Date Experiment 3- Aldehydes and Ketones Name- 3- Draw the structural.docx

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Date Experiment 3: Aldehydes and Ketones Name: 3. Draw the structural isomer with the molecular formula C&H120; that satisfies each classification test result described below. (3 pts) a. Negative Schifts Test, Negative Bisulfite Test, Positive lodoform Test b. Positive Schiff\'s Test, Positive Bisulfite Test, Negative Iodoform Test c. Negative Schiff\'s Test, Positive Bisulfite Test, Positive Iodoform Test Solution (a) negative Schiff\'s = cant be aldehyde negative Bisulfite test = cant be aldehyde andmethyl ketone positive iodoform = can be methyl ketone and methyl alcohol => the compound has to be methyl alcohol => H3C-HC (OH)-CH=CH-CH2-CH3 ( this can be one of the isomer) (b) positive Schiff\'s = should be aldehyde positive Bisulfite test = can be aldehyde or methyl ketone negative iodoform = cant be methyl ketone and methyl alcohol => the compound has to be aldehyde => HC (=O)-CH2-CH2-CH2-CH2-CH3 ( only posibility) (c) Negative Schiff\'s = cant be aldehyde Negative Bisulfite test = can be aldehyde or methyl ketone Positive iodoform = can be methyl ketone or methyl alcohol => the compound has to be methyl ketone => H3C-C(=O)-CH2-CH2-CH2-CH3 ( only posibility) .

Date Experiment 3: Aldehydes and Ketones Name: 3. Draw the structural isomer with the
molecular formula C&H120; that satisfies each classification test result described below. (3 pts)
a. Negative Schifts Test, Negative Bisulfite Test, Positive lodoform Test b. Positive Schiff's
Test, Positive Bisulfite Test, Negative Iodoform Test c. Negative Schiff's Test, Positive Bisulfite
Test, Positive Iodoform Test
Solution
(a) negative Schiff's = cant be aldehyde
negative Bisulfite test = cant be aldehyde andmethyl ketone
positive iodoform = can be methyl ketone and methyl alcohol
=> the compound has to be methyl alcohol => H3C-HC (OH)-CH=CH-CH2-CH3 ( this can be
one of the isomer)
(b) positive Schiff's = should be aldehyde
positive Bisulfite test = can be aldehyde or methyl ketone
negative iodoform = cant be methyl ketone and methyl alcohol
=> the compound has to be aldehyde => HC (=O)-CH2-CH2-CH2-CH2-CH3 ( only posibility)
(c) Negative Schiff's = cant be aldehyde
Negative Bisulfite test = can be aldehyde or methyl ketone
Positive iodoform = can be methyl ketone or methyl alcohol
=> the compound has to be methyl ketone => H3C-C(=O)-CH2-CH2-CH2-CH3 ( only
posibility)

Date Experiment 3- Aldehydes and Ketones Name- 3- Draw the structural.docx

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