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Carbohydrates.pptx
1.
BiochemistryāAn Overview Return to
TOC Section 18.1 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 1
2.
BiochemistryāAn Overview Return to
TOC Section 18.1 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 2 The Study of Living Things ā¢ Biochemistry: Study of the chemical substances found in living organisms and the chemical interactions of these substances with each other ā¢ Biochemical substance: Chemical substance found within a living organism ā¢ Types of biochemical substances: ā Bioinorganic substances - Water and inorganic salts ā Bioorganic substances - Carbohydrates, lipids, proteins, and nucleic acids
3.
BiochemistryāAn Overview Return to
TOC Section 18.1 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 3 ā¢ As isolated compounds, bioinorganic and bioorganic substances have no life in and of themselves ā When these substances are gathered together in a cell, their chemical interactions are able to sustain life Bioinorganic and Bioorganic Substances
4.
BiochemistryāAn Overview Return to
TOC Section 18.1 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 4
5.
BiochemistryāAn Overview Return to
TOC Section 18.1 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 5
6.
Section 18.2 Occurrence and
Functions of Carbohydrates Return to TOC Plants and Carbohydrates Copyright Ā©2016 Cengage Learning. All Rights Reserved. 6
7.
Section 18.2 Occurrence and
Functions of Carbohydrates Return to TOC Photosynthesis ā¢ Process in which plants produce carbohydrates using carbon dioxide, water, and solar energy Copyright Ā©2016 Cengage Learning. All Rights Reserved. 7 Chlorophyll 2 2 2 Plant enzymes CO + H O+solar energy carbohydrates +O ļ¾ļ¾ļ¾ļ¾ļ¾ ļ®
8.
Section 18.2 Occurrence and
Functions of Carbohydrates Return to TOC Functions of Carbohydrates in the Human Body ā¢ Carbohydrate oxidation provides energy ā¢ Carbohydrate storage, in the form of glycogen, provides a short-term energy reserve ā¢ Carbohydrates supply carbon atoms for the synthesis of other biochemical substances (proteins, lipids, and nucleic acids) ā¢ Carbohydrates form part of the structural framework of DNA and RNA molecules Copyright Ā©2016 Cengage Learning. All Rights Reserved. 8
9.
Section 18.2 Occurrence and
Functions of Carbohydrates Return to TOC Functions of Carbohydrates in the Human Body ā¢ Carbohydrates linked to lipids are structural components of cell membranes ā¢ Carbohydrates linked to proteins function in a variety of cellācell and cellāmolecule recognition processes Copyright Ā©2016 Cengage Learning. All Rights Reserved. 9
10.
Section 18.3 Classification of
Carbohydrates Return to TOC ā¢ Empirical formula of simple carbohydrates - ā CnH2nOn or Cn(H2O)n (hydrate of C) ā¢ n is the number of atoms ā¢ Carbohydrate: Polyhydroxy aldehyde, ketone, or a compound that produces such substances upon hydrolysis Copyright Ā©2016 Cengage Learning. All Rights Reserved. 10
11.
Section 18.3 Classification of
Carbohydrates Return to TOC Monosaccharides ā¢ Contain single polyhydroxy aldehyde or ketone unit ā¢ Cannot be broken down into simpler substances by hydrolysis reactions ā¢ Contain 3ā7 C atoms ā¢ 5 and 6 carbon species are more common ā¢ Pure monosaccharides - Water soluble white, crystalline solids ā¢ Monosaccharides - Glucose and fructose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 11
12.
Section 18.3 Classification of
Carbohydrates Return to TOC Disaccharides ā¢ Contain 2 monosaccharide units covalently bonded to each other ā¢ Crystalline and water soluble substances ā¢ Common disaccharides - Table sugar (sucrose) and milk sugar (lactose) ā¢ Upon hydrolysis, they produce 2 monosaccharide units Copyright Ā©2016 Cengage Learning. All Rights Reserved. 12
13.
Section 18.3 Classification of
Carbohydrates Return to TOC Oligosaccharides ā¢ Contain three to ten monosaccharide units covalently bonded to each other ā¢ Free oligosaccharides are seldom encountered in biochemical systems ā¢ Usually found associated with proteins and lipids in complex molecules ā Serve structural and regulatory functions Copyright Ā©2016 Cengage Learning. All Rights Reserved. 13
14.
Section 18.3 Classification of
Carbohydrates Return to TOC Polysaccharides ā¢ Contain many monosaccharide units covalently bonded ā¢ Number of monosaccharide units varies from a few 100 units to 50,000 units ā¢ Examples: ā Cellulose - Paper, cotton, wood ā Starch - Bread, pasta, potatoes, rice, corn, beans, and peas Copyright Ā©2016 Cengage Learning. All Rights Reserved. 14
15.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Objects and Handedness ā¢ Most biological molecules, including carbohydrates, exhibit the property of āhandednessā (form of isomerism) ā¢ Most molecules that possess āhandednessā exist in two forms: ā āLeft-handedā form ā āRight-handedā form ā¢ Related in the same manner as two hands that are āmirror imagesā of each other Copyright Ā©2016 Cengage Learning. All Rights Reserved. 15
16.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 16
17.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 17
18.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 18
19.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 19
20.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 20
21.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Mirror Images ā¢ Mirror image: Reflection of an object in a mirror ā¢ Classes of objects based on mirror images - ā Superimposable mirror images: Images that coincide at all points when the images are laid upon each other ā¢ Achiral molecule ā Nonsuperimposable mirror images: Images where not all points coincide when the images are laid upon each other ā¢ Chiral molecule (handedness) Copyright Ā©2016 Cengage Learning. All Rights Reserved. 21
22.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 22 Chirality ā¢ Chiral center: C atom attached to 4 different groups ā¢ A molecule with chiral center is said to be chiral ā¢ A C atom must have four different groups attached to it in order to be a chiral center ā¢ A chiral C is usually denoted by * ā¢ Bromochloroiodomethane is a chiral organic molecule
23.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Practice Exercise Indicate whether the circled carbon atom in each of the following molecules is a chiral center. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 23
24.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Practice Exercise Indicate whether the circled carbon atom in each of the following molecules is a chiral center. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 24 a. Not a chiral center b. Not a chiral center c. Chiral center d. Not a chiral center
25.
Section 18.4 Chirality: Handedness
in Molecules Return to TOC Responses of Left and Right Handed Forms of a Molecule in a Human Body ā¢ Both forms may be active, one may be more active, or one may be active and other non- active ā¢ Example: ā Response of the body to the right-handed hormone epinephrine is 20 times greater than responses to the left-handed form ā¢ Almost all monosaccharides are right handed ā¢ Amino acids are always left handed Copyright Ā©2016 Cengage Learning. All Rights Reserved. 25
26.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 26 Fischer Project Formula ā¢ Two-dimensional structural notation for showing the spatial arrangement of groups about chiral centers in molecules ā¢ According to this formula, a chiral center is represented as the intersection of vertical and horizontal lines ā¢ Functional groups of high priority will be written at the top
27.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 27
28.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC ā¢ What are the priority functional groups in each molecule? ā¢ How do you number the carbon atoms in each molecule? ā¢ How many chiral centers are there in each molecule? Indicate the carbon numbers of each chiral center. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 28
29.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 29 Tetrahedral Arrangements ā¢ The four groups attached to the atom at the chiral center assume a tetrahedral geometry governed by the following conventions: ā Vertical lines from the chiral center represent bonds to groups directed into the printed page ā Horizontal lines from the chiral center represent bonds to groups directed out of the printed page
30.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 30 Fischer Project Formulas ā¢ L and D system used to designate the handedness of glyceraldehyde enantiomers are shown below
31.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 31
32.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 32 Fischer Project Formulas ā¢ The D,L system used to designate the handedness of glyceraldehyde enantiomers can be extended to other monosaccharides with more than one chiral center ā The carbon chain is numbered starting at the carbonyl group end of the molecule, and the highest-numbered chiral center is used to determine D or L configuration
33.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 33
34.
Section 18.6 Designating Handedness
Using Fischer Projection Formulas Return to TOC ā¢ Draw the L configuration of the three monosaccharides in the previous slide. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 34
35.
Section 18.8 Classification of
Monosaccharides Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 35 ā¢ Classification based on number of carbon atoms: ā Triose - 3 carbon atoms ā Tetrose - 4 carbon atoms ā Pentoses - 5 carbon atoms ā Hexoses - 6 carbon atoms ā¢ Classification based on functional groups: ā Aldoses: Monosaccharides with one aldehyde group ā Ketoses: Monosaccharides with one ketone group Monosaccharides
36.
Section 18.8 Classification of
Monosaccharides Return to TOC Monosaccharides ā¢ Combined number of C atoms and functional group ā Examples: ā¢ Aldohexose - Monosaccharide with aldehyde group and 6 C atoms ā¢ Ketopentose - Monosaccharide with ketone group and 5 C atoms Copyright Ā©2016 Cengage Learning. All Rights Reserved. 36
37.
Section 18.8 Classification of
Monosaccharides Return to TOC Exercise Classify each of the following monosaccharides according to both the number of carbon atoms and the type of carbonyl group present. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 37
38.
Section 18.9 Biochemically Important
Monosaccharides Return to TOC D-Glucose ā¢ Most abundant in nature ā¢ Most important source of human nutrition ā¢ Grape fruit and ripe fruits are good sources of glucose (20ā30% by mass) ā Also named grape sugar ā¢ Other names ā Dextrose ā Blood sugar (70ā100 mg/dL) ā¢ Six-membered cyclic form Copyright Ā©2016 Cengage Learning. All Rights Reserved. 38
39.
Section 18.9 Biochemically Important
Monosaccharides Return to TOC D-Galactose ā¢ Milk sugar ā¢ Synthesized in human beings ā¢ Also called brain sugar ā Part of brain and nerve tissue ā¢ Used to differentiate between blood types ā¢ Six-membered cyclic form Copyright Ā©2016 Cengage Learning. All Rights Reserved. 39
40.
Section 18.9 Biochemically Important
Monosaccharides Return to TOC D-Fructose ā¢ Ketohexose ā¢ Sweetest tasting of all sugars ā Found in many fruits and in honey ā¢ Good dietary sugar due to higher sweetness ā¢ Five-membered cyclic form Copyright Ā©2016 Cengage Learning. All Rights Reserved. 40
41.
Section 18.9 Biochemically Important
Monosaccharides Return to TOC D-Ribose ā¢ Part of a variety of complex molecules which include: ā RNA ā ATP ā DNA ā¢ Five-membered cyclic form Copyright Ā©2016 Cengage Learning. All Rights Reserved. 41
42.
Section 18.10 Cyclic Forms
of Monosaccharides Return to TOC Cyclic Hemiacetal Forms of D-Glucose ā¢ Dominant forms of monosaccharides with 5 or more C atoms ā Cyclic structures are in equilibrium with open chain forms ā¢ Cyclic structures are formed by the reaction of carbonyl group (C=O) with hydroxyl (āOH) group on carbon 5 Copyright Ā©2016 Cengage Learning. All Rights Reserved. 42
43.
Section 18.10 Cyclic Forms
of Monosaccharides Return to TOC HAWORTH PROJECTION Copyright Ā©2016 Cengage Learning. All Rights Reserved. 43
44.
Section 18.11 Haworth Projection
Formulas Return to TOC ā¢ Haworth projection formula: Two-dimensional structural notation that specifies the three- dimensional structure of a cyclic form of a monosaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 44
45.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 45 Ī± and Ī² Configuration ā¢ Determined by the position of the āOH group on C1 relative to the āCH2OH group that determines D or L series ā In a Ī² configuration, both of these groups point in the same direction ā In an Ī± configuration, the two groups point in opposite directions
46.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 46 āOH Group Position ā¢ The specific identity of a monosaccharide is determined by the positioning of the other āOH groups in the Haworth projection formula ā Any āOH group at a chiral center that is to the right in a Fischer projection formula points down in the Haworth projection formula ā Any āOH group to the left in a Fischer projection formula points up in the Haworth projection formula
47.
Section 18.11 Haworth Projection
Formulas Return to TOC Figure 18.17 - The Cyclic Hemiacetal Forms of D- Glucose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 47
48.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 48 ā¢ 2 forms of D-Glucose: ā Ī±-form where the āOH of C1 and CH2OH of C5 are on opposite sides ā Ī²-form where the āOH of C1 and CH2OH of C5 are on the same side Cyclic Hemiacetal Forms of D-Glucose O OH OH OH OH CH2OH O OH OH OH OH CH2OH ļ”-D-Glucose ļ¢-D-Glucose 1 2 3 4 5 6 1 2 3 4 5 6 Anomeric Carbon Anomeric Carbon
49.
Section 18.11 Haworth Projection
Formulas Return to TOC Anomers ā¢ Cyclic monosaccharides that differ only in the position of the substituents on the anomeric carbon atom Copyright Ā©2016 Cengage Learning. All Rights Reserved. 49
50.
Section 18.11 Haworth Projection
Formulas Return to TOC Let us make the Haworth Projection of FRUCTOSE Copyright Ā©2016 Cengage Learning. All Rights Reserved. 50
51.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 51
52.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 52
53.
Section 18.11 Haworth Projection
Formulas Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 53 Pyranose and Furanose ā¢ Pyranose - Cyclic monosaccharide containing a six-atom ring ā¢ Furanose - Cyclic monosaccharide containing a five-atom ring ā¢ Their ring structures resemble the ring structures in the cyclic ethers pyran and furan, respectively
54.
Section 18.11 Haworth Projection
Formulas Return to TOC Practice Exercise Which of the monosaccharides glucose, fructose, galactose, and ribose has each of the following structural characteristics? (There may be more than one correct answer for a given characteristic) a. It is a pentose. b. It is a ketose. c. Its cyclic form has a 6-membered ring. d. Its cyclic form has two carbon atoms outside the ring. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 54
55.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 55 ā¢ Two monosaccharides can react to form a disaccharide ā One monosaccharide acts as a hemiacetal and the other as an alcohol ā Resulting ether bond is a glycosidic linkage
56.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 56
57.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 57
58.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 58 Maltose (Malt Sugar) ā¢ Structurally made of 2 D-glucose units, one of which must be Ī±-D-glucose, linked via an Ī±(1ļ 4) glycosidic linkage ā¢ Digested easily by humans because of an enzyme that can break Ī±(1ļ 4) linkages ā¢ Baby foods are rich in maltose
59.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 59 Cellobiose ā¢ Produced as an intermediate in the hydrolysis of the polysaccharide cellulose ā Contains two D-glucose monosaccharide units, one of which must have a Ī² configuration, linked through a Ī²(1ļ 4) glycosidic linkage ā¢ Cannot be digested by humans
60.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 60 Lactose ā¢ Made up of Ī²-D-galactose unit and a D-glucose unit joined by a Ī²(1ļ 4) glycosidic linkage ā¢ Milk is rich in the disaccharide lactose ā¢ Lactase hydrolyzes Ī²(1ļ 4) glycosidic linkages
61.
Section 18.13 Disaccharides Return to
TOC Lactose Intolerance or Lactase Persistence ā¢ Lactose is the principal carbohydrate in milk ā Human motherās milk - 7%ā8% lactose ā Cowās milk - 4%ā5% lactose ā¢ Lactose intolerance is a condition in which people lack the enzyme lactase needed to hydrolyze lactose to galactose and glucose ā¢ Deficiency of lactase can be caused by a genetic defect, physiological decline with age, or by injuries to intestinal mucosa Copyright Ā©2016 Cengage Learning. All Rights Reserved. 61
62.
Section 18.13 Disaccharides Return to
TOC Lactose Intolerance or Lactase Persistence ā¢ When lactose is undigested, it attracts water causing fullness, discomfort, cramping, nausea, and diarrhea ā¢ Bacterial fermentation of the lactose further along the intestinal tract produces acid (lactic acid) and gas, adding to the discomfort Copyright Ā©2016 Cengage Learning. All Rights Reserved. 62
63.
Section 18.13 Disaccharides Return to
TOC Sucrose (Table Sugar) ā¢ The most abundant of all disaccharides and found in plants ā¢ Produced commercially from the juice of sugar cane and sugar beets ā Sugar cane contains up to 20% by mass sucrose ā Sugar beets contain up to 17% by mass sucrose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 63
64.
Section 18.13 Disaccharides Return to
TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 64
65.
Section 18.13 Disaccharides Return to
TOC What is the linkage that is formed when two monosaccharides react to form a disaccharide called? a.Alcohol group linkage b.Glycosidic linkage c.Hemiacetal linkage d.Acetal linkage Copyright Ā©2016 Cengage Learning. All Rights Reserved. 65
66.
Section 18.13 Disaccharides Return to
TOC What is the linkage that is formed when two monosaccharides react to form a disaccharide called? a.Alcohol group linkage b.Glycosidic linkage c.Hemiacetal linkage d.Acetal linkage Copyright Ā©2016 Cengage Learning. All Rights Reserved. 66
67.
Section 18.13 Disaccharides Return to
TOC Which disaccharide is a nonreducing sugar? a.Maltose b.Lactose c.Cellobiose d.Sucrose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 67
68.
Section 18.13 Disaccharides Return to
TOC Which disaccharide is a nonreducing sugar? a.Maltose b.Lactose c.Cellobiose d.Sucrose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 68
69.
Section 18.13 Disaccharides Return to
TOC Practice Exercise Which of these disaccharides, i.e., maltose, cellobiose, lactose, and sucrose, have the following structural or reaction characteristics? (There may be more than one correct answer for a given characteristic) a.Two different monosaccharide units are present. b.Hydrolysis produces only monosaccharides. c.Its glycosidic linkage is a āhead-to-headā linkage. d.It is not a reducing sugar. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 69
70.
Section 18.13 Disaccharides Return to
TOC Practice Exercise Which of these disaccharides, i.e., maltose, cellobiose, lactose, and sucrose, have the following structural or reaction characteristics? (There may be more than one correct answer for a given characteristic) a.Two different monosaccharide units are present. Lactose, sucrose b.Hydrolysis produces only monosaccharides. Maltose, cellobiose, lactose, sucrose c.Its glycosidic linkage is a āhead-to-headā linkage. Sucrose d.It is not a reducing sugar. Sucrose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 70
71.
Section 18.14 Oligosaccharides Return to
TOC ā¢ Carbohydrates that contain 3ā10 monosaccharide units bonded to each other via glycosidic linkages ā¢ Generally present in association with other complex molecules ā Raffinose - Made of 1 galactose, 1 glucose, and 1 fructose ā Stachyose - Made of 2 galactose, 1 glucose, and 1 fructose units ā¢ Commonly found in onions, cabbage, broccoli, and whole wheat Copyright Ā©2016 Cengage Learning. All Rights Reserved. 71
72.
Section 18.14 Oligosaccharides Return to
TOC Blood Types and Oligosaccharides ā¢ Human blood is classified into four types ā A, B, AB, and O ā The basis for the difference is the type of sugars (oligosaccharides) present ā Blood of one type cannot be given to a recipient with blood of another type ā A transfusion of wrong blood type can cause the blood cells to form clumps, a potentially fatal reaction ā People with type O blood are universal donors, and those with type AB blood are universal recipients Copyright Ā©2016 Cengage Learning. All Rights Reserved. 72
73.
Section 18.14 Oligosaccharides Return to
TOC Blood Types and Oligosaccharides ā¢ In the United States, type O blood is the most common and type A the second most common ā¢ The biochemical basis for the various blood types involves oligosaccharides present on plasma membranes of red blood cells ā¢ The oligosaccharides responsible for blood groups are D-galactose and its derivatives Copyright Ā©2016 Cengage Learning. All Rights Reserved. 73
74.
Section 18.14 Oligosaccharides Return to
TOC Other Oligosaccharides ā¢ Solanine, a potato plant toxin, is a oligosaccharide found in association with an alkaloid ā Bitter taste of potatoes is due to relatively higher levels of solanine Copyright Ā©2016 Cengage Learning. All Rights Reserved. 74
75.
Section 18.14 Oligosaccharides Return to
TOC Which of the following is a toxin produced by potato plants? a.Raffinose b.Stachyose c.Solanine d.None of the above Copyright Ā©2016 Cengage Learning. All Rights Reserved. 75
76.
Section 18.14 Oligosaccharides Return to
TOC Which of the following is a toxin produced by potato plants? a.Raffinose b.Stachyose c.Solanine d.None of the above Copyright Ā©2016 Cengage Learning. All Rights Reserved. 76
77.
Section 18.15 General Characteristics
of Polysaccharides Return to TOC The Polymer Chain ā¢ Polysaccharides are polymers of many monosaccharide units bonded with glycosidic linkages ā¢ Two types: ā Homopolysaccharide ā Heteropolysaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 77
78.
Section 18.15 General Characteristics
of Polysaccharides Return to TOC Figure 18.26 - The Polymer Chains of a Polysaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 78
79.
Section 18.15 General Characteristics
of Polysaccharides Return to TOC Characteristics of Polysaccharides ā¢ Polysaccharides are not sweet and do not show positive tests with Tollenās and Benedictās solutions, whereas monosaccharides are sweet and show positive tests ā¢ Limited water solubility ā¢ Examples: ā Cellulose and glycogen - Storage polysaccharides ā Chitin - Structural polysaccharide ā Hyaluronic acid - Acidic polysaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 79
80.
Section 18.15 General Characteristics
of Polysaccharides Return to TOC A _____ is a polysaccharide in which only one type of monosaccharide monomer is present. a.heteropolysaccharide b.homopolysaccharide c.heteromonosaccharide d.homomonosaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 80
81.
Section 18.15 General Characteristics
of Polysaccharides Return to TOC A _____ is a polysaccharide in which only one type of monosaccharide monomer is present. a.heteropolysaccharide b.homopolysaccharide c.heteromonosaccharide d.homomonosaccharide Copyright Ā©2016 Cengage Learning. All Rights Reserved. 81
82.
Section 18.16 Storage Polysaccharides Return
to TOC Starch ā¢ Storage polysaccharide: Polysaccharide that is a storage form for monosaccharides and used as an energy source in cells ā¢ Starch ā Glucose is the monomeric unit ā Storage polysaccharide in plants Copyright Ā©2016 Cengage Learning. All Rights Reserved. 82
83.
Section 18.16 Storage Polysaccharides Return
to TOC Types of Polysaccharides Isolated From Starch ā¢ Amylose ā Unbranched-chain polymer and accounts for 15%ā 20% of the starch ā Has Ī±(1ļ 4) glycosidic bonds ā¢ Amylopectin ā Branched chain polymer and accounts for 80%ā85% of the starch ā Has Ī±(1ļ 4) and Ī±(1ļ 6) glycosidic bonds ā Up to 100,000 glucose units are present ā Amylopectin is digested more readily by humans (can hydrolyze Ī± linkages but not Ī² linkages) Copyright Ā©2016 Cengage Learning. All Rights Reserved. 83
84.
Section 18.16 Storage Polysaccharides Return
to TOC Glycogen ā¢ Glucose storage polysaccharide in humans and animals ā¢ Contains only glucose units ā¢ Branched chain polymer with Ī±(1ļ 4) glycosidic bonds in straight chains and Ī±(1ļ 6) in branches ā¢ Three times more highly branched than amylopectin in starch ā¢ Contains up to 1,000,000 glucose units Copyright Ā©2016 Cengage Learning. All Rights Reserved. 84
85.
Section 18.16 Storage Polysaccharides Return
to TOC Glycogen ā¢ Excess glucose in blood is stored in the form of glycogen Copyright Ā©2016 Cengage Learning. All Rights Reserved. 85 Glycogenesis Glycogenolysis Glucose glycogen
86.
Section 18.16 Storage Polysaccharides Return
to TOC In starch, two different glucose-containing polysaccharides can be isolated. They are _____ and _____. a.glycogen; amylose b.amylose; amylopectin c.amylose; cellulose d.glycogen; cellulose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 86
87.
Section 18.16 Storage Polysaccharides Return
to TOC In starch, two different glucose-containing polysaccharides can be isolated. They are _____ and _____. a.glycogen; amylose b.amylose; amylopectin c.amylose; cellulose d.glycogen; cellulose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 87
88.
Section 18.17 Structural Polysaccharides Return
to TOC Cellulose ā¢ Linear homopolysaccharide with Ī²(1ļ 4) glycosidic bond ā¢ Contains up to 5000 glucose units with molecular mass of 900,000 amu ā Cotton has 95% cellulose and wood 50% cellulose ā¢ Humans do not have enzymes that hydrolyze Ī²(1ļ 4) linkages and so they cannot digest cellulose ā Animals also lack these enzymes, but they can digest cellulose due to the presence of cellulase-producing bacteria Copyright Ā©2016 Cengage Learning. All Rights Reserved. 88
89.
Section 18.17 Structural Polysaccharides Return
to TOC Cellulose ā¢ It serves as dietary fiber in food and readily absorbs water resulting in softer stools ā 20ā35 g of dietary fiber is desired everyday Copyright Ā©2016 Cengage Learning. All Rights Reserved. 89
90.
Section 18.17 Structural Polysaccharides Return
to TOC Chitin ā¢ Similar to cellulose structurally and functionally ā¢ Linear polymer with all Ī²(1ļ 4) glycosidic linkages ā It has an N-acetyl amino derivative of glucose ā¢ Function is to give rigidity to the exoskeletons of crabs, lobsters, shrimp, insects, and other arthropods Copyright Ā©2016 Cengage Learning. All Rights Reserved. 90
91.
Section 18.17 Structural Polysaccharides Return
to TOC Figure 18.32(b) - The Structure of Chitin Copyright Ā©2016 Cengage Learning. All Rights Reserved. 91
92.
Section 18.17 Structural Polysaccharides Return
to TOC What is the structural component of plant cell walls? a.Starch b.Glycogen c.Chitin d.Cellulose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 92
93.
Section 18.17 Structural Polysaccharides Return
to TOC What is the structural component of plant cell walls? a.Starch b.Glycogen c.Chitin d.Cellulose Copyright Ā©2016 Cengage Learning. All Rights Reserved. 93
94.
Section 18.18 Acidic Polysaccharides Return
to TOC Acidic polysaccharides ā¢ Polysaccharides with a repeating disaccharide unit containing an amino sugar and a sugar with a negative charge due to a sulfate or a carboxyl group ā¢ They are heteropolysaccharides, i.e., different monosaccharides exist in an altering pattern ā¢ Examples: ā Hyaluronic acid ā Heparin Copyright Ā©2016 Cengage Learning. All Rights Reserved. 94
95.
Section 18.18 Acidic Polysaccharides Return
to TOC Hyaluronic Acid ā¢ Alternating residues of N-acetyl- Ī²-D- glucosamine and D-glucuronate ā¢ Highly viscous and serve as lubricants in the fluid of joints as well as vitreous humor of the eye Copyright Ā©2016 Cengage Learning. All Rights Reserved. 95
96.
Section 18.18 Acidic Polysaccharides Return
to TOC Heparin ā¢ Polysaccharide with 15ā90 disaccharide residues per chain ā¢ Blood anticoagulant Copyright Ā©2016 Cengage Learning. All Rights Reserved. 96
97.
Section 18.18 Acidic Polysaccharides Return
to TOC Heparin, a well known acidic polysaccharide, is best known for its biochemical function as a(n) _____. a.coagulant b.anticoagulant c.exoskeleton d.dietary fiber Copyright Ā©2016 Cengage Learning. All Rights Reserved. 97
98.
Section 18.18 Acidic Polysaccharides Return
to TOC Heparin, a well known acidic polysaccharide, is best known for its biochemical function as a(n) _____. a.coagulant b.anticoagulant c.exoskeleton d.dietary fiber Copyright Ā©2016 Cengage Learning. All Rights Reserved. 98
99.
Section 18.19 Dietary Considerations
and Carbohydrates Return to TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 99 Nutrition ā¢ Foods high in carbohydrate content constitute over 50% of the diet of most people of the world ā Corn in South America ā Rice in Asia ā Starchy root vegetables in parts of Africa ā Potato and wheat in North America ā¢ Balanced dietary food should contain about 60% of carbohydrate
100.
Section 18.19 Dietary Considerations
and Carbohydrates Return to TOC Classes of Dietary Carbohydrates ā¢ Simple carbohydrates: Dietary monosaccharides or disaccharides ā Sweet to taste and commonly referred to as sugars ā Constitute 20% of the energy in the US diet ā¢ Complex carbohydrates: Dietary polysaccharides ā Include starch and cellulose, which are normally not sweet to taste Copyright Ā©2016 Cengage Learning. All Rights Reserved. 100
101.
Section 18.19 Dietary Considerations
and Carbohydrates Return to TOC Dietary carbohydrates constitute _____ of the diet of most people. a.10% b.25% c.35% d.50% Copyright Ā©2016 Cengage Learning. All Rights Reserved. 101
102.
Section 18.19 Dietary Considerations
and Carbohydrates Return to TOC Dietary carbohydrates constitute _____ of the diet of most people. a.10% b.25% c.35% d.50% Copyright Ā©2016 Cengage Learning. All Rights Reserved. 102
103.
Section 18.20 Glycolipids and
Glycoproteins: Cell Recognition Return to TOC ā¢ Glycolipid: Lipid molecule that has one or more carbohydrate (or carbohydrate derivative) units covalently bonded to it ā¢ Glycoprotein: Protein molecule that has one or more carbohydrate (or carbohydrate derivative) units covalently bonded to it ā Such carbohydrate complexes are very important in cellular functions such as cell recognition Copyright Ā©2016 Cengage Learning. All Rights Reserved. 103
104.
Section 18.20 Glycolipids and
Glycoproteins: Cell Recognition Return to TOC A protein molecule that has one or more carbohydrate units covalently bonded to it is known as a(n) _____. a.glycolipid b.glucoprotein c.glycoprotein d.oligosaccharide protein Copyright Ā©2016 Cengage Learning. All Rights Reserved. 104
105.
Section 18.20 Glycolipids and
Glycoproteins: Cell Recognition Return to TOC A protein molecule that has one or more carbohydrate units covalently bonded to it is known as a(n) _____. a.glycolipid b.glucoprotein c.glycoprotein d.oligosaccharide protein Copyright Ā©2016 Cengage Learning. All Rights Reserved. 105
106.
Chapter 18 Return to
TOC Concept Question 1 D-glucose consists of six carbon atoms. When drawn using the Fischer projection formula, how do you determine that it is the D isomer? How many chiral carbon centers does it have and how many stereoisomers are possible? a.The āOH on the chiral carbon farthest from the carbonyl group points to the right. There are five chiral centers providing 32 stereoisomers. b.The āOH on the chiral carbon farthest from the carbonyl group points to the right. There are four chiral centers providing 16 stereoisomers. c.The āOH on the chiral carbon farthest from the carbonyl group points to the left. There are five chiral centers providing 32 stereoisomers. d.The āOH on the chiral carbon farthest from the carbonyl group points to the left. There are four chiral centers providing 16 stereoisomers. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 106
107.
Chapter 18 Return to
TOC Concept Question 1 D-glucose consists of six carbon atoms. When drawn using the Fischer projection formula, how do you determine that it is the D isomer? How many chiral carbon centers does it have and how many stereoisomers are possible? a.The āOH on the chiral carbon farthest from the carbonyl group points to the right. There are five chiral centers providing 32 stereoisomers. b.The āOH on the chiral carbon farthest from the carbonyl group points to the right. There are four chiral centers providing 16 stereoisomers. c.The āOH on the chiral carbon farthest from the carbonyl group points to the left. There are five chiral centers providing 32 stereoisomers. d.The āOH on the chiral carbon farthest from the carbonyl group points to the left. There are four chiral centers providing 16 stereoisomers. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 107
108.
Chapter 18 Return to
TOC Concept Question 2 Prior to a marathon run, an athlete consumes large amounts of complex carbohydrates to do what is known as ācarbohydrate loading.ā What happens in the body to the glucose molecules present in these complex carbohydrates and why is carbohydrate loading important? a.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of glycogen, which can be used later as a source of stored energy. b.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of starch, which can be used later as a source of stored energy. c.The complex carbohydrates are broken down to galactose and any excess galactose, not used for immediate energy, is stored in the form of glycogen, which can be used later as a source of stored energy. d.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of glycogen, which can be used later to produce muscle tissue needed to complete the marathon. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 108
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Chapter 18 Return to
TOC Concept Question 2 Prior to a marathon run, an athlete consumes large amounts of complex carbohydrates to do what is known as ācarbohydrate loading.ā What happens in the body to the glucose molecules present in these complex carbohydrates and why is carbohydrate loading important? a.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of glycogen, which can be used later as a source of stored energy. b.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of starch, which can be used later as a source of stored energy. c.The complex carbohydrates are broken down to galactose and any excess galactose, not used for immediate energy, is stored in the form of glycogen, which can be used later as a source of stored energy. d.The complex carbohydrates are broken down to glucose and any excess glucose, not used for immediate energy, is stored in the form of glycogen, which can be used later to produce muscle tissue needed to complete the marathon. Copyright Ā©2016 Cengage Learning. All Rights Reserved. 109
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TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 110
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TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 111
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TOC Copyright Ā©2016 Cengage Learning. All Rights Reserved. 116
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