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y
x
lbfF 1171 
lbfF 2172 
lbfF 3173 
lbfF 5174 
lbfF 4175 
LANGKAH – LANGKAH
TENTUKAN SUMBU X DAN Y  DITARIK DARI EKOR VEKTOR
y
x
lbfF 1171 
lbfF 2172 
lbfF 3173 
lbfF 5174 
lbfF 4175 
o
57
o
33
o
47
o
43
o
63
o
27
yF5
yF1
xF5 xF2 xF1
yF2
  o
FxF 43cos.11
  85.56841xF
  o
1 F1.sin43yF
  79.79381 yF
  o
FxF 63cos.22
  o
FyF 63sin.22
 193.3482 yF
  o
FxF 33cos.55
  349.7265 xF
  o
FyF 33sin.55
  227.1145 yF
  98.51592 xF
  4521 FxFxFxFFx
  -682.641Fx
  3521 FyFyFyFFy
  -203.44Fy
  22
FyFxR
    
22
203.44-682.641-R
712.311R











Fx
Fy1
tan






 
682.641-
203.44-
tan 1

0.28964
Proyeksi vektor faperika unri msp 2015 achmad sovy yusaputra 1504112817

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Proyeksi vektor faperika unri msp 2015 achmad sovy yusaputra 1504112817

  • 1. y x lbfF 1171  lbfF 2172  lbfF 3173  lbfF 5174  lbfF 4175  LANGKAH – LANGKAH TENTUKAN SUMBU X DAN Y  DITARIK DARI EKOR VEKTOR
  • 2. y x lbfF 1171  lbfF 2172  lbfF 3173  lbfF 5174  lbfF 4175  o 57 o 33 o 47 o 43 o 63 o 27 yF5 yF1 xF5 xF2 xF1 yF2
  • 3.   o FxF 43cos.11   85.56841xF   o 1 F1.sin43yF   79.79381 yF   o FxF 63cos.22   o FyF 63sin.22  193.3482 yF   o FxF 33cos.55   349.7265 xF   o FyF 33sin.55   227.1145 yF   98.51592 xF
  • 4.   4521 FxFxFxFFx   -682.641Fx   3521 FyFyFyFFy   -203.44Fy   22 FyFxR      22 203.44-682.641-R 712.311R            Fx Fy1 tan         682.641- 203.44- tan 1  0.28964