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Sound
Sound
Sound is produced by vibrating
objects.
A sound wave consists of
mechanical vibrations in air
and other substances.
Sound is a longitudinal wave
in which the wave energy
travels in the same direction as
the particles within the wave
vibrate.
wave direction
vibrations
LONGITUDINAL WAVE
Through air a sound wave consists of a series of
compressions and rarefactions.
A compression is a region of slightly higher pressure where
the air molecules are closer together than usual.
A rarefaction is the opposite.
The wavelength of the sound wave is equal to the distance
between the centres of two successive compressions.
no sound wavesound wave
wavelength
loudspeaker
rarefaction
compression
Range of hearing
Humans can hear sound frequencies in the range
20 Hz to 20 000 Hz.
Age and damage reduces the upper limit.
For example an old person or someone exposed to
prolonged high sound volume may no be able to hear
above 10 000 Hz.
Some animals can hear
much higher frequencies:
bats and dolphins:
up to 100 000 Hz
dogs – 40 000 to 60 000 Hz
(depends on the breed)
Ultrasound and Infrasound
Ultrasound is high frequency sound,
above 20 000 Hz, too high to be heard by
humans.
Ultrasound echoes can be used to
measure distance (e.g. sonar) and to see
inside objects (scans).
Infrasound is low frequency sound,
inaudible to human, although we may feel
the very slow vibrations.
Earthquake waves are a form of
infrasound. Elephants and some other
large animals can hear infrasound.
Sound waves in different materials
Sound travels quickest through solids.
A train can often be hared approaching
through the rails before it can be heard
through the air.
Sound travels well through liquids.
Whales can communicate over great
distances under water.
Sound travels slowest through gases.
The speed of sound increases with
temperature.
Sound does not travel through a
vacuum.
Sound does not travel in space.
Poster for the
movie ‘Alien’ (1979)
Reflection of sound
Question:
A misguided child shouts ‘Barca!’ at a
nearby cliff and hears an echo 1.4 s
later. How far away is the cliff?
Take the speed of sound = 340 m/s. distance, D
The sound travels to and from the cliff, a total distance of 2D
speed = distance / time
becomes: distance = speed x time
= 340 m/s x 1.4 s
= 476 m
= 2D !
Therefore distance to the cliff = 238 m.
An echo is a reflected sound wave.
cooler air
A B
C
The sound produced by person A may be heard more clearly by
person B than by person C.
The cooler air over the water refracts the sound waves downwards.
Sound refraction
A typical sound wave has a
wavelength of about 1m.
This is similar in size to the
aperture of a doorway.
Therefore sound undergoes
significant diffraction at a doorway
or around the corner of a building.
This is why we can hear someone
in such circumstances even
thought we cannot see them.
Sound diffraction
TRIPLE ONLY
Why does light not diffract as much as sound?
The wavelength of light is about 0.000 5mm
– much smaller than a door aperture.
Measuring the speed of sound
Method 1: Using a visible loud event
Use a stopwatch to time the difference
between seeing and hearing the event
(for example an explosion).
Measure the distance between the
event an the timing position.
Speed = distance / time.
Note: The distance should be as large
as possible in order to avoid significant
reaction time error in the timing
measurement.
Question
A group of students measured the time taken between
seeing and hearing another student, 250 m away, clashing
two pieces of wood together. They obtained the following
timings in seconds: 0.73, 0.78, 0.69, 0.81, 0.77. Use their
measurements to obtain a speed of sound estimate.
average time = (0.73 + 0.78 + 0.69 + 0.81 + 0.77) / 5
= 3.78 / 5
= 0.756 s
speed = distance / time
= 250 m / 0.756 s
= 4 080 m
speed of sound = 331 m/s
Measuring the speed of sound
Method 2: Using echoes
Facing a flat vertical surface (wall or cliff) at least 50m away one
person clashes two pieces of wood together. This person should try to
clap the pieces of wood in time with the echo they hear coming back
from the flat surface.
Another person times 20 claps on a stop-watch. They should count: 0,
1, 2 ,3 …. 20.
Measure the distance, D between the clapping person an the flat
surface.
The total distance travelled by the sound will be 20 x 2D
Speed = total distance / time for 20 claps.
Question
In an experiment to measure the speed of sound
by the echo method when a student stands 75m
away from a wall 20 claps are heard over a time of
8.77s. Calculate the speed of sound.
total distance travelled by the sound
= (20 x 2 x 75)m
= 3000m
speed = total distance / time for 20 claps
= 3000m / 8.77s
speed of sound = 342 m/s
Speed of sound examples
Substance and
temperature
Speed in m/s
Air at 0ºC 330
Air at 20ºC
Air at -10ºC
Fresh water at 25ºC
Sea water at 25ºC
Steel at 20ºC
Vacuum
330
342
1 497
1 560
324
5 000
0
Mach numbers
Mach number = object speed
speed of sound
Thunder and lightning
An observer, 3 miles
away, sees a
lightning flash about
15 seconds before
hearing thunder
Light reaches
the observer in
16 millionths of a
second
The sound
of thunder
reaches the
observer in
about 15
seconds
Every 5 second
difference
equates to a
distance of 1 mile
STORM CLOUD
LIGHTNING
Thunder and lightning question
A thunderclap is heard 12 seconds after a lightning
flash. Calculate the distance to the lightning flash.
Take the speed of sound = 340 m/s
speed = distance / time
becomes: distance = speed x time
= 340 m/s x 12 seconds
= 4 080 m
Distance = 4.08 km
Sound waves on oscilloscopes
An oscilloscope is a
device that with a
microphone attached
can be used to display
a sound wave.
The screen displays a
graph of how the
amplitude of the sound
wave varies with time.
TRIPLE ONLY
Loudness
The loudness of a sound increases with the
amplitude of the sound wave.
quiet
loud
TRIPLE ONLY
Pitch
The pitch of a musical note increases with frequency.
Examples:
Concert pitch A = 440 Hz; Top C = 523 Hz
Doubling the frequency increases the pitch by one octave.
Therefore the ‘A’ above top C will have frequency 880 Hz.
low pitch high pitch
TRIPLE ONLY
Quality or timbre
The quality or timbre of a musical note is what makes one
musical instrument sound different from another.
Despite different instruments producing a note of the same
loudness and pitch, the shape of the wave will be different.
TRIPLE ONLY
Question
The diagram opposite
shows the appearance of a
sound wave on an
oscilloscope. Draw a
second diagram showing
the appearance of a sound
wave of lower pitch but
greater loudness.
TRIPLE ONLY
Measuring frequency using an oscilloscope
The time taken between
peaks on an oscilloscope
trace is equal to the time
period, T of the sound wave.
frequency = 1 / period
f = 1 / T
example:
if T = 0.05s
f = 1 / 0.05
frequency = 20Hz
time
period
TRIPLE ONLY
Question
The distance between peaks on
an oscilloscope trace is 4cm. If
the oscilloscope time scale is set
at 1ms/cm calculate the frequency
of the sound.
1ms/cm means that the trace
covers 1cm in one millisecond
(0.001s)
time period, T = 4cm x 1ms/cm
= 4ms (0.004s)
f = 1 / T
f = 1 / 0.004
frequency = 250Hz
4 cm
TRIPLE ONLY

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Sound Energy

  • 2. Sound Sound is produced by vibrating objects. A sound wave consists of mechanical vibrations in air and other substances. Sound is a longitudinal wave in which the wave energy travels in the same direction as the particles within the wave vibrate. wave direction vibrations LONGITUDINAL WAVE
  • 3. Through air a sound wave consists of a series of compressions and rarefactions. A compression is a region of slightly higher pressure where the air molecules are closer together than usual. A rarefaction is the opposite. The wavelength of the sound wave is equal to the distance between the centres of two successive compressions. no sound wavesound wave wavelength loudspeaker rarefaction compression
  • 4. Range of hearing Humans can hear sound frequencies in the range 20 Hz to 20 000 Hz. Age and damage reduces the upper limit. For example an old person or someone exposed to prolonged high sound volume may no be able to hear above 10 000 Hz. Some animals can hear much higher frequencies: bats and dolphins: up to 100 000 Hz dogs – 40 000 to 60 000 Hz (depends on the breed)
  • 5. Ultrasound and Infrasound Ultrasound is high frequency sound, above 20 000 Hz, too high to be heard by humans. Ultrasound echoes can be used to measure distance (e.g. sonar) and to see inside objects (scans). Infrasound is low frequency sound, inaudible to human, although we may feel the very slow vibrations. Earthquake waves are a form of infrasound. Elephants and some other large animals can hear infrasound.
  • 6. Sound waves in different materials Sound travels quickest through solids. A train can often be hared approaching through the rails before it can be heard through the air. Sound travels well through liquids. Whales can communicate over great distances under water. Sound travels slowest through gases. The speed of sound increases with temperature. Sound does not travel through a vacuum. Sound does not travel in space. Poster for the movie ‘Alien’ (1979)
  • 7. Reflection of sound Question: A misguided child shouts ‘Barca!’ at a nearby cliff and hears an echo 1.4 s later. How far away is the cliff? Take the speed of sound = 340 m/s. distance, D The sound travels to and from the cliff, a total distance of 2D speed = distance / time becomes: distance = speed x time = 340 m/s x 1.4 s = 476 m = 2D ! Therefore distance to the cliff = 238 m. An echo is a reflected sound wave.
  • 8. cooler air A B C The sound produced by person A may be heard more clearly by person B than by person C. The cooler air over the water refracts the sound waves downwards. Sound refraction
  • 9. A typical sound wave has a wavelength of about 1m. This is similar in size to the aperture of a doorway. Therefore sound undergoes significant diffraction at a doorway or around the corner of a building. This is why we can hear someone in such circumstances even thought we cannot see them. Sound diffraction TRIPLE ONLY Why does light not diffract as much as sound? The wavelength of light is about 0.000 5mm – much smaller than a door aperture.
  • 10. Measuring the speed of sound Method 1: Using a visible loud event Use a stopwatch to time the difference between seeing and hearing the event (for example an explosion). Measure the distance between the event an the timing position. Speed = distance / time. Note: The distance should be as large as possible in order to avoid significant reaction time error in the timing measurement.
  • 11. Question A group of students measured the time taken between seeing and hearing another student, 250 m away, clashing two pieces of wood together. They obtained the following timings in seconds: 0.73, 0.78, 0.69, 0.81, 0.77. Use their measurements to obtain a speed of sound estimate. average time = (0.73 + 0.78 + 0.69 + 0.81 + 0.77) / 5 = 3.78 / 5 = 0.756 s speed = distance / time = 250 m / 0.756 s = 4 080 m speed of sound = 331 m/s
  • 12. Measuring the speed of sound Method 2: Using echoes Facing a flat vertical surface (wall or cliff) at least 50m away one person clashes two pieces of wood together. This person should try to clap the pieces of wood in time with the echo they hear coming back from the flat surface. Another person times 20 claps on a stop-watch. They should count: 0, 1, 2 ,3 …. 20. Measure the distance, D between the clapping person an the flat surface. The total distance travelled by the sound will be 20 x 2D Speed = total distance / time for 20 claps.
  • 13. Question In an experiment to measure the speed of sound by the echo method when a student stands 75m away from a wall 20 claps are heard over a time of 8.77s. Calculate the speed of sound. total distance travelled by the sound = (20 x 2 x 75)m = 3000m speed = total distance / time for 20 claps = 3000m / 8.77s speed of sound = 342 m/s
  • 14. Speed of sound examples Substance and temperature Speed in m/s Air at 0ºC 330 Air at 20ºC Air at -10ºC Fresh water at 25ºC Sea water at 25ºC Steel at 20ºC Vacuum 330 342 1 497 1 560 324 5 000 0
  • 15. Mach numbers Mach number = object speed speed of sound
  • 16. Thunder and lightning An observer, 3 miles away, sees a lightning flash about 15 seconds before hearing thunder Light reaches the observer in 16 millionths of a second The sound of thunder reaches the observer in about 15 seconds Every 5 second difference equates to a distance of 1 mile STORM CLOUD LIGHTNING
  • 17. Thunder and lightning question A thunderclap is heard 12 seconds after a lightning flash. Calculate the distance to the lightning flash. Take the speed of sound = 340 m/s speed = distance / time becomes: distance = speed x time = 340 m/s x 12 seconds = 4 080 m Distance = 4.08 km
  • 18. Sound waves on oscilloscopes An oscilloscope is a device that with a microphone attached can be used to display a sound wave. The screen displays a graph of how the amplitude of the sound wave varies with time. TRIPLE ONLY
  • 19. Loudness The loudness of a sound increases with the amplitude of the sound wave. quiet loud TRIPLE ONLY
  • 20. Pitch The pitch of a musical note increases with frequency. Examples: Concert pitch A = 440 Hz; Top C = 523 Hz Doubling the frequency increases the pitch by one octave. Therefore the ‘A’ above top C will have frequency 880 Hz. low pitch high pitch TRIPLE ONLY
  • 21. Quality or timbre The quality or timbre of a musical note is what makes one musical instrument sound different from another. Despite different instruments producing a note of the same loudness and pitch, the shape of the wave will be different. TRIPLE ONLY
  • 22. Question The diagram opposite shows the appearance of a sound wave on an oscilloscope. Draw a second diagram showing the appearance of a sound wave of lower pitch but greater loudness. TRIPLE ONLY
  • 23. Measuring frequency using an oscilloscope The time taken between peaks on an oscilloscope trace is equal to the time period, T of the sound wave. frequency = 1 / period f = 1 / T example: if T = 0.05s f = 1 / 0.05 frequency = 20Hz time period TRIPLE ONLY
  • 24. Question The distance between peaks on an oscilloscope trace is 4cm. If the oscilloscope time scale is set at 1ms/cm calculate the frequency of the sound. 1ms/cm means that the trace covers 1cm in one millisecond (0.001s) time period, T = 4cm x 1ms/cm = 4ms (0.004s) f = 1 / T f = 1 / 0.004 frequency = 250Hz 4 cm TRIPLE ONLY