A sample of ideal gas has a volume of 3.75 L at 14.20 degrees C and 1.50 atm. What is the
volume of the gas at 18.80 degrees C and 0.987 atm?
A sample of ideal gas has a volume of 3.75 L at 14.20 degrees C and 1.50 atm. What is the
volume of the gas at 18.80 degrees C and 0.987 atm?
Solution
Answer :
Initial pressure = P 1 = 1.5 atm; Initial temperature = T 1 = 14.2 0 C = (273+14.2) K = 287.2
K; Initial volume = V 1 = 3.75 L; Final pressure = P 2 = 0.987 atm; Final temperature = T 2 =
18.8 0 C = (273+18.8) K = 291.8K; Final volume = V 2
According to combined Charles's Law and Boyle's Law,
P 1 V 1 /T 1 = P 2 V 2 /T 2
Or, V2 = P 1 V 1 T 2 / P 2 T 1 = (1.5*3.75*291.8) / (0.987*287.2) L = 5.79 L
Hence the final volume of the gas will be 5.79 L.
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