![p = 0.0004. Compute the probability of failure of the system. Component failures are
independentof one another.
Solution
P(system failure)=1-P(system not failure)
now p(system not failure)
= [1-p(component failure)]^11
=[1-0.0004]^11
=(0.9996)^11
=0.99560878944
so
P(system failure)=1-0.99560878944=0.00439121055 ans](https://image.slidesharecdn.com/p0-230325094244-2f545c48/85/p-00004-compute-the-probability-of-failure-of-the-system-componpdf-1-320.jpg)
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Probability of system failure with 11 independent components
- 1. p = 0.0004. Compute the probability of failure of the system. Component failures are independentof one another. Solution P(system failure)=1-P(system not failure) now p(system not failure) = [1-p(component failure)]^11 =[1-0.0004]^11 =(0.9996)^11 =0.99560878944 so P(system failure)=1-0.99560878944=0.00439121055 ans