2. 1638 F.A. Deeney, J.P. O’Leary / Physics Letters A 375 (2011) 1637–1639
As we mentioned in our introduction, it has always been evi-
dent that there are serious problems with the physical implications
of expressions (3) and (4). These include the following:
(i) The disappearance of the kinetic energy of the particles as
they drop into the ground state, leads to the difficult concept
of these particles remaining fixed in position in space.
(ii) According to Eq. (3), the internal energy of the system tends
to zero as the temperature approaches 0 K, implying that now
all of the particles will be static at that temperature, contra-
dicting the Heisenberg uncertainty principle.
(iii) From Eq. (4), P no longer depends on the volume, so that
the isothermal compressibility, κT = − 1
V
(∂V
∂ P
)T , is infinite over
the full temperature range T = 0 → TB . Furthermore, since
CP = V T κT (∂ P/∂T )2
V + CV , the heat capacity CP is also infi-
nite at these temperatures. These unphysical results are some-
times dismissed as arising due to the omission of interactions
between the particles when dealing with an ideal gas [3]. If
one considers the equivalent classical gas, however, the quan-
tities take the form κT = 1
P
and CP = 5/2Nk, respectively i.e.
they remain finite and well behaved at all temperatures. Yet
the only difference between the two gases is that, in the quan-
tum gas, the particles are indistinguishable.
3. New theory
From expression (2) above we obtain
P V = NkT g5/2(1)/g3/2(1) ≈ 0.513NkTB T = TB (5)
when the temperature of the gas is TB . Using the relationship
P V = 2U/3 [2], we then obtain
U ≈ 0.77NkTB
so that the average kinetic energy of a gas particle, when T = TB ,
is ≈ 0.77kTB .
Since there is no experimental evidence that this energy is lost
to the surroundings during Bose–Einstein condensation, we here
make the assumption that it is retained in the system instead. This
means that at any temperature below TB , the particles in the con-
densate have an internal energy
U0(T ) = N0(T ) × 0.77kTB (6)
where N0(T ) = N(1 − (T /TB )3/2
) is the number of particles in the
ground state at that temperature. The total internal energy of the
gas below the temperature TB is then
U =
3
2
cV T 5/2
+ 0.77N 1 − (T /TB )3/2
kTB T < TB (7)
From this we see that, at absolute zero, the gas has the residual
internal energy
U0(0) = 0.77NkTB (8)
which is equal to the kinetic energy of the gas at T = TB . This re-
sult is in excellent agreement with the estimate of the zero point
energy made by Fetter and Walecka [4], using a simple argument
based on the Heisenberg uncertainty principle. They show that the
mean zero point energy of a particle in an ideal boson gas, consist-
ing of N particles in a volume V , and hence confined to a volume
of ∼ V /N, is approximately the same as the mean kinetic energy
of a particle at the Bose–Einstein temperature, in the same gas, un-
der the same conditions. We can thus identify U0(T ) with the zero
point energy of the gas, defined in the usual way as that compo-
nent of the internal energy of a system that does not vanish as
T → 0.
Thus the first two difficulties that are present in the existing
theory, no longer exist in our new model. Looking next at expres-
sion (4) for the pressure, this is now modified to become
P = cT 5/2
+ 0.513 1 − (T /TB )3/2
NkTB /V (9)
where, again, we have used the relationship PV = 2U/3. Thus,
when T = 0 K, the gas exerts a finite pressure P0(0) =
0.513NkTB /V , which is the same as the pressure exerted by the
gas at T = TB . The isothermal compressibility may then be written
as
κT =
1
V
∂V
∂ P T
=
1
P − cT 5/2
(10)
This is a much more satisfactory expression for κT than hitherto,
since its form is similar to κT = 1/P that applies in the ideal
classical gas, with the additional term cT 5/2
arising due to the in-
troduction of the principle of indistinguishability.
Furthermore, the compressibility is now finite at all tempera-
tures except at T = TB . To understand the meaning of the latter,
we note that infinite values of compressibility and heat capacities,
at a particular temperature, are indicative of a phase change taking
place at that point (e.g. Ref. [2] chapter 11). Hence the divergences
at T = TB can be interpreted as arising due to the onset of Bose–
Einstein condensation. We thus find that the final difficulty listed
above for the existing theory, is also absent in our analysis.
We then obtain a new equation of state for an ideal boson gas
at temperatures below TB , to replace Eq. (4). This may be written
as
PV = cV T 5/2
+ 0.513 1 − (T /TB )3/2
NkTB T < TB (11)
Taken together with Eq. (2) for temperatures above TB , it expresses
the thermodynamic behaviour of an ideal boson gas at all temper-
atures.
4. Density maximum in liquid 4
He
A further feature of our new theory is the prediction that ex-
trema in the pressure and density of an ideal boson gas, will occur
at some critical temperature between 0 K and TB . To see this, con-
sider expression (9). Keeping the volume of the system constant,
we find the expression
Tc =
0.308
c
N
V
k
T
1/2
B
(12)
for the critical temperature Tc at which the pressure will be a min-
imum. Writing c = g5/2(1)k5/2
(2πm/h2
)3/2
as before, and using
the expression for the number density
N
V
= ζ(3/2)
2πmk
h2
3/2
T
3/2
B (13)
Eq. (12) simplifies to
Tc = 0.308
ζ(3/2)
g5/2(1)
TB =
0.308 × 2.612
1.341
≈ 0.60TB (14)
In the case of an ideal gas of 4
He, for example, TB ≈ 3.13 K, and a
pressure minimum is predicted to occur at ≈ 1.88 K. Furthermore,
if we allow the volume of the gas to vary but keep the pressure
constant, the density of the gas will pass through an extremum,
in this case a maximum value. At that point d(N/V )/dT = 0 and
using Eq. (9) again, but now keeping P fixed, we find that a max-
imum occurs in N/V at exactly the same temperature Tc given
by (11). Hence, for an ideal helium gas, the density should pass
through a maximum at a temperature ≈ 1.88 K.
3. F.A. Deeney, J.P. O’Leary / Physics Letters A 375 (2011) 1637–1639 1639
We may compare this prediction with experiment by examin-
ing the variation with temperature of liquid 4
He, which is a real
boson system with atoms interacting via van der Waals’ forces.
Here one finds that, despite the presence of these forces, the same
arguments as were used in the ideal gas should broadly apply. Fol-
lowing the standard van der Waals’ approach [2], the equation of
state above TB can be modified by changing expression (2) to ob-
tain the following approximate form for the equation of state of
liquid 4
He,
Pe = {NkT /V }g5/2(z)/g3/2(z) + PV deW T > TB (15)
where the extra term PV deW represents the effect of the van der
Waals forces on the gas pressure. At temperatures below TB , the
modified Eq. (9) becomes
P = cT 5/2
+ 1 − (T /TB )3/2
NkTB /3V + PV deW T < TB (16)
The density maximum, as before, will occur when d(N/V )dT
= 0. The only difference from the ideal gas case is that one now
has the presence of the term ∂ PV deW /∂T . The van der Waals’ force
is not expected to have a large temperature dependence, so the
extra term will be small. Neglecting this term to first approxima-
tion, the theory predicts that the density maximum in liquid 4
He
should occur at a temperature ≈ 1.88 K, which is in very good
agreement with the measured value of 2.18 K [5]. The difference
between the two may be attributed to the action of the van der
Waals’ force. The latter has the effect of increasing the overlap be-
tween the wave functions of neighbouring particles, compared to
the ideal gas equivalent, thereby raising the value of TB and with
it the value of Tc.
By including the additional term U0 in the internal energy of
the condensate at temperatures below TB , our new theory suc-
ceeds in predicting the occurrence of a density maximum in an
ideal boson gas, and in giving a very good estimate of the temper-
ature at which this phenomenon should occur in liquid 4
He. We
have already commented upon this in a general way elsewhere [6].
There we noted that liquid 4
He is a particularly simple liquid,
in that its atoms are spherically symmetrical and the interatomic
forces are purely van der Waals’ in nature. It is difficult to envisage
how a density maximum could occur in such a system other than
in the way described above, since such a phenomenon requires
the presence of two independent sources of kinetic energy, one
of which decreases and one of which increases with temperature
change. The point at which the effects of these two mechanisms
intersect will then give rise to a maximum in the density of liquid
4
He.
5. Conclusion
In conclusion, we have examined the issue of the kinetic energy
of particles in the ground state of a boson gas. By assuming that
the kinetic energy of these particles, as they drop into the con-
densate, is retained in the system, we obtain expressions for the
internal energy and pressure of the gas below the temperature TB ,
that lack the difficulties associated with the corresponding expres-
sions in the current theory. In addition, the new analysis predicts
that a density maximum will occur in the gas at some critical tem-
perature below TB . On applying the theory to the case of liquid
4
He, a value is predicted for this temperature that is in very good
agreement with the experimentally observed value.
Acknowledgement
The authors wish to thank Dr. J.J. Lennon for his valuable assis-
tance throughout this work.
References
[1] K. Huang, Introduction to Statistical Physics, Taylor and Francis, London, New
York, 2001, Chap. 11.
[2] R.K. Pathria, Statistical Mechanics, 2nd ed., Butterworth–Heinemann, 1996,
Chap. 7.
[3] D.C. Mattis, R.H. Swendsen, Statistical Mechanics, 2nd ed., World Scientific Pub-
lishing, 2008.
[4] A.L. Fetter, J.D. Walecka, Quantum Theory of Many-Particle Systems, McGraw–
Hill, New York, 1971.
[5] K. Mendelssohn, Liquid helium, in: S. Flugge (Ed.), Low Temperature Physics II,
in: Handbuch der Physik, vol. XV, Springer-Verlag, Berlin, 1962, p. 373.
[6] F.A. Deeney, J.P. O’Leary, Phys. Lett. A 358 (2006) 53.