2. Ernest Rutherford (1871-1937) British physicist, believed in the plum pudding model of the atom. With his associate Hans Geiger(1882-1945) a German physicist, studied the alpha particles emitted by radium which was isolated by Marie and Pierre Curie. Alpha particles are found to be helium atoms with their electrons removed, positively charged and mass of 2500 times that of the electron.
7. Rutherford’s Hypotheses The alpha particles to pass through without changing direction very much Because most of the mass of the atom (positive charges) were spread. Alone they were not enough to stop the alpha particles If the Thomson model were correct, all the alpha particles, travelling at high speeds and massive, would have passed through the metal foil undeflected or only slightly deflected
12. What he got They observed that although majority of the alpha particles passed through undeflected, some were only slightly deflected, some were scattered by more than 90 degrees and a few by nearly 180 degrees or almost completely turned back
13. + How he explained it Atom consists of a very small nucleus surrounded by electrons. Rutherford estimated the radius at 10-12 to 10-13 cm compared to radius of the atom of about 10-8 cm The nucleus contains most of the mass of the atom and all of its positive charge. Alpha particles are deflected by nucleus it if they get close enough at each other
18. ELECTROMAGNETIC SPECTRUM The waves in the spectrum all travel at same speed through a vacuum but differ in the frequency and, therefore, wavelength.
22. Energy states of a Hydrogen Atom When a sample of gaseous H atoms is excited, different atoms absorb different quantities of energy Each atom has one electron, but so many atoms are present that all the energy levels (orbit) are populated by electrons Ground state – lowest energy level (n = 1) Excited state - higher energy level (n= 2…)
23. When dropped from n = 3 orbit (second excited state) = infrared series or lines were emitted by photons –PASCHEN SERIES When dropped from n = 2 orbit (first excited state) = visible series or lines – BALMER SERIES When dropped from n = 1 orbit (ground state) = ultraviolet series or lines – LYMAN SERIES
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25. An electron could jump from one allowed energy state to another by emitting or absorbing photons whose energy corresponds exactly to the energy difference between the two states. ΔE = Ef– Ei Line spectra are produced because these energy changes correspond to photons of specific wavelengths
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27. The PARTICLE Nature of Light Blackbody Radiation Light given off by hot objects Wavelength distribution of the radiation depends on temperature “red-hot” object being cooler than a “white-hot” one
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29. MAX PLANCK ( 1858-1947) Energy can be released or absorbed by atoms only in discrete “chunks” of some minimum size. Quantum – “fixed amount”, smallest amount of energy that can be mitted or absorbed as electromagnetic radiation.
30. Hot glowing object could emit (or absorb) only certain quantities of energy E = hv E = energy of radiation v= frequency h= Planck’s constant ( 6.63 x 10-34 joule-seconds)
31. Hot object’s radiation is emitted by the atoms contained within it. The atom itself can have only certain quantities of energy. The energy is quantized- values are restricted only in certain quantities
39. Radiant energy striking the metal surface is a stream of energy packets PHOTON Behaves like a particle Has an energy proportional to Energy of photon= E = hv
40. A photon transfers its energy to an electron in the metal. A certain amount of energy is required to overcome the attractive forces that hold it within the metal.
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42. Three postulates of Bohr Only orbits of certain radii, corresponding to certain energies, are permitted for electrons in an atom called STATIONARY STATES. – fixed circular orbit An electron in a permitted orbit has a specific energy and is in an “allowed” energy state. Electron will not radiate energy while moving within an orbit. Energy is only emitted or absorbed by an electron as it changes from one allowed energy state to another. This energy is emitted or absorbed as a photon. Ephoton = Estate A – Estate B = hv