1.
Write a code that ask the user for the number n of decimal to average.
Then n times the code the user to enter all numbers that you save or accumulate each time.
Finaly print to the console the average of the n values the user entered using the format:
cout << " The average of the " << n << " number you entered is: " << averagedValue <<endl;
Solution
Answer
#include <iostream>
using namespace std;
int main()
{
int n,averagedValue,num,total=0;
cout<<" Enter count of numbers : "; //input count of numbers
cin>>n;
for(int i=1;i<=n;i++)
{
cout<<" Enter number "<<i<<" : "; //input number
cin>>num;
total=total+num; //adds to total
}
averagedValue=total/n; //calculates average
cout<<" The average of the "<<n<<" number you entered is: "<<averagedValue;
return 0;
}