1. By: Kishoj Bajracharya (062-BCT-515)
Q. No: 1) Use the linear congruential method to generate the sequence of three two-digit random
integers assuming Xo=27, a=8, c=47 and m=100.
Solution:
Given, Xo = 27, a = 8, c = 47, m = 100
Using formula, Xi = (a * Xi-1 + c) mod(m)
X1 = (8 * 27 + 47) mod (100) = 263 mod (100) = 2.63
Quotient = 2; Remainder or Residue = 63
X1 = Residue = 63;
X2 = (8 * 63 + 47) mod (100) = 551 mod (100) = 5.51
Quotient = 5; Remainder or Residue = 51
X2 = Residue = 51;
X3 = (8 * 51 + 47) mod (100) = 455 mod (100) = 4.55
Quotient = 4; Remainder or Residue = 55
X = (27 63 51 55)
The three two-digit random integers we are looking for are 63, 51 and 55.
Q. No: 2) Use the multiplicative congruential method to generate the four three-digit random integers
assuming Xo=117, a=43, and m=1000.
Solution:
Given, Xo = 117, a =43, m = 1000
Using formula, Xi = (a * Xi-1) mod(m)
X1 = (43 * 117) mod (1000) = 5031 mod (1000) = 5.031
Quotient = 5; Remainder or Residue = 31 (2-digit)
X1 = Residue = 31;
X2 = (43 * 31) mod (1000) = 1333 mod (1000) = 1.333
Quotient = 1; Remainder or Residue = 333 (First 3-digit Random Number)

2. By: Kishoj Bajracharya (062-BCT-515)
X2 = Residue = 333;
X3 = (43 * 333) mod (1000) = 14319 mod (1000) = 14.319
Quotient = 14; Remainder or Residue = 319 (Second 3-digit Random Number)
X3 = Residue = 319;
X4 = (43 * 319) mod (1000) = 13717 mod (1000) = 13.717
Quotient = 13; Remainder or Residue = 717 (Third 3-digit Random Number)
X4 = Residue = 717;
X5 = (43 * 717) mod (1000) = 30831 mod (1000) = 30.831
Quotient = 30; Remainder or Residue = 831 (Fourth 3-digit Random Number)
X = (117 31 333 319 717 831)
The four three-digit random integers we are looking for are 333, 319, 717 and 831.
Q. No: 3) Use the mixed congruential method to generate a sequence of three two-digit random
numbers with Xo=37, a=7, c=29 and m=100.
Solution:
Given, Xo = 37, a = 7, c = 29, m = 100
Using formula, Xi = (a * Xi-1 + c) mod(m)
X1 = (7 * 37 + 29) mod (100) = 288 mod (100) = 2.88
Quotient = 2; Remainder or Residue = 88
X1 = Residue = 88;
X2 = (7 * 88 + 29) mod (100) = 645 mod (100) = 6.45
Quotient = 6; Remainder or Residue = 45
X2 = Residue = 45;
X3 = (7 * 45 + 29) mod (100) = 344 mod (100) = 3.44
Quotient = 3; Remainder or Residue = 44

3. By: Kishoj Bajracharya (062-BCT-515)
X = (37 88 45 44)
The 3 two-digit random numbers we are looking for are 88, 45, and 44.