Solution to the weekly extreme Str8ts puzzle #13 from www.str8ts.com

1. Weekly Extreme Str8ts Puzzle #13www.str8ts.com Solution bySlowThinker

2. Start

3. C8=3c, A8=4d, B8=1s, B7=2s, B9=3s

4. A9=5s, A7=3s, C9=2s, G9=7h

5. D9=1p, D7=5s, H6=5s, G5=5s

6. Setti‘sruleappliedto 4  H3=1s Setti‘s rule applied to 4: all columns contain a 4  4 must be set in all rows  B1..5:-9c  J123=2345 (-1c)  H3=1s

7. H9=4Setti, F9=8s, H7=6c, H8=8c H9 istheonly 4 in row H now H9=4

8. J7=7s, F7=9s, J8=6s, J6=8s, G8=9s, G6=6s, F8=7s

9. Uniquenessconstraint: J1=5 The green area (GHJ12) only contains the digits 2345. If 5 in J1 were to be removed, the uniqueness constraint would be violated  J1 has to be 5 (Uniqueness idea by Siegbert in the str8ts.de forum.)

10. J1=5u, J3=4c, J2=3s, F3=2s

11. H2=2s, H1=3s, G2=4s, G1=2s

12. F4=5s, C2=5s, D2=7c, A2=6c

13. E6=7sD..J6, E4=8c, E5=9c, E1=4Setti We still knowthatthere must be a 4 in everyrow E1=4

14. F1=6s, B1=7s, A4=7s, A3=8s, C3=7s

15. C4=6s, C5=8s, C1=9s, D1=8s, B1=4s

16. B5=6s, D5=4s, D6=9s, F5=3s, F6=4s Done

17. Weekly Extreme Str8ts Puzzle #13www.str8ts.com Solution by SlowThinker (Uniqueness idea by Siegbert) Note: There are other (maybe easier or more logical) ways to solve this puzzle.