General Organic Chemistry-03- Assignments

Chemistry : General Organic Chemistry & Isomerism
ASSIGNMENTS
SECTION - I
SUBJECTIVE QUESTIONS
LEVEL - I
1. Give the IUPAC name for the amine.
3
3 2 3
5
2
3
CH
|
CH —N —C —CH CH
|
|
C H
CH
2. Write the aci-form of nitromethane.
3. Draw Newman projections for theanti and gauche conformations of indicated stability of theconformers.
(a) 1-bromo-2-chloroethane (b) 3-hydroxypropanoic acid
4. Classify the following as nucleophiles and electrophiles :
(i) H3O+ (ii) NH3 (iii) AlCl3 (iv) ROH
(iv) BF3 (v) CN– (vi) SO3 (vii) R—O—R
5. Arrange given compounds in order of decreasing acidity :
(a) CH3
– NO2
(b) NO2
– CH2
– NO2
(c) CH3
– CH2
– NO2
(d) 2 2
2
NO CH NO
|
NO
 
6. Give IUPAC names of the following compounds :
(a) 3
CH C CH CH CHO
|| | |
O OH Cl
   
(b) 2 2
3
HOOC CH CH CH COOH
|
CH
   
7. Arrange the following in decreasing order of their stability :
(a)    
3 6 5 2 3 2 3
3 2
I II III IV
CH C C H CH CH CH CH CH
   
8. How many isomers are possible for C3
H6
O.
9. C – C single bond length in propene appears to be less than C – C single bond length in propane. Why ?
10. How many Aromatic isomers are possible for CH2
CH3

LEVEL - II
1. Explain why alkyl groups act as electron donors when attached to a p-system.
2. Convert the following formula for alanine to a Fischer projection :
C
NH2
COOH
C
H3
C
H3
3. Draw all possible stereoisomers of 2, 3-dichlorobutane. Indicate enantiomeric and diastereomeric pairs.
4. Do the following structures represent identical molecules or a pair of enantiomers?
(a) C
CH3
H
C2H5
O
H
and C
OH
CH3
H
C2H5
(b) C
CH2Br
OH
CH3
H
and C
H
CH3
CH2Br
O
H
5. Acid amides are amphoteric in nature. Explain.
6. Addition of HBr to 1-bromopropene on the presence of benzoyl peroxide gives 1-bromopropane as the
main product. Justify.
7. Arrange basicity of the given compounds in decreasing order :
(a) CH3
– CH2
– NH2
(b) CH2
= CH – NH2
(c) CH  C – NH2
8. Decreasing order of stability of given carbocations is as :
(a)
+
(b) 2 2
CH CH CH

 
(c) 6 5 6 5
C H CH C H

  (d) 3 3
CH CH CH

 
9. Identify the pairs of enantiomers and diastereomers amongst the following compounds
H OH
CH3
CH3
H
(a)
H
H
OH
OH
CH3 CH3
(b) (c)
H
CH3 OH
H
CH3

10. How many optical isomers are possible for
CH3
H H
H
H
H H
CH3
LEVEL - III
1. Arrange the following in increasing order of acidic strength
COOH
OCH3
COOH
OCH3
COOH
OCH3
COOH
2. How many optically active isomers are possible for glucose and fructose.
3. Arrange the carbocations in increasing order of stability when the following compounds are treated
with aqueous KOH.
CH2Cl CH2Cl
OCH3
CH2Cl
CH3
CH2Cl
NO2
4. Arrange the following in increasing order of melting point.
CH3
COOH HCOOH CH3
CH2
COOH CH3
CH2
CH2
COOH
5. How many aromatic isomers are possible for C7
H8
O and total isomers for C4
H6
6. An optically pure compound X gain an []0
25
= + 29.0°. A mixture of X and its enantiomer Y gain
[]0
25
= 10.0°. What is the ratio of X and Y in the mixutre.
7. Why amines are more basic than amide and cyanides.
8. Arrange the following compounds in increasing order of stability.
N N
H
N
H
O
N
H
9. The configuration of the chiral centre of the given compound
H OH
CH3
Br H
Et
is 2s, 3s explain.

10. Pick out the compound which can be obtained is an optically active from.
HOOC
HOOC
NO2
NO2
H
C
H3 H
COOH
H OH
COOH
O
H H
H OH
COOH
, ,
O2N
HOOC
NO2
COOH
.

SECTION - II
SINGLE CHOICE QUESTIONS
1. Consider the following carbanions :
(1) 3 2
CH CH

 (2) 2
CH CH


(3) CH C


Correct order of stability of these carbanions in decreasing order is
(a) 1 > 2 > 3 (b) 2 > 1 > 3
(c) 3 > 2 > 1 (d) 3 > 1 > 2
2. Consider the following carbocations :
(a) 2
CH CH

 (b) 3 2
CH CH


(c) 2 2
CH CH CH

  (d) 2
6 5
C H CH


Stability of these carbocations in decreasing order is
(a) 4 > 3 > 2 > 1 (b) 4 > 3 > 2 > 1
(c) 3 > 4 > 2 > 1 (d) 3 > 4 > 1 > 2
3. Which of the following compounds is most basic :
(a)
NH2
(b)
NH2
NO2
(c)
NH2
CN
(d)
NH2
CH3
4. Consider the following compounds :
(1)
N
H
(2)
N
(3)
N N
O
H
(4)
N
O
H
(4)
H
N
Order of basicity of these compounds in decreasing order is :
(a) 4 > 1 > 2 > 3 (b) 1 > 3 > 4 > 2
(c) 2 > 3 > 4 > 1 (d) 1 > 3 > 2 > 4
5. In which compound carbon-carbon bond length is maximum ?
(a) Ethane (b) Propene
(c) 2-butene (d) 2, 3-dimethyl-2-butene

6. Which of these species are electrophiles :
(a) CCl2
(b) BF3
(c) 2
NO

(d) All of these
7. Which of the following species is electrophile :
(a) OH

(b) 3
CH O


(c) BF3
(d) NH3
8. Acyl cation has two resonating structures (I) and (II)
   
I II
R C O R C O
 
    
Which statement is correct for (I) and (II)
(a) (I) is more stable than (II)
(b) (II) is more stable than (I)
(c) Stability of (I) and (II) will be the same
(d) For some time (I) will be more stable and for remaining time (II) will be more stable
9. Tautomerism is shown by
(a) 3 2 3
O O
| | | |
CH C CH C CH
    (b) 3 2 2 5
O O
| | | |
CH C CH COOC H
  
(c) 3 2
CH CH N
 
O
O
(d) All of these
10. Which one of the following compounds has maximum enol content in solution
(a) 3 2 2 5
O
||
CH C CH COOC H
   (b) 3 2
O
||
CH C CH CN
  
(c) 3 3
O
||
CH C CH
  (d) O
11. Which one of the following has the highest nucleophilicity
(a) F–
(b) OH–
(c) CH 3

(d) –
NH2
12. The most stable free radical is :
(a) 3 2
CH CH
 (b) 2 2
CH CH CH
 
(c) 3 3
CH CH CH
  (d) 3
CH
13. +R effect will be shown by :
(a) NO2
(b) —CN
(c) CHO (d) – NHCOCH3

14. The number of delocalised  -electrons in the given compound is

(a) 4 (b) 6
(c) 8 (d) 2
15. In pyridine :
N
:
Number of conjugated electrons are ;
(a) 6 (b) 8
(c) Zero (d) 5
16. Consider the following isomeric alkanes
(1) n-pentane (2) Isopentane
(3) Neopentane
Arrange bp of these compounds in decreasing order :
(a) 1 > 2 > 3 (b) 3 > 2 > 1
(c) 1 > 3 > 2 (d) 3 > 1 > 2
17. In which of the following structures the pair of carbon atoms do not lie in the same plane
(a)
H C
3
C == C
CH3
H
CH _ H C
3 2
*
*
(b)
CH3
*
*
(c)
CH ==C
*
*
H
H (d)
H C
3
C == C
H
CH _ CH
2 3
*
*
H C
3
18. In which of the following molecules all the effects namely inductive, mesomeric and hyperconjugation
operate
(a) (b) 3
COCH
3
CH
(c)
3
CH
3
CH (d)
19. Most acidic hydrogen is present in
(a)
O O
(b)
O
(c) (CH3
CO)3
CH (d) None of these
20. Which one of the following chlorides gives white precipitate with AgNO3
most readily
(a) CH3
= CH – CH2
Cl (b) CH2
= CH– Cl
(c) CH3
– CH2
– CH2
Cl (d) (C6
H5
)2
CH – Cl

SECTION - III
MULTIPLE CHOICE QUESTIONS
1. Carbanion (X) loses a leaving group to form alkene which is/are correct statements?
CH3
CH3
C
H3
C
H3
H L
H , I


CH3
CH3
C
H3
C
H3
L
L
II




CH3
C
H3
CH3
C
H3
(a) It is E2
type (b) It is E1
type
(c) It is E1-CB type (d) Step I is fast and II is slow
2. In which case/cases SE
will be in meta position?
(a) N2
(b) NH C
O
CH3
(c) N(CH3)3 (d) CF3
3. Which of the following cannot undergo nucleophilic substitution under ordinary condition?
(a) Benzyl chloride (b) Allyl chloride
(c) Vinyl chloride (d) n-Propyl chloride
4. HCN and HNC are which type of isomers?
(a) Position (b) Chain
(c) Tautomers (d) Functional
5. Which is/are correct statements for
A B
(a) A is Z and B is E (b) A and B are same structures
(c) A is cis and B is trans (d) A is R and B is S
6. Which of the following is an optically active compound?
(a) 1, 3-Butadiene (b) Propadiene
(c) 2, 3-Pentadiene (d) 1, 3-Pentadiene
7. Which of the following will show geometrical isomerism?
(a) HO—N==N—OH (b) CH3
CH2
NO2
(c) (d) C NOH
C
H3
C
H3

8. Which of the following pairs of compounds are tautomers?
(a) Propanal and propanone (b) 1-Propanol and 2-Propanol
(c) Ethanol and vinyl alcohol (d) Vinyl alcohol and ethanal
9. Geometric isomerism will be exhibited by
(a) 1-Pentene (b) 3-Methyl-1-butene
(c) 2-Pentene (d) All of these compounds
10. Which of the following compounds is not chiral?
(a) DCH2
CD2
CH2
Cl (b) 3 2
CH CH CH—Cl
|
D
(c) CH3
CHDCH2
Cl (d) CH3
CHCl·CH2
D

MISCELLANEOUS QUESTIONS
SECTION - IV
COMPREHENSION TYPE QUESTIONS
Write up - I
Isomers which are nonsuper-imposable mirror images of each other are called enantiomers. All optically
active compounds exhibit enantiomerims. The stereoisomers which are not mirror images of each
other are called diastereomers. Enantiomers are always chiral molecules wheres diastereomers may
or may not be chiral, configuration of the compound having no element of symmetry is always chiral.
Chiral molecule may or may not contain chiral carbon.
1. Which of the following compounds are chiral?
(a)
2
CHO
|
H —C — OH
|
CH OH
(b)
C C
H
C
H3
C
C2H5
H
(c)
Br
Cl
C
CH3
H
(d) all of these
2. Which of the following pairs are diastereomers?
(a)
3 3
CHO CHO
| |
H —C —OH and HO —C — H
| |
CH CH
(b)
H C
COOH
C
Br
Br H
C6H5
Br C
COOH
C
H
H Br
C6H5
and
(c) C C
H
CH3
C
H3
H
C C
CH3
H
C
H3
H
and (d) all of these
3. Which statement is correct for enantiomers :
(a) Both are non-superimposable mirror images
(b) Both are superimposable mirror images
(c) Physical properties are different
(d) Reaction velocity with optically active compound is same

Write up - II
Delocalisation of electrons take place in alternate single and multiple bonds involving carbon atoms.
Delocalisation may also occur in a conjugated system involving carbon atom and atom other than the
carbon. There are also examples in which pi orbital and p orbital (vacant or half-filled or filled)
overlap. Thus delocalisation are of the following types :
(i) delocalisation by ,  overlap
(ii) delocalisation by , p overlap
Delocalisation makes system stable. More is the number of resonating structures more is the stability
of the system.
4. In which of the following compounds delocalisation is not possible
(a) 1, 4-pentadiene (b) 1, 3-butadiene
(c) 1, 3, 5-hexatriene (d) benzene
5. Arrange the following resonating structures of formic acid in decreasing order of stability.
(I)
O
||
H —C —O — H (II)
O
|
H —C O— H



(III)
O
|
H —C—OH


(IV)
O
|
H —C—OH


(a) I > II > IV > III (b) I > II > III > IV
(c) IV > III > II > I (d) I > IV > II > III
6. Which one of the following carbocation is most stable due to the resonance?
(a) (b) 6 5 2
C H — CH

(c) 6 5 6 5
C H — CH — C H

(d) 6 5 6 5
3
C H —C —C H
|
CH


MULTIPLE MATCHING TYPE QUESTIONS
Match the following
7. Column A Column B
(A) CH2
=CH2
+ HBr in presence of oxygen (1) Carbocation
(B) Dehydrobromination of
2-methyl-2-bromopropane (2) Carbanion
(C) Alkaline hydrolysis of chloroform (3) Free radical
(D) Rearrangement not possible in (4) Carbene
(A) (B) (C) (D)
(a) 1, 3 2 3, 4 2
(b) 2, 3 1, 3 4 3
(c) 1, 4 3 2 1
(d) 3 1 4 2, 3, 4
(A) sp (1) Carbocation
(B) sp2
(2) Carbanion
(C) sp3
(3) Free radical
(D) Both sp2
and sp3
(4) Triplet carbene
(A) (B) (C) (D)
(a) 2 2 3, 4 1
(b) 2 2, 3, 4 2 1
(c) 3 2, 3, 4 1 2
(d) 4 3 2 1
(A) C6
H5
CH2
CD2
Br on reacting with
C2
H5
O–
gives C6
H5
—CH==CD2
(1) E1
(B) PhCHBrCH3
and PhCHBrCD3
both
react with the same rate. (2) E2
(C) C6
H5
CH2
CH2
Br on treatment
with C2
H5
O–
and C2
H5
OD
gives C6
H5
CD==CH2
(3) E1CB
(D) C6
H5
CH2
CH2
Br reacts faster
than C6
H5
CD2
CH2
Br on reaction
with C2
H5
O–
in ethanol (4) First order reaction

(A) (B) (C) (D)
(a) 1, 4 2 3 2, 3
(b) 2 1, 4 3 2
(c) 2 1, 4 1, 3 2, 3
(d) 1, 4, 2, 3 3 2
ASSERTION-REASON TYPE QUESTIONS
The question given below consist of an ASSERTION and the REASON. Use the following key for the
appropriate answers
(a) If both Assertion and Reason are correct and Reason is the correct explanation for Assertion
(b) If both Assertion and Reason are correct and Reason is not the correct explanation for
Assertion
(c) If Assertion is correct but Reason is not correct.
(d) If Assertion is incorrect but Reason is correct.
10. Assertion : Cyclobutane is more reactive than cyclopentane.
Reason : The carbocyclic ring in cyclobutane is more strained than in cyclopentane.
11. Assertion : SN
1 reaction of 2-chloro-3, 3-dimethylbutane with NaOH gives 2, 3-dimethyl-2-butanol as
the major product.
Reason : Intermediate is a secondary carbocation which undergoes 1, 2-methyl shift giving more
stable tertiary carbocation.
12. Assertion : Hyperconjugation results in thestabilisationo f carbocation by delocalising the positive charge.
Reason : Hyperconjugation produces some additional bonding between the electron-deficient carbon
and the adjacent carbon.
13. Assertion : Ortho-hydroxy benzoic acid is much more acidic than benzoic acid.
Reason : Anion formed from ortho-hydroxy benzoic acid is stabilised by hydrogen bonding.
14. Assertion : The carbocation CF3
—C+
H2
is less stable than C+
F3
.
Reason : In case of CF3
—C+H
2, CF3 is strong electron withdrawing therefore increases +ve charge
when in C+F3, Ione pair of F overlap with vacant p-orbital of carbon reducing +ve change by
p-pt bonding or back bonding.
15. Assertion : The Friedel craft alkylation of nitrobenzene gives meta alkylated nitrobenzene.
Reason : Nitrogroups an meta directing.

SECTION - V
(PROBLEMS )
A. Only one option is correct (Objective Questions)
1. Among the following, the least stable resonance structure is
(a) N
O
O
(b) N
O
O
(c) N
O
O
(d) N
O
O
2. The IUPAC name of C6
H5
COCl is :
(a) Benzoyl chloride (b) Benzene chloro ketone
(c) Benzene carbonyl chloride (d) Chloro phenyl ketone
3. 4-methyl benzene sulphonic acid reacts with sodium acetate to give :
(a)
CH3
SO3Na
; CHCOOH (b)
COONa
CH3
; SO3
(c)
CH3
; SO3
(d)
O2S
CH3
OCOCH3
; NaOH
4. Which of the following resonating structures of 1-methyoxy-1, 3-butadiene is least stable?
(a) 2 3
CH — CH CH — CH O— CH
 
 
(b) 2 2 3
CH CH — CH — CH O— CH
 
 
(c) 2 3
CH — CH — CH CH — O — CH
 

(d) 2 3
CH CH — CH — CH — O — CH
 


5. Arrange in order of increasing acidic strength
N
+
H3
H3N
+
COOH
Z
X
Y
(a) X > Z > Y (b) Z < X > Y
(c) X > Y > Z (d) Z > X > Y
6. C2
is rotated anticlockwise 120°C about C2
—C3
bond. The resulting conformer is :
CH3
H
H
H
CH3
H
3
2
(a) partially eclipsed (b) eclipsed
(c) gauche (d) staggered
7. Among the following the molecule with the highest dipole moment is :
(a) CH3
Cl (b) CH2
Cl2
(c) CHCl3
(d) CCl4
8. Which of the following represent the given mode of hybridization sp2
– sp2
– sp – sp from left to right?
(a) H2
C==CH—CCH (b) HCC—C—CCH
(c) H2
C==C==C==CH2
(d) C
H2
CH2
9. Which of the following hydrocarbons has the lowest dipole moment?
(a) C C
H
CH3
C
H3
H
(b) CH3
—HC==HC—CH3
(c) CH3
—CH2
CH==CH2
(d) CH2
==CH—CH==CH2
10. Which of the following compounds exhibits, stereoisomerism?
(a) 2-methyl butene-1 (b) 3-methyl butyne-1
(c) 3-methyl butanoic acid (d) 2-methyl butanoic acid

B. More than one options are correct (Objective Questions)
1. Only two isomeric monochloro derivatives are possible for :
(a) n-butane (b) 2, 4-dimethyl pentane
(c) benzene (d) 2-methyl propane
2. The compound in which C uses its sp3
- hybrid orbitals for bond formation is :
(a) HCOOH (b) (H2
N)2
CO
(c) (CH3
)3
COH (d) CH3
CHO
3. Which of the following have asymmetric carbon atom?
(a) H C C H
H
Cl
H
Br
(b) H C C Cl
H
H
H
Cl
(c) H C C D
H
H
H
Cl
(d) H C C CH3
Br
H
OH
H
4. The molecules that will have dipole moment are :
(a) 2, 2 dimethyl propane (b) trans 2-pentene
(c) cis-3-hexene (d) 2, 2, 3, 3-tetramethyl butane
5. What is the decreasing order of strength of the bases :
2 3 2
OH , NH , H — C C and CH — CH ?
   

(a) 3 2 2
CH — CH NH H — C C OH
   
   
(b) 3 2 2
H — C C CH — CH NH OH
   
   
(c) 2 3 2
OH NH H — C C CH — CH
   
   
(d) 2 3 2
NH H — C C OH CH — CH
   
   
6. Which of the following compounds will show geometrical isomerism?
(a) 2-butene (b) propene
(c) 1-phenyl propane (d) 2-methyl butene
7. Tautomerism is exhibited by :
(a) CH==CH—OH (b) O O
(c) O
O
(d) O
O

C. Assertion-Reason Type Questions
1. In the following a statement (S) in the left hand column and an explanation (E) in the right hand column.
Ascertain the relationship between S and E and select the correct code among a, b, c and d which are
defined below :
(a) Both S and E are true, and E is the correct explanation of S
(b) Both S and E are true, but E is not the correct explanation of S
(c) S is true but E is false
(d) S is false but E is true
Statement (S) : p-Hydroxybenzoic acid has a lower boiling point than o-hydroxybenzoic acid.
Explanation (E) :o-Hydroxybenzoic acid has intramolecular hydrogen bonding.
SUBJECTIVEQUESTIONS
1. Write the IUPAC name of CH3CH2CH==CH·COOH
2. Give the IUPAC name of the following compound :
Me
Me
Me
Me
Me
(Me = methyl)
3. Write the IUPAC name for the following :
C
H3 N C CH2 CH3
CH3 C2H5
CH3
4. Write tautomeric forms of phenol.
5. Draw the setreochemical structures of the products in the following reactions :
(i) Br H
C2H5
C2H5
2
N
NaOH
S


(ii) 2
H
Lindlar catalyst
R — C C — R
 
6. Write down the structures of the stereoisomers formed when cis-2-butene is reacted with bromine.
7. Discuss the hybridization of carbon atoms in alkene (C3H4) and show the -orbital overlaps.

8. Identify the pairs of enantiomers and diastereomers from the following :
H OH
CH3
O
H H
CH3
I
O
H H
CH3
O
H H
CH3
II
O
H H
CH3
H OH
CH3
III
9. (a) Draw Newmann’s projection for the less stable staggered form of butane.
(b) Relatively less stability of the staggered form is due to :
(i) Torsional strain
(ii) van der Waal’s strain
(iii) Combination of the above two
10. obs ix
   l
where l is the dipole moment of stable conformer and xi is the mole fraction of that conformer.
.
(a) Write stable conformer for Z—CH2—CH2—Z in Newmann’s projection.
If µsolution = 1.0 D and mole fraction of anti form = 0.82, find µGauche
(b) Write most stable meso conformer of
CHDY
|
CHDY
If (i) Y = CH3 about C2—C3 rotation and
(ii) Y = OH about C! —C2 rotation.

ANSWERS
EXERCISE - 1
1. (3 Cyano Propanal) 2. (3 Ethyl 2, 5 di Methyl hexane)
3. (2, 3 dipoxy pentane) 4. (3 Chloro Pentanidoi Acid)
EXERCISE - 2
1. (4) 2. (4)
3. (2) 4. (3)
5. (2)
EXERCISE - 3
1. (3) 2. (2)
3. (1) 4. (4)
5. (3) 6. (2)
EXERCISE - 4
1. (a) C6H5
+
is a vinyl carbocation and is less stable than C6H11
+
, a 2° carbocation.
(b) In C6
H5
: –
, the electron pair is in an sp2
hybrid orbital. The carbanion has more s-character and is
more stable than C6
H11
: –
whose unshared electron pair is in an sp3
hybrid orbital.
EXERCISE - 5
1. (a) There are four stereoisomers. A and B are enantiomers, are are C and D.
(b) A and B are diastereomers of C and D.
CH3
C H5
2
Cl
H
HO H
CH3
C H5
2
H
Cl
H OH
(A) (B)
(racemate)1
CH3
C H5
2
Cl
H
H HO
CH3
C H5
2
H
Cl
HO H
(C) (D)
(racemate)2
2. Cyclopentane is best considered as a flat ring. All trans-isomers exist as a pair of enantiomers. All cis-
isomers are meso.

Me
Me
Me
Me
racemate
trans–1, 2-Dimethylcyclopentane
Me
Me
meso
cis –1, 2-Dimethylcyclopentane
Me
Me Me
Me
racemate
trans–1, 3-Dimethylcyclopentane
meso
cis –1, 3-Dimethylcyclopentane
Me Me
+
C H
6 5
+
+
C H
6 11
+
H –
C H
6 5:
–
sp
2
C H
6 11:
–
H
–
sp
3
SECTION - I
(Subjective Questions)
Answers are given in the separate booklet (Level – I to Level – III)
SECTION - II
(Single Choice Questions)
1. (c) 2. (a)
3. (d) 4. (d)
5. (a) 6. (d)
7. (c) 8. (b)
9. (d) 10. (d)
11. (c) 12. (b)
13. (d) 14. (b)
15. (a) 16. (a)
17. (d) 18. (b)
19. (c) 20. (d)

SECTION - III
(Multiple Choice Questions)
1. (c, d) 2. (c, d)
3. (d) 4. (c, d)
5. (a, c) 6. (c)
7. (a, b, c) 8. (d)
9. (c) 10. (a)
SECTION - IV
(Comprehension Type Questions)
1. (d) 2. (c)
3. (a) 4. (a)
5. (b) 6. (d)
(Multiple Matching Type Questions)
7. (d) 8. (b)
9. (b)
(Assertion Reason Type Questions)
10. (b)
11. (a) 12. (a)
13. (a) 14. (a)
15. (d)
SECTION - V
A. Only one option is correct (Objective Questions)
1. (a) 2. (c)

3. (a) 4. (c)
5. (a) 6. (c)
7. (a) 8. (a)
9. (b) 10. (d)
C. Assertion-reason type questions
1. (d)
SUBJECTIVE
Answers are given in the separate booklet.

General Organic Chemistry-03- Assignments

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