This document discusses Boyle's law, which states that the pressure and volume of a gas are inversely proportional when temperature and amount of gas are kept constant. It provides examples of how Boyle's law can be applied to calculate changes in pressure or volume. For instance, if the volume of a gas decreases, the pressure must increase according to the relationship PV=constant. The document also explains how Boyle's law relates to breathing through examples of how lung pressure and volume change during inhalation and exhalation. It includes sample problems and solutions for calculating new volumes or pressures using the formula for Boyle's law.
5. What is Boyle’s Law?
•Boyle’s Law is one of the laws in
physics that concern with the
behaviour of gases
•When a gas is under pressure it
takes up less space
•The higher the pressure, the
smaller the volume
8. Boyle’s Law
Boyle’s Law states that
•the pressure of a gas
is inversely related to
its volume when T and
n are constant.
•if volume decreases,
the pressure
increases.
8
9. PV Constant in Boyle’s Law
Boyle’s Law can be stated as:
P1V1 = P2V2
(T, n constant)
9
17. LET’S USE GRASA IN SOLVING:
•G
•R
•A
•S
•A 17
GIVEN
REQUIRE
D
ANSWER
SOLUTION
ANALYSIS
18. Calculation with Boyle’s Law
Freon-12, CCl2F2, is used in refrigeration
systems. What is the new volume (L) of a 8.0
L sample of Freon gas initially at 550 mm Hg
after its pressure is changed to 2200 mm Hg at
constant T?
1. Set up a data table:
Conditions 1 Conditions 2
P1 = 550 mm Hg P2 = 2200 mm Hg
V1 = 8.0 L V2 =
18
?
19. Calculation with Boyle’s Law (Continued)
2. When pressure increases, volume decreases.
Solve Boyle’s Law for V2:
P1V1 = P2V2
V2 = V1 x P1
P2
V2 = 8.0 L x 550 mm Hg = 2.0 L
2200 mm Hg
pressure ratio 19
20. Learning Check
For a cylinder containing helium gas indicate if
cylinder A or cylinder B represents the new volume
for the following changes (n and T are constant).
1) pressure decreases
2) pressure increases
20
21. Solution
For a cylinder containing helium gas indicate if
cylinder A or cylinder B represents the new volume
for the following changes (n and T are constant):
1) Pressure decreases B
2) Pressure increases A
21
22. Learning Check
If a sample of helium gas has a volume
of 120 mL and a pressure of 850 mm
Hg, what is the new volume if the
pressure is changed to 425 mm Hg ?
1) 60 mL 2) 120 mL 3) 240 mL
22
23. Solution
3) 240 mL
P1 = 850 mm Hg P2 = 425 mm Hg
V1 = 120 mL V2 = ??
V2= V1 x P1= 120 mL x 850 mm Hg = 240 mL
P2 425 mm Hg
Pressure
ratio increases volume
23
24. Learning Check
A sample of helium gas in a balloon has a
volume of 6.4 L at a pressure of 0.70 atm. At
1.40 atm (T constant), is the new volume
represented by A, B, or C?
24
25. Solution
A sample of helium gas in a balloon has a volume
of 6.4 L at a pressure of 0.70 atm. At a higher
pressure (T constant), the new volume is
represented by the smaller balloon A.
25
26. Learning Check
If the sample of helium gas has a
volume of 6.4 L at a pressure of 0.70
atm, what is the new volume when the
pressure is increased to 1.40 atm (T
constant)?
A) 3.2 L B) 6.4 L C) 12.8 L 26
27. Solution
If the sample of helium gas has a volume of 6.4 L at a pressure of
0.70 atm, what is the new volume when the pressure is increased
to 1.40 atm (T constant)?
A) 3.2 L
V2 = V1 x P1
P2
V2 = 6.4 L x 0.70 atm = 3.2 L
1.40 atm
Volume decreases when there is an increase in the pressure
(temperature is constant.)
27
28. Learning Check
A sample of oxygen gas has a
volume of 12.0 L at 600. mm Hg.
What is the new pressure when
the volume changes to 36.0 L? (T
and n constant).
1) 200. mm Hg
2) 400. mm Hg
3) 1200 mm Hg
28
29. Solution
1) 200. mm Hg
Data table
Conditions 1 Conditions 2
P1 = 600. mm Hg P2 = ???
V1 = 12.0 L V2 = 36.0 L
P2 =P1 x V1
V2
600. mm Hg x 12.0 L = 200. mm Hg
36.0 L 29
30. LET’S DO IT!
•1. Oxygen gas inside a 1.5 L gas tank has a
pressure of 0.95 atm. Provided that the
temperature remains constant, how much
pressure is needed to reduce by ½?
•Required:?
•Pressure ₂/P₂
30
31. LET’S DO IT!
•1. Oxygen gas inside a 1.5 L gas tank has a pressure
of 0.95 atm. Provided that the temperature remains
constant, how much pressure is needed to reduce by
½?
•GIVEN:
•V₁=1.5L
•P₁=0.95atm
•V₂=½( V₁)
•P₂=? 31
32. LET’S DO IT!
•1. Oxygen gas inside a 1.5 L gas tank has a
pressure of 0.95 atm. Provided that the
temperature remains constant, how much
pressure is needed to reduce by ½?
•FORMULA:
•P2=P1V1/V2
32
33. LET’S DO IT!
•1. Oxygen gas inside a 1.5 L gas tank has a pressure
of 0.95 atm. Provided that the temperature remains
constant, how much pressure is needed to reduce by
½?
• FINAL ANSWER:
•1.9 atm
•The volume is reduced/decreased so pressure
increase
33
34. LET’S DO IT!
•1.A scuba diver needs a diving tank in order to
provide breathing gas while he is underwater.
How much pressure is needed for 6L of gas at
1.01 atmospheric pressure to be compressed in
a 3L cylinder?
•2. a sample of fluorine gas occupies a volume of
600mL at 760 torr. Given that the temperature
remains the same, calculate the pressure
required to reduce its volume by 1/3?
34