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A man at A walks to a neigborhoring town, B, at the rate of 5mph and.pdf

2 de Apr de 2023
A man at A walks to a neigborhoring town, B, at the rate of 5mph and.pdf
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A man at A walks to a neigborhoring town, B, at the rate of 5mph and.pdf

  1. A man at A walks to a neigborhoring town, B, at the rate of 5mph and returns at a alower rate of 4mph. if it took him 3 hours and 9 minutes for the entire trip, how far is town from A. Solution D=RT T=D/R 3.15=D/5+D/4 3.15=(4D+5D)/20 3.15=9D/20 CROSS MULTIPLY. 9D=20*3.15 9D=63 D=63/9 D=7 MILES BETWEEN A & B. PROOF: 3.15=7/5+7/4 3.15=(4*7+5*7)/20 3.15=(28+35)/20 3.15=63/20 3.15=3.15
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