# a normal distribution has a man of 80 and a standard deviation of 14.pdf

A

a normal distribution has a man of 80 and a standard deviation of 14. Determine the value above which 80 percent of the value will occur Solution from a table: left-tail | P(z<-0.842) = 0.2 z score = obs-exp / sd -0.842=(x-80)/14 x=68.2.

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