C# Revisiting the concept of arrays - Strings vs. Char Arrays in C#
Review the following code:
string hello1 = \"hello!\" ;
char [] hello2 = new char [10]{ \'h\' , \'e\' , \'l\' , \'l\' , \'o\' , \'!\' , \'\\0\' , \'\\0\' , \'\\0\' , \'\\0\' };
hello1 = \"Hi!\" ;
hello2[1] = \'h\' ;
hello2[2] = \'i\' ;
hello2[3] = \'!\' ;
int len1 = hello1.Length;
int len2 = hello2.Length;
Speak to the ramifications of this code and how strings are handled vs. how arrays of char are handled - declared, initialized, modified. What does this mean for how you use these particular language constructs?
Solution
In the code, hello2 will be containing:
{\'h\',\'h\',\'i\',\'!\',\'o\',\'!\',\'\\0\',\'\\0\',\'\\0\',\'\\0\'};
Because we are assigning the character values to the individual characters of the array.
hello2[3] =\'!\';
After this statement, if we put:
hello2[4] =\'\\0\';
then hello2 will be:
{\'h\' \'h\', \'i\', \'!\', \'\\0\'}
Because \'\\0\' marks the end of the string.
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C# Revisiting the concept of arrays - Strings vs- Char Arrays in C# Re.docx
1. C# Revisiting the concept of arrays - Strings vs. Char Arrays in C#
Review the following code:
string hello1 = "hello!" ;
char [] hello2 = new char [10]{ 'h' , 'e' , 'l' , 'l' , 'o' , '!' , '0' , '0' , '0' , '0' };
hello1 = "Hi!" ;
hello2[1] = 'h' ;
hello2[2] = 'i' ;
hello2[3] = '!' ;
int len1 = hello1.Length;
int len2 = hello2.Length;
Speak to the ramifications of this code and how strings are handled vs. how arrays of char are
handled - declared, initialized, modified. What does this mean for how you use these particular
language constructs?
Solution
In the code, hello2 will be containing:
{'h','h','i','!','o','!','0','0','0','0'};
Because we are assigning the character values to the individual characters of the array.
hello2[3] ='!';
After this statement, if we put:
hello2[4] ='0';
then hello2 will be:
{'h' 'h', 'i', '!', '0'}
Because '0' marks the end of the string.
![C# Revisiting the concept of arrays - Strings vs. Char Arrays in C#
Review the following code:
string hello1 = "hello!" ;
char [] hello2 = new char [10]{ 'h' , 'e' , 'l' , 'l' , 'o' , '!' , '0' , '0' , '0' , '0' };
hello1 = "Hi!" ;
hello2[1] = 'h' ;
hello2[2] = 'i' ;
hello2[3] = '!' ;
int len1 = hello1.Length;
int len2 = hello2.Length;
Speak to the ramifications of this code and how strings are handled vs. how arrays of char are
handled - declared, initialized, modified. What does this mean for how you use these particular
language constructs?
Solution
In the code, hello2 will be containing:
{'h','h','i','!','o','!','0','0','0','0'};
Because we are assigning the character values to the individual characters of the array.
hello2[3] ='!';
After this statement, if we put:
hello2[4] ='0';
then hello2 will be:
{'h' 'h', 'i', '!', '0'}
Because '0' marks the end of the string.](https://image.slidesharecdn.com/crevisitingtheconceptofarrays-stringsvs-chararraysincre-230204022348-14a424fc/85/c-revisiting-the-concept-of-arrays-strings-vs-char-arrays-in-c-redocx-1-320.jpg)
