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Projection Md. Sahidul Islam Ripon Department of statistics  Rajshahi University Email: ripon.ru.statistics@gmail.com
Content ,[object Object],[object Object],[object Object],[object Object]
Orthogonal vector ,[object Object],[object Object],Fig :  The line segments AB and CD are orthogonal to each other
Orthogonal vector x y x + y Pythagoras,  This always not true. This only true when
Example Are the vector (1,2,2) T  and (2,3,-4) T  are orthogonal ? Are the vector (4,2,3) T  and (7,3,-4) T  are orthogonal ?
Theorem 1:  An orthogonal set of non zero vectors in a vector space is linearly independent.
Subspace S is orthogonal to subspace T How??? row space is orthogonal to null space Orthogonal Subspace
Orthonormal vector  ,[object Object],Example:  Two vector   are said to be orthogonal
Orthonormal vector Theorem: Let { u 1 , …, u n } be an orthonormal basis for a vector space V. Let v be a vector in V. v can be written as a linear combination of these vectors as follows.  Proof:  Since  { u 1 , …, u n } is a basis there exist scalars c 1 ,…,c n  such that  v= c 1 u 1 +…+c n  u n   We shall  show that, c 1  =v 1  .u 1 ,…,c n  =v n  .u n
Projection ,[object Object]
Projection ,[object Object],[object Object]
Orthogonal projection ,[object Object],[object Object],[object Object],[object Object]
 
Projection Graph
Orthogonal projection
[object Object],[object Object]
[object Object],[object Object],[object Object]
E xample ,[object Object],[object Object],[object Object],[object Object],Find the orthogonal projection of Y=(2,7,1) on to the vector X=(5,6,4)
Projection on to a plan
Find the orthogonal projection of Y=(7,7,8) on to the plane spanned by vector X 1 =(5,6,4) and X 2 =(9,5,1). Solution:  Since must lie in the plane spanned by X 1  and X 2
[object Object]
Application ,[object Object],[object Object],[object Object]
Gram Schmit Orthogonalization ,[object Object],[object Object],[object Object],[object Object],[object Object],Jorgen Pedersen Gram (1850 - 1916) Erhard Schmidt (1876 - 1959)
Gram Schmit Orthogonalization Let  be a basis for vector space V. The set of vector  defined as follows is orthogonal. To obtain a orthogonal basis for V, normalized each of the vector
Fig:  First two steps of Gram schmidt orthogonalization Geometric Interpretation
Consider the following set of vectors in  R 2  (with the conventional inner product) Now, perform Gram–Schmidt, to obtain an orthogonal set of vectors: We check that the vectors  u 1  and  u 2  are indeed orthogonal: noting that if the dot product of two vectors is  0  then they are orthogonal. We can then normalize the vectors by dividing out their sizes as shown above: ; Example
Example ,[object Object],[object Object],[object Object]
 
 
 
Modified Gram-Schmidt orthogonalization When this process is implemented on a computer, the vectors  u k  are often not quite orthogonal, due to  rounding errors . For the Gram–Schmidt process as described above (sometimes referred to as "classical Gram–Schmidt") this loss of orthogonality is particularly bad; therefore, it is said that the (classical) Gram–Schmidt process is  numerically unstable . The Gram–Schmidt process can be stabilized by a small modification; this version is sometimes referred to as  modified Gram-Schmidt  or MGS. This approach gives the same result as the original formula in exact arithmetic and introduces smaller errors in finite-precision arithmetic. Instead of computing the vector  u k  as it is computed as Each step finds a vector  orthogonal to  .  Thus  is also orthogonalized against any errors introduced in computation of  .
Modified Gram-Schmidt orthogonalization
[object Object],Making approximation
Classical Vs Modified
Classical Vs Modified
Classical Vs Modified ,[object Object]
Curve fitting by ordinary least square method ,[object Object]
Refference ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object]

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Orthogonal porjection in statistics

  • 1. Projection Md. Sahidul Islam Ripon Department of statistics Rajshahi University Email: ripon.ru.statistics@gmail.com
  • 2.
  • 3.
  • 4. Orthogonal vector x y x + y Pythagoras, This always not true. This only true when
  • 5. Example Are the vector (1,2,2) T and (2,3,-4) T are orthogonal ? Are the vector (4,2,3) T and (7,3,-4) T are orthogonal ?
  • 6. Theorem 1: An orthogonal set of non zero vectors in a vector space is linearly independent.
  • 7. Subspace S is orthogonal to subspace T How??? row space is orthogonal to null space Orthogonal Subspace
  • 8.
  • 9. Orthonormal vector Theorem: Let { u 1 , …, u n } be an orthonormal basis for a vector space V. Let v be a vector in V. v can be written as a linear combination of these vectors as follows. Proof: Since { u 1 , …, u n } is a basis there exist scalars c 1 ,…,c n such that v= c 1 u 1 +…+c n u n We shall show that, c 1 =v 1 .u 1 ,…,c n =v n .u n
  • 10.
  • 11.
  • 12.
  • 13.  
  • 16.
  • 17.
  • 18.
  • 20. Find the orthogonal projection of Y=(7,7,8) on to the plane spanned by vector X 1 =(5,6,4) and X 2 =(9,5,1). Solution: Since must lie in the plane spanned by X 1 and X 2
  • 21.
  • 22.
  • 23.
  • 24. Gram Schmit Orthogonalization Let be a basis for vector space V. The set of vector defined as follows is orthogonal. To obtain a orthogonal basis for V, normalized each of the vector
  • 25. Fig: First two steps of Gram schmidt orthogonalization Geometric Interpretation
  • 26. Consider the following set of vectors in R 2 (with the conventional inner product) Now, perform Gram–Schmidt, to obtain an orthogonal set of vectors: We check that the vectors u 1 and u 2 are indeed orthogonal: noting that if the dot product of two vectors is 0 then they are orthogonal. We can then normalize the vectors by dividing out their sizes as shown above: ; Example
  • 27.
  • 28.  
  • 29.  
  • 30.  
  • 31. Modified Gram-Schmidt orthogonalization When this process is implemented on a computer, the vectors u k are often not quite orthogonal, due to rounding errors . For the Gram–Schmidt process as described above (sometimes referred to as "classical Gram–Schmidt") this loss of orthogonality is particularly bad; therefore, it is said that the (classical) Gram–Schmidt process is numerically unstable . The Gram–Schmidt process can be stabilized by a small modification; this version is sometimes referred to as modified Gram-Schmidt or MGS. This approach gives the same result as the original formula in exact arithmetic and introduces smaller errors in finite-precision arithmetic. Instead of computing the vector u k as it is computed as Each step finds a vector orthogonal to . Thus is also orthogonalized against any errors introduced in computation of .
  • 33.
  • 36.
  • 37.
  • 38.
  • 39.