WORK BOOK_P_IV.doc

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Work Book (Phase - IV) Subjective: Board Type Questions 1. Which bond is more polar in the following pairs of molecules? (a) H3C – H, H3C – Br (b) H3C – NH2, H3C – OH (c) H3C – OH, H3C – SH 2. Write resonance structures of (a) CH3COO– and (b) C6H5NH2. Show the movement of electrons by curved arrows. 3. Write the resonance structures of CH2 = CH – CHO and arrange them in order of decreasing stability. 4. Give reasons why the following two structures (I and II) cannot be the major contributors to the real structure of CH3COOCH3. 5. Using curved arrow notation, show the formation of reactive intermediates when the following covalent bonds undergo heterolytic cleavage. (a) CH3 – SH (b) CH3 – CN (c) CH3 – Cu 6. Giving proper justification, categories the following molecules/ions as nucleophile or electrophile: 7. Identify the electrophilic centres in the following: CH2 = C = O, CH3CN, CH3I 8. What is the relationship between the members of following pairs of structures? Are they identical, structural or geometrical isomers, or resonance contributors? (a) (b) (c) (d) 9. What type of aromatic compounds are present as particulates in the air? 10. Why ‘photochemical smog’ is so called? 11. Draw the structure of the tautomer of phenol and write its IUPAC name. 12. Arrange the following in increasing order of C – C bond length: C2H6, C2H4, C2H2. 13. Name the alkyl groups derived from isobutene. 14. Select electrophiles out of the following: H+, Na+, Cl–, C2H5OH, AlCl3, SO3, CN–, 15. Arrange the following: (i) in order of increasing stability. (ii) in order of decreasing stability. (iii) in order of increasing stability. 16. Which is expected to be more stable, O2NCH2CH2O– or CH3CH2O– and why? 17. Indicate σ- and π-bonds in the following compounds: (a) C6H6 (b) C6H12 (c) CH2Cl2 (d) CH2 = C = CH2 (e) CH3NO2 (f) HCONHCH3 18. A hydrocarbon has the molecular mass 70. Write all the possible structural isomers and give their IUPAC names. 19. What is the nature of ‘photochemical smog’? 20. Explain inductive and electromeric effect with examples. 21. Explain hyperconjugation effect. 22. What is COD? Which chemical substance is generally used in its measurement? 23. For the following bond cleavages, use curved arrows to show the electron flow and classify each as homolysis or heterolysis. Identify reactive intermediate products as free radical, carbocation and carbanion. (a) (b) (c) (d) 24. Draw the resonance structures of the following carbocation? Use curved arrows to show how one structure is converted into another. 25. (a) Write the resonance structures of diazomethane (CH2N2). (b) Give the hybridized state of carbon and each N in each structure. (c) How does the H – C – H bond angle in the hybrid compare with the bond angles predicted from each contributing structure? 26. With proper justification, arrange the following in order of increasing stability. 27. Give the IUPAC name for the a

Work Book (Phase - IV)
Subjective:
Board Type Questions
1. Which bond is more polar in the following pairs of molecules?
(a) H3C – H, H3C – Br
(b) H3C – NH2, H3C – OH
(c) H3C – OH, H3C – SH
2. Write resonance structures of (a) CH3COO– and (b) C6H5NH2. Show the movement of
electrons by curved arrows.
3. Write the resonance structures of CH2 = CH – CHO and arrange them in order of
decreasing stability.
4. Give reasons why the following two structures (I and II) cannot be the major contributors
to the real structure of CH3COOCH3.
C
H3
C
O
O
CH3
I
C
H3
C
O
O
CH3
II
5. Using curved arrow notation, show the formation of reactive intermediates when the
following covalent bonds undergo heterolytic cleavage.
(a) CH3 – SH
(b) CH3 – CN
(c) CH3 – Cu
6. Giving proper justification, categories the following molecules/ions as nucleophile or
electrophile: +
3 2 5 3 3 3 2 2
HS , BF , C H O , (CH ) N , Cl , CH C O, H N , NO .
  
  

: :
7. Identify the electrophilic centres in the following: CH2 = C = O, CH3CN, CH3I
8. What is the relationship between the members of following pairs of structures? Are they
identical, structural or geometrical isomers, or resonance contributors?
(a) O O
,
(b) Cl
H
H
Cl
,
H
Cl H
Cl
(c)
,
H OH
OH
H OH
OH (d) D
H D
H
,
D
H H
D
9. What type of aromatic compounds are present as particulates in the air?
10. Why ‘photochemical smog’ is so called?
11. Draw the structure of the tautomer of phenol and write its IUPAC name.
12. Arrange the following in increasing order of C – C bond length: C2H6, C2H4, C2H2.
13. Name the alkyl groups derived from isobutene.
14. Select electrophiles out of the following:
H+, Na+, Cl–, C2H5OH, AlCl3, SO3, CN–, 3 2 2
CH CH , CCl , R X


:
15. Arrange the following:
(i) 6 5 3 6 5 2 6 5 2 2 6 5 3 2
C H CHCH , C H CHCH CH , C H CH CH , C H C(CH )
   
 in order of increasing
stability.
(ii) 3 2 6 5 2 3 3 2 2
CH CH , C H CH , (CH ) C , CH CHCH
   
 in order of decreasing stability.
(iii) 2 3 2 3 3 2 6 5 2
HC C , CH CH , CH CH , CH , (CH ) CH , C H CH
     
  in order of increasing
stability.
16. Which is expected to be more stable, O2NCH2CH2O– or CH3CH2O– and why?
17. Indicate - and -bonds in the following compounds:
(a) C6H6 (b) C6H12
(c) CH2Cl2 (d) CH2 = C = CH2
(e) CH3NO2 (f) HCONHCH3
18. A hydrocarbon has the molecular mass 70. Write all the possible structural isomers and
give their IUPAC names.
19. What is the nature of ‘photochemical smog’?
20. Explain inductive and electromeric effect with examples.
21. Explain hyperconjugation effect.
22. What is COD? Which chemical substance is generally used in its measurement?
23. For the following bond cleavages, use curved arrows to show the electron flow and
classify each as homolysis or heterolysis. Identify reactive intermediate products as free
radical, carbocation and carbanion.
(a)
3 3 3 3
CH O OCH CH O OCH
 
 
 
(b)
O OH
 
 O 2
H O

(c)
Br
Br

(d)
E
 

E
24. Draw the resonance structures of the following carbocation? Use curved arrows to show
how one structure is converted into another.
C
H
H
O
H
25. (a) Write the resonance structures of diazomethane (CH2N2).
(b) Give the hybridized state of carbon and each N in each structure.
(c) How does the H – C – H bond angle in the hybrid compare with the bond angles
predicted from each contributing structure?
26. With proper justification, arrange the following in order of increasing stability.
3 2 2
CH CH , CH C , CH CH .
  
 
27. Give the IUPAC name for the amine.
C
H3
N
C
H3
CH3
C2H5
CH3
28. Write resonance structures of the given compound.
C
H3 CH2
OH
29. trans-pent-2-ene is polar while trans-but-2-ene is non-polar. Explain.
30. Starting with acetylene, how will you prepare pentan-2-one?
31. Acetylene reacts with dil. H2SO4 in presence of mercury salts to give acetaldehyde but
with dil. HCl under similar conditions, it gives vinyl chloride. Explain why?
32. Draw the structures of the following showing all C and H atoms.
(a) 2-methyl-3-isopropylheptane (b) Dicyclopropylmethane
33. Arrange the following in increasing order of their release of energy on combustion.
(i) (ii)
(iii) (iv)
34. Arrange the following set of compounds in order of their decreasing relative reactivity with
an electrophile, E+.
(i) Chlorobenzene, 2, 4-dinitrochlorobenzene, p-nitrochlorobenzene
(ii) toluene, p-H3C – C6H4 – CH3, p-H3C – C6H4 – NO2, p-O2N – C6H4 – NO2.
35. Which of the following shows geometrical isomerism?
(i) CHCl = CHCl (ii) CH2 = CCl2 (iii) CCl2 = CHCl
36. A compound is formed by the substitution of two chlorine atoms for two hydrogen atoms
in propane. What is the number of structural isomers possible?
Fill in the blanks
37. Out of three isomers of C5H12, ……………..has the highest boiling point
while……………has the lowest boiling point.
38. Out of cis-2-butene and trans-2-butne, …………………..has lower melting point.
39. A four – carbon alkyne having weakly acidic character is…………………….
40. Alkanes undergo…………………reactions whereas alkyes gives………………reactions.
IIT Level Questions
41. Alc. KOH HBr
6 5 2 3
heat
C H CH CHCH A B
|
Br

 

42. CH3

 


2
O
N
CH3
Predict the major and minor product with reason
43. Use Markovnikov’s rule to predict the product of the following reactions:
(i) HCl with CH3CCl = CH2 and
(ii) HCl with CH3CH = C(CH3)2.
44. Arrange the following: HCl, HBr, HI, HF in order of decreasing reactivity towards alkenes.
45. Give the structure of an alkene (C4H8) which when treated with H2O/H2SO4 gives C4H10O
which cannot be resolved into optical isomers.
46. How will you demonstrate that double bonds of benzene are somewhat different from that
of olefines?
47. Write the ozonolysis products of (i) mesitylene (ii) o-xylene.
48. An organic compound C8H18 on monochlorination gives a single monochloride. Write the
structure of the hydrocarbon.
49. Which of the following has larger dipole moment? Explain.
1-butyne or 1-butene.
50. State whether true or false:
Photobromination of 2 – methylbutane gives a mixture of 1- bromo-2-methyl propane &
2 – methylpropane in the ratio 9:1.
Objective:
Multiple choice questions with single correct options
1. The condition that cannot be applied for the interconversion of geometrical isomers is
(A) heat (B) pressure
(C) ultraviolet rays (D) catalysis
2. The maximum number of isomers for an alkene with the molecular formula C4H8 is
(A) 2 (B) 3
(C) 4 (D) 5
3. Keto–enol tautomerism is observed in
(A)
H5C6 H
O
(B)
H5C6 CH3
O
(C)
H5C6 C6H5
O
(D) None of the above
4. The two isomers given below are
CO2H
H OH
O
H H
CO2H
CO2H
H OH
H OH
CO2H
(A) enantiomers (B) diastereomers
(C) regiomers (D) position isomers
5.
H C2H5
C
H3
Br

aq. NaOH
H C2H5
C
H3
OH
(60%)
O
H C2H5
C
H3
H
(40%)
This reaction is leading to % racemization equal to
(A) 40 (B) 60
(C) 80 (D) 20
6. But-2-ene exhibit cis–trans isomerism due to
(A) Rotation around C3–C4 sigma bond
(B) Restricted rotation around C=C bond
(C) Rotation about C1–C2 bond
(D) Rotation around C2–C3 double bond
7. C2 is rotated anti-clockwise 120about C2–C3 bond.
3
CH3
H
H .
CH3
.
H
.
H
2
1
The resulting conformer is
(A) partially eclipsed (B) eclipsed
(C) gauche (D) staggered
8. Which of the following compound will exhibit cis–trans (geometrical) isomerism?
(A) 2-butene (B) 2-butyne
(C) 2-butanol (D) Butanal
9. The number of isomers of dibromo derivative (molar mass 186 gmol-1) of an alkene is
(A) two (B) three
(C) four (D) six
10. The amount of optical rotation does not depend on the
(A) concentration of the solution
(B) wavelength of the colour of the solution
(C) temperature
(D) length of the column transversed
11. Which of the following does not posses any element of symmetry?
(A) Ethane (B) (+)–Tartaric acid
(C) Carbon tetrachloride (D) Meso–tartaric acid
12. Which of the following is the uppermost region of atmosphere?
(A) Stratosphere (B) Troposphere
(C) Mesosphere (D) Exosphere
13. Which of the following compound will show geometrical isomerism?
1. 2-Butene 2. Propene
3. 1-Phenylpropene 4. 2-Methylbut-2-ene
(A) 1, 2 (B) 3, 4
(C) 1, 2, 3 (D) 1,3
14. An organic molecule necessarily shows optical activity if it
(A) contains asymmetric carbon atoms
(B) is non-planar
(C) is non-superimposable on its mirror image
(D) is superimposable on its mirror image
15. Which of the following ketone cannot produce oximes that can be geometrical isomers?
(A) Acetophenone (B) Methyl ethyl ketone
(C) Benzophenone (D) Ethyl isopropyl ketone
16. Which one of the following hydrocarbons has the lowest dipole moment?
(A)
C
H3
H H
CH3
(B) C
H3 CH3
(C) C
H3
CH
(D) C
H2
CH
17. Which of the following statement is correct?
(A) Metamerism belongs to the category of structural isomerism.
(B) Tautomeric structures are the resonating structures of a molecule.
(C) The violet colouration produced by a molecule with neutral ferric chloride solution
indicates the presence of keto group in the molecule.
(D) Geometrical isomerism is shown only by alkenes.
18. The optically active tartaric acid is named as D (+) tartaric acid because it has a positive
(A) optical rotation and is derived from D glucose
(B) pH in an organic solvent
(C) optical rotation and is derived from D (+) glyceraldehyde
(D) optical rotation only when substituted by deuterium
19. An enantiomerically pure acid is treated with racemic mixture of an alcohol having one
chiral carbon. The ester formed will be
(A) optically active mixture (B) pure enantiomer
(C) meso compound (D) racemic mixture
20. Which of the following statement is correct?
(A) Allyl carbonium ion (CH2=CH–
+
2
C H ) is more stable than propyl carbonium ion.
(B) Propyl carbonium ion is more stable than allyl carbonium ion.
(C) Both are equally stable.
(D) None of the above
21. Which of the following species is most stable?
(A) 2 6 4 2
p NO C H CH

 (B) 6 5 2
C H CH

(C) 6 4 2
p ClC H CH

 (D) 6 4 2
p HOC H CH


22. Which is the strongest carboxylic acid among the following?
(A) Cl3CCO2H (B) Br3CCO2H
(C) F3CCO2H (D) Cl2CHCO2H
23. The compound with the most acidic hydrogen is
(A) CH3CHO (B) CH3COCH3
(C) CH3
O
C 2CHO (D) CH3 2 2CH3
24. Which of the following is easily debrominated?
(A)
Br
(B)
Br
(C)
Br
(D)
Br
25. Which carbocation is most stable?
(A) 3
CH
(B) 3 2
CH CH
(C)
C
H3 CH
+
CH3
(D)
C
H2
CH2
+
26. The order of the basicity among the amines is
NH2
O2N
NH2
Cl
NH2
CH3 OCH3
NH2
I II III IV
(A) I<II<III<IV (B) II<I<III<IV
(C) I<II<IV<III (D) II<I<IV<III
27. What is the decreasing order of strength of the basesOH , NH2 C and
CH3 2 ?
(A) CH3 CH2 > NH2 C > OH C
>CH3CH2 >NH2 >OH
(C) OH >NH2 C >CH3 2 (D) NH2 C >OH >CH3 2
28. Aniline is a weaker base than ethylamine. This is due to
(A) 2 in aniline (B) 2 in aniline
(C) +I effect of NH2 in aniline (D) + M effect of NH2 in aniline
29.
N(CH3)2
CH3
CH3
(H3C)2N
a b
In the above compound which is true for basic strength of nitrogen marked as ‘a’ and ‘b’
(A) a = b (B) b > a
(C) a >b (D) cannot be correlated
30. Safe alternative of CFC is
(A) HCFC (B) HCFC14
(C) HFA142b (D) All of these
31. The possible mechanism of addition reaction between ethene and bromine in non-polar
medium would be
(A) free radical addition (B) carbene addition
(C) electrophilic addition (D) nucleophilic addition
32. The molecule in which distance between the two adjacent carbon atoms is largest is
(A) ethane (B) ethene
(C) ethyne (D) benzene
33. Among the following which is the strongest base
(A)
CH2NH2
(B)
NH2
(C) CH3
NH2
(D)
NH2
NO2
34. Which one of the following is least acidic?
(A)
OH
CH3
(B)
OH
CH3
(C)
OH
(D )
OH
CH3
35. 
 

light Na/ether
5 12 2 5 11
(A) (B)
C H +Cl C H Cl (C) . Only one structure of B is possible (A), (B) and
(C) are
(A)
CH3
C
H3
CH3
CH3
C
H3
CH3
CH3
Cl CH3
CH3
CH3
C
H3
CH3
CH3
(B) C
H3
C
H3 CH3
C
H3
Cl CH3
CH3
CH3
CH3
CH3
C
H3
CH3
CH3
(C) both are correct
(D) none is correct
36. CH2 = CH – CH = CH2
3 2
2 O /H O
H /Pt
1 equiv.
A B

 

A and B are
(A) CH3 – CH2 – CH = CH2, (CH3CH2COOH + CO2)
(B) CH3 – CH = CH – CH3, CH3COOH (2 mol)
(C) CH3 – CH = CH – CH3, CH3CHO (2 mol)
(D) CH3 – CH2 – CH = CH2, (CH3CH2CHO + HCHO)
37. Which of the following alkene has the lowest heat of hydrogenation?
(A)
H
H H
H
(B)
H H
CH3
CH2
(C)
C
H3
C
H3 H
H
(D)
H
C
H3 H
CH3
38. C
H3
H H
CH3
alkaline KMnO4 (A)


Which is true about this reaction?
(A) A is meso 1, 2-butan-di-ol formed by syn addition
(B) A is meso 1, 2-butan-di-ol fomred by anti addition
(C) A is a racemic mixture of d and l, 1, 2-butan-di-ol formed by anti addition
(D) A is a racemic mixture of d and l 1, 2-butan-di-ol formed by syn addition
39. Which of the following will be the correct product (P) of the reaction
C
H3
CH2
NBS
P ?


(A) C
H3
Br
(B)
C
H3 CH2
Br
(C)
C
H3 CH2
Br
(D) CH2
Br
40.
3
2
O / Zn
H O
(A) 

C
H3
O
H
O
. (A) is
(A)
CH3
(B)
CH3
(C)
CH3
CH3
(D)
CH3
41.
C
H3
H CH3
H
Br
H
CH3
CH3
Br
H
Br2


trans A
Which is true statement?
(A) A is formed by anti addition and is meso
(B) A is formed by syn addition and is meso
(C) A is formed by anti addition and is racemic
(D) A is formed by syn addition and is racemic
42. In the reaction sequence
CH3
3
CH
CH
I
  CH2
3
3
(i) BH
(ii) CH COOH
[x]

 will be
(A) 2-methl propane (B) 2- methyl propanone
(C) 2- methyl -2- propanol (D) 2- methyl propanal
43. Consider the reaction:
Ph
CH2
H
P
HCl

 

The product P is:
(A)
Ph
H Cl
Me
(d-form)
(B)
Ph
Cl H
Me
(l-form)
(C)
An equi molecular mixture of (A)
and (B)
(D)
Ph
H H
CH2Cl
44.
CH2
BH /THF
3
H O /OH
2 2
(B)
 H O
3 (A)


A and B are
(A)
OH
both (B)
CH3
OH
both
(C)
CH3
OH
OH
(D)
CH3
OH
OH
45. Which of the following will undergo faster dehydro-bromination?
(A)
Br
(B)
Br
(C)
Br
(D)
Br
46. Ph C C CH3
2
Hg /H
A. A is :
 


(A)
Ph
O
C
H3
(B)
Ph
C
H3
O
(C)
Ph
OH
C
H3
(D)
Ph
C
H3
OH
47. Identify the reagent from the following list which can easily distinguish between 1-butyne
and 2-butyne.
(A) bromine, CCl4 (B) H2, Lindlar catalyst
(C) dilute H2SO4, HgSO4 (D) ammoniacal Cu2Cl2 solution
48. Which of the following hydrocarbons has the lowest dipole moment?
(A)
C
H3
H H
CH3
(B) CH3CCCH3
(C) CH3CH2CCH (D) CH2=CH—CCH
49. The reaction of propene with HOCl proceeds via the addition of
(A) H+ in the first step (B) Cl+ in the first step
(C) OH– in the first step (D) Cl+ and OH– in a single step
50. In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give
anti-Markonikov’s addition to alkenes because
(A) both are highly ionic
(B) one is oxidizing and the other is reducing
(C) one of the steps is endothermic in both the cases
(D) all the steps are exothermic in both the cases
51.
is
)
A
(
).
A
(
HI


C
H3 CH3
(A)
C
H3 CH3
I
(B) C
H3 CH3
I
I
(C)
C
H3 CH3
I
(D) C
H3
I
52.
O2N
C
CH3
:
is
P
,
P
H
/
Hg2


 



(A)
O2N
O
C
H3
(B)
O2N
O
O
CH3
(C)
O2N
C
H3
O
(D) None of these
Multiple choice questions with more than one option correct
53. The gas is/are involved in the formation of photochemical smog
(A) CO2 (B) SO2
(C) NO (D) Hydrocarbons
54. Of the following compounds, which will have zero dipole moment?
(A) 1, 1-dichloro ethylene (B) cis-1, 2-dichloro ethylene
(C) trans-1, 2-dichloro ethylene (D) benzene
55. Which of the following do not represent the first number of their homologous series?
(A) CH3OH (B) CH3Cl
(C) CH3CN (D) CH3COOH
56. The molecules that will have dipole moment are:
(A) 2, 2-dimethylpropane (B) cis-3-hexene
(C) 2, 2, 3, 3-tetramethylbutane (D) trans-2-pentene
57. The formula C4H11N represents:
(A) four p-amines (B) three s-amines
(C) two s-amines (D) one t-amine
58. Keto-enol tautomerism is observed in:
(A)
H5C6 H
O (B)
H5C6 CH3
O
(C)
H5C6 C6H5
O (D)
H5C6
O
O
C
H3
59. Only two isomeric monochloro derivatives are possible for:
(A) n-butane (B) 2, 4-dimethyl pentane
(C) benzene (D) 2-methyl propane
60. The molecules which exhibit metamerism:
(A) C4H10O (ether) (B) C4H8 (alkene)
(C) C5H10O (ketone) (D) C4H11N (amine)
61. Isomers will have similar:
(A) structural formula (B) molecular mass
(C) molecular formula (D) chemical and physical properties
62. Which of the following statements is/are incorrect regarding two organic compounds A
and B which are stereoisomers?
(A) they must be enantiomers (B) they must be geometrical isomers
(C) they can be diastereomers (D) they can be meso compounds
63. Reforming is the process used for
(A) preparation of hydrocarbon (B) increasing the octane number
(C) preparation of straight chain (D) preparation of
64. The compound (s) which will give propylene on dehydration with conc. H2SO4 at 440 K
are
(A) isobutyl alcohol (B) n-propyl alcohol
(C) isopropyl alcohol (D) n-butyl alcohol
65. Which of the following alkynes show acidic character?
(A) H C C H (B) C
H3 C C H
(C)
C C H
(D) C
H3 C C CH3
66. Grignard reagent gives alkane with
(A) C2H5OH (B) HOH
(C) NH3 (D) C2H5NH2
67. Both methane & ethane may be obtained by one step reaction from
(A) CH3I (B) CH3COOK
(C) H2C = CH2 (D) CH3MgBr
68. CnH2nO is the general formula of
(A) aldehydes (B) ketones
(C) unsaturated alcohols (D) unsaturated acids
69. Which of the following do not represented the first number of their homologous series?
(A) CH3OH (B) CH3Cl
(C) CH3CN (D) CH3COOH
70. The molecules that will have dipole moment are
(A) 2, 2 – dimethyl propane (B) cis-3-hexane
(C) 2, 2, 3, 3 – tetramethyl butane (D) trans-2-pentene
71. The name
C
H3 N C
is
(A) methyl isocyanide (B) methyl carbylamine
(C) acetoisonitrile (D) methylisonitrile
72. Cis-2-butene & trans-2-butene are
(A) geometrical isomers (B) diasteromers
(C) enantiomers (D) position isomers
73. Which of the following can exist in ‘syn & ‘anti’ form?
(A) 6 5
C H N N OH
   (B) 6 5 6 5
C H N N C H
  
(C) 6 5
C H CH N OH
   (D)  
6 5 2
C H C N OH
 
74. The 2-isomer among the following are
C
C
H7C3
C
H3 H
C2H5
(I)
C
C
H5C2
C
H3 H
C3H7
(II)
C
C
H
Cl Br
F
(III)
C
C
F
Cl Br
H
(IV)
(A) I (B) II
(C) III (D) IV
75. Keto – enol tautomerism is observed in
(A) C2H5CHO (B) C6H5COCH3
(C) C6H5COC6H5 (D) C6H5COCH2COCH3
76. Which of the following statement (s) is/are correct about tautomers?
(A) they posses different electronic & atomic arrangements
(B) They posses different electronic but same atomic arrangement
(C) The have different atomic arrangements but same electronic arrangement
(D) They exist in equilibrium
Comprehension - I
Read the paragraph carefully and answer the following questions:
Pyridine like benzene, has six  -electrons in delocalized  -orbitals, but unlike benzene the
orbitals will be deformed as electrons are more attracted towards the nitrogen atom because of its
high electronegativity. This is reflected in the dipole of pyridine which has the negative end on N
and the positive end on the nucleus. Pyridine is thus referred to as a  -deficient heterocycle. By
analogy with a benzene ring that carries an electron withdrawing substituent, NO2, one would
expect it to be deactivated towards electrophilic attack with the help of  -delocalized molecular
orbital. We can compare the respective properties of benzene, pyridine, pyrrole, furan and
thiophene which very frequently give aromatic electrophilic and nucleophilic substitution reactions
in different positions.
77. Arrange the following in increasing order of aromatic character.
(i)
,
N
(ii)
,
N
H
(iii)
,
O
(iv)
,
S
(v)
(A)(i) > (v) > (iv) > (iii) > (ii) (B) (v) > (iv) > (iii) > (ii) > (i)
(C)(ii) > (i) > (v) > (iv) > (iii) (D) (i) > (v) > (ii) > (iv) > (iii)
78. Assertion: Dipole moment of pyridine is greater than pyrrole but in opposite direction.
Reason: In pyrrole, N atom contributes two electrons for delocalized  -orbital but this is not
true for pyridine.
(A)Assertion is correct but not reason. (B) Assertion and reason both are correct.
(C)Assertion and reason both are false. (D) Assertion is wrong but not reason.
79. Electrophilic attack is very difficult for pyridine, but at which position it is relatively easy?
(A)Only 2 (B) Only 4
(C)Only 3 (D) 2 and 4 both
80.
N
H
+
+ E (P)


Identify the product, (P).
(A)
N
H
H
E
(B)
N
H
H
E
(C)
N
H
E
H (D) All of the above
Comprehension-II
Read the paragraph carefully and answer the following questions:
The dehydration of alcohols and the conversion of alcohols to alkyl halides by treatment of
hydrogen halides are similar in two important ways:
1. Both reactions are protonated by acids.
2. The reactivity of alcohols decrease in the order, tertiary > secondary > primary.
It is due to the formation of stable carbocations, which is stabilized by hyperconjugation and +I
effect. These common features suggest that carbocations are key intermediates in alcohol
dehydration. It follows three steps mechanism for acid catalysed dehydration of least stable
tertiary butyl alcohol. The overall reaction is 2 4
H SO
3 3 3 2 2 2
(CH ) COH (CH ) C CH H O



  
In step I, protonation of tert-butyl alcohol takes place. In step II, dissociation of tert-butyloxenium
ion takes place followed by formation of carbocation. Alkene is formed in step III by deprotonation
of tert-butyl cation.
Step I:
CH3
CH3
H3C O
H
O
H
H
H
Fast


CH3
CH3
H3C O
H
H
O
H
H
Step II:
CH3
CH3
H3C O
H
H


Slow
CH3
CH3
H3C O
H
H
Step III:
H3C
H3C H
CH2
H3C
H3C
+
H



81. What will be the order of rearrangement takes place in case of dehydration of alcohols?
(A)Phenyl > alkyl > hydride (B) Hydride > phenyl > alkyl
(C)Phenyl > hydride > alkyl (D) Alkyl > hydride > phenyl
82. Why dehydration of vinyl alcohol is not difficult?
(A)Due to high enthalpy of vinylic –C–OH bond.
(B)Due to unstable nature of =C–OH bond by tautomerism
(C)Carbocation never forms in case of vinyl alcohol
(D)A and B are correct
83. OH
+
H
A, the product A is


(A) (B)
(C) (D)
84. Which carbocation will not form an intermediate?
(A)
6 5 3
(C H ) C
 (B)
(C) (D)
2
CH CH


Comprehension-III
Alkene can be oxidised in presence of different reagent to give different product. Alkene on
oxidation in presence of silver at high temperature give cyclic ether which also be synthesis by
using per acids. Alkene on reductive ozonolysis gives carbonyl compound in presence of zinc and
peroxide. On reaction with acidic KMnO4 it also produce corresponding carbonyl compound.
Alkyne also oxidised in presence of such reagent but the products are different.
Read the above paragraph carefully and give the answer of following questions:
85. Cyclohexene is allowed to reacts with ozone and subsequently with H2O2 and water. The
product formed is:
(A) Oxylic acid (B) Malenic acid
(C) Succinic acid (D) Adipic acid
86. Ethene on reaction with MCPBA in CH2Cl2 forms a compound (A) which on reaction with
CH3–MgI and subsequent hydrolysis gives a compound (B). (A) and (B) are respectively
(A)
O
H
OH
and O
(B)
and
O
C
H3
OH
CH3
(C)
and
O
C
H3
OH (D)
and
C
H3 CH3
OH
C
H3 CHO
87. An open chain hydrocarbon C7H12 on ozonolysis produces propanone, methanol and 2–
oxopropanal. The hydrocarbon could be:
(A)
CH3
C
H3 CH3
CH3
(B)
CH3
C
H3 CH2
CH3
(C) Either of these (D) Neither of these
88. A hydrocarbon C8H16 on oxidation with a hot acidified solution of KMnO4 forms
2–butanone and isobutyric acid. The hydrocarbon is
(A) 3 2 2 3 2
(CH ) C C(CH CH )
 (B)
CH3
C
H3
CH3
CH3
(C)
C
CH3
CH3
C
H3
CH3
CH3
(D)
C
H3
CH3 CH3
CH3
Comprehension – IV
Reaction intermediates are generated by breaking of covalent bond of the substrate. They are
short lived species and are highly reactive. There are six important types of reaction
intermediates–carbocation, carbanion, free radical, carbene, benzyne and nitrene.
Carbon atom bearing six electrons in its outermost orbit and has a positive charge is called
carbocation. Stability of alkyl carbocations can be explained by Inductive effect and
hyperconjugation. Anion of carbon is known as carbanion, it carries three bond pairs and one
lone pair, thus making the carbon atom negatively charged. Stability of carbanions may be
explained by electronegativity of carbanionic carbon, inductive effect and by resonance.
Carbon free radicals are odd electron species in which carbon atom bears the odd electron.
Stability of alkyl free radicals can be explained by hyperconjugation and number of resonating
structures due to hyperconjugation.
89. Consider the following carbocations.
(1) 3 2
CH CH

 (2) 2
CH CH


(3) 2 2
CH CH CH

  (4) 6 5 2
C H CH


Stability of these carbocation in decreasing order is:
(A) (4) > (3) > (1) > (2) (B) (4) > (3) > (2) > (1)
(C) (3) > (4) > (2) > (1) (D) (3) > (4) > (1) > (2)
90. Stability of given free radicals in decreasing order is
(1) 3 2
CH CH

 (2) 3 3
CH CH CH

 
(3)
H3C CH3
CH3 (4)
3
CH

(A) (3) > (4) > (1) > (2) (B) (1) > (2) > (3) > (4)
(C) (3) > (2) > (4) > (1) (D) (3) > (2) > (1) > (4)
91. For the following reactions:
(1)
Cl 0
1
Cl , H

 
(2)
Cl 0
2
Cl , H

 
(3)
Cl
CH2
0
3
Cl, H
 
(4)
Cl 0
4
Cl , H

 
The correct decreasing order of enthalpies of formation of carbocation is:
(A)
0 0 0 0
4 2 3 1
H H H H
       (B)
0 0 0 0
4 1 2 3
H H H H
      
(C)
0 0 0 0
3 2 1 4
H H H H
       (D)
0 0 0 0
2 1 4 3
H H H H
      
92. Which allylic carbocation is the most stable carbocation?
(A) (
3 2
CH CH CH CH

  
(B)
3 3
CH CH CH CH CH

   
(C)
H3C
CH3
CH3
(D) All have same stability
Match the following
93. Match the following List – I and List – II.
List-I (Groups) List-II (Characteristics)
(a) R (p) +Inductive
(b) Cl (q)  Mesomeric
(c) NH2 (r) Deactivating
(d) NO2 (s) Activating
94. Match the following List – I and List – II.
List-I (Reactions) List-II (Reagents)
(a)
C
H3 CH CH2 C
H3 CH CH3
Br (p) Br2 water
(b) C
H3 CH CH2 CH3CH2CH2Br (q) N – bromosuccinimide
(c) C
H3 CH CH2 Br CH2 CH CH2 (r) HBr (peroxide)
(d) C
H3 CH CH2 C
H3 CH CH2
Br Br
(s) HBr (aqueous)
95. Match the following List – I and List – II.
List-I (Reactions) List-II (Reagents)
(a) Cyclopropane (p) Non-planar
(b) Cyclobutane (r) Planar
(c) Cyclopentane (r) Least stable cycloalkane
(d) Cyclohexane (s) Shows conformations
96. Match the following List – I and List – II.
List-I (Compounds) List-II (Properties)
(a) CH2 = CH2 (p) Do not show geometrical isomerism
(b)
C C
C
H3
H H
CH3 (q) Reacts with HBr according to
Markownikoff’s rule
(c)
C C
C
H3
H CH3
H (r) Symmetrical molecule
(d)
C C
C
H3
C
H3 H
H (s) Decolourise Bayer’s reagent
ANSWERS TO WORK BOOK
Objective:
Single Correct Questions
1. B 2. D 3. B 4. B
5. C 6. B 7. C 8. A
9. B 10. C 11. B 12. D
13. D 14. C 15. C 16. B
17. A 18. C 19. B 20. A
21. D 22. C 23. C 24. B
25. D 26. A 27. B 28. D
29. B 30. D 31. A 32. A
33. A 34. A 35. A 36. B
37. B 38. A 39. B 40. A
41. A 42. A 43. C 44. D
45. D 46. A 47. D 48. B
49. B 50. C 51. C 52. A
Multiple Correct Questions
53. A, C 54. C, D 55. C, D 56. B, D
57. A, B, D 58. B, D 59. A, D 60. A, C, D
61. B, C 62. A, B 63. A, B 64. B, C
65. A, B, C 66. A, B, C, D 67. A, B 68. A, B, C
69. C, D 70. B, D 71. A, B, C 72. A, B
73. A, B, C 74. A, C 75. B, D 76. A, D
Comprehension
77. A 78. B 79. C 80. D
81. C 82. D 83. D 84. C
85. D 86. C 87. C 88. D
89. A 90. D 91. C 92. B
Match the following
93. (a)-(p, s); (b)-(r); (c)-(s); (d)-(q, r)
94. (a)-(s); (b)-(r); (c)-(q); (d)-(p)
95. (a)-(q, r); (b)-(q); (c)-(q); (d)-(p, s)
96. (a)-(p, s, r); (b)-(r, s); (c)-(s); (d)-(p, q, s)

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WORK BOOK_P_IV.doc

  • 1. Work Book (Phase - IV) Subjective: Board Type Questions 1. Which bond is more polar in the following pairs of molecules? (a) H3C – H, H3C – Br (b) H3C – NH2, H3C – OH (c) H3C – OH, H3C – SH 2. Write resonance structures of (a) CH3COO– and (b) C6H5NH2. Show the movement of electrons by curved arrows. 3. Write the resonance structures of CH2 = CH – CHO and arrange them in order of decreasing stability. 4. Give reasons why the following two structures (I and II) cannot be the major contributors to the real structure of CH3COOCH3. C H3 C O O CH3 I C H3 C O O CH3 II 5. Using curved arrow notation, show the formation of reactive intermediates when the following covalent bonds undergo heterolytic cleavage. (a) CH3 – SH (b) CH3 – CN (c) CH3 – Cu 6. Giving proper justification, categories the following molecules/ions as nucleophile or electrophile: + 3 2 5 3 3 3 2 2 HS , BF , C H O , (CH ) N , Cl , CH C O, H N , NO .        : : 7. Identify the electrophilic centres in the following: CH2 = C = O, CH3CN, CH3I 8. What is the relationship between the members of following pairs of structures? Are they identical, structural or geometrical isomers, or resonance contributors? (a) O O , (b) Cl H H Cl , H Cl H Cl (c) , H OH OH H OH OH (d) D H D H , D H H D 9. What type of aromatic compounds are present as particulates in the air? 10. Why ‘photochemical smog’ is so called? 11. Draw the structure of the tautomer of phenol and write its IUPAC name. 12. Arrange the following in increasing order of C – C bond length: C2H6, C2H4, C2H2.
  • 2. 13. Name the alkyl groups derived from isobutene. 14. Select electrophiles out of the following: H+, Na+, Cl–, C2H5OH, AlCl3, SO3, CN–, 3 2 2 CH CH , CCl , R X   : 15. Arrange the following: (i) 6 5 3 6 5 2 6 5 2 2 6 5 3 2 C H CHCH , C H CHCH CH , C H CH CH , C H C(CH )      in order of increasing stability. (ii) 3 2 6 5 2 3 3 2 2 CH CH , C H CH , (CH ) C , CH CHCH      in order of decreasing stability. (iii) 2 3 2 3 3 2 6 5 2 HC C , CH CH , CH CH , CH , (CH ) CH , C H CH         in order of increasing stability. 16. Which is expected to be more stable, O2NCH2CH2O– or CH3CH2O– and why? 17. Indicate - and -bonds in the following compounds: (a) C6H6 (b) C6H12 (c) CH2Cl2 (d) CH2 = C = CH2 (e) CH3NO2 (f) HCONHCH3 18. A hydrocarbon has the molecular mass 70. Write all the possible structural isomers and give their IUPAC names. 19. What is the nature of ‘photochemical smog’? 20. Explain inductive and electromeric effect with examples. 21. Explain hyperconjugation effect. 22. What is COD? Which chemical substance is generally used in its measurement? 23. For the following bond cleavages, use curved arrows to show the electron flow and classify each as homolysis or heterolysis. Identify reactive intermediate products as free radical, carbocation and carbanion. (a) 3 3 3 3 CH O OCH CH O OCH       (b) O OH    O 2 H O  (c) Br Br  (d) E    E 24. Draw the resonance structures of the following carbocation? Use curved arrows to show how one structure is converted into another. C H H O H 25. (a) Write the resonance structures of diazomethane (CH2N2). (b) Give the hybridized state of carbon and each N in each structure. (c) How does the H – C – H bond angle in the hybrid compare with the bond angles predicted from each contributing structure? 26. With proper justification, arrange the following in order of increasing stability. 3 2 2 CH CH , CH C , CH CH .     
  • 3. 27. Give the IUPAC name for the amine. C H3 N C H3 CH3 C2H5 CH3 28. Write resonance structures of the given compound. C H3 CH2 OH 29. trans-pent-2-ene is polar while trans-but-2-ene is non-polar. Explain. 30. Starting with acetylene, how will you prepare pentan-2-one? 31. Acetylene reacts with dil. H2SO4 in presence of mercury salts to give acetaldehyde but with dil. HCl under similar conditions, it gives vinyl chloride. Explain why? 32. Draw the structures of the following showing all C and H atoms. (a) 2-methyl-3-isopropylheptane (b) Dicyclopropylmethane 33. Arrange the following in increasing order of their release of energy on combustion. (i) (ii) (iii) (iv) 34. Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+. (i) Chlorobenzene, 2, 4-dinitrochlorobenzene, p-nitrochlorobenzene (ii) toluene, p-H3C – C6H4 – CH3, p-H3C – C6H4 – NO2, p-O2N – C6H4 – NO2. 35. Which of the following shows geometrical isomerism? (i) CHCl = CHCl (ii) CH2 = CCl2 (iii) CCl2 = CHCl 36. A compound is formed by the substitution of two chlorine atoms for two hydrogen atoms in propane. What is the number of structural isomers possible? Fill in the blanks 37. Out of three isomers of C5H12, ……………..has the highest boiling point while……………has the lowest boiling point. 38. Out of cis-2-butene and trans-2-butne, …………………..has lower melting point. 39. A four – carbon alkyne having weakly acidic character is……………………. 40. Alkanes undergo…………………reactions whereas alkyes gives………………reactions.
  • 4. IIT Level Questions 41. Alc. KOH HBr 6 5 2 3 heat C H CH CHCH A B | Br     42. CH3      2 O N CH3 Predict the major and minor product with reason 43. Use Markovnikov’s rule to predict the product of the following reactions: (i) HCl with CH3CCl = CH2 and (ii) HCl with CH3CH = C(CH3)2. 44. Arrange the following: HCl, HBr, HI, HF in order of decreasing reactivity towards alkenes. 45. Give the structure of an alkene (C4H8) which when treated with H2O/H2SO4 gives C4H10O which cannot be resolved into optical isomers. 46. How will you demonstrate that double bonds of benzene are somewhat different from that of olefines? 47. Write the ozonolysis products of (i) mesitylene (ii) o-xylene. 48. An organic compound C8H18 on monochlorination gives a single monochloride. Write the structure of the hydrocarbon. 49. Which of the following has larger dipole moment? Explain. 1-butyne or 1-butene. 50. State whether true or false: Photobromination of 2 – methylbutane gives a mixture of 1- bromo-2-methyl propane & 2 – methylpropane in the ratio 9:1.
  • 5. Objective: Multiple choice questions with single correct options 1. The condition that cannot be applied for the interconversion of geometrical isomers is (A) heat (B) pressure (C) ultraviolet rays (D) catalysis 2. The maximum number of isomers for an alkene with the molecular formula C4H8 is (A) 2 (B) 3 (C) 4 (D) 5 3. Keto–enol tautomerism is observed in (A) H5C6 H O (B) H5C6 CH3 O (C) H5C6 C6H5 O (D) None of the above 4. The two isomers given below are CO2H H OH O H H CO2H CO2H H OH H OH CO2H (A) enantiomers (B) diastereomers (C) regiomers (D) position isomers 5. H C2H5 C H3 Br  aq. NaOH H C2H5 C H3 OH (60%) O H C2H5 C H3 H (40%) This reaction is leading to % racemization equal to (A) 40 (B) 60 (C) 80 (D) 20 6. But-2-ene exhibit cis–trans isomerism due to (A) Rotation around C3–C4 sigma bond (B) Restricted rotation around C=C bond (C) Rotation about C1–C2 bond (D) Rotation around C2–C3 double bond 7. C2 is rotated anti-clockwise 120about C2–C3 bond. 3 CH3 H H . CH3 . H . H 2 1 The resulting conformer is (A) partially eclipsed (B) eclipsed (C) gauche (D) staggered
  • 6. 8. Which of the following compound will exhibit cis–trans (geometrical) isomerism? (A) 2-butene (B) 2-butyne (C) 2-butanol (D) Butanal 9. The number of isomers of dibromo derivative (molar mass 186 gmol-1) of an alkene is (A) two (B) three (C) four (D) six 10. The amount of optical rotation does not depend on the (A) concentration of the solution (B) wavelength of the colour of the solution (C) temperature (D) length of the column transversed 11. Which of the following does not posses any element of symmetry? (A) Ethane (B) (+)–Tartaric acid (C) Carbon tetrachloride (D) Meso–tartaric acid 12. Which of the following is the uppermost region of atmosphere? (A) Stratosphere (B) Troposphere (C) Mesosphere (D) Exosphere 13. Which of the following compound will show geometrical isomerism? 1. 2-Butene 2. Propene 3. 1-Phenylpropene 4. 2-Methylbut-2-ene (A) 1, 2 (B) 3, 4 (C) 1, 2, 3 (D) 1,3 14. An organic molecule necessarily shows optical activity if it (A) contains asymmetric carbon atoms (B) is non-planar (C) is non-superimposable on its mirror image (D) is superimposable on its mirror image 15. Which of the following ketone cannot produce oximes that can be geometrical isomers? (A) Acetophenone (B) Methyl ethyl ketone (C) Benzophenone (D) Ethyl isopropyl ketone 16. Which one of the following hydrocarbons has the lowest dipole moment? (A) C H3 H H CH3 (B) C H3 CH3 (C) C H3 CH (D) C H2 CH 17. Which of the following statement is correct? (A) Metamerism belongs to the category of structural isomerism. (B) Tautomeric structures are the resonating structures of a molecule. (C) The violet colouration produced by a molecule with neutral ferric chloride solution indicates the presence of keto group in the molecule. (D) Geometrical isomerism is shown only by alkenes. 18. The optically active tartaric acid is named as D (+) tartaric acid because it has a positive (A) optical rotation and is derived from D glucose (B) pH in an organic solvent (C) optical rotation and is derived from D (+) glyceraldehyde (D) optical rotation only when substituted by deuterium
  • 7. 19. An enantiomerically pure acid is treated with racemic mixture of an alcohol having one chiral carbon. The ester formed will be (A) optically active mixture (B) pure enantiomer (C) meso compound (D) racemic mixture 20. Which of the following statement is correct? (A) Allyl carbonium ion (CH2=CH– + 2 C H ) is more stable than propyl carbonium ion. (B) Propyl carbonium ion is more stable than allyl carbonium ion. (C) Both are equally stable. (D) None of the above 21. Which of the following species is most stable? (A) 2 6 4 2 p NO C H CH   (B) 6 5 2 C H CH  (C) 6 4 2 p ClC H CH   (D) 6 4 2 p HOC H CH   22. Which is the strongest carboxylic acid among the following? (A) Cl3CCO2H (B) Br3CCO2H (C) F3CCO2H (D) Cl2CHCO2H 23. The compound with the most acidic hydrogen is (A) CH3CHO (B) CH3COCH3 (C) CH3 O C 2CHO (D) CH3 2 2CH3 24. Which of the following is easily debrominated? (A) Br (B) Br (C) Br (D) Br 25. Which carbocation is most stable? (A) 3 CH (B) 3 2 CH CH (C) C H3 CH + CH3 (D) C H2 CH2 + 26. The order of the basicity among the amines is NH2 O2N NH2 Cl NH2 CH3 OCH3 NH2 I II III IV (A) I<II<III<IV (B) II<I<III<IV (C) I<II<IV<III (D) II<I<IV<III 27. What is the decreasing order of strength of the basesOH , NH2 C and CH3 2 ? (A) CH3 CH2 > NH2 C > OH C >CH3CH2 >NH2 >OH (C) OH >NH2 C >CH3 2 (D) NH2 C >OH >CH3 2 28. Aniline is a weaker base than ethylamine. This is due to (A) 2 in aniline (B) 2 in aniline
  • 8. (C) +I effect of NH2 in aniline (D) + M effect of NH2 in aniline 29. N(CH3)2 CH3 CH3 (H3C)2N a b In the above compound which is true for basic strength of nitrogen marked as ‘a’ and ‘b’ (A) a = b (B) b > a (C) a >b (D) cannot be correlated 30. Safe alternative of CFC is (A) HCFC (B) HCFC14 (C) HFA142b (D) All of these 31. The possible mechanism of addition reaction between ethene and bromine in non-polar medium would be (A) free radical addition (B) carbene addition (C) electrophilic addition (D) nucleophilic addition 32. The molecule in which distance between the two adjacent carbon atoms is largest is (A) ethane (B) ethene (C) ethyne (D) benzene 33. Among the following which is the strongest base (A) CH2NH2 (B) NH2 (C) CH3 NH2 (D) NH2 NO2 34. Which one of the following is least acidic? (A) OH CH3 (B) OH CH3 (C) OH (D ) OH CH3 35.     light Na/ether 5 12 2 5 11 (A) (B) C H +Cl C H Cl (C) . Only one structure of B is possible (A), (B) and (C) are (A) CH3 C H3 CH3 CH3 C H3 CH3 CH3 Cl CH3 CH3 CH3 C H3 CH3 CH3 (B) C H3 C H3 CH3 C H3 Cl CH3 CH3 CH3 CH3 CH3 C H3 CH3 CH3 (C) both are correct
  • 9. (D) none is correct 36. CH2 = CH – CH = CH2 3 2 2 O /H O H /Pt 1 equiv. A B     A and B are (A) CH3 – CH2 – CH = CH2, (CH3CH2COOH + CO2) (B) CH3 – CH = CH – CH3, CH3COOH (2 mol) (C) CH3 – CH = CH – CH3, CH3CHO (2 mol) (D) CH3 – CH2 – CH = CH2, (CH3CH2CHO + HCHO) 37. Which of the following alkene has the lowest heat of hydrogenation? (A) H H H H (B) H H CH3 CH2 (C) C H3 C H3 H H (D) H C H3 H CH3 38. C H3 H H CH3 alkaline KMnO4 (A)   Which is true about this reaction? (A) A is meso 1, 2-butan-di-ol formed by syn addition (B) A is meso 1, 2-butan-di-ol fomred by anti addition (C) A is a racemic mixture of d and l, 1, 2-butan-di-ol formed by anti addition (D) A is a racemic mixture of d and l 1, 2-butan-di-ol formed by syn addition 39. Which of the following will be the correct product (P) of the reaction C H3 CH2 NBS P ?   (A) C H3 Br (B) C H3 CH2 Br (C) C H3 CH2 Br (D) CH2 Br 40. 3 2 O / Zn H O (A)   C H3 O H O . (A) is (A) CH3 (B) CH3 (C) CH3 CH3 (D) CH3
  • 10. 41. C H3 H CH3 H Br H CH3 CH3 Br H Br2   trans A Which is true statement? (A) A is formed by anti addition and is meso (B) A is formed by syn addition and is meso (C) A is formed by anti addition and is racemic (D) A is formed by syn addition and is racemic 42. In the reaction sequence CH3 3 CH CH I   CH2 3 3 (i) BH (ii) CH COOH [x]   will be (A) 2-methl propane (B) 2- methyl propanone (C) 2- methyl -2- propanol (D) 2- methyl propanal 43. Consider the reaction: Ph CH2 H P HCl     The product P is: (A) Ph H Cl Me (d-form) (B) Ph Cl H Me (l-form) (C) An equi molecular mixture of (A) and (B) (D) Ph H H CH2Cl 44. CH2 BH /THF 3 H O /OH 2 2 (B)  H O 3 (A)   A and B are (A) OH both (B) CH3 OH both (C) CH3 OH OH (D) CH3 OH OH 45. Which of the following will undergo faster dehydro-bromination? (A) Br (B) Br (C) Br (D) Br
  • 11. 46. Ph C C CH3 2 Hg /H A. A is :     (A) Ph O C H3 (B) Ph C H3 O (C) Ph OH C H3 (D) Ph C H3 OH 47. Identify the reagent from the following list which can easily distinguish between 1-butyne and 2-butyne. (A) bromine, CCl4 (B) H2, Lindlar catalyst (C) dilute H2SO4, HgSO4 (D) ammoniacal Cu2Cl2 solution 48. Which of the following hydrocarbons has the lowest dipole moment? (A) C H3 H H CH3 (B) CH3CCCH3 (C) CH3CH2CCH (D) CH2=CH—CCH 49. The reaction of propene with HOCl proceeds via the addition of (A) H+ in the first step (B) Cl+ in the first step (C) OH– in the first step (D) Cl+ and OH– in a single step 50. In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give anti-Markonikov’s addition to alkenes because (A) both are highly ionic (B) one is oxidizing and the other is reducing (C) one of the steps is endothermic in both the cases (D) all the steps are exothermic in both the cases 51. is ) A ( ). A ( HI   C H3 CH3 (A) C H3 CH3 I (B) C H3 CH3 I I (C) C H3 CH3 I (D) C H3 I 52. O2N C CH3 : is P , P H / Hg2        (A) O2N O C H3 (B) O2N O O CH3 (C) O2N C H3 O (D) None of these
  • 12. Multiple choice questions with more than one option correct 53. The gas is/are involved in the formation of photochemical smog (A) CO2 (B) SO2 (C) NO (D) Hydrocarbons 54. Of the following compounds, which will have zero dipole moment? (A) 1, 1-dichloro ethylene (B) cis-1, 2-dichloro ethylene (C) trans-1, 2-dichloro ethylene (D) benzene 55. Which of the following do not represent the first number of their homologous series? (A) CH3OH (B) CH3Cl (C) CH3CN (D) CH3COOH 56. The molecules that will have dipole moment are: (A) 2, 2-dimethylpropane (B) cis-3-hexene (C) 2, 2, 3, 3-tetramethylbutane (D) trans-2-pentene 57. The formula C4H11N represents: (A) four p-amines (B) three s-amines (C) two s-amines (D) one t-amine 58. Keto-enol tautomerism is observed in: (A) H5C6 H O (B) H5C6 CH3 O (C) H5C6 C6H5 O (D) H5C6 O O C H3 59. Only two isomeric monochloro derivatives are possible for: (A) n-butane (B) 2, 4-dimethyl pentane (C) benzene (D) 2-methyl propane 60. The molecules which exhibit metamerism: (A) C4H10O (ether) (B) C4H8 (alkene) (C) C5H10O (ketone) (D) C4H11N (amine) 61. Isomers will have similar: (A) structural formula (B) molecular mass (C) molecular formula (D) chemical and physical properties 62. Which of the following statements is/are incorrect regarding two organic compounds A and B which are stereoisomers? (A) they must be enantiomers (B) they must be geometrical isomers (C) they can be diastereomers (D) they can be meso compounds 63. Reforming is the process used for (A) preparation of hydrocarbon (B) increasing the octane number (C) preparation of straight chain (D) preparation of
  • 13. 64. The compound (s) which will give propylene on dehydration with conc. H2SO4 at 440 K are (A) isobutyl alcohol (B) n-propyl alcohol (C) isopropyl alcohol (D) n-butyl alcohol 65. Which of the following alkynes show acidic character? (A) H C C H (B) C H3 C C H (C) C C H (D) C H3 C C CH3 66. Grignard reagent gives alkane with (A) C2H5OH (B) HOH (C) NH3 (D) C2H5NH2 67. Both methane & ethane may be obtained by one step reaction from (A) CH3I (B) CH3COOK (C) H2C = CH2 (D) CH3MgBr 68. CnH2nO is the general formula of (A) aldehydes (B) ketones (C) unsaturated alcohols (D) unsaturated acids 69. Which of the following do not represented the first number of their homologous series? (A) CH3OH (B) CH3Cl (C) CH3CN (D) CH3COOH 70. The molecules that will have dipole moment are (A) 2, 2 – dimethyl propane (B) cis-3-hexane (C) 2, 2, 3, 3 – tetramethyl butane (D) trans-2-pentene 71. The name C H3 N C is (A) methyl isocyanide (B) methyl carbylamine (C) acetoisonitrile (D) methylisonitrile 72. Cis-2-butene & trans-2-butene are (A) geometrical isomers (B) diasteromers (C) enantiomers (D) position isomers 73. Which of the following can exist in ‘syn & ‘anti’ form? (A) 6 5 C H N N OH    (B) 6 5 6 5 C H N N C H    (C) 6 5 C H CH N OH    (D)   6 5 2 C H C N OH   74. The 2-isomer among the following are C C H7C3 C H3 H C2H5 (I) C C H5C2 C H3 H C3H7 (II) C C H Cl Br F (III) C C F Cl Br H (IV) (A) I (B) II (C) III (D) IV
  • 14. 75. Keto – enol tautomerism is observed in (A) C2H5CHO (B) C6H5COCH3 (C) C6H5COC6H5 (D) C6H5COCH2COCH3 76. Which of the following statement (s) is/are correct about tautomers? (A) they posses different electronic & atomic arrangements (B) They posses different electronic but same atomic arrangement (C) The have different atomic arrangements but same electronic arrangement (D) They exist in equilibrium Comprehension - I Read the paragraph carefully and answer the following questions: Pyridine like benzene, has six  -electrons in delocalized  -orbitals, but unlike benzene the orbitals will be deformed as electrons are more attracted towards the nitrogen atom because of its high electronegativity. This is reflected in the dipole of pyridine which has the negative end on N and the positive end on the nucleus. Pyridine is thus referred to as a  -deficient heterocycle. By analogy with a benzene ring that carries an electron withdrawing substituent, NO2, one would expect it to be deactivated towards electrophilic attack with the help of  -delocalized molecular orbital. We can compare the respective properties of benzene, pyridine, pyrrole, furan and thiophene which very frequently give aromatic electrophilic and nucleophilic substitution reactions in different positions. 77. Arrange the following in increasing order of aromatic character. (i) , N (ii) , N H (iii) , O (iv) , S (v) (A)(i) > (v) > (iv) > (iii) > (ii) (B) (v) > (iv) > (iii) > (ii) > (i) (C)(ii) > (i) > (v) > (iv) > (iii) (D) (i) > (v) > (ii) > (iv) > (iii) 78. Assertion: Dipole moment of pyridine is greater than pyrrole but in opposite direction. Reason: In pyrrole, N atom contributes two electrons for delocalized  -orbital but this is not true for pyridine. (A)Assertion is correct but not reason. (B) Assertion and reason both are correct. (C)Assertion and reason both are false. (D) Assertion is wrong but not reason. 79. Electrophilic attack is very difficult for pyridine, but at which position it is relatively easy? (A)Only 2 (B) Only 4 (C)Only 3 (D) 2 and 4 both 80. N H + + E (P)   Identify the product, (P). (A) N H H E (B) N H H E (C) N H E H (D) All of the above
  • 15. Comprehension-II Read the paragraph carefully and answer the following questions: The dehydration of alcohols and the conversion of alcohols to alkyl halides by treatment of hydrogen halides are similar in two important ways: 1. Both reactions are protonated by acids. 2. The reactivity of alcohols decrease in the order, tertiary > secondary > primary. It is due to the formation of stable carbocations, which is stabilized by hyperconjugation and +I effect. These common features suggest that carbocations are key intermediates in alcohol dehydration. It follows three steps mechanism for acid catalysed dehydration of least stable tertiary butyl alcohol. The overall reaction is 2 4 H SO 3 3 3 2 2 2 (CH ) COH (CH ) C CH H O       In step I, protonation of tert-butyl alcohol takes place. In step II, dissociation of tert-butyloxenium ion takes place followed by formation of carbocation. Alkene is formed in step III by deprotonation of tert-butyl cation. Step I: CH3 CH3 H3C O H O H H H Fast   CH3 CH3 H3C O H H O H H Step II: CH3 CH3 H3C O H H   Slow CH3 CH3 H3C O H H Step III: H3C H3C H CH2 H3C H3C + H    81. What will be the order of rearrangement takes place in case of dehydration of alcohols? (A)Phenyl > alkyl > hydride (B) Hydride > phenyl > alkyl (C)Phenyl > hydride > alkyl (D) Alkyl > hydride > phenyl 82. Why dehydration of vinyl alcohol is not difficult? (A)Due to high enthalpy of vinylic –C–OH bond. (B)Due to unstable nature of =C–OH bond by tautomerism (C)Carbocation never forms in case of vinyl alcohol (D)A and B are correct 83. OH + H A, the product A is   (A) (B) (C) (D)
  • 16. 84. Which carbocation will not form an intermediate? (A) 6 5 3 (C H ) C  (B) (C) (D) 2 CH CH   Comprehension-III Alkene can be oxidised in presence of different reagent to give different product. Alkene on oxidation in presence of silver at high temperature give cyclic ether which also be synthesis by using per acids. Alkene on reductive ozonolysis gives carbonyl compound in presence of zinc and peroxide. On reaction with acidic KMnO4 it also produce corresponding carbonyl compound. Alkyne also oxidised in presence of such reagent but the products are different. Read the above paragraph carefully and give the answer of following questions: 85. Cyclohexene is allowed to reacts with ozone and subsequently with H2O2 and water. The product formed is: (A) Oxylic acid (B) Malenic acid (C) Succinic acid (D) Adipic acid 86. Ethene on reaction with MCPBA in CH2Cl2 forms a compound (A) which on reaction with CH3–MgI and subsequent hydrolysis gives a compound (B). (A) and (B) are respectively (A) O H OH and O (B) and O C H3 OH CH3 (C) and O C H3 OH (D) and C H3 CH3 OH C H3 CHO 87. An open chain hydrocarbon C7H12 on ozonolysis produces propanone, methanol and 2– oxopropanal. The hydrocarbon could be: (A) CH3 C H3 CH3 CH3 (B) CH3 C H3 CH2 CH3 (C) Either of these (D) Neither of these 88. A hydrocarbon C8H16 on oxidation with a hot acidified solution of KMnO4 forms 2–butanone and isobutyric acid. The hydrocarbon is (A) 3 2 2 3 2 (CH ) C C(CH CH )  (B) CH3 C H3 CH3 CH3 (C) C CH3 CH3 C H3 CH3 CH3 (D) C H3 CH3 CH3 CH3
  • 17. Comprehension – IV Reaction intermediates are generated by breaking of covalent bond of the substrate. They are short lived species and are highly reactive. There are six important types of reaction intermediates–carbocation, carbanion, free radical, carbene, benzyne and nitrene. Carbon atom bearing six electrons in its outermost orbit and has a positive charge is called carbocation. Stability of alkyl carbocations can be explained by Inductive effect and hyperconjugation. Anion of carbon is known as carbanion, it carries three bond pairs and one lone pair, thus making the carbon atom negatively charged. Stability of carbanions may be explained by electronegativity of carbanionic carbon, inductive effect and by resonance. Carbon free radicals are odd electron species in which carbon atom bears the odd electron. Stability of alkyl free radicals can be explained by hyperconjugation and number of resonating structures due to hyperconjugation. 89. Consider the following carbocations. (1) 3 2 CH CH   (2) 2 CH CH   (3) 2 2 CH CH CH    (4) 6 5 2 C H CH   Stability of these carbocation in decreasing order is: (A) (4) > (3) > (1) > (2) (B) (4) > (3) > (2) > (1) (C) (3) > (4) > (2) > (1) (D) (3) > (4) > (1) > (2) 90. Stability of given free radicals in decreasing order is (1) 3 2 CH CH   (2) 3 3 CH CH CH    (3) H3C CH3 CH3 (4) 3 CH  (A) (3) > (4) > (1) > (2) (B) (1) > (2) > (3) > (4) (C) (3) > (2) > (4) > (1) (D) (3) > (2) > (1) > (4) 91. For the following reactions: (1) Cl 0 1 Cl , H    (2) Cl 0 2 Cl , H    (3) Cl CH2 0 3 Cl, H   (4) Cl 0 4 Cl , H    The correct decreasing order of enthalpies of formation of carbocation is: (A) 0 0 0 0 4 2 3 1 H H H H        (B) 0 0 0 0 4 1 2 3 H H H H        (C) 0 0 0 0 3 2 1 4 H H H H        (D) 0 0 0 0 2 1 4 3 H H H H       
  • 18. 92. Which allylic carbocation is the most stable carbocation? (A) ( 3 2 CH CH CH CH     (B) 3 3 CH CH CH CH CH      (C) H3C CH3 CH3 (D) All have same stability Match the following 93. Match the following List – I and List – II. List-I (Groups) List-II (Characteristics) (a) R (p) +Inductive (b) Cl (q)  Mesomeric (c) NH2 (r) Deactivating (d) NO2 (s) Activating 94. Match the following List – I and List – II. List-I (Reactions) List-II (Reagents) (a) C H3 CH CH2 C H3 CH CH3 Br (p) Br2 water (b) C H3 CH CH2 CH3CH2CH2Br (q) N – bromosuccinimide (c) C H3 CH CH2 Br CH2 CH CH2 (r) HBr (peroxide) (d) C H3 CH CH2 C H3 CH CH2 Br Br (s) HBr (aqueous) 95. Match the following List – I and List – II. List-I (Reactions) List-II (Reagents) (a) Cyclopropane (p) Non-planar (b) Cyclobutane (r) Planar (c) Cyclopentane (r) Least stable cycloalkane (d) Cyclohexane (s) Shows conformations 96. Match the following List – I and List – II. List-I (Compounds) List-II (Properties) (a) CH2 = CH2 (p) Do not show geometrical isomerism (b) C C C H3 H H CH3 (q) Reacts with HBr according to Markownikoff’s rule (c) C C C H3 H CH3 H (r) Symmetrical molecule (d) C C C H3 C H3 H H (s) Decolourise Bayer’s reagent
  • 19. ANSWERS TO WORK BOOK Objective: Single Correct Questions 1. B 2. D 3. B 4. B 5. C 6. B 7. C 8. A 9. B 10. C 11. B 12. D 13. D 14. C 15. C 16. B 17. A 18. C 19. B 20. A 21. D 22. C 23. C 24. B 25. D 26. A 27. B 28. D 29. B 30. D 31. A 32. A 33. A 34. A 35. A 36. B 37. B 38. A 39. B 40. A 41. A 42. A 43. C 44. D 45. D 46. A 47. D 48. B 49. B 50. C 51. C 52. A Multiple Correct Questions 53. A, C 54. C, D 55. C, D 56. B, D 57. A, B, D 58. B, D 59. A, D 60. A, C, D 61. B, C 62. A, B 63. A, B 64. B, C 65. A, B, C 66. A, B, C, D 67. A, B 68. A, B, C 69. C, D 70. B, D 71. A, B, C 72. A, B 73. A, B, C 74. A, C 75. B, D 76. A, D Comprehension 77. A 78. B 79. C 80. D 81. C 82. D 83. D 84. C 85. D 86. C 87. C 88. D 89. A 90. D 91. C 92. B Match the following 93. (a)-(p, s); (b)-(r); (c)-(s); (d)-(q, r) 94. (a)-(s); (b)-(r); (c)-(q); (d)-(p) 95. (a)-(q, r); (b)-(q); (c)-(q); (d)-(p, s) 96. (a)-(p, s, r); (b)-(r, s); (c)-(s); (d)-(p, q, s)