g. An electron with quantum no. n =3, how many subshells does it have? Name them. Ans: 3 subshells, I.e. 3s, 3p, 3d
  • 24.
  • 25. What do we know from the value of quantum no. L and m L ? d x y d xz d yz d x 2 - y 2 d z 2 5 d P x , p y , p z 3 p s 1 s Symbol No. of orbitals Sub-shell
  • 26.
  • 27.
  • 28. The shapes of atomic orbitals 1s 2s 3s z x y z z y y x x 2p x 2p y 2p z
  • 29. y x z y z z y x x z y x z x y d xy d xz d yz d x 2 - y 2 d z 2
  • 30.
  • 31. Exercise 4. Sketch the shape of the the orbitals below: 1s, 2s, 3p x , 4p y , 5p z :, 3d xy , 3d x2-y2 Give one similarity and one difference between: a) 1s and 2s b) 3p x , 4p y , 5p z c) 3d xy ,, 3d x2-y2 5. For quantum shell n = 3, write the symbols of all the subshells in it. Hence the symbols of all the orbitals present.
  • 32. The relative energy levels of orbitals E n=4 n=3 n=2 n=1 1s 2s 2p (3 degerate orbitals) 3s 4s 3p (3 degerate orbitals) 3d (5 degerate orbitals) 4d (5 degerate orbitals) 4p (3 degerate orbitals) Order of energy levels: 1s < 2s < 2p < 3s < 3p < 4s < 3d
  • 33.
  • 34.
  • 35. The order of filling the atomic subshells ( orbitals) are in the foll. Sequence: 1s 2s 2p 3s 3p 3d 4s 4p 4d 4f 5s 5p 5d 5f 6s 6p 6d 7s 7p List the order of increase in energy of the above orbitals. 1s < 2s < 2p <3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s
  • 36.
  • 37. 3. Hund’s Rule: When electrons are added to orbitals of equivalent energy (degenerate orbitals), Each orbital is filled with a single electron of the same spin 1st before it is paired. e.g. The elect. Config. of 7 N 1s 2 2s 2 2p 3 1s 2s 2p x 2p y 2p z The elect. config of 8 O 1s 2 2s 2 2p 4 1s 2s 2p x 2p y 2p z Exercise: Write electronic conf. of F and Ne by continuing the process above using Hund’s Rule and Pauli Exclusion Principle..
  • 38.
  • 39.
  • 40. Exercise: 1. Write the electronic configuration of the following species by using: I. the s, p, d,f notation ii. An orbital diagram.: a) Cl (Z= 17) d) Zn 2+ (Z = 30) b) K + ( Z = 19) e) Mn 4+ (Z =24) c) S 2- ( Z = 16) d) Cu + (Z = 29) 2. Write the electronic configuration in orbital notation of : a) Na b) N c) B d) Se Underline the electronic configuration of their respective valence shells.
  • 41. Anomalous E. conf. – exception to the Aufbau Principle In terms of orbital diagram: Cr [Ar] 3d 4s Reason: a half –filled 3d subshell has extra added stability. In terms of orbital diagram: Cu [Ar] 3d 4s Reason: a filled 3d subshell has extra added stability. [Ar]3d 5 4s 1 [Ar]3d 10 4s 1 [Ar]3d 4 4s 2 [Ar]3d 9 4s 2 Cr (Z =24) Cu( z = 29) Observed Expected Element
  • 42.
  • 43.
  • 44. Formulae to remember and apply 1.Energy of electron at energy level n, E n = - A / n 2 (Bohr equation) 2. Amount of energy released or absorbed by electron(photon) :  E = E f – E i = A( 1/n i 2 – 1/n f 2 ) 3. Planck relate energy of a radiation to its frequency or wavelength : E = h  or E = h c/ 
  • 45.