Consider the sample of the following data: 13 5 202 15 99 4 67 83 36 11 301 23 213 40 66 106 78 69 166 84 64 Obtain a 92% confidence interval for the median ?1/2 Solution j = nq - 1.92 root(nq(1-q)) k = nq + 1.92 root(nq(1-q)) n=21 median = 301 [11th value] q=0.5 j=6.1 k=14.899 => 92% confidence interval is from 7th to 15th value.