1. Andrés Mancebo
2Batx A
8.
a)
R2,3 =2+4= 6Ω
R2,3,4 = (6x3/6+3) = 2Ω
RT = 2+2+1 = 5Ω
b)
R1,2 = 10+20= 30Ω
R1,2,3 = (30x15/30+15) = 10Ω
R1,2,3,4 = 10+5 = 15Ω
R5,6 = 10+10 = 20Ω
RT= (20x15/20+15) = 8,57Ω
c)
R2,3= 2200+680= 2880Ω
R2,3,4,5= 759Ω
R1,2,3,4,5= 1000+759 = 1759Ω
RT= (1759x4700/1759+4700= 1280 Ω

2. d)
R2,3,4 = 217,47Ω
R2,3,4,5 = 217,47+330 =547,47Ω
R2,3,4,5,6= (547,47x2200 / 547,47+2200) =438,38Ω
R1,2,3,4,5,6= 1000+438,38 = 1438,38Ω
RT = (1438,38x820 / 1438,38+820) =522,27Ω

3. 9.
d)
R2,3= 15Ω
R2,3,4=5,22Ω
RT= 6+5,22+2 = 13,22Ω
IT= 10/13,22=0,76A
V1= R1xIT = 4,54V
V2=R5xIT = 1,52V
V2,3,4= VT-V1-V6=3,94 = V4
I4=3,94/8 = 0,5A
I2,3= IT -I4 = 0,26A
V2= 0,26x10= 2,6V
V3= 0,26x5= 1,3V
P1= 3,45W
P2=0,67W
P3=0,338W
P4=1,97W
P5=1,15W
PT=7,578W

4. f)

5. 10.
RT= 2,55Ω
I2= 1A
V2= R2 x I2 = 6V = V1 = V3 = VT
IT = VT / RT = 2,35 A
I1 = VT / R1 = 0,6A
I3 = VT / R3 = 0,75A

6. 11.
VT = 12V
IT = I1 = 3A
I3 = I1 – I2 = 2A
RT = VT / IT = 4Ω
V3 = 3x2 = 6V
V2= 6V = V1
R1= 6/3=2Ω
R2 = 6/1=6Ω
12.

7. 11.
VT = 12V
IT = I1 = 3A
I3 = I1 – I2 = 2A
RT = VT / IT = 4Ω
V3 = 3x2 = 6V
V2= 6V = V1
R1= 6/3=2Ω
R2 = 6/1=6Ω
12.