SlideShare a Scribd company logo
1 of 12
1
Basic Calculus
Quarter 3 – Module 5:
Slope of the Tangent Line
to a Curve
Basic Calculus – Grade 11
2
Assessment
A. Read and answer each question.Write your answer on a separate sheet
of paper.
1. Which of the following does NOT define the slope of the tangent
line to the curve?
A. It is constant.
B. It is not constant and must be determined by a point.
C. It is equal the derivative of the function.
D. It is derived from the concept of the slope of a second line.
2. On which of the following conditions will a tangent line exist?
A. Function continuous at P.
B. Function discontinuousat P.
C. Curve with cusp at P.
D. Curve with corner at P.
3. Which of the following describes a line tangent to a given curve drawn at its
maximum or minimum point?
A. has a positive slope C. horizontal
B. has a negative slope D. vertical
4. Which is the line perpendicular to the tangent line at the point of tangency?
A. secant C. parallel
B. skew D. normal
5. Which of the following is equal to the slope of the tangent line?
A. Average rate of change
B. Instantaneous rate of change
C. Slope of the secant line
D. Slope of the line perpendicular to the given tangent line.
3
B. Evaluate 𝑓′(2) for the given functions.
6. (𝑥) = 5𝑥 − 1
A. 1 B. 5 C. – 1 D. 2
7. (𝑥) = 3𝑥2
A. 3 B. 2 C. 6 D. 12
𝑓′(𝑥) = lim
ℎ→0
𝑓(𝑥 + ℎ) − 𝑓(𝑥)
ℎ
= lim
ℎ→0
[5(𝑥 + ℎ) − 1] − 5𝑥 − 1
ℎ
= lim
ℎ→0
5𝑥 + 5ℎ − 1 − 5𝑥 − 1
ℎ
= lim
ℎ→0
5ℎ
ℎ
= lim
ℎ→0
5
𝑓′(𝑥) = lim
ℎ→0
𝑓(𝑥 + ℎ) − 𝑓(𝑥)
ℎ
= lim
ℎ→0
3(𝑥 + ℎ)2 − 3𝑥2
ℎ
= lim
ℎ→0
3(𝑥2 + 3𝑥ℎ + ℎ2) − 3𝑥2
ℎ
= lim
ℎ→0
3𝑥2 + 6𝑥ℎ + 3ℎ2 − 3𝑥2
ℎ
= lim
ℎ→0
3𝑥2 + 6𝑥ℎ + 3ℎ2 − 3𝑥2
ℎ
= lim
ℎ→0
6𝑥ℎ + 3ℎ2
ℎ
= lim
ℎ→0
ℎ(6𝑥 + 3ℎ)
ℎ
= lim
ℎ→0
6𝑥 + 3ℎ = 6𝑥 + 3(0) = 6𝑥
𝑓′(2) = 6𝑥 = 6(2) = 12
4
8. (𝑥) = 𝑥2 − 6𝑥 + 9
A. – 2
9. 𝑓(𝑥) = 𝑥3 − 4
B. – 6 C. 1 D. 2
A. 3 B. 6 C. 12 D. 2
𝑓′(𝑥) = lim
ℎ→0
𝑓(𝑥 + ℎ) − 𝑓(𝑥)
ℎ
= lim
ℎ→0
[(𝑥 + ℎ)2 − 6(𝑥 + ℎ) + 9]−𝑥2 − 6𝑥 + 9
ℎ
= lim
ℎ→0
𝑥2 + 2𝑥ℎ + ℎ2 − 6𝑥 + 6ℎ + 9−𝑥2 − 6𝑥 + 9
ℎ
= lim
ℎ→0
𝑥2 + 2𝑥ℎ + ℎ2 − 6𝑥 + 6ℎ + 9−𝑥2 − 6𝑥 + 9
ℎ
= lim
ℎ→0
2𝑥ℎ + ℎ2 − 6ℎ
ℎ
= lim
ℎ→0
ℎ(2𝑥 + ℎ − 6)
ℎ
= lim
ℎ→0
2𝑥 + ℎ − 6 = 2𝑥 + (0) − 6 = 2𝑥 − 6
𝑓′(2) = 2𝑥 − 6 = 2(2) − 6 = 4 − 6 = −2
𝑓′(𝑥) = lim
ℎ→0
𝑓(𝑥 + ℎ) − 𝑓(𝑥)
ℎ
= lim
ℎ→0
[(𝑥 + ℎ)3 − 4] − 𝑥3 − 4
ℎ
= lim
ℎ→0
𝑥3 + 3𝑥2ℎ + 3𝑥ℎ2 + ℎ3 − 4 − 𝑥3 − 4
ℎ
= lim
ℎ→0
𝑥3 + 3𝑥2ℎ + 3𝑥ℎ2 + ℎ3 − 4 − 𝑥3 − 4
ℎ
= lim
ℎ→0
3𝑥2ℎ + 3𝑥ℎ2 + ℎ3
ℎ
= lim
ℎ→0
ℎ(3𝑥2 + 3𝑥ℎ + ℎ2)
ℎ
= lim
ℎ→0
3𝑥2 + 3𝑥ℎ + ℎ2
= lim
ℎ→0
3𝑥2 + 3𝑥(0) + (0)2
= lim
ℎ→0
3𝑥2
𝑓′(2) = 3𝑥2 = 3(2)2 = 3(4) = 12
5
A. – 2 B. 2 C. 1 D. – 1
C. Solve what is asked in the following problems. Write your solutions and final
answers on a separate sheet.
Tangent and normal lines are drawn to the curve 𝐲 = 𝐱𝟑 at 𝐱 = 𝟐.
11. What is the equation of the line tangent to the curve at the given point?
A. 𝑦 = 12𝑥 − 16 C. 𝑦 = 𝑥 − 12
B.𝑦 = 𝑥 − 16 D. 𝑦 = 12𝑥
𝑓′(𝑥) = lim
ℎ→0
𝑓(𝑥 + ℎ) − 𝑓(𝑥)
ℎ
= lim
ℎ→0
2𝑥
𝑥 + ℎ − 1
−
2𝑥
𝑥 − 1
ℎ
= lim
ℎ→0
2𝑥(𝑥 − 1) − 2𝑥(𝑥 + ℎ − 1)
ℎ(𝑥 + ℎ − 1)(𝑥 − 1)
= lim
ℎ→0
2𝑥2 − 2𝑥 − 2𝑥2 − 2ℎ − 2𝑥
ℎ(𝑥 + ℎ − 1)(𝑥 − 1)
= lim
ℎ→0
2𝑥2 − 2𝑥 − 2𝑥2 − 2ℎ − 2𝑥
ℎ(𝑥 + ℎ − 1)(𝑥 − 1)
= lim
ℎ→0
−2ℎ
ℎ(𝑥 + ℎ − 1)(𝑥 − 1)
= lim
ℎ→0
ℎ(−2)
ℎ(𝑥 + ℎ − 1)(𝑥 − 1)
= lim
ℎ→0
−2
(𝑥 + ℎ − 1)(𝑥 − 1)
=
−2
(𝑥 + 0 − 1)(𝑥 − 1)
=
−2
(𝑥 − 1)(𝑥 − 1)
𝑓′(2)=
−2
(𝑥 − 1)(𝑥 − 1)
=
−2
(2 − 1)(2 − 1)
=
−2
(1)(1)
= =
−2
1
= −2
𝑥 = 2, 𝑦 = 23 = 𝑦 = 8 𝑎𝑛𝑑
𝑑𝑦
𝑑𝑥
= 3𝑥2
𝑠𝑙𝑜𝑝𝑒 𝑎𝑡 𝑥 = 2,
𝑑𝑦
𝑑𝑥
= 3 × 22 = 𝑚 = 12
𝑒𝑞𝑢𝑎𝑡𝑖𝑜𝑛 𝑜𝑓 𝑡ℎ𝑒 𝑙𝑖𝑛𝑒 𝑡𝑎𝑛𝑔𝑒𝑛𝑡,
𝑦 − 8 = 12(𝑥 − 2)
𝑦 = 12𝑥 − 24 + 8
𝑦 = 12𝑥 − 16
6
12. What is the equation of the normal line drawn to the curve at the given point?
A. C.
B. D. 𝑦 = 𝑥 + 98
Mr. Dela Cruz encourageshis students to solve Math problems fast and with
accuracy. He observed in his Math class that the time it takes a student to
solve x word problems is defined by the function (𝒙) = 𝟑𝒙𝟐 − 𝒙 where f(x) is in
minutes.
13. Find the average rate of change in solving time from 1 to 3-word problems.
A. 6 minutes/problem C. 11 minutes/problem
B. 21 minutes/problem D. 25 minutes/problem
𝑥 = 2, 𝑦 = 23 = 𝑦 = 8 𝑎𝑛𝑑
𝑑𝑦
𝑑𝑥
= 3𝑥2
𝑠𝑙𝑜𝑝𝑒 𝑎𝑡 𝑥 = 2,
𝑑𝑦
𝑑𝑥
= 3 × 22 = 𝑚 = 12
𝑚1𝑚2 = 1
𝑚2 =
1
12
𝑡ℎ𝑒 𝑒𝑞𝑢𝑎𝑡𝑖𝑜𝑛 𝑓𝑜𝑟 𝑛𝑜𝑟𝑚𝑎𝑙
𝑦 − 𝑦1 = 𝑚2(𝑥 + 𝑥1)
𝑦 − 8 =
1
2
(𝑥 + 2)
𝑦 =
𝑥 + 2 + 96
12
𝑦 =
𝑥 + 98
12
=
∆𝑓(𝑥)
∆𝑥
=
𝑓(3) − 𝑓(1)
3 − 1
=
3𝑥32 − 3𝑥2 − 1
2
=
22
2
= 11 (11 𝑚𝑖𝑛𝑠 𝑝𝑒𝑟 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚)
7
14. Find the average rate of change in solving time from 3 to 5-word problems.
A. 5 minutes/problem C. 13 minutes/problem
B. 20 minutes/problem D. 23 minutes/problem
15. Solve for the instantaneous rate of change in solving time at 2-word problems.
A. 6 minutes/problem C. 11 minutes/problem
B. 21 minutes/problem D. 26 minutes/problem
3 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚:𝑓(3) = 3 × 32 − 3 = 27 − 3 = 24 𝑚𝑖𝑛
5 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚:𝑓(5) = 3 × 52 − 5 = 75 − 5 = 70 𝑚𝑖𝑛
𝑟𝑎𝑡𝑒 =
70 − 24
5 − 3
=
46
2
= 23 ( min 𝑝𝑒𝑟 𝑝𝑟𝑜𝑏𝑙𝑒𝑚)
𝑓′(𝑥) = (3𝑥2 − 𝑥)′
= 6𝑥 − 1
𝑠𝑜 𝑓′(2) = 6(2) − 1
= 12 − 1
= 11(min 𝑝𝑒𝑟 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚)
8
Additional Activities
Solve the following problems:
1. Determine the values of x where a curve 𝑦 = 𝑥3 − 3𝑥2 − 9𝑥 + 12 has horizontal
tangent lines.
Bataan is known for its mountains and trails such as the Dambana ng Kagitingan and Duhat Trail which
are ideal for history and nature lovers. The slopes of the hills in Duhat trail represent a curve. (Photo
credits: Bataan Weather Page)
𝑑𝑦
𝑑𝑥
=
𝑑
𝑑𝑥
(𝑥3 − 3𝑥2 − 9𝑥 + 12)
=
𝑑
𝑑𝑥
(𝑥3)−
𝑑
𝑑𝑥
(3𝑥2) −
𝑑
𝑑𝑥
(9𝑥) +
𝑑
𝑑𝑥
(12)
=
𝑑
𝑑𝑥
(𝑥3)− 3
𝑑
𝑑𝑥
(𝑥2) − 9
𝑑
𝑑𝑥
(𝑥) + 0
=
𝑑
𝑑𝑥
(𝑥3)− 3
𝑑
𝑑𝑥
(𝑥2) − 9
𝑑
𝑑𝑥
(𝑥) + 0
𝑑𝑦
𝑑𝑥
= 3𝑥3−1 − (3 × 2𝑥2−1) − 9𝑥1−1
= 3𝑥2 − 6𝑥 − 9
= 3(𝑥2 − 2𝑥 − 3)
3(𝑥2 − 2𝑥 − 3) = 0
𝑥2 − 2𝑥 − 3 = 0
9
2. Aside from mountain ranges and trails, Bataan is known for its beautiful
beaches.
White beach in Barangay Paysawan, Bagac, Bataan
A tourist threw a pebble in the sea, causing water ripples. The shape formed
were circles increasing in area. The formula for finding the area of a circle is
given by 𝐴 = 𝜋𝑟2.
a. Find the average rate at which the area of a circle changes with r as the
radius increases from 2 to 4 units.
𝑥2 − 3𝑥 + 𝑥 − 3 = 0
𝑥(𝑥 − 3) − (𝑥 − 3) = 0
(𝑥 − 3)(𝑥 + 1) = 0
𝑥 − 3 = 0 | 𝑥 + 1 = 0
𝑥 = 3 | 𝑥 = −1
𝑟
1 = 2: 𝐴1 = 𝜋𝑟2 = 𝜋 × 22 = 4𝜋
𝑟2 = 4: 𝐴2 = 𝜋𝑟2 = 𝜋 × 42 = 16𝜋
𝑣 =
𝐴2 − 𝐴1
𝑟2 − 𝑟
1
=
16𝜋 − 4𝜋
4 − 2
=
12𝜋
2
= 6𝜋
10
b. Solve for the instantaneous rate at which the area changes with r, when r
= 5.
𝐴 = 𝜋𝑟2
𝐴′ = 2𝜋𝑟
𝑟 = 5 𝑣 = 𝐴′ = 2𝜋 × 5 = 10𝜋
11
basiccalculus_q3_mod5_slopeofatangentline_finalJan-Avegail-Tubat.docx

More Related Content

What's hot

linear equation and gaussian elimination
linear equation and gaussian eliminationlinear equation and gaussian elimination
linear equation and gaussian eliminationAju Thadikulangara
 
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...KelvinSmart2
 
Gauss Jordan Method
Gauss Jordan MethodGauss Jordan Method
Gauss Jordan MethodZunAib Ali
 
Pair of linear equations in two variables for classX
Pair of linear equations in two variables for classXPair of linear equations in two variables for classX
Pair of linear equations in two variables for classXswastik999
 
Linear equations in two variables
Linear equations in two variablesLinear equations in two variables
Linear equations in two variablesvijayapatil27
 
324 1.3 solvinglinearequations
324 1.3 solvinglinearequations324 1.3 solvinglinearequations
324 1.3 solvinglinearequationsbrettdive
 
Gaussian elimination method & homogeneous linear equation
Gaussian elimination method & homogeneous linear equationGaussian elimination method & homogeneous linear equation
Gaussian elimination method & homogeneous linear equationStudent
 
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINESsumanmathews
 
Calculus revision card
Calculus  revision cardCalculus  revision card
Calculus revision cardPuna Ripiye
 
Calculus revision card
Calculus  revision cardCalculus  revision card
Calculus revision cardPuna Ripiye
 
Linear equation in two variable for class X(TEN) by G R Ahmed
Linear equation in two variable for class X(TEN) by G R AhmedLinear equation in two variable for class X(TEN) by G R Ahmed
Linear equation in two variable for class X(TEN) by G R AhmedMD. G R Ahmed
 
Simultaneous equations elimination 2
Simultaneous equations elimination 2Simultaneous equations elimination 2
Simultaneous equations elimination 2castellanos72hector
 
تطبيقات المعادلات التفاضلية
تطبيقات المعادلات التفاضليةتطبيقات المعادلات التفاضلية
تطبيقات المعادلات التفاضليةMohammedRazzaqSalman
 
Ultimate guide to systems of equations
Ultimate guide to systems of equationsUltimate guide to systems of equations
Ultimate guide to systems of equationskhyps13
 
Solving Quadratic Equations by Extracting Square Roots
Solving Quadratic Equations by Extracting Square RootsSolving Quadratic Equations by Extracting Square Roots
Solving Quadratic Equations by Extracting Square RootsFree Math Powerpoints
 

What's hot (20)

linear equation and gaussian elimination
linear equation and gaussian eliminationlinear equation and gaussian elimination
linear equation and gaussian elimination
 
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
 
3.3g
3.3g3.3g
3.3g
 
Gauss Jordan Method
Gauss Jordan MethodGauss Jordan Method
Gauss Jordan Method
 
Pair of linear equations in two variables for classX
Pair of linear equations in two variables for classXPair of linear equations in two variables for classX
Pair of linear equations in two variables for classX
 
Linear equations in two variables
Linear equations in two variablesLinear equations in two variables
Linear equations in two variables
 
324 1.3 solvinglinearequations
324 1.3 solvinglinearequations324 1.3 solvinglinearequations
324 1.3 solvinglinearequations
 
Tugas Aljabar Linear
Tugas Aljabar LinearTugas Aljabar Linear
Tugas Aljabar Linear
 
Gaussian elimination method & homogeneous linear equation
Gaussian elimination method & homogeneous linear equationGaussian elimination method & homogeneous linear equation
Gaussian elimination method & homogeneous linear equation
 
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES
3 D GEOMETRY: SHORTEST DISTANCE BETWEEN 2 LINES
 
Calculus revision card
Calculus  revision cardCalculus  revision card
Calculus revision card
 
Calculus revision card
Calculus  revision cardCalculus  revision card
Calculus revision card
 
Slope of a Line
Slope of a LineSlope of a Line
Slope of a Line
 
Maths project
Maths projectMaths project
Maths project
 
Linear equation in two variable for class X(TEN) by G R Ahmed
Linear equation in two variable for class X(TEN) by G R AhmedLinear equation in two variable for class X(TEN) by G R Ahmed
Linear equation in two variable for class X(TEN) by G R Ahmed
 
Simultaneous equations elimination 2
Simultaneous equations elimination 2Simultaneous equations elimination 2
Simultaneous equations elimination 2
 
تطبيقات المعادلات التفاضلية
تطبيقات المعادلات التفاضليةتطبيقات المعادلات التفاضلية
تطبيقات المعادلات التفاضلية
 
Ultimate guide to systems of equations
Ultimate guide to systems of equationsUltimate guide to systems of equations
Ultimate guide to systems of equations
 
Solving Quadratic Equations by Extracting Square Roots
Solving Quadratic Equations by Extracting Square RootsSolving Quadratic Equations by Extracting Square Roots
Solving Quadratic Equations by Extracting Square Roots
 
Raj
RajRaj
Raj
 

Similar to basiccalculus_q3_mod5_slopeofatangentline_finalJan-Avegail-Tubat.docx

IIT JAM MATH 2019 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2019 Question Paper | Sourav Sir's ClassesIIT JAM MATH 2019 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2019 Question Paper | Sourav Sir's ClassesSOURAV DAS
 
Ejercicios resueltos de analisis matematico 1
Ejercicios resueltos de analisis matematico 1Ejercicios resueltos de analisis matematico 1
Ejercicios resueltos de analisis matematico 1tinardo
 
matrices and determinantes
matrices and determinantes matrices and determinantes
matrices and determinantes gandhinagar
 
Notes and formulae mathematics
Notes and formulae mathematicsNotes and formulae mathematics
Notes and formulae mathematicsZainonie Ma'arof
 
2014 st josephs geelong spec maths
2014 st josephs geelong spec maths2014 st josephs geelong spec maths
2014 st josephs geelong spec mathsAndrew Smith
 
elemetary algebra review.pdf
elemetary algebra review.pdfelemetary algebra review.pdf
elemetary algebra review.pdfDianaOrcino2
 
IIT JAM Math 2022 Question Paper | Sourav Sir's Classes
IIT JAM Math 2022 Question Paper | Sourav Sir's ClassesIIT JAM Math 2022 Question Paper | Sourav Sir's Classes
IIT JAM Math 2022 Question Paper | Sourav Sir's ClassesSOURAV DAS
 
Solucao_Marion_Thornton_Dinamica_Classic (1).pdf
Solucao_Marion_Thornton_Dinamica_Classic (1).pdfSolucao_Marion_Thornton_Dinamica_Classic (1).pdf
Solucao_Marion_Thornton_Dinamica_Classic (1).pdfFranciscoJavierCaedo
 
Questions and Solutions Basic Trigonometry.pdf
Questions and Solutions Basic Trigonometry.pdfQuestions and Solutions Basic Trigonometry.pdf
Questions and Solutions Basic Trigonometry.pdferbisyaputra
 
11 kisi2 dan cara pat matematika tp 2020 2021
11 kisi2 dan cara pat matematika tp 2020 202111 kisi2 dan cara pat matematika tp 2020 2021
11 kisi2 dan cara pat matematika tp 2020 2021Eva Nurmalasari
 
GCSE-CompletingTheSquare.pptx
GCSE-CompletingTheSquare.pptxGCSE-CompletingTheSquare.pptx
GCSE-CompletingTheSquare.pptxMitaDurenSawit
 
IIT JAM MATH 2020 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2020 Question Paper | Sourav Sir's ClassesIIT JAM MATH 2020 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2020 Question Paper | Sourav Sir's ClassesSOURAV DAS
 
Banco de preguntas para el ap
Banco de preguntas para el apBanco de preguntas para el ap
Banco de preguntas para el apMARCELOCHAVEZ23
 
Spm add-maths-formula-list-form4-091022090639-phpapp01
Spm add-maths-formula-list-form4-091022090639-phpapp01Spm add-maths-formula-list-form4-091022090639-phpapp01
Spm add-maths-formula-list-form4-091022090639-phpapp01Asad Bukhari
 

Similar to basiccalculus_q3_mod5_slopeofatangentline_finalJan-Avegail-Tubat.docx (20)

Mte (1)
Mte (1)Mte (1)
Mte (1)
 
IIT JAM MATH 2019 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2019 Question Paper | Sourav Sir's ClassesIIT JAM MATH 2019 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2019 Question Paper | Sourav Sir's Classes
 
Ejercicios resueltos de analisis matematico 1
Ejercicios resueltos de analisis matematico 1Ejercicios resueltos de analisis matematico 1
Ejercicios resueltos de analisis matematico 1
 
matrices and determinantes
matrices and determinantes matrices and determinantes
matrices and determinantes
 
TABREZ KHAN.ppt
TABREZ KHAN.pptTABREZ KHAN.ppt
TABREZ KHAN.ppt
 
Notes and formulae mathematics
Notes and formulae mathematicsNotes and formulae mathematics
Notes and formulae mathematics
 
2014 st josephs geelong spec maths
2014 st josephs geelong spec maths2014 st josephs geelong spec maths
2014 st josephs geelong spec maths
 
elemetary algebra review.pdf
elemetary algebra review.pdfelemetary algebra review.pdf
elemetary algebra review.pdf
 
IIT JAM Math 2022 Question Paper | Sourav Sir's Classes
IIT JAM Math 2022 Question Paper | Sourav Sir's ClassesIIT JAM Math 2022 Question Paper | Sourav Sir's Classes
IIT JAM Math 2022 Question Paper | Sourav Sir's Classes
 
Solucao_Marion_Thornton_Dinamica_Classic (1).pdf
Solucao_Marion_Thornton_Dinamica_Classic (1).pdfSolucao_Marion_Thornton_Dinamica_Classic (1).pdf
Solucao_Marion_Thornton_Dinamica_Classic (1).pdf
 
Questions and Solutions Basic Trigonometry.pdf
Questions and Solutions Basic Trigonometry.pdfQuestions and Solutions Basic Trigonometry.pdf
Questions and Solutions Basic Trigonometry.pdf
 
Rumus matematik examonline spa
Rumus matematik examonline spaRumus matematik examonline spa
Rumus matematik examonline spa
 
11 kisi2 dan cara pat matematika tp 2020 2021
11 kisi2 dan cara pat matematika tp 2020 202111 kisi2 dan cara pat matematika tp 2020 2021
11 kisi2 dan cara pat matematika tp 2020 2021
 
GCSE-CompletingTheSquare.pptx
GCSE-CompletingTheSquare.pptxGCSE-CompletingTheSquare.pptx
GCSE-CompletingTheSquare.pptx
 
Escola naval 2015
Escola naval 2015Escola naval 2015
Escola naval 2015
 
IIT JAM MATH 2020 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2020 Question Paper | Sourav Sir's ClassesIIT JAM MATH 2020 Question Paper | Sourav Sir's Classes
IIT JAM MATH 2020 Question Paper | Sourav Sir's Classes
 
Banco de preguntas para el ap
Banco de preguntas para el apBanco de preguntas para el ap
Banco de preguntas para el ap
 
Indices
IndicesIndices
Indices
 
Sample question paper 2 with solution
Sample question paper 2 with solutionSample question paper 2 with solution
Sample question paper 2 with solution
 
Spm add-maths-formula-list-form4-091022090639-phpapp01
Spm add-maths-formula-list-form4-091022090639-phpapp01Spm add-maths-formula-list-form4-091022090639-phpapp01
Spm add-maths-formula-list-form4-091022090639-phpapp01
 

Recently uploaded

Botany 4th semester series (krishna).pdf
Botany 4th semester series (krishna).pdfBotany 4th semester series (krishna).pdf
Botany 4th semester series (krishna).pdfSumit Kumar yadav
 
A relative description on Sonoporation.pdf
A relative description on Sonoporation.pdfA relative description on Sonoporation.pdf
A relative description on Sonoporation.pdfnehabiju2046
 
Presentation Vikram Lander by Vedansh Gupta.pptx
Presentation Vikram Lander by Vedansh Gupta.pptxPresentation Vikram Lander by Vedansh Gupta.pptx
Presentation Vikram Lander by Vedansh Gupta.pptxgindu3009
 
Recombination DNA Technology (Nucleic Acid Hybridization )
Recombination DNA Technology (Nucleic Acid Hybridization )Recombination DNA Technology (Nucleic Acid Hybridization )
Recombination DNA Technology (Nucleic Acid Hybridization )aarthirajkumar25
 
Hubble Asteroid Hunter III. Physical properties of newly found asteroids
Hubble Asteroid Hunter III. Physical properties of newly found asteroidsHubble Asteroid Hunter III. Physical properties of newly found asteroids
Hubble Asteroid Hunter III. Physical properties of newly found asteroidsSérgio Sacani
 
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...Sérgio Sacani
 
Orientation, design and principles of polyhouse
Orientation, design and principles of polyhouseOrientation, design and principles of polyhouse
Orientation, design and principles of polyhousejana861314
 
Biopesticide (2).pptx .This slides helps to know the different types of biop...
Biopesticide (2).pptx  .This slides helps to know the different types of biop...Biopesticide (2).pptx  .This slides helps to know the different types of biop...
Biopesticide (2).pptx .This slides helps to know the different types of biop...RohitNehra6
 
Bentham & Hooker's Classification. along with the merits and demerits of the ...
Bentham & Hooker's Classification. along with the merits and demerits of the ...Bentham & Hooker's Classification. along with the merits and demerits of the ...
Bentham & Hooker's Classification. along with the merits and demerits of the ...Nistarini College, Purulia (W.B) India
 
Disentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTDisentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTSérgio Sacani
 
Biological Classification BioHack (3).pdf
Biological Classification BioHack (3).pdfBiological Classification BioHack (3).pdf
Biological Classification BioHack (3).pdfmuntazimhurra
 
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...Sérgio Sacani
 
Artificial Intelligence In Microbiology by Dr. Prince C P
Artificial Intelligence In Microbiology by Dr. Prince C PArtificial Intelligence In Microbiology by Dr. Prince C P
Artificial Intelligence In Microbiology by Dr. Prince C PPRINCE C P
 
Cultivation of KODO MILLET . made by Ghanshyam pptx
Cultivation of KODO MILLET . made by Ghanshyam pptxCultivation of KODO MILLET . made by Ghanshyam pptx
Cultivation of KODO MILLET . made by Ghanshyam pptxpradhanghanshyam7136
 
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral Analysis
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral AnalysisRaman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral Analysis
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral AnalysisDiwakar Mishra
 
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...Sérgio Sacani
 
Broad bean, Lima Bean, Jack bean, Ullucus.pptx
Broad bean, Lima Bean, Jack bean, Ullucus.pptxBroad bean, Lima Bean, Jack bean, Ullucus.pptx
Broad bean, Lima Bean, Jack bean, Ullucus.pptxjana861314
 

Recently uploaded (20)

Botany 4th semester series (krishna).pdf
Botany 4th semester series (krishna).pdfBotany 4th semester series (krishna).pdf
Botany 4th semester series (krishna).pdf
 
Engler and Prantl system of classification in plant taxonomy
Engler and Prantl system of classification in plant taxonomyEngler and Prantl system of classification in plant taxonomy
Engler and Prantl system of classification in plant taxonomy
 
A relative description on Sonoporation.pdf
A relative description on Sonoporation.pdfA relative description on Sonoporation.pdf
A relative description on Sonoporation.pdf
 
Presentation Vikram Lander by Vedansh Gupta.pptx
Presentation Vikram Lander by Vedansh Gupta.pptxPresentation Vikram Lander by Vedansh Gupta.pptx
Presentation Vikram Lander by Vedansh Gupta.pptx
 
CELL -Structural and Functional unit of life.pdf
CELL -Structural and Functional unit of life.pdfCELL -Structural and Functional unit of life.pdf
CELL -Structural and Functional unit of life.pdf
 
The Philosophy of Science
The Philosophy of ScienceThe Philosophy of Science
The Philosophy of Science
 
Recombination DNA Technology (Nucleic Acid Hybridization )
Recombination DNA Technology (Nucleic Acid Hybridization )Recombination DNA Technology (Nucleic Acid Hybridization )
Recombination DNA Technology (Nucleic Acid Hybridization )
 
Hubble Asteroid Hunter III. Physical properties of newly found asteroids
Hubble Asteroid Hunter III. Physical properties of newly found asteroidsHubble Asteroid Hunter III. Physical properties of newly found asteroids
Hubble Asteroid Hunter III. Physical properties of newly found asteroids
 
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...
PossibleEoarcheanRecordsoftheGeomagneticFieldPreservedintheIsuaSupracrustalBe...
 
Orientation, design and principles of polyhouse
Orientation, design and principles of polyhouseOrientation, design and principles of polyhouse
Orientation, design and principles of polyhouse
 
Biopesticide (2).pptx .This slides helps to know the different types of biop...
Biopesticide (2).pptx  .This slides helps to know the different types of biop...Biopesticide (2).pptx  .This slides helps to know the different types of biop...
Biopesticide (2).pptx .This slides helps to know the different types of biop...
 
Bentham & Hooker's Classification. along with the merits and demerits of the ...
Bentham & Hooker's Classification. along with the merits and demerits of the ...Bentham & Hooker's Classification. along with the merits and demerits of the ...
Bentham & Hooker's Classification. along with the merits and demerits of the ...
 
Disentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTDisentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOST
 
Biological Classification BioHack (3).pdf
Biological Classification BioHack (3).pdfBiological Classification BioHack (3).pdf
Biological Classification BioHack (3).pdf
 
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...
Discovery of an Accretion Streamer and a Slow Wide-angle Outflow around FUOri...
 
Artificial Intelligence In Microbiology by Dr. Prince C P
Artificial Intelligence In Microbiology by Dr. Prince C PArtificial Intelligence In Microbiology by Dr. Prince C P
Artificial Intelligence In Microbiology by Dr. Prince C P
 
Cultivation of KODO MILLET . made by Ghanshyam pptx
Cultivation of KODO MILLET . made by Ghanshyam pptxCultivation of KODO MILLET . made by Ghanshyam pptx
Cultivation of KODO MILLET . made by Ghanshyam pptx
 
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral Analysis
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral AnalysisRaman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral Analysis
Raman spectroscopy.pptx M Pharm, M Sc, Advanced Spectral Analysis
 
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
 
Broad bean, Lima Bean, Jack bean, Ullucus.pptx
Broad bean, Lima Bean, Jack bean, Ullucus.pptxBroad bean, Lima Bean, Jack bean, Ullucus.pptx
Broad bean, Lima Bean, Jack bean, Ullucus.pptx
 

basiccalculus_q3_mod5_slopeofatangentline_finalJan-Avegail-Tubat.docx

  • 1. 1 Basic Calculus Quarter 3 – Module 5: Slope of the Tangent Line to a Curve Basic Calculus – Grade 11
  • 2. 2 Assessment A. Read and answer each question.Write your answer on a separate sheet of paper. 1. Which of the following does NOT define the slope of the tangent line to the curve? A. It is constant. B. It is not constant and must be determined by a point. C. It is equal the derivative of the function. D. It is derived from the concept of the slope of a second line. 2. On which of the following conditions will a tangent line exist? A. Function continuous at P. B. Function discontinuousat P. C. Curve with cusp at P. D. Curve with corner at P. 3. Which of the following describes a line tangent to a given curve drawn at its maximum or minimum point? A. has a positive slope C. horizontal B. has a negative slope D. vertical 4. Which is the line perpendicular to the tangent line at the point of tangency? A. secant C. parallel B. skew D. normal 5. Which of the following is equal to the slope of the tangent line? A. Average rate of change B. Instantaneous rate of change C. Slope of the secant line D. Slope of the line perpendicular to the given tangent line.
  • 3. 3 B. Evaluate 𝑓′(2) for the given functions. 6. (𝑥) = 5𝑥 − 1 A. 1 B. 5 C. – 1 D. 2 7. (𝑥) = 3𝑥2 A. 3 B. 2 C. 6 D. 12 𝑓′(𝑥) = lim ℎ→0 𝑓(𝑥 + ℎ) − 𝑓(𝑥) ℎ = lim ℎ→0 [5(𝑥 + ℎ) − 1] − 5𝑥 − 1 ℎ = lim ℎ→0 5𝑥 + 5ℎ − 1 − 5𝑥 − 1 ℎ = lim ℎ→0 5ℎ ℎ = lim ℎ→0 5 𝑓′(𝑥) = lim ℎ→0 𝑓(𝑥 + ℎ) − 𝑓(𝑥) ℎ = lim ℎ→0 3(𝑥 + ℎ)2 − 3𝑥2 ℎ = lim ℎ→0 3(𝑥2 + 3𝑥ℎ + ℎ2) − 3𝑥2 ℎ = lim ℎ→0 3𝑥2 + 6𝑥ℎ + 3ℎ2 − 3𝑥2 ℎ = lim ℎ→0 3𝑥2 + 6𝑥ℎ + 3ℎ2 − 3𝑥2 ℎ = lim ℎ→0 6𝑥ℎ + 3ℎ2 ℎ = lim ℎ→0 ℎ(6𝑥 + 3ℎ) ℎ = lim ℎ→0 6𝑥 + 3ℎ = 6𝑥 + 3(0) = 6𝑥 𝑓′(2) = 6𝑥 = 6(2) = 12
  • 4. 4 8. (𝑥) = 𝑥2 − 6𝑥 + 9 A. – 2 9. 𝑓(𝑥) = 𝑥3 − 4 B. – 6 C. 1 D. 2 A. 3 B. 6 C. 12 D. 2 𝑓′(𝑥) = lim ℎ→0 𝑓(𝑥 + ℎ) − 𝑓(𝑥) ℎ = lim ℎ→0 [(𝑥 + ℎ)2 − 6(𝑥 + ℎ) + 9]−𝑥2 − 6𝑥 + 9 ℎ = lim ℎ→0 𝑥2 + 2𝑥ℎ + ℎ2 − 6𝑥 + 6ℎ + 9−𝑥2 − 6𝑥 + 9 ℎ = lim ℎ→0 𝑥2 + 2𝑥ℎ + ℎ2 − 6𝑥 + 6ℎ + 9−𝑥2 − 6𝑥 + 9 ℎ = lim ℎ→0 2𝑥ℎ + ℎ2 − 6ℎ ℎ = lim ℎ→0 ℎ(2𝑥 + ℎ − 6) ℎ = lim ℎ→0 2𝑥 + ℎ − 6 = 2𝑥 + (0) − 6 = 2𝑥 − 6 𝑓′(2) = 2𝑥 − 6 = 2(2) − 6 = 4 − 6 = −2 𝑓′(𝑥) = lim ℎ→0 𝑓(𝑥 + ℎ) − 𝑓(𝑥) ℎ = lim ℎ→0 [(𝑥 + ℎ)3 − 4] − 𝑥3 − 4 ℎ = lim ℎ→0 𝑥3 + 3𝑥2ℎ + 3𝑥ℎ2 + ℎ3 − 4 − 𝑥3 − 4 ℎ = lim ℎ→0 𝑥3 + 3𝑥2ℎ + 3𝑥ℎ2 + ℎ3 − 4 − 𝑥3 − 4 ℎ = lim ℎ→0 3𝑥2ℎ + 3𝑥ℎ2 + ℎ3 ℎ = lim ℎ→0 ℎ(3𝑥2 + 3𝑥ℎ + ℎ2) ℎ = lim ℎ→0 3𝑥2 + 3𝑥ℎ + ℎ2 = lim ℎ→0 3𝑥2 + 3𝑥(0) + (0)2 = lim ℎ→0 3𝑥2 𝑓′(2) = 3𝑥2 = 3(2)2 = 3(4) = 12
  • 5. 5 A. – 2 B. 2 C. 1 D. – 1 C. Solve what is asked in the following problems. Write your solutions and final answers on a separate sheet. Tangent and normal lines are drawn to the curve 𝐲 = 𝐱𝟑 at 𝐱 = 𝟐. 11. What is the equation of the line tangent to the curve at the given point? A. 𝑦 = 12𝑥 − 16 C. 𝑦 = 𝑥 − 12 B.𝑦 = 𝑥 − 16 D. 𝑦 = 12𝑥 𝑓′(𝑥) = lim ℎ→0 𝑓(𝑥 + ℎ) − 𝑓(𝑥) ℎ = lim ℎ→0 2𝑥 𝑥 + ℎ − 1 − 2𝑥 𝑥 − 1 ℎ = lim ℎ→0 2𝑥(𝑥 − 1) − 2𝑥(𝑥 + ℎ − 1) ℎ(𝑥 + ℎ − 1)(𝑥 − 1) = lim ℎ→0 2𝑥2 − 2𝑥 − 2𝑥2 − 2ℎ − 2𝑥 ℎ(𝑥 + ℎ − 1)(𝑥 − 1) = lim ℎ→0 2𝑥2 − 2𝑥 − 2𝑥2 − 2ℎ − 2𝑥 ℎ(𝑥 + ℎ − 1)(𝑥 − 1) = lim ℎ→0 −2ℎ ℎ(𝑥 + ℎ − 1)(𝑥 − 1) = lim ℎ→0 ℎ(−2) ℎ(𝑥 + ℎ − 1)(𝑥 − 1) = lim ℎ→0 −2 (𝑥 + ℎ − 1)(𝑥 − 1) = −2 (𝑥 + 0 − 1)(𝑥 − 1) = −2 (𝑥 − 1)(𝑥 − 1) 𝑓′(2)= −2 (𝑥 − 1)(𝑥 − 1) = −2 (2 − 1)(2 − 1) = −2 (1)(1) = = −2 1 = −2 𝑥 = 2, 𝑦 = 23 = 𝑦 = 8 𝑎𝑛𝑑 𝑑𝑦 𝑑𝑥 = 3𝑥2 𝑠𝑙𝑜𝑝𝑒 𝑎𝑡 𝑥 = 2, 𝑑𝑦 𝑑𝑥 = 3 × 22 = 𝑚 = 12 𝑒𝑞𝑢𝑎𝑡𝑖𝑜𝑛 𝑜𝑓 𝑡ℎ𝑒 𝑙𝑖𝑛𝑒 𝑡𝑎𝑛𝑔𝑒𝑛𝑡, 𝑦 − 8 = 12(𝑥 − 2) 𝑦 = 12𝑥 − 24 + 8 𝑦 = 12𝑥 − 16
  • 6. 6 12. What is the equation of the normal line drawn to the curve at the given point? A. C. B. D. 𝑦 = 𝑥 + 98 Mr. Dela Cruz encourageshis students to solve Math problems fast and with accuracy. He observed in his Math class that the time it takes a student to solve x word problems is defined by the function (𝒙) = 𝟑𝒙𝟐 − 𝒙 where f(x) is in minutes. 13. Find the average rate of change in solving time from 1 to 3-word problems. A. 6 minutes/problem C. 11 minutes/problem B. 21 minutes/problem D. 25 minutes/problem 𝑥 = 2, 𝑦 = 23 = 𝑦 = 8 𝑎𝑛𝑑 𝑑𝑦 𝑑𝑥 = 3𝑥2 𝑠𝑙𝑜𝑝𝑒 𝑎𝑡 𝑥 = 2, 𝑑𝑦 𝑑𝑥 = 3 × 22 = 𝑚 = 12 𝑚1𝑚2 = 1 𝑚2 = 1 12 𝑡ℎ𝑒 𝑒𝑞𝑢𝑎𝑡𝑖𝑜𝑛 𝑓𝑜𝑟 𝑛𝑜𝑟𝑚𝑎𝑙 𝑦 − 𝑦1 = 𝑚2(𝑥 + 𝑥1) 𝑦 − 8 = 1 2 (𝑥 + 2) 𝑦 = 𝑥 + 2 + 96 12 𝑦 = 𝑥 + 98 12 = ∆𝑓(𝑥) ∆𝑥 = 𝑓(3) − 𝑓(1) 3 − 1 = 3𝑥32 − 3𝑥2 − 1 2 = 22 2 = 11 (11 𝑚𝑖𝑛𝑠 𝑝𝑒𝑟 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚)
  • 7. 7 14. Find the average rate of change in solving time from 3 to 5-word problems. A. 5 minutes/problem C. 13 minutes/problem B. 20 minutes/problem D. 23 minutes/problem 15. Solve for the instantaneous rate of change in solving time at 2-word problems. A. 6 minutes/problem C. 11 minutes/problem B. 21 minutes/problem D. 26 minutes/problem 3 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚:𝑓(3) = 3 × 32 − 3 = 27 − 3 = 24 𝑚𝑖𝑛 5 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚:𝑓(5) = 3 × 52 − 5 = 75 − 5 = 70 𝑚𝑖𝑛 𝑟𝑎𝑡𝑒 = 70 − 24 5 − 3 = 46 2 = 23 ( min 𝑝𝑒𝑟 𝑝𝑟𝑜𝑏𝑙𝑒𝑚) 𝑓′(𝑥) = (3𝑥2 − 𝑥)′ = 6𝑥 − 1 𝑠𝑜 𝑓′(2) = 6(2) − 1 = 12 − 1 = 11(min 𝑝𝑒𝑟 𝑤𝑜𝑟𝑑 𝑝𝑟𝑜𝑏𝑙𝑒𝑚)
  • 8. 8 Additional Activities Solve the following problems: 1. Determine the values of x where a curve 𝑦 = 𝑥3 − 3𝑥2 − 9𝑥 + 12 has horizontal tangent lines. Bataan is known for its mountains and trails such as the Dambana ng Kagitingan and Duhat Trail which are ideal for history and nature lovers. The slopes of the hills in Duhat trail represent a curve. (Photo credits: Bataan Weather Page) 𝑑𝑦 𝑑𝑥 = 𝑑 𝑑𝑥 (𝑥3 − 3𝑥2 − 9𝑥 + 12) = 𝑑 𝑑𝑥 (𝑥3)− 𝑑 𝑑𝑥 (3𝑥2) − 𝑑 𝑑𝑥 (9𝑥) + 𝑑 𝑑𝑥 (12) = 𝑑 𝑑𝑥 (𝑥3)− 3 𝑑 𝑑𝑥 (𝑥2) − 9 𝑑 𝑑𝑥 (𝑥) + 0 = 𝑑 𝑑𝑥 (𝑥3)− 3 𝑑 𝑑𝑥 (𝑥2) − 9 𝑑 𝑑𝑥 (𝑥) + 0 𝑑𝑦 𝑑𝑥 = 3𝑥3−1 − (3 × 2𝑥2−1) − 9𝑥1−1 = 3𝑥2 − 6𝑥 − 9 = 3(𝑥2 − 2𝑥 − 3) 3(𝑥2 − 2𝑥 − 3) = 0 𝑥2 − 2𝑥 − 3 = 0
  • 9. 9 2. Aside from mountain ranges and trails, Bataan is known for its beautiful beaches. White beach in Barangay Paysawan, Bagac, Bataan A tourist threw a pebble in the sea, causing water ripples. The shape formed were circles increasing in area. The formula for finding the area of a circle is given by 𝐴 = 𝜋𝑟2. a. Find the average rate at which the area of a circle changes with r as the radius increases from 2 to 4 units. 𝑥2 − 3𝑥 + 𝑥 − 3 = 0 𝑥(𝑥 − 3) − (𝑥 − 3) = 0 (𝑥 − 3)(𝑥 + 1) = 0 𝑥 − 3 = 0 | 𝑥 + 1 = 0 𝑥 = 3 | 𝑥 = −1 𝑟 1 = 2: 𝐴1 = 𝜋𝑟2 = 𝜋 × 22 = 4𝜋 𝑟2 = 4: 𝐴2 = 𝜋𝑟2 = 𝜋 × 42 = 16𝜋 𝑣 = 𝐴2 − 𝐴1 𝑟2 − 𝑟 1 = 16𝜋 − 4𝜋 4 − 2 = 12𝜋 2 = 6𝜋
  • 10. 10 b. Solve for the instantaneous rate at which the area changes with r, when r = 5. 𝐴 = 𝜋𝑟2 𝐴′ = 2𝜋𝑟 𝑟 = 5 𝑣 = 𝐴′ = 2𝜋 × 5 = 10𝜋
  • 11. 11