Find parametric equations for the line through the point, that is parallel to the given plane, and perpendicular to the following line. (0, 3, 2) x + y + z = 5 x = 1 + t, y = 3 - t, z = 2t x = 3s y = z = Solution line is parallel to (1,-1,2) so, the required line is perpendicular to the first line and the normal of the plane so, it\'s parallel to the cross product of \'em = ( i-j+2k)*(i+j+k) =k-j+k- i+2j-2i =-3i+j+2k => eqn of line is x=0-3t, y=3+t,z=2+2t.