IGNOU UNIVERSITY SOLVED ASSIGNMENTS

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Course Code : MCS-011
Course Title : Problem Solving and Programming
Assignment Number : MCA(1)/011/Assign/13
Maximum Marks : 100
Weightage : 25%
Last Dates for Submission : 15th October, 2013 (For July 2013 Session) 15th April, 2014 (For
January 2014 Session)
There are six questions in this assignment, which carry 80 marks. Rest 20 marks are for viva-voce.
Answer all the questions. You may use illustrations and diagrams to enhance the explanations.
Please go through the guidelines regarding assignments given in the Programme Guide for the
format of presentation. Insert comments in the coding for better understanding.
Question 1:
Write a C program to find out perfect numbers from 1 and 50 .
Solution :
#include<stdio.h>
#include<conio.h> voidmain()
{
voidperfect(); clrscr(); perfect(); getch();
}
void perfect()
{
int n,i,s,lim; lim=1; while(lim<=50)
{ i=1;s=0;
while(i<lim)
{
if(lim%i==0)
{
s=s+i;
} i++;
}
if(s==lim)

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printf("perfect no =%dn",lim); lim++;
}
}
 Question 2: Write an algorithm, draw a corresponding flowchart and write an interactive
program to convert a binary number to its octal equivalent.
Solution :
Alogrithm:
Binary to octal conversion method:
Step1: Arrange the binary number in the group 3 from
right side.
Step 2: Replace the each group with following
values:
Binary number Octal values
000 0
001 1
010 2
011 3
100 4
101 5
110 6
111 7
Binary to octal chart
Binary to octal conversion examples:
For example we want to convert binary number
1011010101001101 to octal.
Step 1: 001 011 010 101 001 101
Step 2: 1 3 2 5 1 5
So (1011010101001101)2 = (132515)8

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c program to convert binary to octal
#include<stdio.h>
int main(){
long int binaryNumber,octalNumber=0,j=1,remainder;
printf("Enter any number any binary number: ");
scanf("%ld",&binaryNumber);
while(binaryNumber!=0){
remainder=binaryNumber%10;
octalNumber=octalNumber+remainder*j;
j=j*2;
binaryNumber=binaryNumber/10;
}
printf("Equivalent octal value:
%lo",octalNumber);
return 0;
}
Sample output:
Enter any number any binary number: 1101
Equivalent hexadecimal value: 15

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Question 3 : Write the function strreplace(s, chr, repl_chr)
which will replace each occurrences of character chr with the
character repl_chr in the string s. The function returns the
number of replacements. Place the source code of this function in
a file named strreplace.c
Solution :
char *replace_str(const char *str, const char *old, const char
*new)
{
char *ret, *r;
const char *p, *q;
size_t oldlen = strlen(old);
size_t count, retlen, newlen = strlen(new);
if (oldlen != newlen) {
for (count = 0, p = str; (q = strstr(p, old)) != NULL; p = q +
oldlen)
count++;
/* this is undefined if p - str > PTRDIFF_MAX */
retlen = p - str + strlen(p) + count * (newlen - oldlen);
} else
retlen = strlen(str);
if ((ret = malloc(retlen + 1)) == NULL)
return NULL;
for (r = ret, p = str; (q = strstr(p, old)) != NULL; p = q +
oldlen) {
/* this is undefined if q - p > PTRDIFF_MAX */

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ptrdiff_t l = q - p;
memcpy(r, p, l);
r += l;
memcpy(r, new, newlen);
r += newlen;
}
strcpy(r, p);
return ret;
}
Question 4: Writer an interactive C program to check whether the given string is a palindrome or
not, using pointers.
Solution :
#include<stdio.h>
#include<conio.h>
int main()
{
char str[30];
char *p,*t;
printf("Enter any string : ");
gets(str);
for(p=str ; *p!=NULL ; p++);
for(t=str, p-- ; p>=t; )
{
if(*p==*t)
{
p--;
t++;
}

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else
break;
}
if(t>p)
printf("nString is palindrome");
else
printf("nString is Not palindrome");
getch();
return 0;
}
Question 5: Write an interactive program called “WEIGHT CONVERTER” that accepts the
weight in milligrams / decigrams / centigrams / kilograms /ounces / pounds / tons and displays its
equivalent in grams .
Solution :
#include <stdio.h>
void print_converted(int pounds)
/* Convert U.S. Weight to Imperial and International
Units. Print the results */
{ int stones = pounds / 14;
int uklbs = pounds % 14;
float kilos_per_pound = 0.45359;

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float kilos = pounds * kilos_per_pound;
printf(" %3d %2d %2d %6.2f", pounds, stones, uklbs, kilos);
}
Main (int argc,char *argv[])
{ int pounds;
if(argc != 2)
{ printf ("Usage: convert weight_in_pounds");
exit(1);
}
Sscanf (argv[1], "%d", &pounds); /* Convert String to int */
Printf (" US lbs UK st. lbs INT Kg");
print_converted (pounds);
}

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Question 6. Write an interactive program to generate pay slips for the staff of size 12 employees
(2 members are clerks, one computer operator, 6 salesmen, 3 helpers) , working in a small chemist
retail shop.
Assumptions can be made wherever necessary. The payslip should display the employee no.,
employee name, no. of days worked during the month, date of generation of the payslip, month
for which the salary is being paid, all the details of the payment, deductions, gross-pay and net-
pay.
Solution :
#include<stdio.h>
#include<conio.h> void main()
{
int n,i,k;
struct employee
{
char name[50],des[30],mon[10],level; int empid,accno;
float hra,da,cca,ca,gpf,grossal,totdeduc,netsal,basic;
}emp[10];
clrscr();
printf("ENTER THE NUMBER OF EMPLOYEE: ");
scanf("%d",&n); for(i=1;i<=n;i++)
{
printf("n ENTER NAME OF THE EMPLOYEE:");
scanf("%s",emp[i].name);
printf("n ENTER DESIGANTION OF THE EMPLOYEE:");
scanf("%s",emp[i].des); printf("n ENTER MONTH:"); scanf("%s",emp[i].mon);
printf("n ENTER EMPLOYEE ID:");
scanf("%d",&emp[i].empid); printf("n ENTER ACCNO:"); scanf("%d",&emp[i].accno);
printf("nENTER BASIC PAY: ");
scanf("%f",&emp[i].basic);
printf("ENTER CITY LEVEL: ");
scanf("%s",&emp[i].level);

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}
for(i=1;i<=n;i++)
{
emp[i].hra=emp[i].basic*0.30; if(emp[i].basic<=6500)
emp[i].ca=100; else
{
if(emp[i].basic>6500&&emp[i].basic<=8000)
emp[i].ca=400; else emp[i].ca=800;
}
emp[i].da=emp[i].basic/2; if(emp[i].level=='a'||emp[i].level=='A')
emp[i].cca=400; else
{
if(emp[i].level=='b'||emp[i].level=='B') emp[i].cca=100;
else
emp[i].cca=50;
}
emp[i].gpf=emp[i].basic * 0.075; emp[i].grossal=emp[i].basic+emp[i].hra+emp[i].da+emp[ i].cca;
emp[i].totdeduc=emp[i].gpf;
emp[i].netsal=emp[i].grossal-emp[i].totdeduc;
}
for(i=1;i<=n;i++)
{
do
{ clrscr();
printf("ntt V R SIDDHARTHA ENGINEERNG COLLEGE");
printf("nttt KANURU::VIJAYAWADA-7n"); printf("ntttt PAY SLIP");

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printf("nttt************************"); printf("nttt Salary Slip for %s ",emp[i].mon);
printf("nttt***********************"); printf("nn tNAME: %s tttEMPID: %d
",emp[i].name,emp[i].empid);
printf("nn tDESIGNATION:%s
ttACCNO:%d",emp[i].des,emp[i].accno);
printf("n-----------------------------------------
----n");
printf("<----------EARNINGS----------> <------- DEDUCTIONS------------>n");
printf("n BASIC=%f
ttttP.F.=%.2f",emp[i].basic,emp[i].gpf);
printf("nn D.A=%.2f ttttINCOME TAX=",emp[i].da);
printf("nn H.R.A=%.2f ttttP.F. LOAN=",emp[i].hra);
printf("nn C.C.A=%.2f
ttttL.I.C=",emp[i].cca);
printf("nn---------------------------------------
----------");
printf("nn GROSS SALARY=%.2f ttTOTAL DEDUCTIONS=%.2f " ,emp[i].grossal,emp[i].totdeduc);
printf("nn---------------------------------------
------------");
printf("nnttt NET SALARY=%.2f",emp[i].netsal); printf("nn---------------------------------------
------------");
printf("nnnttttttEMPLOYEE SIGNATURE"); printf("nnnPRESS 1 TO NEXT ......");
scanf("%d",&k);
}while(k==2);
}
getch();
}
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